Map varray of number(10) with hibernate and spring data jpa












1















If I have type in oracle declared like this :



CREATE TYPE group_ids AS VARRAY(1000000) OF NUMBER(10);


And a table like this :



CREATE TABLE player_group_included
(
group_id NUMBER(10) PRIMARY KEY,
ids group_ids,

CONSTRAINT fk_grIncl_group FOREIGN KEY (group_id) REFERENCES player_group (id)
);


How can I map the player_group_included table to the Java entity with Hibernate/Spring Data JPA?



The obvious problem here is the ids column because it is using the custom Oracle type (array of numbers) and Hibernate cant recognize that by default.










share|improve this question























  • Have a look at this: vladmihalcea.com/…

    – Simon Martinelli
    Dec 30 '18 at 10:33
















1















If I have type in oracle declared like this :



CREATE TYPE group_ids AS VARRAY(1000000) OF NUMBER(10);


And a table like this :



CREATE TABLE player_group_included
(
group_id NUMBER(10) PRIMARY KEY,
ids group_ids,

CONSTRAINT fk_grIncl_group FOREIGN KEY (group_id) REFERENCES player_group (id)
);


How can I map the player_group_included table to the Java entity with Hibernate/Spring Data JPA?



The obvious problem here is the ids column because it is using the custom Oracle type (array of numbers) and Hibernate cant recognize that by default.










share|improve this question























  • Have a look at this: vladmihalcea.com/…

    – Simon Martinelli
    Dec 30 '18 at 10:33














1












1








1








If I have type in oracle declared like this :



CREATE TYPE group_ids AS VARRAY(1000000) OF NUMBER(10);


And a table like this :



CREATE TABLE player_group_included
(
group_id NUMBER(10) PRIMARY KEY,
ids group_ids,

CONSTRAINT fk_grIncl_group FOREIGN KEY (group_id) REFERENCES player_group (id)
);


How can I map the player_group_included table to the Java entity with Hibernate/Spring Data JPA?



The obvious problem here is the ids column because it is using the custom Oracle type (array of numbers) and Hibernate cant recognize that by default.










share|improve this question














If I have type in oracle declared like this :



CREATE TYPE group_ids AS VARRAY(1000000) OF NUMBER(10);


And a table like this :



CREATE TABLE player_group_included
(
group_id NUMBER(10) PRIMARY KEY,
ids group_ids,

CONSTRAINT fk_grIncl_group FOREIGN KEY (group_id) REFERENCES player_group (id)
);


How can I map the player_group_included table to the Java entity with Hibernate/Spring Data JPA?



The obvious problem here is the ids column because it is using the custom Oracle type (array of numbers) and Hibernate cant recognize that by default.







spring oracle hibernate spring-data-jpa






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asked Dec 28 '18 at 19:25









Saša ŠijakSaša Šijak

3,65522857




3,65522857













  • Have a look at this: vladmihalcea.com/…

    – Simon Martinelli
    Dec 30 '18 at 10:33



















  • Have a look at this: vladmihalcea.com/…

    – Simon Martinelli
    Dec 30 '18 at 10:33

















Have a look at this: vladmihalcea.com/…

– Simon Martinelli
Dec 30 '18 at 10:33





Have a look at this: vladmihalcea.com/…

– Simon Martinelli
Dec 30 '18 at 10:33












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