Run Batch with Drag-and-Drop Parameter in Powershell












0















I have a batch program where I can drag-and-drop a file from my pendrive, and it will copy it onto my computer. I want to create a function in PowerShell (that I will save to the $profile document) so that I can do this in powershell



>>copy-from-pendrive "file-path"


Where "file-path" is the path to the file I want to copy.



I know that I can start batch files with start batch.bat, but how can I pass a parameter in it?



Here is the code for the batch file



@echo off
if [%1] EQU (set /p from="From: ") else (set from=%1)

set from=%from:"=%
set from=%from:E:Elliot=%

echo from E:Elliot%from% to D:UsersElliot%from%" & echo.

xcopy "E:Elliot%from%" "D:UsersElliot%from%" /i /s /e /y

echo.









share|improve this question




















  • 1





    With set from=%from:"=% you want to remove surrounding quotes from this variable? But what is your question and what has to with PowerShell (if it is how can I pass a parameter in it)?

    – double-beep
    Dec 31 '18 at 18:54











  • @double-beep Yes, sorry. I forgot the question mark there. My question is how I could do start batch.bat and specify the file path as the %1 parameter in line 2 of the batch program. And I want to do this in powershell.

    – ElliotThomas
    Dec 31 '18 at 19:00













  • To trim (outer) double quotes from an argument use the ~ modifier. if "%~1"=="" (set /p from="From: ") else (set "from=%~1")

    – LotPings
    Dec 31 '18 at 19:01
















0















I have a batch program where I can drag-and-drop a file from my pendrive, and it will copy it onto my computer. I want to create a function in PowerShell (that I will save to the $profile document) so that I can do this in powershell



>>copy-from-pendrive "file-path"


Where "file-path" is the path to the file I want to copy.



I know that I can start batch files with start batch.bat, but how can I pass a parameter in it?



Here is the code for the batch file



@echo off
if [%1] EQU (set /p from="From: ") else (set from=%1)

set from=%from:"=%
set from=%from:E:Elliot=%

echo from E:Elliot%from% to D:UsersElliot%from%" & echo.

xcopy "E:Elliot%from%" "D:UsersElliot%from%" /i /s /e /y

echo.









share|improve this question




















  • 1





    With set from=%from:"=% you want to remove surrounding quotes from this variable? But what is your question and what has to with PowerShell (if it is how can I pass a parameter in it)?

    – double-beep
    Dec 31 '18 at 18:54











  • @double-beep Yes, sorry. I forgot the question mark there. My question is how I could do start batch.bat and specify the file path as the %1 parameter in line 2 of the batch program. And I want to do this in powershell.

    – ElliotThomas
    Dec 31 '18 at 19:00













  • To trim (outer) double quotes from an argument use the ~ modifier. if "%~1"=="" (set /p from="From: ") else (set "from=%~1")

    – LotPings
    Dec 31 '18 at 19:01














0












0








0








I have a batch program where I can drag-and-drop a file from my pendrive, and it will copy it onto my computer. I want to create a function in PowerShell (that I will save to the $profile document) so that I can do this in powershell



>>copy-from-pendrive "file-path"


Where "file-path" is the path to the file I want to copy.



I know that I can start batch files with start batch.bat, but how can I pass a parameter in it?



Here is the code for the batch file



@echo off
if [%1] EQU (set /p from="From: ") else (set from=%1)

set from=%from:"=%
set from=%from:E:Elliot=%

echo from E:Elliot%from% to D:UsersElliot%from%" & echo.

xcopy "E:Elliot%from%" "D:UsersElliot%from%" /i /s /e /y

echo.









share|improve this question
















I have a batch program where I can drag-and-drop a file from my pendrive, and it will copy it onto my computer. I want to create a function in PowerShell (that I will save to the $profile document) so that I can do this in powershell



>>copy-from-pendrive "file-path"


Where "file-path" is the path to the file I want to copy.



I know that I can start batch files with start batch.bat, but how can I pass a parameter in it?



Here is the code for the batch file



@echo off
if [%1] EQU (set /p from="From: ") else (set from=%1)

set from=%from:"=%
set from=%from:E:Elliot=%

echo from E:Elliot%from% to D:UsersElliot%from%" & echo.

xcopy "E:Elliot%from%" "D:UsersElliot%from%" /i /s /e /y

echo.






powershell batch-file drag-and-drop






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 31 '18 at 18:58







ElliotThomas

















asked Dec 31 '18 at 18:44









ElliotThomasElliotThomas

217




217








  • 1





    With set from=%from:"=% you want to remove surrounding quotes from this variable? But what is your question and what has to with PowerShell (if it is how can I pass a parameter in it)?

    – double-beep
    Dec 31 '18 at 18:54











  • @double-beep Yes, sorry. I forgot the question mark there. My question is how I could do start batch.bat and specify the file path as the %1 parameter in line 2 of the batch program. And I want to do this in powershell.

    – ElliotThomas
    Dec 31 '18 at 19:00













  • To trim (outer) double quotes from an argument use the ~ modifier. if "%~1"=="" (set /p from="From: ") else (set "from=%~1")

    – LotPings
    Dec 31 '18 at 19:01














  • 1





    With set from=%from:"=% you want to remove surrounding quotes from this variable? But what is your question and what has to with PowerShell (if it is how can I pass a parameter in it)?

    – double-beep
    Dec 31 '18 at 18:54











  • @double-beep Yes, sorry. I forgot the question mark there. My question is how I could do start batch.bat and specify the file path as the %1 parameter in line 2 of the batch program. And I want to do this in powershell.

    – ElliotThomas
    Dec 31 '18 at 19:00













  • To trim (outer) double quotes from an argument use the ~ modifier. if "%~1"=="" (set /p from="From: ") else (set "from=%~1")

    – LotPings
    Dec 31 '18 at 19:01








1




1





With set from=%from:"=% you want to remove surrounding quotes from this variable? But what is your question and what has to with PowerShell (if it is how can I pass a parameter in it)?

– double-beep
Dec 31 '18 at 18:54





With set from=%from:"=% you want to remove surrounding quotes from this variable? But what is your question and what has to with PowerShell (if it is how can I pass a parameter in it)?

– double-beep
Dec 31 '18 at 18:54













@double-beep Yes, sorry. I forgot the question mark there. My question is how I could do start batch.bat and specify the file path as the %1 parameter in line 2 of the batch program. And I want to do this in powershell.

– ElliotThomas
Dec 31 '18 at 19:00







@double-beep Yes, sorry. I forgot the question mark there. My question is how I could do start batch.bat and specify the file path as the %1 parameter in line 2 of the batch program. And I want to do this in powershell.

– ElliotThomas
Dec 31 '18 at 19:00















To trim (outer) double quotes from an argument use the ~ modifier. if "%~1"=="" (set /p from="From: ") else (set "from=%~1")

– LotPings
Dec 31 '18 at 19:01





To trim (outer) double quotes from an argument use the ~ modifier. if "%~1"=="" (set /p from="From: ") else (set "from=%~1")

– LotPings
Dec 31 '18 at 19:01












1 Answer
1






active

oldest

votes


















0














You can use the param feature to require a parameter of a file path, then use Copy-Item the same as you do in the batch file:



 param(
[parameter(Mandatory=$true)] [String]$path
)
copy-item -path $path -destination 'D:UsersElliot'





share|improve this answer
























  • I hadn't though about just making a powershell function to do what my batch file did. Thanks for the suggestion. I ended up making the function like this: function copy-from-pendrive ($path) { $destination = $path.Trim("E:Elliot") copy-item -Force -Recurse -Verbose -Path "$path*" -Destination "D:UsersElliot$destination" } to get everything working the way I wanted it to.

    – ElliotThomas
    Dec 31 '18 at 20:01













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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














You can use the param feature to require a parameter of a file path, then use Copy-Item the same as you do in the batch file:



 param(
[parameter(Mandatory=$true)] [String]$path
)
copy-item -path $path -destination 'D:UsersElliot'





share|improve this answer
























  • I hadn't though about just making a powershell function to do what my batch file did. Thanks for the suggestion. I ended up making the function like this: function copy-from-pendrive ($path) { $destination = $path.Trim("E:Elliot") copy-item -Force -Recurse -Verbose -Path "$path*" -Destination "D:UsersElliot$destination" } to get everything working the way I wanted it to.

    – ElliotThomas
    Dec 31 '18 at 20:01


















0














You can use the param feature to require a parameter of a file path, then use Copy-Item the same as you do in the batch file:



 param(
[parameter(Mandatory=$true)] [String]$path
)
copy-item -path $path -destination 'D:UsersElliot'





share|improve this answer
























  • I hadn't though about just making a powershell function to do what my batch file did. Thanks for the suggestion. I ended up making the function like this: function copy-from-pendrive ($path) { $destination = $path.Trim("E:Elliot") copy-item -Force -Recurse -Verbose -Path "$path*" -Destination "D:UsersElliot$destination" } to get everything working the way I wanted it to.

    – ElliotThomas
    Dec 31 '18 at 20:01
















0












0








0







You can use the param feature to require a parameter of a file path, then use Copy-Item the same as you do in the batch file:



 param(
[parameter(Mandatory=$true)] [String]$path
)
copy-item -path $path -destination 'D:UsersElliot'





share|improve this answer













You can use the param feature to require a parameter of a file path, then use Copy-Item the same as you do in the batch file:



 param(
[parameter(Mandatory=$true)] [String]$path
)
copy-item -path $path -destination 'D:UsersElliot'






share|improve this answer












share|improve this answer



share|improve this answer










answered Dec 31 '18 at 19:09









shawnshawn

1665




1665













  • I hadn't though about just making a powershell function to do what my batch file did. Thanks for the suggestion. I ended up making the function like this: function copy-from-pendrive ($path) { $destination = $path.Trim("E:Elliot") copy-item -Force -Recurse -Verbose -Path "$path*" -Destination "D:UsersElliot$destination" } to get everything working the way I wanted it to.

    – ElliotThomas
    Dec 31 '18 at 20:01





















  • I hadn't though about just making a powershell function to do what my batch file did. Thanks for the suggestion. I ended up making the function like this: function copy-from-pendrive ($path) { $destination = $path.Trim("E:Elliot") copy-item -Force -Recurse -Verbose -Path "$path*" -Destination "D:UsersElliot$destination" } to get everything working the way I wanted it to.

    – ElliotThomas
    Dec 31 '18 at 20:01



















I hadn't though about just making a powershell function to do what my batch file did. Thanks for the suggestion. I ended up making the function like this: function copy-from-pendrive ($path) { $destination = $path.Trim("E:Elliot") copy-item -Force -Recurse -Verbose -Path "$path*" -Destination "D:UsersElliot$destination" } to get everything working the way I wanted it to.

– ElliotThomas
Dec 31 '18 at 20:01







I hadn't though about just making a powershell function to do what my batch file did. Thanks for the suggestion. I ended up making the function like this: function copy-from-pendrive ($path) { $destination = $path.Trim("E:Elliot") copy-item -Force -Recurse -Verbose -Path "$path*" -Destination "D:UsersElliot$destination" } to get everything working the way I wanted it to.

– ElliotThomas
Dec 31 '18 at 20:01






















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