double quotes in zsh parameter expansion
I have two test cases in zsh
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
However if I first assign the output of echo to a variable, the quotes do not have any effect:
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
Questions:
- comparing A and B, what causes the differences?
- comparing A and C, what causes the differences?
zsh double-quotes parameter-expansion
asked Dec 31 '18 at 3:34
Liu ShaLiu Sha
596320
add a comment |
I have two test cases in zsh
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
However if I first assign the output of echo to a variable, the quotes do not have any effect:
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
Questions:
- comparing A and B, what causes the differences?
- comparing A and C, what causes the differences?
zsh double-quotes parameter-expansion
asked Dec 31 '18 at 3:34
Liu ShaLiu Sha
596320
add a comment |
I have two test cases in zsh
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
However if I first assign the output of echo to a variable, the quotes do not have any effect:
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
Questions:
- comparing A and B, what causes the differences?
- comparing A and C, what causes the differences?
zsh double-quotes parameter-expansion
asked Dec 31 '18 at 3:34
Liu ShaLiu Sha
596320
I have two test cases in zsh
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
However if I first assign the output of echo to a variable, the quotes do not have any effect:
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
Questions:
- comparing A and B, what causes the differences?
- comparing A and C, what causes the differences?
zsh double-quotes parameter-expansion
zsh double-quotes parameter-expansion
asked Dec 31 '18 at 3:34
Liu ShaLiu Sha
596320
asked Dec 31 '18 at 3:34
Liu ShaLiu Sha
596320
asked Dec 31 '18 at 3:34
Liu ShaLiu Sha
596320
asked Dec 31 '18 at 3:34
Liu ShaLiu Sha
596320
asked Dec 31 '18 at 3:34
Liu ShaLiu Sha
596320
596320
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
After some experiment, I feel the following rules may have been applied
Sec1. direct use
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
unquoted
$()produces words split byIFS: see http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
quoted
$()produces a single string
Sec2. assignment to scalar
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
Sec3. assignment to array
y=($(echo -e "a bnc d"))
Follows Sec1 http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
answered Jan 11 at 6:03
Liu ShaLiu Sha
596320
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
After some experiment, I feel the following rules may have been applied
Sec1. direct use
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
unquoted
$()produces words split byIFS: see http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
quoted
$()produces a single string
Sec2. assignment to scalar
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
Sec3. assignment to array
y=($(echo -e "a bnc d"))
Follows Sec1 http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
answered Jan 11 at 6:03
Liu ShaLiu Sha
596320
add a comment |
After some experiment, I feel the following rules may have been applied
Sec1. direct use
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
unquoted
$()produces words split byIFS: see http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
quoted
$()produces a single string
Sec2. assignment to scalar
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
Sec3. assignment to array
y=($(echo -e "a bnc d"))
Follows Sec1 http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
answered Jan 11 at 6:03
Liu ShaLiu Sha
596320
add a comment |
After some experiment, I feel the following rules may have been applied
Sec1. direct use
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
unquoted
$()produces words split byIFS: see http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
quoted
$()produces a single string
Sec2. assignment to scalar
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
Sec3. assignment to array
y=($(echo -e "a bnc d"))
Follows Sec1 http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
answered Jan 11 at 6:03
Liu ShaLiu Sha
596320
After some experiment, I feel the following rules may have been applied
Sec1. direct use
A. without quotes
~$ y=(${(f)$(echo -e "a bnc d")}); printf "<%s>n" "${y[@]}"
<a b c d>
unquoted
$()produces words split byIFS: see http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
B. with quotes
~$ y=(${(f)"$(echo -e "a bnc d")"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
quoted
$()produces a single string
Sec2. assignment to scalar
C. without quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)${x}}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
D. with quotes
~$ x=$(echo -e "a bnc d"); y=(${(f)"${x}"}); printf "<%s>n" "${y[@]}"
<a b>
<c d>
when being assigned to a scalar, it works as automatically quoted
Sec3. assignment to array
y=($(echo -e "a bnc d"))
Follows Sec1 http://zsh.sourceforge.net/Doc/Release/Expansion.html#Command-Substitution
answered Jan 11 at 6:03
Liu ShaLiu Sha
596320
answered Jan 11 at 6:03
Liu ShaLiu Sha
596320
answered Jan 11 at 6:03
Liu ShaLiu Sha
596320
answered Jan 11 at 6:03
Liu ShaLiu Sha
596320
596320
add a comment |
add a comment |
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