How to transform array to this json pattern?
-2
I have array something like this
Array
(
[0] => Array
(
[product_id] => 13
[unit] => 1
[price] => 20.0000
[total] => 20.0000
)
[1] => Array
(
[product_id] => 15
[unit] => 2
[price] => 30.0000
[total] => 10.0000
)
)
I was stuck to transform above array to the "ProductList" in the following pattern
array(
"UserID" => 2,
"ProductList" => [
{
"ProductID"=> 13,
"Price"=> 20.0000
},
{
"ProductID"=> 15,
"Price"=> 30.0000
}
]
)
I tried like this:
$products = ;
foreach($items as $item) {
if(!empty($item['product_id'])) {
$product = '{"ProductID"=>' . $item['product_id'] . '}';
$products = $product;
}
}
But not the expected result.
php
edited Dec 31 '18 at 7:48
marc_s
575k12811101257
asked Dec 31 '18 at 3:25
KuangKuang
203
add a comment |
-2
I have array something like this
Array
(
[0] => Array
(
[product_id] => 13
[unit] => 1
[price] => 20.0000
[total] => 20.0000
)
[1] => Array
(
[product_id] => 15
[unit] => 2
[price] => 30.0000
[total] => 10.0000
)
)
I was stuck to transform above array to the "ProductList" in the following pattern
array(
"UserID" => 2,
"ProductList" => [
{
"ProductID"=> 13,
"Price"=> 20.0000
},
{
"ProductID"=> 15,
"Price"=> 30.0000
}
]
)
I tried like this:
$products = ;
foreach($items as $item) {
if(!empty($item['product_id'])) {
$product = '{"ProductID"=>' . $item['product_id'] . '}';
$products = $product;
}
}
But not the expected result.
php
edited Dec 31 '18 at 7:48
marc_s
575k12811101257
asked Dec 31 '18 at 3:25
KuangKuang
203
use the php providedjson_encodefunction
– Hasta Dhana
Dec 31 '18 at 3:26
What you want to transform to isn't really JSON with that outerarray(). What is it that you want, exactly?
– Brad
Dec 31 '18 at 3:30
@Brad I have array from the first block of code. Just wondered how to pass the values into "ProductList" of second block of code (Need exactly same pattern like this) Failed with json_encode, maybe I did something wrong.
– Kuang
Dec 31 '18 at 3:40
@Kuang First, get the structure you want in a regular object. Then, usejson_encode()on that object. It's a two-step process since you want to transform that object first.
– Brad
Dec 31 '18 at 3:41
add a comment |
-2
-2
-2
I have array something like this
Array
(
[0] => Array
(
[product_id] => 13
[unit] => 1
[price] => 20.0000
[total] => 20.0000
)
[1] => Array
(
[product_id] => 15
[unit] => 2
[price] => 30.0000
[total] => 10.0000
)
)
I was stuck to transform above array to the "ProductList" in the following pattern
array(
"UserID" => 2,
"ProductList" => [
{
"ProductID"=> 13,
"Price"=> 20.0000
},
{
"ProductID"=> 15,
"Price"=> 30.0000
}
]
)
I tried like this:
$products = ;
foreach($items as $item) {
if(!empty($item['product_id'])) {
$product = '{"ProductID"=>' . $item['product_id'] . '}';
$products = $product;
}
}
But not the expected result.
php
edited Dec 31 '18 at 7:48
marc_s
575k12811101257
asked Dec 31 '18 at 3:25
KuangKuang
203
I have array something like this
Array
(
[0] => Array
(
[product_id] => 13
[unit] => 1
[price] => 20.0000
[total] => 20.0000
)
[1] => Array
(
[product_id] => 15
[unit] => 2
[price] => 30.0000
[total] => 10.0000
)
)
I was stuck to transform above array to the "ProductList" in the following pattern
array(
"UserID" => 2,
"ProductList" => [
{
"ProductID"=> 13,
"Price"=> 20.0000
},
{
"ProductID"=> 15,
"Price"=> 30.0000
}
]
)
I tried like this:
$products = ;
foreach($items as $item) {
if(!empty($item['product_id'])) {
$product = '{"ProductID"=>' . $item['product_id'] . '}';
$products = $product;
}
}
But not the expected result.
php
php
edited Dec 31 '18 at 7:48
marc_s
575k12811101257
asked Dec 31 '18 at 3:25
KuangKuang
203
edited Dec 31 '18 at 7:48
marc_s
575k12811101257
asked Dec 31 '18 at 3:25
KuangKuang
203
edited Dec 31 '18 at 7:48
marc_s
575k12811101257
edited Dec 31 '18 at 7:48
marc_s
575k12811101257
edited Dec 31 '18 at 7:48
marc_s
575k12811101257
575k12811101257
asked Dec 31 '18 at 3:25
KuangKuang
203
asked Dec 31 '18 at 3:25
KuangKuang
203
asked Dec 31 '18 at 3:25
KuangKuang
203
203
use the php providedjson_encodefunction
– Hasta Dhana
Dec 31 '18 at 3:26
What you want to transform to isn't really JSON with that outerarray(). What is it that you want, exactly?
– Brad
Dec 31 '18 at 3:30
@Brad I have array from the first block of code. Just wondered how to pass the values into "ProductList" of second block of code (Need exactly same pattern like this) Failed with json_encode, maybe I did something wrong.
– Kuang
Dec 31 '18 at 3:40
@Kuang First, get the structure you want in a regular object. Then, usejson_encode()on that object. It's a two-step process since you want to transform that object first.
– Brad
Dec 31 '18 at 3:41
add a comment |
use the php providedjson_encodefunction
– Hasta Dhana
Dec 31 '18 at 3:26
What you want to transform to isn't really JSON with that outerarray(). What is it that you want, exactly?
– Brad
Dec 31 '18 at 3:30
@Brad I have array from the first block of code. Just wondered how to pass the values into "ProductList" of second block of code (Need exactly same pattern like this) Failed with json_encode, maybe I did something wrong.
– Kuang
Dec 31 '18 at 3:40
@Kuang First, get the structure you want in a regular object. Then, usejson_encode()on that object. It's a two-step process since you want to transform that object first.
– Brad
Dec 31 '18 at 3:41
use the php provided
json_encode function– Hasta Dhana
Dec 31 '18 at 3:26
use the php provided
json_encode function– Hasta Dhana
Dec 31 '18 at 3:26
What you want to transform to isn't really JSON with that outer
array(). What is it that you want, exactly?– Brad
Dec 31 '18 at 3:30
What you want to transform to isn't really JSON with that outer
array(). What is it that you want, exactly?– Brad
Dec 31 '18 at 3:30
@Brad I have array from the first block of code. Just wondered how to pass the values into "ProductList" of second block of code (Need exactly same pattern like this) Failed with json_encode, maybe I did something wrong.
– Kuang
Dec 31 '18 at 3:40
@Brad I have array from the first block of code. Just wondered how to pass the values into "ProductList" of second block of code (Need exactly same pattern like this) Failed with json_encode, maybe I did something wrong.
– Kuang
Dec 31 '18 at 3:40
@Kuang First, get the structure you want in a regular object. Then, use
json_encode() on that object. It's a two-step process since you want to transform that object first.– Brad
Dec 31 '18 at 3:41
@Kuang First, get the structure you want in a regular object. Then, use
json_encode() on that object. It's a two-step process since you want to transform that object first.– Brad
Dec 31 '18 at 3:41
add a comment |
2 Answers
2
active
oldest
votes
0
You're looking for json_encode(): http://php.net/manual/en/function.json-encode.php
Assign your array to a variable, for example $products, and then you can simply write json_encode($products) to achieve your desired result.
answered Dec 31 '18 at 3:28
James GrimshawJames Grimshaw
10618
Link-only answers aren't usually all that useful. While you're right, assume the person asking the question actually did look in the manual and probably doesn't know what they're looking for. You don't have to write a book on the topic or anything, but some in-context code would be helpful.
– Brad
Dec 31 '18 at 3:31
add a comment |
0
Try this,
$prodlist = array();
$x = 0;
foreach($arrs as $arr) {
//if ($arr['product_id'] == "" && $arr['price'] == "") continue;
$prodlist[$x]['Price'] = $arr['price'];
$prodlist[$x]['ProductID'] = $arr['product_id'];
$x += 1;
}
$arr2return['user_id'] = $user_id;
$arr2return['ProductList'] = $prodlist;
json_encode($arr2return);
answered Dec 31 '18 at 4:10
Apetu GideonApetu Gideon
564
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You're looking for json_encode(): http://php.net/manual/en/function.json-encode.php
Assign your array to a variable, for example $products, and then you can simply write json_encode($products) to achieve your desired result.
answered Dec 31 '18 at 3:28
James GrimshawJames Grimshaw
10618
Link-only answers aren't usually all that useful. While you're right, assume the person asking the question actually did look in the manual and probably doesn't know what they're looking for. You don't have to write a book on the topic or anything, but some in-context code would be helpful.
– Brad
Dec 31 '18 at 3:31
add a comment |
0
You're looking for json_encode(): http://php.net/manual/en/function.json-encode.php
Assign your array to a variable, for example $products, and then you can simply write json_encode($products) to achieve your desired result.
answered Dec 31 '18 at 3:28
James GrimshawJames Grimshaw
10618
Link-only answers aren't usually all that useful. While you're right, assume the person asking the question actually did look in the manual and probably doesn't know what they're looking for. You don't have to write a book on the topic or anything, but some in-context code would be helpful.
– Brad
Dec 31 '18 at 3:31
add a comment |
0
0
0
You're looking for json_encode(): http://php.net/manual/en/function.json-encode.php
Assign your array to a variable, for example $products, and then you can simply write json_encode($products) to achieve your desired result.
answered Dec 31 '18 at 3:28
James GrimshawJames Grimshaw
10618
You're looking for json_encode(): http://php.net/manual/en/function.json-encode.php
Assign your array to a variable, for example $products, and then you can simply write json_encode($products) to achieve your desired result.
answered Dec 31 '18 at 3:28
James GrimshawJames Grimshaw
10618
edited Dec 31 '18 at 3:34
answered Dec 31 '18 at 3:28
James GrimshawJames Grimshaw
10618
answered Dec 31 '18 at 3:28
James GrimshawJames Grimshaw
10618
answered Dec 31 '18 at 3:28
James GrimshawJames Grimshaw
10618
10618
Link-only answers aren't usually all that useful. While you're right, assume the person asking the question actually did look in the manual and probably doesn't know what they're looking for. You don't have to write a book on the topic or anything, but some in-context code would be helpful.
– Brad
Dec 31 '18 at 3:31
add a comment |
Link-only answers aren't usually all that useful. While you're right, assume the person asking the question actually did look in the manual and probably doesn't know what they're looking for. You don't have to write a book on the topic or anything, but some in-context code would be helpful.
– Brad
Dec 31 '18 at 3:31
Link-only answers aren't usually all that useful. While you're right, assume the person asking the question actually did look in the manual and probably doesn't know what they're looking for. You don't have to write a book on the topic or anything, but some in-context code would be helpful.
– Brad
Dec 31 '18 at 3:31
Link-only answers aren't usually all that useful. While you're right, assume the person asking the question actually did look in the manual and probably doesn't know what they're looking for. You don't have to write a book on the topic or anything, but some in-context code would be helpful.
– Brad
Dec 31 '18 at 3:31
add a comment |
0
Try this,
$prodlist = array();
$x = 0;
foreach($arrs as $arr) {
//if ($arr['product_id'] == "" && $arr['price'] == "") continue;
$prodlist[$x]['Price'] = $arr['price'];
$prodlist[$x]['ProductID'] = $arr['product_id'];
$x += 1;
}
$arr2return['user_id'] = $user_id;
$arr2return['ProductList'] = $prodlist;
json_encode($arr2return);
answered Dec 31 '18 at 4:10
Apetu GideonApetu Gideon
564
add a comment |
0
Try this,
$prodlist = array();
$x = 0;
foreach($arrs as $arr) {
//if ($arr['product_id'] == "" && $arr['price'] == "") continue;
$prodlist[$x]['Price'] = $arr['price'];
$prodlist[$x]['ProductID'] = $arr['product_id'];
$x += 1;
}
$arr2return['user_id'] = $user_id;
$arr2return['ProductList'] = $prodlist;
json_encode($arr2return);
answered Dec 31 '18 at 4:10
Apetu GideonApetu Gideon
564
add a comment |
0
0
0
Try this,
$prodlist = array();
$x = 0;
foreach($arrs as $arr) {
//if ($arr['product_id'] == "" && $arr['price'] == "") continue;
$prodlist[$x]['Price'] = $arr['price'];
$prodlist[$x]['ProductID'] = $arr['product_id'];
$x += 1;
}
$arr2return['user_id'] = $user_id;
$arr2return['ProductList'] = $prodlist;
json_encode($arr2return);
answered Dec 31 '18 at 4:10
Apetu GideonApetu Gideon
564
Try this,
$prodlist = array();
$x = 0;
foreach($arrs as $arr) {
//if ($arr['product_id'] == "" && $arr['price'] == "") continue;
$prodlist[$x]['Price'] = $arr['price'];
$prodlist[$x]['ProductID'] = $arr['product_id'];
$x += 1;
}
$arr2return['user_id'] = $user_id;
$arr2return['ProductList'] = $prodlist;
json_encode($arr2return);
answered Dec 31 '18 at 4:10
Apetu GideonApetu Gideon
564
answered Dec 31 '18 at 4:10
Apetu GideonApetu Gideon
564
answered Dec 31 '18 at 4:10
Apetu GideonApetu Gideon
564
answered Dec 31 '18 at 4:10
Apetu GideonApetu Gideon
564
564
add a comment |
add a comment |
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use the php provided
json_encodefunction– Hasta Dhana
Dec 31 '18 at 3:26
What you want to transform to isn't really JSON with that outer
array(). What is it that you want, exactly?– Brad
Dec 31 '18 at 3:30
@Brad I have array from the first block of code. Just wondered how to pass the values into "ProductList" of second block of code (Need exactly same pattern like this) Failed with json_encode, maybe I did something wrong.
– Kuang
Dec 31 '18 at 3:40
@Kuang First, get the structure you want in a regular object. Then, use
json_encode()on that object. It's a two-step process since you want to transform that object first.– Brad
Dec 31 '18 at 3:41