How to replace data in a data frame in R?
-2
I am currently a novice in R (I have the basics, that's all), and I have a small issue in a data frame :
What I want to do here is :
- For all elements in the Wage column, replace the 'K' with '000'
- For all elements in the Value column : if the cell contains a '.', then replace the 'M' with '00000', if not, then replace it with '000000'
I guess this could by achieved with a for loop, but after trying I can say that I am not used to it.
Thanks for your answers,
Rémi
r
edited Dec 28 '18 at 18:36
Lyngbakr
4,50111325
asked Dec 28 '18 at 18:18
Rémi PtsRémi Pts
112
add a comment |
-2
I am currently a novice in R (I have the basics, that's all), and I have a small issue in a data frame :
What I want to do here is :
- For all elements in the Wage column, replace the 'K' with '000'
- For all elements in the Value column : if the cell contains a '.', then replace the 'M' with '00000', if not, then replace it with '000000'
I guess this could by achieved with a for loop, but after trying I can say that I am not used to it.
Thanks for your answers,
Rémi
r
edited Dec 28 '18 at 18:36
Lyngbakr
4,50111325
asked Dec 28 '18 at 18:18
Rémi PtsRémi Pts
112
5
Hi, please consider editing your question to add the output ofdput(head(dataframe,20))rather than an image. Also sample code of what you've tried is appreciated. Cheers!
– NelsonGon
Dec 28 '18 at 18:20
add a comment |
-2
-2
-2
I am currently a novice in R (I have the basics, that's all), and I have a small issue in a data frame :
What I want to do here is :
- For all elements in the Wage column, replace the 'K' with '000'
- For all elements in the Value column : if the cell contains a '.', then replace the 'M' with '00000', if not, then replace it with '000000'
I guess this could by achieved with a for loop, but after trying I can say that I am not used to it.
Thanks for your answers,
Rémi
r
edited Dec 28 '18 at 18:36
Lyngbakr
4,50111325
asked Dec 28 '18 at 18:18
Rémi PtsRémi Pts
112
I am currently a novice in R (I have the basics, that's all), and I have a small issue in a data frame :
What I want to do here is :
- For all elements in the Wage column, replace the 'K' with '000'
- For all elements in the Value column : if the cell contains a '.', then replace the 'M' with '00000', if not, then replace it with '000000'
I guess this could by achieved with a for loop, but after trying I can say that I am not used to it.
Thanks for your answers,
Rémi
r
r
edited Dec 28 '18 at 18:36
Lyngbakr
4,50111325
asked Dec 28 '18 at 18:18
Rémi PtsRémi Pts
112
edited Dec 28 '18 at 18:36
Lyngbakr
4,50111325
asked Dec 28 '18 at 18:18
Rémi PtsRémi Pts
112
edited Dec 28 '18 at 18:36
Lyngbakr
4,50111325
edited Dec 28 '18 at 18:36
Lyngbakr
4,50111325
edited Dec 28 '18 at 18:36
Lyngbakr
4,50111325
4,50111325
asked Dec 28 '18 at 18:18
Rémi PtsRémi Pts
112
asked Dec 28 '18 at 18:18
Rémi PtsRémi Pts
112
asked Dec 28 '18 at 18:18
Rémi PtsRémi Pts
112
112
5
Hi, please consider editing your question to add the output ofdput(head(dataframe,20))rather than an image. Also sample code of what you've tried is appreciated. Cheers!
– NelsonGon
Dec 28 '18 at 18:20
add a comment |
5
Hi, please consider editing your question to add the output ofdput(head(dataframe,20))rather than an image. Also sample code of what you've tried is appreciated. Cheers!
– NelsonGon
Dec 28 '18 at 18:20
5
5
Hi, please consider editing your question to add the output of
dput(head(dataframe,20)) rather than an image. Also sample code of what you've tried is appreciated. Cheers!– NelsonGon
Dec 28 '18 at 18:20
Hi, please consider editing your question to add the output of
dput(head(dataframe,20)) rather than an image. Also sample code of what you've tried is appreciated. Cheers!– NelsonGon
Dec 28 '18 at 18:20
add a comment |
1 Answer
1
active
oldest
votes
0
A solution similar to this is probably more comprehensive:
parseBigNumbers <- function(vec) {
vec <- gsub("K", "e+3", vec)
vec <- gsub("M", "e+6", vec)
as.numeric(substr(vec, 2, nchar(vec)))
}
df$Wage <- parseBigNumbers(df$Wage)
df$Value <- parseBigNumbers(df$Value)
answered Dec 28 '18 at 19:05
mpjdemmpjdem
1,334413
Thank you, this worked too ! I might go for this solution because I might have other columns where I need to use this method. Thanks !
– Rémi Pts
Dec 28 '18 at 20:07
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
A solution similar to this is probably more comprehensive:
parseBigNumbers <- function(vec) {
vec <- gsub("K", "e+3", vec)
vec <- gsub("M", "e+6", vec)
as.numeric(substr(vec, 2, nchar(vec)))
}
df$Wage <- parseBigNumbers(df$Wage)
df$Value <- parseBigNumbers(df$Value)
answered Dec 28 '18 at 19:05
mpjdemmpjdem
1,334413
Thank you, this worked too ! I might go for this solution because I might have other columns where I need to use this method. Thanks !
– Rémi Pts
Dec 28 '18 at 20:07
add a comment |
0
A solution similar to this is probably more comprehensive:
parseBigNumbers <- function(vec) {
vec <- gsub("K", "e+3", vec)
vec <- gsub("M", "e+6", vec)
as.numeric(substr(vec, 2, nchar(vec)))
}
df$Wage <- parseBigNumbers(df$Wage)
df$Value <- parseBigNumbers(df$Value)
answered Dec 28 '18 at 19:05
mpjdemmpjdem
1,334413
Thank you, this worked too ! I might go for this solution because I might have other columns where I need to use this method. Thanks !
– Rémi Pts
Dec 28 '18 at 20:07
add a comment |
0
0
0
A solution similar to this is probably more comprehensive:
parseBigNumbers <- function(vec) {
vec <- gsub("K", "e+3", vec)
vec <- gsub("M", "e+6", vec)
as.numeric(substr(vec, 2, nchar(vec)))
}
df$Wage <- parseBigNumbers(df$Wage)
df$Value <- parseBigNumbers(df$Value)
answered Dec 28 '18 at 19:05
mpjdemmpjdem
1,334413
A solution similar to this is probably more comprehensive:
parseBigNumbers <- function(vec) {
vec <- gsub("K", "e+3", vec)
vec <- gsub("M", "e+6", vec)
as.numeric(substr(vec, 2, nchar(vec)))
}
df$Wage <- parseBigNumbers(df$Wage)
df$Value <- parseBigNumbers(df$Value)
answered Dec 28 '18 at 19:05
mpjdemmpjdem
1,334413
answered Dec 28 '18 at 19:05
mpjdemmpjdem
1,334413
answered Dec 28 '18 at 19:05
mpjdemmpjdem
1,334413
answered Dec 28 '18 at 19:05
mpjdemmpjdem
1,334413
1,334413
Thank you, this worked too ! I might go for this solution because I might have other columns where I need to use this method. Thanks !
– Rémi Pts
Dec 28 '18 at 20:07
add a comment |
Thank you, this worked too ! I might go for this solution because I might have other columns where I need to use this method. Thanks !
– Rémi Pts
Dec 28 '18 at 20:07
Thank you, this worked too ! I might go for this solution because I might have other columns where I need to use this method. Thanks !
– Rémi Pts
Dec 28 '18 at 20:07
Thank you, this worked too ! I might go for this solution because I might have other columns where I need to use this method. Thanks !
– Rémi Pts
Dec 28 '18 at 20:07
add a comment |
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5
Hi, please consider editing your question to add the output of
dput(head(dataframe,20))rather than an image. Also sample code of what you've tried is appreciated. Cheers!– NelsonGon
Dec 28 '18 at 18:20