Same interface from multiple type












1















I have an interface, and there are some implementations for this. Each implementation belongs to some type.
I want that when I'm using autowired I would able to get all the implementation of the certain type. How can I do it?



public interface someInterface{}

public class impl1OfType1 implements someInterface{}
public class impl2OfType1 implements someInterface{}

public class impl1OfType2 implements someInterface{}
public class impl2OfType2 implements someInterface{}

public class someClass{
@autowired
public someClass(List<someInterface> interfaceList){}

}


I want to get only impl1OfType1 and impl2OfType1. And not all the implementation.
And at other place I want to get only impl1OfType2 and impl2OfType2.



more concrete example -



    public interface EntityCreator{
createEntity();
}

@Component
public class DogCreator implements entityCreator{}
@Component
public class CatCreator implements entityCreator{}
@Component
public class CarCreator implements entityCreator{}
@Component
public class TruckCreator implements entityCreator{}

@Component
public class AnimalsFactory{
@Autowired
public AnimalsFactory(List<EntityCreator> creators){}

}









share|improve this question




















  • 2





    a class implements an interface, not extends it

    – Andrew Tobilko
    Dec 31 '18 at 12:00








  • 2





    Please read about Java naming conventions. Class names go UpperCase always!

    – GhostCat
    Dec 31 '18 at 12:01






  • 1





    Given what you posted, you should get nothing at all since none of the classes is annotated with @Component. Post a complete minimal example reproducing the problem, otherwise all we can do is guess what the problem might be.

    – JB Nizet
    Dec 31 '18 at 12:07











  • @eliranyosef Please be accurate with the edits, 2 CarCreators and @autowired make little sense

    – Andrew Tobilko
    Dec 31 '18 at 12:39


















1















I have an interface, and there are some implementations for this. Each implementation belongs to some type.
I want that when I'm using autowired I would able to get all the implementation of the certain type. How can I do it?



public interface someInterface{}

public class impl1OfType1 implements someInterface{}
public class impl2OfType1 implements someInterface{}

public class impl1OfType2 implements someInterface{}
public class impl2OfType2 implements someInterface{}

public class someClass{
@autowired
public someClass(List<someInterface> interfaceList){}

}


I want to get only impl1OfType1 and impl2OfType1. And not all the implementation.
And at other place I want to get only impl1OfType2 and impl2OfType2.



more concrete example -



    public interface EntityCreator{
createEntity();
}

@Component
public class DogCreator implements entityCreator{}
@Component
public class CatCreator implements entityCreator{}
@Component
public class CarCreator implements entityCreator{}
@Component
public class TruckCreator implements entityCreator{}

@Component
public class AnimalsFactory{
@Autowired
public AnimalsFactory(List<EntityCreator> creators){}

}









share|improve this question




















  • 2





    a class implements an interface, not extends it

    – Andrew Tobilko
    Dec 31 '18 at 12:00








  • 2





    Please read about Java naming conventions. Class names go UpperCase always!

    – GhostCat
    Dec 31 '18 at 12:01






  • 1





    Given what you posted, you should get nothing at all since none of the classes is annotated with @Component. Post a complete minimal example reproducing the problem, otherwise all we can do is guess what the problem might be.

    – JB Nizet
    Dec 31 '18 at 12:07











  • @eliranyosef Please be accurate with the edits, 2 CarCreators and @autowired make little sense

    – Andrew Tobilko
    Dec 31 '18 at 12:39
















1












1








1








I have an interface, and there are some implementations for this. Each implementation belongs to some type.
I want that when I'm using autowired I would able to get all the implementation of the certain type. How can I do it?



public interface someInterface{}

public class impl1OfType1 implements someInterface{}
public class impl2OfType1 implements someInterface{}

public class impl1OfType2 implements someInterface{}
public class impl2OfType2 implements someInterface{}

public class someClass{
@autowired
public someClass(List<someInterface> interfaceList){}

}


I want to get only impl1OfType1 and impl2OfType1. And not all the implementation.
And at other place I want to get only impl1OfType2 and impl2OfType2.



more concrete example -



    public interface EntityCreator{
createEntity();
}

@Component
public class DogCreator implements entityCreator{}
@Component
public class CatCreator implements entityCreator{}
@Component
public class CarCreator implements entityCreator{}
@Component
public class TruckCreator implements entityCreator{}

@Component
public class AnimalsFactory{
@Autowired
public AnimalsFactory(List<EntityCreator> creators){}

}









share|improve this question
















I have an interface, and there are some implementations for this. Each implementation belongs to some type.
I want that when I'm using autowired I would able to get all the implementation of the certain type. How can I do it?



public interface someInterface{}

public class impl1OfType1 implements someInterface{}
public class impl2OfType1 implements someInterface{}

public class impl1OfType2 implements someInterface{}
public class impl2OfType2 implements someInterface{}

public class someClass{
@autowired
public someClass(List<someInterface> interfaceList){}

}


I want to get only impl1OfType1 and impl2OfType1. And not all the implementation.
And at other place I want to get only impl1OfType2 and impl2OfType2.



more concrete example -



    public interface EntityCreator{
createEntity();
}

@Component
public class DogCreator implements entityCreator{}
@Component
public class CatCreator implements entityCreator{}
@Component
public class CarCreator implements entityCreator{}
@Component
public class TruckCreator implements entityCreator{}

@Component
public class AnimalsFactory{
@Autowired
public AnimalsFactory(List<EntityCreator> creators){}

}






java spring dependency-injection autowired






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 31 '18 at 12:53









Andrew Tobilko

27.4k104285




27.4k104285










asked Dec 31 '18 at 11:56









eliran yosefeliran yosef

212




212








  • 2





    a class implements an interface, not extends it

    – Andrew Tobilko
    Dec 31 '18 at 12:00








  • 2





    Please read about Java naming conventions. Class names go UpperCase always!

    – GhostCat
    Dec 31 '18 at 12:01






  • 1





    Given what you posted, you should get nothing at all since none of the classes is annotated with @Component. Post a complete minimal example reproducing the problem, otherwise all we can do is guess what the problem might be.

    – JB Nizet
    Dec 31 '18 at 12:07











  • @eliranyosef Please be accurate with the edits, 2 CarCreators and @autowired make little sense

    – Andrew Tobilko
    Dec 31 '18 at 12:39
















  • 2





    a class implements an interface, not extends it

    – Andrew Tobilko
    Dec 31 '18 at 12:00








  • 2





    Please read about Java naming conventions. Class names go UpperCase always!

    – GhostCat
    Dec 31 '18 at 12:01






  • 1





    Given what you posted, you should get nothing at all since none of the classes is annotated with @Component. Post a complete minimal example reproducing the problem, otherwise all we can do is guess what the problem might be.

    – JB Nizet
    Dec 31 '18 at 12:07











  • @eliranyosef Please be accurate with the edits, 2 CarCreators and @autowired make little sense

    – Andrew Tobilko
    Dec 31 '18 at 12:39










2




2





a class implements an interface, not extends it

– Andrew Tobilko
Dec 31 '18 at 12:00







a class implements an interface, not extends it

– Andrew Tobilko
Dec 31 '18 at 12:00






2




2





Please read about Java naming conventions. Class names go UpperCase always!

– GhostCat
Dec 31 '18 at 12:01





Please read about Java naming conventions. Class names go UpperCase always!

– GhostCat
Dec 31 '18 at 12:01




1




1





Given what you posted, you should get nothing at all since none of the classes is annotated with @Component. Post a complete minimal example reproducing the problem, otherwise all we can do is guess what the problem might be.

– JB Nizet
Dec 31 '18 at 12:07





Given what you posted, you should get nothing at all since none of the classes is annotated with @Component. Post a complete minimal example reproducing the problem, otherwise all we can do is guess what the problem might be.

– JB Nizet
Dec 31 '18 at 12:07













@eliranyosef Please be accurate with the edits, 2 CarCreators and @autowired make little sense

– Andrew Tobilko
Dec 31 '18 at 12:39







@eliranyosef Please be accurate with the edits, 2 CarCreators and @autowired make little sense

– Andrew Tobilko
Dec 31 '18 at 12:39














2 Answers
2






active

oldest

votes


















1














The solution would be using @Qualifier.



@Component
@Qualifier("place1")
class Impl1OfType2 implements SomeInterface {}

@Component
@Qualifier("place1")
class Impl2OfType2 implements SomeInterface {}

@Service
class SomeClass {
@Autowired
public SomeClass(@Qualifier("place1") List<SomeInterface> interfaceList) {
System.out.println(interfaceList);
}
}


I slightly changed the names to adhere to the Java convention. They are still a bit awkward and contextless.



UPDATE



You might use generics, Spring is good at dealing with them. For instance, it will inject only DogCreator and CatCreator into a List<EntityCreator<Animal>>.



interface Animal {}
interface Machine {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator<Animal> {}
@Component
class CatCreator implements EntityCreator<Animal> {}

@Component
class CarCreator implements EntityCreator<Machine> {}
@Component
class TruckCreator implements EntityCreator<Machine> {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<EntityCreator<Animal>> creators) { }
}


UPDATE 2



You could write marker interfaces which would break down existing implementations into logical groups.



interface AnimalCreator {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator, AnimalCreator {}
@Component
class CatCreator implements EntityCreator, AnimalCreator {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<AnimalCreator> creators) {
System.out.println(creators);
}

}





share|improve this answer


























  • Thank you for the solution I had think about this idea, but I don't want that each one who will create implementation to interface should add qualifier. How can I do it?

    – eliran yosef
    Dec 31 '18 at 12:27











  • @eliranyosef Spring operates on presented meta-information, I don't think there's any different to tell Spring filter out candidates for autowiring.

    – Andrew Tobilko
    Dec 31 '18 at 12:30











  • @eliranyosef you may write another interface which would be shared by the interfaces that are supposed to be used in the same place.

    – Andrew Tobilko
    Dec 31 '18 at 12:32



















0














If you correct your code with above comments and I understand your problem, I assume this can be a way to solve your issue.



public interface Someinterface<T extends someType> {}
public class someType{}
public class Type1 extends someType{}
public class Type2 extends someType{}

public class TypedInterface1 implements Someinterface<Type1> {}
public class TypedInterface2 implements Someinterface<Type2> {}

public class someClass{
@Autowired
public someClass(List<TypedInterface1> interfaceList){}
}


Let me know if I answered your question.






share|improve this answer


























  • your answer absolutely makes no sense to me. Compare your code to OP's. I downvoted.

    – Andrew Tobilko
    Dec 31 '18 at 12:17













  • In OP post, the type cannot be deduced because of multiple implementations of Someinterface. In my solution however Type inference is not a problem. So DI framework should have no issue injecting the correct implementation. However I have just begin in JAVA from C++ and may have misunderstood something.

    – Akshay Mathur
    Dec 31 '18 at 12:22













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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














The solution would be using @Qualifier.



@Component
@Qualifier("place1")
class Impl1OfType2 implements SomeInterface {}

@Component
@Qualifier("place1")
class Impl2OfType2 implements SomeInterface {}

@Service
class SomeClass {
@Autowired
public SomeClass(@Qualifier("place1") List<SomeInterface> interfaceList) {
System.out.println(interfaceList);
}
}


I slightly changed the names to adhere to the Java convention. They are still a bit awkward and contextless.



UPDATE



You might use generics, Spring is good at dealing with them. For instance, it will inject only DogCreator and CatCreator into a List<EntityCreator<Animal>>.



interface Animal {}
interface Machine {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator<Animal> {}
@Component
class CatCreator implements EntityCreator<Animal> {}

@Component
class CarCreator implements EntityCreator<Machine> {}
@Component
class TruckCreator implements EntityCreator<Machine> {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<EntityCreator<Animal>> creators) { }
}


UPDATE 2



You could write marker interfaces which would break down existing implementations into logical groups.



interface AnimalCreator {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator, AnimalCreator {}
@Component
class CatCreator implements EntityCreator, AnimalCreator {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<AnimalCreator> creators) {
System.out.println(creators);
}

}





share|improve this answer


























  • Thank you for the solution I had think about this idea, but I don't want that each one who will create implementation to interface should add qualifier. How can I do it?

    – eliran yosef
    Dec 31 '18 at 12:27











  • @eliranyosef Spring operates on presented meta-information, I don't think there's any different to tell Spring filter out candidates for autowiring.

    – Andrew Tobilko
    Dec 31 '18 at 12:30











  • @eliranyosef you may write another interface which would be shared by the interfaces that are supposed to be used in the same place.

    – Andrew Tobilko
    Dec 31 '18 at 12:32
















1














The solution would be using @Qualifier.



@Component
@Qualifier("place1")
class Impl1OfType2 implements SomeInterface {}

@Component
@Qualifier("place1")
class Impl2OfType2 implements SomeInterface {}

@Service
class SomeClass {
@Autowired
public SomeClass(@Qualifier("place1") List<SomeInterface> interfaceList) {
System.out.println(interfaceList);
}
}


I slightly changed the names to adhere to the Java convention. They are still a bit awkward and contextless.



UPDATE



You might use generics, Spring is good at dealing with them. For instance, it will inject only DogCreator and CatCreator into a List<EntityCreator<Animal>>.



interface Animal {}
interface Machine {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator<Animal> {}
@Component
class CatCreator implements EntityCreator<Animal> {}

@Component
class CarCreator implements EntityCreator<Machine> {}
@Component
class TruckCreator implements EntityCreator<Machine> {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<EntityCreator<Animal>> creators) { }
}


UPDATE 2



You could write marker interfaces which would break down existing implementations into logical groups.



interface AnimalCreator {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator, AnimalCreator {}
@Component
class CatCreator implements EntityCreator, AnimalCreator {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<AnimalCreator> creators) {
System.out.println(creators);
}

}





share|improve this answer


























  • Thank you for the solution I had think about this idea, but I don't want that each one who will create implementation to interface should add qualifier. How can I do it?

    – eliran yosef
    Dec 31 '18 at 12:27











  • @eliranyosef Spring operates on presented meta-information, I don't think there's any different to tell Spring filter out candidates for autowiring.

    – Andrew Tobilko
    Dec 31 '18 at 12:30











  • @eliranyosef you may write another interface which would be shared by the interfaces that are supposed to be used in the same place.

    – Andrew Tobilko
    Dec 31 '18 at 12:32














1












1








1







The solution would be using @Qualifier.



@Component
@Qualifier("place1")
class Impl1OfType2 implements SomeInterface {}

@Component
@Qualifier("place1")
class Impl2OfType2 implements SomeInterface {}

@Service
class SomeClass {
@Autowired
public SomeClass(@Qualifier("place1") List<SomeInterface> interfaceList) {
System.out.println(interfaceList);
}
}


I slightly changed the names to adhere to the Java convention. They are still a bit awkward and contextless.



UPDATE



You might use generics, Spring is good at dealing with them. For instance, it will inject only DogCreator and CatCreator into a List<EntityCreator<Animal>>.



interface Animal {}
interface Machine {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator<Animal> {}
@Component
class CatCreator implements EntityCreator<Animal> {}

@Component
class CarCreator implements EntityCreator<Machine> {}
@Component
class TruckCreator implements EntityCreator<Machine> {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<EntityCreator<Animal>> creators) { }
}


UPDATE 2



You could write marker interfaces which would break down existing implementations into logical groups.



interface AnimalCreator {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator, AnimalCreator {}
@Component
class CatCreator implements EntityCreator, AnimalCreator {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<AnimalCreator> creators) {
System.out.println(creators);
}

}





share|improve this answer















The solution would be using @Qualifier.



@Component
@Qualifier("place1")
class Impl1OfType2 implements SomeInterface {}

@Component
@Qualifier("place1")
class Impl2OfType2 implements SomeInterface {}

@Service
class SomeClass {
@Autowired
public SomeClass(@Qualifier("place1") List<SomeInterface> interfaceList) {
System.out.println(interfaceList);
}
}


I slightly changed the names to adhere to the Java convention. They are still a bit awkward and contextless.



UPDATE



You might use generics, Spring is good at dealing with them. For instance, it will inject only DogCreator and CatCreator into a List<EntityCreator<Animal>>.



interface Animal {}
interface Machine {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator<Animal> {}
@Component
class CatCreator implements EntityCreator<Animal> {}

@Component
class CarCreator implements EntityCreator<Machine> {}
@Component
class TruckCreator implements EntityCreator<Machine> {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<EntityCreator<Animal>> creators) { }
}


UPDATE 2



You could write marker interfaces which would break down existing implementations into logical groups.



interface AnimalCreator {}

interface EntityCreator<T> {}

@Component
class DogCreator implements EntityCreator, AnimalCreator {}
@Component
class CatCreator implements EntityCreator, AnimalCreator {}

@Component
class AnimalsFactory {
@Autowired
public AnimalsFactory(List<AnimalCreator> creators) {
System.out.println(creators);
}

}






share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 31 '18 at 12:51

























answered Dec 31 '18 at 12:07









Andrew TobilkoAndrew Tobilko

27.4k104285




27.4k104285













  • Thank you for the solution I had think about this idea, but I don't want that each one who will create implementation to interface should add qualifier. How can I do it?

    – eliran yosef
    Dec 31 '18 at 12:27











  • @eliranyosef Spring operates on presented meta-information, I don't think there's any different to tell Spring filter out candidates for autowiring.

    – Andrew Tobilko
    Dec 31 '18 at 12:30











  • @eliranyosef you may write another interface which would be shared by the interfaces that are supposed to be used in the same place.

    – Andrew Tobilko
    Dec 31 '18 at 12:32



















  • Thank you for the solution I had think about this idea, but I don't want that each one who will create implementation to interface should add qualifier. How can I do it?

    – eliran yosef
    Dec 31 '18 at 12:27











  • @eliranyosef Spring operates on presented meta-information, I don't think there's any different to tell Spring filter out candidates for autowiring.

    – Andrew Tobilko
    Dec 31 '18 at 12:30











  • @eliranyosef you may write another interface which would be shared by the interfaces that are supposed to be used in the same place.

    – Andrew Tobilko
    Dec 31 '18 at 12:32

















Thank you for the solution I had think about this idea, but I don't want that each one who will create implementation to interface should add qualifier. How can I do it?

– eliran yosef
Dec 31 '18 at 12:27





Thank you for the solution I had think about this idea, but I don't want that each one who will create implementation to interface should add qualifier. How can I do it?

– eliran yosef
Dec 31 '18 at 12:27













@eliranyosef Spring operates on presented meta-information, I don't think there's any different to tell Spring filter out candidates for autowiring.

– Andrew Tobilko
Dec 31 '18 at 12:30





@eliranyosef Spring operates on presented meta-information, I don't think there's any different to tell Spring filter out candidates for autowiring.

– Andrew Tobilko
Dec 31 '18 at 12:30













@eliranyosef you may write another interface which would be shared by the interfaces that are supposed to be used in the same place.

– Andrew Tobilko
Dec 31 '18 at 12:32





@eliranyosef you may write another interface which would be shared by the interfaces that are supposed to be used in the same place.

– Andrew Tobilko
Dec 31 '18 at 12:32













0














If you correct your code with above comments and I understand your problem, I assume this can be a way to solve your issue.



public interface Someinterface<T extends someType> {}
public class someType{}
public class Type1 extends someType{}
public class Type2 extends someType{}

public class TypedInterface1 implements Someinterface<Type1> {}
public class TypedInterface2 implements Someinterface<Type2> {}

public class someClass{
@Autowired
public someClass(List<TypedInterface1> interfaceList){}
}


Let me know if I answered your question.






share|improve this answer


























  • your answer absolutely makes no sense to me. Compare your code to OP's. I downvoted.

    – Andrew Tobilko
    Dec 31 '18 at 12:17













  • In OP post, the type cannot be deduced because of multiple implementations of Someinterface. In my solution however Type inference is not a problem. So DI framework should have no issue injecting the correct implementation. However I have just begin in JAVA from C++ and may have misunderstood something.

    – Akshay Mathur
    Dec 31 '18 at 12:22


















0














If you correct your code with above comments and I understand your problem, I assume this can be a way to solve your issue.



public interface Someinterface<T extends someType> {}
public class someType{}
public class Type1 extends someType{}
public class Type2 extends someType{}

public class TypedInterface1 implements Someinterface<Type1> {}
public class TypedInterface2 implements Someinterface<Type2> {}

public class someClass{
@Autowired
public someClass(List<TypedInterface1> interfaceList){}
}


Let me know if I answered your question.






share|improve this answer


























  • your answer absolutely makes no sense to me. Compare your code to OP's. I downvoted.

    – Andrew Tobilko
    Dec 31 '18 at 12:17













  • In OP post, the type cannot be deduced because of multiple implementations of Someinterface. In my solution however Type inference is not a problem. So DI framework should have no issue injecting the correct implementation. However I have just begin in JAVA from C++ and may have misunderstood something.

    – Akshay Mathur
    Dec 31 '18 at 12:22
















0












0








0







If you correct your code with above comments and I understand your problem, I assume this can be a way to solve your issue.



public interface Someinterface<T extends someType> {}
public class someType{}
public class Type1 extends someType{}
public class Type2 extends someType{}

public class TypedInterface1 implements Someinterface<Type1> {}
public class TypedInterface2 implements Someinterface<Type2> {}

public class someClass{
@Autowired
public someClass(List<TypedInterface1> interfaceList){}
}


Let me know if I answered your question.






share|improve this answer















If you correct your code with above comments and I understand your problem, I assume this can be a way to solve your issue.



public interface Someinterface<T extends someType> {}
public class someType{}
public class Type1 extends someType{}
public class Type2 extends someType{}

public class TypedInterface1 implements Someinterface<Type1> {}
public class TypedInterface2 implements Someinterface<Type2> {}

public class someClass{
@Autowired
public someClass(List<TypedInterface1> interfaceList){}
}


Let me know if I answered your question.







share|improve this answer














share|improve this answer



share|improve this answer








edited Dec 31 '18 at 12:45









Andrew Tobilko

27.4k104285




27.4k104285










answered Dec 31 '18 at 12:09









Akshay MathurAkshay Mathur

88210




88210













  • your answer absolutely makes no sense to me. Compare your code to OP's. I downvoted.

    – Andrew Tobilko
    Dec 31 '18 at 12:17













  • In OP post, the type cannot be deduced because of multiple implementations of Someinterface. In my solution however Type inference is not a problem. So DI framework should have no issue injecting the correct implementation. However I have just begin in JAVA from C++ and may have misunderstood something.

    – Akshay Mathur
    Dec 31 '18 at 12:22





















  • your answer absolutely makes no sense to me. Compare your code to OP's. I downvoted.

    – Andrew Tobilko
    Dec 31 '18 at 12:17













  • In OP post, the type cannot be deduced because of multiple implementations of Someinterface. In my solution however Type inference is not a problem. So DI framework should have no issue injecting the correct implementation. However I have just begin in JAVA from C++ and may have misunderstood something.

    – Akshay Mathur
    Dec 31 '18 at 12:22



















your answer absolutely makes no sense to me. Compare your code to OP's. I downvoted.

– Andrew Tobilko
Dec 31 '18 at 12:17







your answer absolutely makes no sense to me. Compare your code to OP's. I downvoted.

– Andrew Tobilko
Dec 31 '18 at 12:17















In OP post, the type cannot be deduced because of multiple implementations of Someinterface. In my solution however Type inference is not a problem. So DI framework should have no issue injecting the correct implementation. However I have just begin in JAVA from C++ and may have misunderstood something.

– Akshay Mathur
Dec 31 '18 at 12:22







In OP post, the type cannot be deduced because of multiple implementations of Someinterface. In my solution however Type inference is not a problem. So DI framework should have no issue injecting the correct implementation. However I have just begin in JAVA from C++ and may have misunderstood something.

– Akshay Mathur
Dec 31 '18 at 12:22




















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