Getting “filler” empty values for a GROUP BY

Multi tool use
Assuming I want to get 'weekly' results from a date range, and the date range contains four separate weeks, but my database only has a record for one week, how can I get filler values for the remaining three weeks?
For example, given this date range: 6/2018 - 7/2018
I run this query:
SELECT
DATE_FORMAT(period, '%m %d') || ' - ' || DATE_FORMAT(period, '%m %d') AS period,
SUM(clicks) AS clicks
FROM tablename
WHERE period >= ? AND period <= ?
GROUP BY YEAR(period), WEEK(period)
With these table rows in the database:
| period | clicks |
| 07/01/2018T:00:00:00Z | 1000 |
And I get these query results:
| period | clicks |
| Jul 1 - Jul 5 | 1000 |
But I want to get these query results to cover default values for the empty weeks so I can use them to populate a d3 chart:
| period | clicks |
| Jul 1 - Jul 5 | 1000 |
| Jun 25 - Jun 23 | 0 |
| Jun 18 - Jun 24 | 0 |
| Jun 12 - Jun 18 | 0 |
Any ideas? This sort of "filler" phenomena should be generic enough to work with other intervals, such as daily, monthly, yearly, hourly.
mysql sql
add a comment |
Assuming I want to get 'weekly' results from a date range, and the date range contains four separate weeks, but my database only has a record for one week, how can I get filler values for the remaining three weeks?
For example, given this date range: 6/2018 - 7/2018
I run this query:
SELECT
DATE_FORMAT(period, '%m %d') || ' - ' || DATE_FORMAT(period, '%m %d') AS period,
SUM(clicks) AS clicks
FROM tablename
WHERE period >= ? AND period <= ?
GROUP BY YEAR(period), WEEK(period)
With these table rows in the database:
| period | clicks |
| 07/01/2018T:00:00:00Z | 1000 |
And I get these query results:
| period | clicks |
| Jul 1 - Jul 5 | 1000 |
But I want to get these query results to cover default values for the empty weeks so I can use them to populate a d3 chart:
| period | clicks |
| Jul 1 - Jul 5 | 1000 |
| Jun 25 - Jun 23 | 0 |
| Jun 18 - Jun 24 | 0 |
| Jun 12 - Jun 18 | 0 |
Any ideas? This sort of "filler" phenomena should be generic enough to work with other intervals, such as daily, monthly, yearly, hourly.
mysql sql
In most RDBMS we achieve such results using a Calendar table. You should create your own calendar table and JOIN it. Search for that, you will find plenty of examples here or on google. [stackoverflow.com/questions/36789953/… answer) from me is a good example.
– Thomas G
Dec 31 '18 at 12:16
JOIN the table withSELECT 1 UNION SELECT 2 ... SELECT 5
.
– Salman A
Dec 31 '18 at 12:18
add a comment |
Assuming I want to get 'weekly' results from a date range, and the date range contains four separate weeks, but my database only has a record for one week, how can I get filler values for the remaining three weeks?
For example, given this date range: 6/2018 - 7/2018
I run this query:
SELECT
DATE_FORMAT(period, '%m %d') || ' - ' || DATE_FORMAT(period, '%m %d') AS period,
SUM(clicks) AS clicks
FROM tablename
WHERE period >= ? AND period <= ?
GROUP BY YEAR(period), WEEK(period)
With these table rows in the database:
| period | clicks |
| 07/01/2018T:00:00:00Z | 1000 |
And I get these query results:
| period | clicks |
| Jul 1 - Jul 5 | 1000 |
But I want to get these query results to cover default values for the empty weeks so I can use them to populate a d3 chart:
| period | clicks |
| Jul 1 - Jul 5 | 1000 |
| Jun 25 - Jun 23 | 0 |
| Jun 18 - Jun 24 | 0 |
| Jun 12 - Jun 18 | 0 |
Any ideas? This sort of "filler" phenomena should be generic enough to work with other intervals, such as daily, monthly, yearly, hourly.
mysql sql
Assuming I want to get 'weekly' results from a date range, and the date range contains four separate weeks, but my database only has a record for one week, how can I get filler values for the remaining three weeks?
For example, given this date range: 6/2018 - 7/2018
I run this query:
SELECT
DATE_FORMAT(period, '%m %d') || ' - ' || DATE_FORMAT(period, '%m %d') AS period,
SUM(clicks) AS clicks
FROM tablename
WHERE period >= ? AND period <= ?
GROUP BY YEAR(period), WEEK(period)
With these table rows in the database:
| period | clicks |
| 07/01/2018T:00:00:00Z | 1000 |
And I get these query results:
| period | clicks |
| Jul 1 - Jul 5 | 1000 |
But I want to get these query results to cover default values for the empty weeks so I can use them to populate a d3 chart:
| period | clicks |
| Jul 1 - Jul 5 | 1000 |
| Jun 25 - Jun 23 | 0 |
| Jun 18 - Jun 24 | 0 |
| Jun 12 - Jun 18 | 0 |
Any ideas? This sort of "filler" phenomena should be generic enough to work with other intervals, such as daily, monthly, yearly, hourly.
mysql sql
mysql sql
edited Dec 31 '18 at 12:26
Lansana
asked Dec 31 '18 at 12:13


LansanaLansana
4,83422351
4,83422351
In most RDBMS we achieve such results using a Calendar table. You should create your own calendar table and JOIN it. Search for that, you will find plenty of examples here or on google. [stackoverflow.com/questions/36789953/… answer) from me is a good example.
– Thomas G
Dec 31 '18 at 12:16
JOIN the table withSELECT 1 UNION SELECT 2 ... SELECT 5
.
– Salman A
Dec 31 '18 at 12:18
add a comment |
In most RDBMS we achieve such results using a Calendar table. You should create your own calendar table and JOIN it. Search for that, you will find plenty of examples here or on google. [stackoverflow.com/questions/36789953/… answer) from me is a good example.
– Thomas G
Dec 31 '18 at 12:16
JOIN the table withSELECT 1 UNION SELECT 2 ... SELECT 5
.
– Salman A
Dec 31 '18 at 12:18
In most RDBMS we achieve such results using a Calendar table. You should create your own calendar table and JOIN it. Search for that, you will find plenty of examples here or on google. [stackoverflow.com/questions/36789953/… answer) from me is a good example.
– Thomas G
Dec 31 '18 at 12:16
In most RDBMS we achieve such results using a Calendar table. You should create your own calendar table and JOIN it. Search for that, you will find plenty of examples here or on google. [stackoverflow.com/questions/36789953/… answer) from me is a good example.
– Thomas G
Dec 31 '18 at 12:16
JOIN the table with
SELECT 1 UNION SELECT 2 ... SELECT 5
.– Salman A
Dec 31 '18 at 12:18
JOIN the table with
SELECT 1 UNION SELECT 2 ... SELECT 5
.– Salman A
Dec 31 '18 at 12:18
add a comment |
2 Answers
2
active
oldest
votes
rewrite your query as
ifnull( SUM(clicks),0) AS clicks
do you really think this is answering the question in any way?
– Thomas G
Dec 31 '18 at 12:38
ya.if value is null.it returns 0.he wants to show 0 anyway if the value is 0 in myself that return date also @ThomasG
– Ram
Dec 31 '18 at 12:47
@Ram Problem is, that in this case - without any data row for the given week - there will not be a result row to Group on, so "No row at all".
– dognose
Dec 31 '18 at 12:53
add a comment |
You can use this query to generate the weeks and then left join with your current query to get what you want.
DECLARE @StartingFromDate DATETIME = '2018-12-01';
DECLARE @EndingAtDate DATETIME = '2018-12-31';
WITH CTE_DateRange (DateRange)
AS (SELECT DATEADD(WEEK, DATEDIFF(WEEK, 0, @EndingAtDate) - DATEDIFF(WEEK, @StartingFromDate, @EndingAtDate), 0)
UNION ALL
SELECT DATEADD(WEEK, 1, DateRange)
FROM CTE_DateRange
WHERE DATEADD(WEEK, 1, DateRange) < @EndingAtDate)
SELECT CTE_DateRange.DateRange
FROM CTE_DateRange
WHERE CTE_DateRange.DateRange BETWEEN @StartingFromDate AND @EndingAtDate
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53987394%2fgetting-filler-empty-values-for-a-group-by%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
rewrite your query as
ifnull( SUM(clicks),0) AS clicks
do you really think this is answering the question in any way?
– Thomas G
Dec 31 '18 at 12:38
ya.if value is null.it returns 0.he wants to show 0 anyway if the value is 0 in myself that return date also @ThomasG
– Ram
Dec 31 '18 at 12:47
@Ram Problem is, that in this case - without any data row for the given week - there will not be a result row to Group on, so "No row at all".
– dognose
Dec 31 '18 at 12:53
add a comment |
rewrite your query as
ifnull( SUM(clicks),0) AS clicks
do you really think this is answering the question in any way?
– Thomas G
Dec 31 '18 at 12:38
ya.if value is null.it returns 0.he wants to show 0 anyway if the value is 0 in myself that return date also @ThomasG
– Ram
Dec 31 '18 at 12:47
@Ram Problem is, that in this case - without any data row for the given week - there will not be a result row to Group on, so "No row at all".
– dognose
Dec 31 '18 at 12:53
add a comment |
rewrite your query as
ifnull( SUM(clicks),0) AS clicks
rewrite your query as
ifnull( SUM(clicks),0) AS clicks
answered Dec 31 '18 at 12:27


RamRam
397
397
do you really think this is answering the question in any way?
– Thomas G
Dec 31 '18 at 12:38
ya.if value is null.it returns 0.he wants to show 0 anyway if the value is 0 in myself that return date also @ThomasG
– Ram
Dec 31 '18 at 12:47
@Ram Problem is, that in this case - without any data row for the given week - there will not be a result row to Group on, so "No row at all".
– dognose
Dec 31 '18 at 12:53
add a comment |
do you really think this is answering the question in any way?
– Thomas G
Dec 31 '18 at 12:38
ya.if value is null.it returns 0.he wants to show 0 anyway if the value is 0 in myself that return date also @ThomasG
– Ram
Dec 31 '18 at 12:47
@Ram Problem is, that in this case - without any data row for the given week - there will not be a result row to Group on, so "No row at all".
– dognose
Dec 31 '18 at 12:53
do you really think this is answering the question in any way?
– Thomas G
Dec 31 '18 at 12:38
do you really think this is answering the question in any way?
– Thomas G
Dec 31 '18 at 12:38
ya.if value is null.it returns 0.he wants to show 0 anyway if the value is 0 in myself that return date also @ThomasG
– Ram
Dec 31 '18 at 12:47
ya.if value is null.it returns 0.he wants to show 0 anyway if the value is 0 in myself that return date also @ThomasG
– Ram
Dec 31 '18 at 12:47
@Ram Problem is, that in this case - without any data row for the given week - there will not be a result row to Group on, so "No row at all".
– dognose
Dec 31 '18 at 12:53
@Ram Problem is, that in this case - without any data row for the given week - there will not be a result row to Group on, so "No row at all".
– dognose
Dec 31 '18 at 12:53
add a comment |
You can use this query to generate the weeks and then left join with your current query to get what you want.
DECLARE @StartingFromDate DATETIME = '2018-12-01';
DECLARE @EndingAtDate DATETIME = '2018-12-31';
WITH CTE_DateRange (DateRange)
AS (SELECT DATEADD(WEEK, DATEDIFF(WEEK, 0, @EndingAtDate) - DATEDIFF(WEEK, @StartingFromDate, @EndingAtDate), 0)
UNION ALL
SELECT DATEADD(WEEK, 1, DateRange)
FROM CTE_DateRange
WHERE DATEADD(WEEK, 1, DateRange) < @EndingAtDate)
SELECT CTE_DateRange.DateRange
FROM CTE_DateRange
WHERE CTE_DateRange.DateRange BETWEEN @StartingFromDate AND @EndingAtDate
add a comment |
You can use this query to generate the weeks and then left join with your current query to get what you want.
DECLARE @StartingFromDate DATETIME = '2018-12-01';
DECLARE @EndingAtDate DATETIME = '2018-12-31';
WITH CTE_DateRange (DateRange)
AS (SELECT DATEADD(WEEK, DATEDIFF(WEEK, 0, @EndingAtDate) - DATEDIFF(WEEK, @StartingFromDate, @EndingAtDate), 0)
UNION ALL
SELECT DATEADD(WEEK, 1, DateRange)
FROM CTE_DateRange
WHERE DATEADD(WEEK, 1, DateRange) < @EndingAtDate)
SELECT CTE_DateRange.DateRange
FROM CTE_DateRange
WHERE CTE_DateRange.DateRange BETWEEN @StartingFromDate AND @EndingAtDate
add a comment |
You can use this query to generate the weeks and then left join with your current query to get what you want.
DECLARE @StartingFromDate DATETIME = '2018-12-01';
DECLARE @EndingAtDate DATETIME = '2018-12-31';
WITH CTE_DateRange (DateRange)
AS (SELECT DATEADD(WEEK, DATEDIFF(WEEK, 0, @EndingAtDate) - DATEDIFF(WEEK, @StartingFromDate, @EndingAtDate), 0)
UNION ALL
SELECT DATEADD(WEEK, 1, DateRange)
FROM CTE_DateRange
WHERE DATEADD(WEEK, 1, DateRange) < @EndingAtDate)
SELECT CTE_DateRange.DateRange
FROM CTE_DateRange
WHERE CTE_DateRange.DateRange BETWEEN @StartingFromDate AND @EndingAtDate
You can use this query to generate the weeks and then left join with your current query to get what you want.
DECLARE @StartingFromDate DATETIME = '2018-12-01';
DECLARE @EndingAtDate DATETIME = '2018-12-31';
WITH CTE_DateRange (DateRange)
AS (SELECT DATEADD(WEEK, DATEDIFF(WEEK, 0, @EndingAtDate) - DATEDIFF(WEEK, @StartingFromDate, @EndingAtDate), 0)
UNION ALL
SELECT DATEADD(WEEK, 1, DateRange)
FROM CTE_DateRange
WHERE DATEADD(WEEK, 1, DateRange) < @EndingAtDate)
SELECT CTE_DateRange.DateRange
FROM CTE_DateRange
WHERE CTE_DateRange.DateRange BETWEEN @StartingFromDate AND @EndingAtDate
answered Dec 31 '18 at 12:34
Riaz RazaRiaz Raza
11810
11810
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53987394%2fgetting-filler-empty-values-for-a-group-by%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
TbP8C9x,eglx7i,P,qeU Z2rmZPJIJGHb 7pZeYlSp,dG,BdqRhU227dhY2qsxDPShbu PPCcVGvj 5rz
In most RDBMS we achieve such results using a Calendar table. You should create your own calendar table and JOIN it. Search for that, you will find plenty of examples here or on google. [stackoverflow.com/questions/36789953/… answer) from me is a good example.
– Thomas G
Dec 31 '18 at 12:16
JOIN the table with
SELECT 1 UNION SELECT 2 ... SELECT 5
.– Salman A
Dec 31 '18 at 12:18