Extract unique monthly periods from pandas datetime column
I have a date column like this.
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-29
2012-01-29
2012-01-29
2012-01-29
2012-01-29
2012-01-29
....
2016-12-31
2016-12-31
2016-12-31
2016-12-31
I want to convert it into any of the below format: i.e get the unique yyyy-mm
2012-01 or 2012-Jan or Jan
2012-02 or 2012-Feb or Feb
2012-03
...
2016-12 or 2012-Dec or Dec
python pandas datetime
add a comment |
I have a date column like this.
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-29
2012-01-29
2012-01-29
2012-01-29
2012-01-29
2012-01-29
....
2016-12-31
2016-12-31
2016-12-31
2016-12-31
I want to convert it into any of the below format: i.e get the unique yyyy-mm
2012-01 or 2012-Jan or Jan
2012-02 or 2012-Feb or Feb
2012-03
...
2016-12 or 2012-Dec or Dec
python pandas datetime
Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. StackOverflow is not a design, coding, research, or tutorial resource. However, if you follow whatever resources you find on line, make an honest coding attempt, and run into a problem, you'd have a good example to post.
– Prune
Dec 28 '18 at 20:16
If your question was answered, please vote on, and accept the most helpful answer here. You can accept an answer by clicking the grey check to the left of the answer to toggle it green. TIA.
– coldspeed
Jan 12 at 23:04
add a comment |
I have a date column like this.
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-29
2012-01-29
2012-01-29
2012-01-29
2012-01-29
2012-01-29
....
2016-12-31
2016-12-31
2016-12-31
2016-12-31
I want to convert it into any of the below format: i.e get the unique yyyy-mm
2012-01 or 2012-Jan or Jan
2012-02 or 2012-Feb or Feb
2012-03
...
2016-12 or 2012-Dec or Dec
python pandas datetime
I have a date column like this.
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-28
2012-01-29
2012-01-29
2012-01-29
2012-01-29
2012-01-29
2012-01-29
....
2016-12-31
2016-12-31
2016-12-31
2016-12-31
I want to convert it into any of the below format: i.e get the unique yyyy-mm
2012-01 or 2012-Jan or Jan
2012-02 or 2012-Feb or Feb
2012-03
...
2016-12 or 2012-Dec or Dec
python pandas datetime
python pandas datetime
edited Dec 28 '18 at 19:45
coldspeed
124k22125208
124k22125208
asked Dec 28 '18 at 19:40
Dhiraj KumarDhiraj Kumar
434
434
Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. StackOverflow is not a design, coding, research, or tutorial resource. However, if you follow whatever resources you find on line, make an honest coding attempt, and run into a problem, you'd have a good example to post.
– Prune
Dec 28 '18 at 20:16
If your question was answered, please vote on, and accept the most helpful answer here. You can accept an answer by clicking the grey check to the left of the answer to toggle it green. TIA.
– coldspeed
Jan 12 at 23:04
add a comment |
Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. StackOverflow is not a design, coding, research, or tutorial resource. However, if you follow whatever resources you find on line, make an honest coding attempt, and run into a problem, you'd have a good example to post.
– Prune
Dec 28 '18 at 20:16
If your question was answered, please vote on, and accept the most helpful answer here. You can accept an answer by clicking the grey check to the left of the answer to toggle it green. TIA.
– coldspeed
Jan 12 at 23:04
Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. StackOverflow is not a design, coding, research, or tutorial resource. However, if you follow whatever resources you find on line, make an honest coding attempt, and run into a problem, you'd have a good example to post.
– Prune
Dec 28 '18 at 20:16
Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. StackOverflow is not a design, coding, research, or tutorial resource. However, if you follow whatever resources you find on line, make an honest coding attempt, and run into a problem, you'd have a good example to post.
– Prune
Dec 28 '18 at 20:16
If your question was answered, please vote on, and accept the most helpful answer here. You can accept an answer by clicking the grey check to the left of the answer to toggle it green. TIA.
– coldspeed
Jan 12 at 23:04
If your question was answered, please vote on, and accept the most helpful answer here. You can accept an answer by clicking the grey check to the left of the answer to toggle it green. TIA.
– coldspeed
Jan 12 at 23:04
add a comment |
1 Answer
1
active
oldest
votes
Use DatetimeIndex.to_period
:
pd.DatetimeIndex(df['date']).to_period('M').unique()
# PeriodIndex(['2012-01', '2016-12'], dtype='period[M]', name='date', freq='M')
If month names are needed, use strftime
:
df['date'].dt.strftime('%Y-%b').unique()
# array(['2012-Jan', '2016-Dec'], dtype=object)
If Series format is necessary, use drop_duplicates
:
df['date'].dt.strftime('%Y-%b').drop_duplicates()
0 2012-Jan
18 2016-Dec
Name: date, dtype: object
@W-B Wow, did not notice such a thread... interesting indeed!
– coldspeed
Dec 28 '18 at 19:51
1
Just Jez, you and Pir are too good and' jealous people'
– W-B
Dec 28 '18 at 19:52
@W-B Add yourself to that list please, you are one of us and have been so for a long time.
– coldspeed
Dec 28 '18 at 19:53
1
Nope I only have limit years experience with python and learn from your guys :-)
– W-B
Dec 28 '18 at 19:54
1
Just catch an good answer there
– W-B
Dec 28 '18 at 20:07
|
show 2 more comments
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use DatetimeIndex.to_period
:
pd.DatetimeIndex(df['date']).to_period('M').unique()
# PeriodIndex(['2012-01', '2016-12'], dtype='period[M]', name='date', freq='M')
If month names are needed, use strftime
:
df['date'].dt.strftime('%Y-%b').unique()
# array(['2012-Jan', '2016-Dec'], dtype=object)
If Series format is necessary, use drop_duplicates
:
df['date'].dt.strftime('%Y-%b').drop_duplicates()
0 2012-Jan
18 2016-Dec
Name: date, dtype: object
@W-B Wow, did not notice such a thread... interesting indeed!
– coldspeed
Dec 28 '18 at 19:51
1
Just Jez, you and Pir are too good and' jealous people'
– W-B
Dec 28 '18 at 19:52
@W-B Add yourself to that list please, you are one of us and have been so for a long time.
– coldspeed
Dec 28 '18 at 19:53
1
Nope I only have limit years experience with python and learn from your guys :-)
– W-B
Dec 28 '18 at 19:54
1
Just catch an good answer there
– W-B
Dec 28 '18 at 20:07
|
show 2 more comments
Use DatetimeIndex.to_period
:
pd.DatetimeIndex(df['date']).to_period('M').unique()
# PeriodIndex(['2012-01', '2016-12'], dtype='period[M]', name='date', freq='M')
If month names are needed, use strftime
:
df['date'].dt.strftime('%Y-%b').unique()
# array(['2012-Jan', '2016-Dec'], dtype=object)
If Series format is necessary, use drop_duplicates
:
df['date'].dt.strftime('%Y-%b').drop_duplicates()
0 2012-Jan
18 2016-Dec
Name: date, dtype: object
@W-B Wow, did not notice such a thread... interesting indeed!
– coldspeed
Dec 28 '18 at 19:51
1
Just Jez, you and Pir are too good and' jealous people'
– W-B
Dec 28 '18 at 19:52
@W-B Add yourself to that list please, you are one of us and have been so for a long time.
– coldspeed
Dec 28 '18 at 19:53
1
Nope I only have limit years experience with python and learn from your guys :-)
– W-B
Dec 28 '18 at 19:54
1
Just catch an good answer there
– W-B
Dec 28 '18 at 20:07
|
show 2 more comments
Use DatetimeIndex.to_period
:
pd.DatetimeIndex(df['date']).to_period('M').unique()
# PeriodIndex(['2012-01', '2016-12'], dtype='period[M]', name='date', freq='M')
If month names are needed, use strftime
:
df['date'].dt.strftime('%Y-%b').unique()
# array(['2012-Jan', '2016-Dec'], dtype=object)
If Series format is necessary, use drop_duplicates
:
df['date'].dt.strftime('%Y-%b').drop_duplicates()
0 2012-Jan
18 2016-Dec
Name: date, dtype: object
Use DatetimeIndex.to_period
:
pd.DatetimeIndex(df['date']).to_period('M').unique()
# PeriodIndex(['2012-01', '2016-12'], dtype='period[M]', name='date', freq='M')
If month names are needed, use strftime
:
df['date'].dt.strftime('%Y-%b').unique()
# array(['2012-Jan', '2016-Dec'], dtype=object)
If Series format is necessary, use drop_duplicates
:
df['date'].dt.strftime('%Y-%b').drop_duplicates()
0 2012-Jan
18 2016-Dec
Name: date, dtype: object
answered Dec 28 '18 at 19:45
coldspeedcoldspeed
124k22125208
124k22125208
@W-B Wow, did not notice such a thread... interesting indeed!
– coldspeed
Dec 28 '18 at 19:51
1
Just Jez, you and Pir are too good and' jealous people'
– W-B
Dec 28 '18 at 19:52
@W-B Add yourself to that list please, you are one of us and have been so for a long time.
– coldspeed
Dec 28 '18 at 19:53
1
Nope I only have limit years experience with python and learn from your guys :-)
– W-B
Dec 28 '18 at 19:54
1
Just catch an good answer there
– W-B
Dec 28 '18 at 20:07
|
show 2 more comments
@W-B Wow, did not notice such a thread... interesting indeed!
– coldspeed
Dec 28 '18 at 19:51
1
Just Jez, you and Pir are too good and' jealous people'
– W-B
Dec 28 '18 at 19:52
@W-B Add yourself to that list please, you are one of us and have been so for a long time.
– coldspeed
Dec 28 '18 at 19:53
1
Nope I only have limit years experience with python and learn from your guys :-)
– W-B
Dec 28 '18 at 19:54
1
Just catch an good answer there
– W-B
Dec 28 '18 at 20:07
@W-B Wow, did not notice such a thread... interesting indeed!
– coldspeed
Dec 28 '18 at 19:51
@W-B Wow, did not notice such a thread... interesting indeed!
– coldspeed
Dec 28 '18 at 19:51
1
1
Just Jez, you and Pir are too good and' jealous people'
– W-B
Dec 28 '18 at 19:52
Just Jez, you and Pir are too good and' jealous people'
– W-B
Dec 28 '18 at 19:52
@W-B Add yourself to that list please, you are one of us and have been so for a long time.
– coldspeed
Dec 28 '18 at 19:53
@W-B Add yourself to that list please, you are one of us and have been so for a long time.
– coldspeed
Dec 28 '18 at 19:53
1
1
Nope I only have limit years experience with python and learn from your guys :-)
– W-B
Dec 28 '18 at 19:54
Nope I only have limit years experience with python and learn from your guys :-)
– W-B
Dec 28 '18 at 19:54
1
1
Just catch an good answer there
– W-B
Dec 28 '18 at 20:07
Just catch an good answer there
– W-B
Dec 28 '18 at 20:07
|
show 2 more comments
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Welcome to StackOverflow. Please read and follow the posting guidelines in the help documentation, as suggested when you created this account. On topic, how to ask, and ... the perfect question apply here. StackOverflow is not a design, coding, research, or tutorial resource. However, if you follow whatever resources you find on line, make an honest coding attempt, and run into a problem, you'd have a good example to post.
– Prune
Dec 28 '18 at 20:16
If your question was answered, please vote on, and accept the most helpful answer here. You can accept an answer by clicking the grey check to the left of the answer to toggle it green. TIA.
– coldspeed
Jan 12 at 23:04