How to get only string from mysql result?
I need to get the string out of mysql result query
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
rows=[i[0] for i in myresult]
for x in myresult:
print(x[0])
It only returns one row but it returns in this format:
(u'I need this string',)
I tried this
rows=[i[0] for i in myresult]
print(myresult)
python
edited Dec 30 '18 at 4:54
JacobIRR
3,39521228
asked Dec 30 '18 at 4:44
Danny J.Danny J.
1213
add a comment |
I need to get the string out of mysql result query
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
rows=[i[0] for i in myresult]
for x in myresult:
print(x[0])
It only returns one row but it returns in this format:
(u'I need this string',)
I tried this
rows=[i[0] for i in myresult]
print(myresult)
python
edited Dec 30 '18 at 4:54
JacobIRR
3,39521228
asked Dec 30 '18 at 4:44
Danny J.Danny J.
1213
add a comment |
I need to get the string out of mysql result query
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
rows=[i[0] for i in myresult]
for x in myresult:
print(x[0])
It only returns one row but it returns in this format:
(u'I need this string',)
I tried this
rows=[i[0] for i in myresult]
print(myresult)
python
edited Dec 30 '18 at 4:54
JacobIRR
3,39521228
asked Dec 30 '18 at 4:44
Danny J.Danny J.
1213
I need to get the string out of mysql result query
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
rows=[i[0] for i in myresult]
for x in myresult:
print(x[0])
It only returns one row but it returns in this format:
(u'I need this string',)
I tried this
rows=[i[0] for i in myresult]
print(myresult)
python
python
edited Dec 30 '18 at 4:54
JacobIRR
3,39521228
asked Dec 30 '18 at 4:44
Danny J.Danny J.
1213
edited Dec 30 '18 at 4:54
JacobIRR
3,39521228
asked Dec 30 '18 at 4:44
Danny J.Danny J.
1213
edited Dec 30 '18 at 4:54
JacobIRR
3,39521228
edited Dec 30 '18 at 4:54
JacobIRR
3,39521228
edited Dec 30 '18 at 4:54
JacobIRR
3,39521228
3,39521228
asked Dec 30 '18 at 4:44
Danny J.Danny J.
1213
asked Dec 30 '18 at 4:44
Danny J.Danny J.
1213
asked Dec 30 '18 at 4:44
Danny J.Danny J.
1213
1213
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
I think your syntax is off. Try this version:
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
for row in myresult:
print(row[0])
The offending line of code might be this:
rows=[i[0] for i in myresult]
This appears to be consuming the cursor by iterating through the entire result set.
answered Dec 30 '18 at 5:03
Tim BiegeleisenTim Biegeleisen
222k1390143
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think your syntax is off. Try this version:
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
for row in myresult:
print(row[0])
The offending line of code might be this:
rows=[i[0] for i in myresult]
This appears to be consuming the cursor by iterating through the entire result set.
answered Dec 30 '18 at 5:03
Tim BiegeleisenTim Biegeleisen
222k1390143
add a comment |
I think your syntax is off. Try this version:
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
for row in myresult:
print(row[0])
The offending line of code might be this:
rows=[i[0] for i in myresult]
This appears to be consuming the cursor by iterating through the entire result set.
answered Dec 30 '18 at 5:03
Tim BiegeleisenTim Biegeleisen
222k1390143
add a comment |
I think your syntax is off. Try this version:
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
for row in myresult:
print(row[0])
The offending line of code might be this:
rows=[i[0] for i in myresult]
This appears to be consuming the cursor by iterating through the entire result set.
answered Dec 30 '18 at 5:03
Tim BiegeleisenTim Biegeleisen
222k1390143
I think your syntax is off. Try this version:
mycursor.execute("Select text from text_table")
myresult = mycursor.fetchall()
for row in myresult:
print(row[0])
The offending line of code might be this:
rows=[i[0] for i in myresult]
This appears to be consuming the cursor by iterating through the entire result set.
answered Dec 30 '18 at 5:03
Tim BiegeleisenTim Biegeleisen
222k1390143
answered Dec 30 '18 at 5:03
Tim BiegeleisenTim Biegeleisen
222k1390143
answered Dec 30 '18 at 5:03
Tim BiegeleisenTim Biegeleisen
222k1390143
answered Dec 30 '18 at 5:03
Tim BiegeleisenTim Biegeleisen
222k1390143
222k1390143
add a comment |
add a comment |
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