PHP - How to fix date_format() error 'boolean given, instead of DateTimeInterface'?
I'm getting this error:
"Warning: date_format() expects parameter 1 to be DateTimeInterface, boolean given in C:...myFile.php on line 24"
I've tried that code using strtotime instead of time():
$strDate = time();
$str = strtotime($strDate);
$date = date_create($str);
echo date_format($date, "Y/m/d");
And works: //--> 2018/12/31
But can't understand why, because both strtotime, and time return same Unix timestamps.
$dtObj = date_create(time(), timezone_open("Europe/Oslo"));
echo $dtObj . '</br>'; // Works ok
date_format($dtObj, "d-m-Y"); // This throws error
I expected the same result wiht both codes. Any clue about what's happening?
php date date-format
asked Dec 31 '18 at 18:41
oxk4roxk4r
549
add a comment |
I'm getting this error:
"Warning: date_format() expects parameter 1 to be DateTimeInterface, boolean given in C:...myFile.php on line 24"
I've tried that code using strtotime instead of time():
$strDate = time();
$str = strtotime($strDate);
$date = date_create($str);
echo date_format($date, "Y/m/d");
And works: //--> 2018/12/31
But can't understand why, because both strtotime, and time return same Unix timestamps.
$dtObj = date_create(time(), timezone_open("Europe/Oslo"));
echo $dtObj . '</br>'; // Works ok
date_format($dtObj, "d-m-Y"); // This throws error
I expected the same result wiht both codes. Any clue about what's happening?
php date date-format
asked Dec 31 '18 at 18:41
oxk4roxk4r
549
1
strtotime is returning false, because you're passing an integer in.$strDateis already a time.strtotimeexpects a string, such as'2018-12-30'.date_createdoes the same in your second bit of code, because it expects a string, not a number.
– aynber
Dec 31 '18 at 18:53
add a comment |
I'm getting this error:
"Warning: date_format() expects parameter 1 to be DateTimeInterface, boolean given in C:...myFile.php on line 24"
I've tried that code using strtotime instead of time():
$strDate = time();
$str = strtotime($strDate);
$date = date_create($str);
echo date_format($date, "Y/m/d");
And works: //--> 2018/12/31
But can't understand why, because both strtotime, and time return same Unix timestamps.
$dtObj = date_create(time(), timezone_open("Europe/Oslo"));
echo $dtObj . '</br>'; // Works ok
date_format($dtObj, "d-m-Y"); // This throws error
I expected the same result wiht both codes. Any clue about what's happening?
php date date-format
asked Dec 31 '18 at 18:41
oxk4roxk4r
549
I'm getting this error:
"Warning: date_format() expects parameter 1 to be DateTimeInterface, boolean given in C:...myFile.php on line 24"
I've tried that code using strtotime instead of time():
$strDate = time();
$str = strtotime($strDate);
$date = date_create($str);
echo date_format($date, "Y/m/d");
And works: //--> 2018/12/31
But can't understand why, because both strtotime, and time return same Unix timestamps.
$dtObj = date_create(time(), timezone_open("Europe/Oslo"));
echo $dtObj . '</br>'; // Works ok
date_format($dtObj, "d-m-Y"); // This throws error
I expected the same result wiht both codes. Any clue about what's happening?
php date date-format
php date date-format
asked Dec 31 '18 at 18:41
oxk4roxk4r
549
asked Dec 31 '18 at 18:41
oxk4roxk4r
549
asked Dec 31 '18 at 18:41
oxk4roxk4r
549
asked Dec 31 '18 at 18:41
oxk4roxk4r
549
asked Dec 31 '18 at 18:41
oxk4roxk4r
549
549
1
strtotime is returning false, because you're passing an integer in.$strDateis already a time.strtotimeexpects a string, such as'2018-12-30'.date_createdoes the same in your second bit of code, because it expects a string, not a number.
– aynber
Dec 31 '18 at 18:53
add a comment |
1
strtotime is returning false, because you're passing an integer in.$strDateis already a time.strtotimeexpects a string, such as'2018-12-30'.date_createdoes the same in your second bit of code, because it expects a string, not a number.
– aynber
Dec 31 '18 at 18:53
1
1
strtotime is returning false, because you're passing an integer in.
$strDate is already a time. strtotime expects a string, such as '2018-12-30'. date_create does the same in your second bit of code, because it expects a string, not a number.– aynber
Dec 31 '18 at 18:53
strtotime is returning false, because you're passing an integer in.
$strDate is already a time. strtotime expects a string, such as '2018-12-30'. date_create does the same in your second bit of code, because it expects a string, not a number.– aynber
Dec 31 '18 at 18:53
add a comment |
1 Answer
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oldest
votes
date_create() expects as first parameter a string representing date and time.
Passing a number as you do (you pass time() that return the unix timestamp) will result in date_create returning false that of course cannot be parsed by date_format().
You can read the documentation to see how the data string can be formatted.
You can pass "now" if you want to create a DateTime object set to the present moment.
$dtObj = date_create( "now", timezone_open("Europe/Oslo"));
echo date_format($dtObj, "d-m-Y") . "<br>";
answered Dec 31 '18 at 19:09
PaoloPaolo
9,779244767
Ok, it seems that was the problem. Thank you.
– oxk4r
Jan 1 at 12:10
add a comment |
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1 Answer
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date_create() expects as first parameter a string representing date and time.
Passing a number as you do (you pass time() that return the unix timestamp) will result in date_create returning false that of course cannot be parsed by date_format().
You can read the documentation to see how the data string can be formatted.
You can pass "now" if you want to create a DateTime object set to the present moment.
$dtObj = date_create( "now", timezone_open("Europe/Oslo"));
echo date_format($dtObj, "d-m-Y") . "<br>";
answered Dec 31 '18 at 19:09
PaoloPaolo
9,779244767
Ok, it seems that was the problem. Thank you.
– oxk4r
Jan 1 at 12:10
add a comment |
date_create() expects as first parameter a string representing date and time.
Passing a number as you do (you pass time() that return the unix timestamp) will result in date_create returning false that of course cannot be parsed by date_format().
You can read the documentation to see how the data string can be formatted.
You can pass "now" if you want to create a DateTime object set to the present moment.
$dtObj = date_create( "now", timezone_open("Europe/Oslo"));
echo date_format($dtObj, "d-m-Y") . "<br>";
answered Dec 31 '18 at 19:09
PaoloPaolo
9,779244767
Ok, it seems that was the problem. Thank you.
– oxk4r
Jan 1 at 12:10
add a comment |
date_create() expects as first parameter a string representing date and time.
Passing a number as you do (you pass time() that return the unix timestamp) will result in date_create returning false that of course cannot be parsed by date_format().
You can read the documentation to see how the data string can be formatted.
You can pass "now" if you want to create a DateTime object set to the present moment.
$dtObj = date_create( "now", timezone_open("Europe/Oslo"));
echo date_format($dtObj, "d-m-Y") . "<br>";
answered Dec 31 '18 at 19:09
PaoloPaolo
9,779244767
date_create() expects as first parameter a string representing date and time.
Passing a number as you do (you pass time() that return the unix timestamp) will result in date_create returning false that of course cannot be parsed by date_format().
You can read the documentation to see how the data string can be formatted.
You can pass "now" if you want to create a DateTime object set to the present moment.
$dtObj = date_create( "now", timezone_open("Europe/Oslo"));
echo date_format($dtObj, "d-m-Y") . "<br>";
answered Dec 31 '18 at 19:09
PaoloPaolo
9,779244767
answered Dec 31 '18 at 19:09
PaoloPaolo
9,779244767
answered Dec 31 '18 at 19:09
PaoloPaolo
9,779244767
answered Dec 31 '18 at 19:09
PaoloPaolo
9,779244767
9,779244767
Ok, it seems that was the problem. Thank you.
– oxk4r
Jan 1 at 12:10
add a comment |
Ok, it seems that was the problem. Thank you.
– oxk4r
Jan 1 at 12:10
Ok, it seems that was the problem. Thank you.
– oxk4r
Jan 1 at 12:10
Ok, it seems that was the problem. Thank you.
– oxk4r
Jan 1 at 12:10
add a comment |
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1
strtotime is returning false, because you're passing an integer in.
$strDateis already a time.strtotimeexpects a string, such as'2018-12-30'.date_createdoes the same in your second bit of code, because it expects a string, not a number.– aynber
Dec 31 '18 at 18:53