How to continue program execution when using bufio.Scanner in golang
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Forgive me I am starting out in Go and I am learning about the bufio package but every time I use the Scanner type the command line is stuck on the input and does not continue with normal program flow. I have tried pressing Enter but it just keeps going to a new line.
Here is my code.
/*
Dup 1 prints the text of each line that appears more than
once in the standard input, proceeded by its count.
*/
package main
import(
"bufio"
"fmt"
"os"
)
func main(){
counts := make(map[string]int)
fmt.Println("Type Some Text")
input := bufio.NewScanner(os.Stdin)
for input.Scan(){
counts[input.Text()]++
}
//NOTE: Ignoring potential Errors from input.Err()
for line,n := range counts{
if n > 1{
fmt.Printf("%d t %s n",n,line)
}
}
}
go stdin
edited Jan 4 at 15:26
icza
178k25360389
asked Jan 4 at 10:28
Kwabena MuriukiKwabena Muriuki
468
add a comment |
Forgive me I am starting out in Go and I am learning about the bufio package but every time I use the Scanner type the command line is stuck on the input and does not continue with normal program flow. I have tried pressing Enter but it just keeps going to a new line.
Here is my code.
/*
Dup 1 prints the text of each line that appears more than
once in the standard input, proceeded by its count.
*/
package main
import(
"bufio"
"fmt"
"os"
)
func main(){
counts := make(map[string]int)
fmt.Println("Type Some Text")
input := bufio.NewScanner(os.Stdin)
for input.Scan(){
counts[input.Text()]++
}
//NOTE: Ignoring potential Errors from input.Err()
for line,n := range counts{
if n > 1{
fmt.Printf("%d t %s n",n,line)
}
}
}
go stdin
edited Jan 4 at 15:26
icza
178k25360389
asked Jan 4 at 10:28
Kwabena MuriukiKwabena Muriuki
468
add a comment |
Forgive me I am starting out in Go and I am learning about the bufio package but every time I use the Scanner type the command line is stuck on the input and does not continue with normal program flow. I have tried pressing Enter but it just keeps going to a new line.
Here is my code.
/*
Dup 1 prints the text of each line that appears more than
once in the standard input, proceeded by its count.
*/
package main
import(
"bufio"
"fmt"
"os"
)
func main(){
counts := make(map[string]int)
fmt.Println("Type Some Text")
input := bufio.NewScanner(os.Stdin)
for input.Scan(){
counts[input.Text()]++
}
//NOTE: Ignoring potential Errors from input.Err()
for line,n := range counts{
if n > 1{
fmt.Printf("%d t %s n",n,line)
}
}
}
go stdin
edited Jan 4 at 15:26
icza
178k25360389
asked Jan 4 at 10:28
Kwabena MuriukiKwabena Muriuki
468
Forgive me I am starting out in Go and I am learning about the bufio package but every time I use the Scanner type the command line is stuck on the input and does not continue with normal program flow. I have tried pressing Enter but it just keeps going to a new line.
Here is my code.
/*
Dup 1 prints the text of each line that appears more than
once in the standard input, proceeded by its count.
*/
package main
import(
"bufio"
"fmt"
"os"
)
func main(){
counts := make(map[string]int)
fmt.Println("Type Some Text")
input := bufio.NewScanner(os.Stdin)
for input.Scan(){
counts[input.Text()]++
}
//NOTE: Ignoring potential Errors from input.Err()
for line,n := range counts{
if n > 1{
fmt.Printf("%d t %s n",n,line)
}
}
}
go stdin
go stdin
edited Jan 4 at 15:26
icza
178k25360389
asked Jan 4 at 10:28
Kwabena MuriukiKwabena Muriuki
468
edited Jan 4 at 15:26
icza
178k25360389
asked Jan 4 at 10:28
Kwabena MuriukiKwabena Muriuki
468
edited Jan 4 at 15:26
icza
178k25360389
edited Jan 4 at 15:26
icza
178k25360389
edited Jan 4 at 15:26
icza
178k25360389
178k25360389
asked Jan 4 at 10:28
Kwabena MuriukiKwabena Muriuki
468
asked Jan 4 at 10:28
Kwabena MuriukiKwabena Muriuki
468
asked Jan 4 at 10:28
Kwabena MuriukiKwabena Muriuki
468
468
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You have a for loop which reads lines from the standard input. This loop will run as long as os.Stdin doesn't report io.EOF (that's one case when Scanner.Scan() would return false). Normally this won't happen.
If you want to "simulate" the end of input, press Ctrl+Z on Windows, or Ctrl+D on Linux / unix systems.
So enter some lines (each "closed" by Enter), and when you're finished, press the above mentioned key.
Example output:
Type Some Text
a
a
bb
bb
bbb <-- CTRL+D pressed here
2 a
2 bb
Another option would be to use a "special" word for termination, such as "exit". It could look like this:
for input.Scan() {
line := input.Text()
if line == "exit" {
break
}
counts[line]++
}
Testing it:
Type Some Text
a
a
bb
bb
bbb
exit
2 a
2 bb
answered Jan 4 at 10:33
iczaicza
178k25360389
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You have a for loop which reads lines from the standard input. This loop will run as long as os.Stdin doesn't report io.EOF (that's one case when Scanner.Scan() would return false). Normally this won't happen.
If you want to "simulate" the end of input, press Ctrl+Z on Windows, or Ctrl+D on Linux / unix systems.
So enter some lines (each "closed" by Enter), and when you're finished, press the above mentioned key.
Example output:
Type Some Text
a
a
bb
bb
bbb <-- CTRL+D pressed here
2 a
2 bb
Another option would be to use a "special" word for termination, such as "exit". It could look like this:
for input.Scan() {
line := input.Text()
if line == "exit" {
break
}
counts[line]++
}
Testing it:
Type Some Text
a
a
bb
bb
bbb
exit
2 a
2 bb
answered Jan 4 at 10:33
iczaicza
178k25360389
add a comment |
You have a for loop which reads lines from the standard input. This loop will run as long as os.Stdin doesn't report io.EOF (that's one case when Scanner.Scan() would return false). Normally this won't happen.
If you want to "simulate" the end of input, press Ctrl+Z on Windows, or Ctrl+D on Linux / unix systems.
So enter some lines (each "closed" by Enter), and when you're finished, press the above mentioned key.
Example output:
Type Some Text
a
a
bb
bb
bbb <-- CTRL+D pressed here
2 a
2 bb
Another option would be to use a "special" word for termination, such as "exit". It could look like this:
for input.Scan() {
line := input.Text()
if line == "exit" {
break
}
counts[line]++
}
Testing it:
Type Some Text
a
a
bb
bb
bbb
exit
2 a
2 bb
answered Jan 4 at 10:33
iczaicza
178k25360389
add a comment |
You have a for loop which reads lines from the standard input. This loop will run as long as os.Stdin doesn't report io.EOF (that's one case when Scanner.Scan() would return false). Normally this won't happen.
If you want to "simulate" the end of input, press Ctrl+Z on Windows, or Ctrl+D on Linux / unix systems.
So enter some lines (each "closed" by Enter), and when you're finished, press the above mentioned key.
Example output:
Type Some Text
a
a
bb
bb
bbb <-- CTRL+D pressed here
2 a
2 bb
Another option would be to use a "special" word for termination, such as "exit". It could look like this:
for input.Scan() {
line := input.Text()
if line == "exit" {
break
}
counts[line]++
}
Testing it:
Type Some Text
a
a
bb
bb
bbb
exit
2 a
2 bb
answered Jan 4 at 10:33
iczaicza
178k25360389
You have a for loop which reads lines from the standard input. This loop will run as long as os.Stdin doesn't report io.EOF (that's one case when Scanner.Scan() would return false). Normally this won't happen.
If you want to "simulate" the end of input, press Ctrl+Z on Windows, or Ctrl+D on Linux / unix systems.
So enter some lines (each "closed" by Enter), and when you're finished, press the above mentioned key.
Example output:
Type Some Text
a
a
bb
bb
bbb <-- CTRL+D pressed here
2 a
2 bb
Another option would be to use a "special" word for termination, such as "exit". It could look like this:
for input.Scan() {
line := input.Text()
if line == "exit" {
break
}
counts[line]++
}
Testing it:
Type Some Text
a
a
bb
bb
bbb
exit
2 a
2 bb
answered Jan 4 at 10:33
iczaicza
178k25360389
edited Jan 4 at 13:12
answered Jan 4 at 10:33
iczaicza
178k25360389
answered Jan 4 at 10:33
iczaicza
178k25360389
answered Jan 4 at 10:33
iczaicza
178k25360389
178k25360389
add a comment |
add a comment |
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