Filter array of objects based on a field in each object

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Let's say I have an array of objects like this:

[

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]

And I want to filter through it and create new objects based on the model field.

With the end result being:

[

  { "type": 121, "model": "model1" }

]



[

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]

I'm using typescript and lodash so anything with that would be best

I tried lodash groupBy and ES6 mapping, but no success so far. I guess I could do it in a dirty way with multiple forEach loops but I'm pretty sure there is a much easier way.

asked Jan 4 at 10:34

raulicious

991213

can you please provide your code or https://stackblitz.com/?

– Abhishek
Jan 4 at 10:39

add a comment |

Let's say I have an array of objects like this:

[

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]

And I want to filter through it and create new objects based on the model field.

With the end result being:

[

  { "type": 121, "model": "model1" }

]



[

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]

I'm using typescript and lodash so anything with that would be best

I tried lodash groupBy and ES6 mapping, but no success so far. I guess I could do it in a dirty way with multiple forEach loops but I'm pretty sure there is a much easier way.

asked Jan 4 at 10:34

raulicious

991213

can you please provide your code or https://stackblitz.com/?

– Abhishek
Jan 4 at 10:39

add a comment |

Let's say I have an array of objects like this:

[

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]

And I want to filter through it and create new objects based on the model field.

With the end result being:

[

  { "type": 121, "model": "model1" }

]



[

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]

I'm using typescript and lodash so anything with that would be best

I tried lodash groupBy and ES6 mapping, but no success so far. I guess I could do it in a dirty way with multiple forEach loops but I'm pretty sure there is a much easier way.

asked Jan 4 at 10:34

raulicious

991213

Let's say I have an array of objects like this:

[

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]

And I want to filter through it and create new objects based on the model field.

With the end result being:

[

  { "type": 121, "model": "model1" }

]



[

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]

I'm using typescript and lodash so anything with that would be best

I tried lodash groupBy and ES6 mapping, but no success so far. I guess I could do it in a dirty way with multiple forEach loops but I'm pretty sure there is a much easier way.

angular typescript object ecmascript-6 lodash

asked Jan 4 at 10:34

raulicious

991213

asked Jan 4 at 10:34

raulicious

991213

asked Jan 4 at 10:34

raulicious

991213

asked Jan 4 at 10:34

raulicious

991213

asked Jan 4 at 10:34

raulicious

991213

can you please provide your code or https://stackblitz.com/?

– Abhishek
Jan 4 at 10:39

add a comment |

can you please provide your code or https://stackblitz.com/?

– Abhishek
Jan 4 at 10:39

can you please provide your code or https://stackblitz.com/?

– Abhishek
Jan 4 at 10:39

add a comment |

6 Answers
6

active

oldest

votes

See, if this help with lodash

var data = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];



var grouped = _.groupBy(data, function(item) {

  return item.model;

});



console.log(grouped);

<script src='https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js'></script>

answered Jan 4 at 11:15

Rohit.007

1,7892521

add a comment |

You can use .filter, like this:

let newarray1 = array.filter(obj => obj.model === 'model1');

let newarray2 = array.filter(obj => obj.model === 'model2');

...

answered Jan 4 at 10:40

Pedro Lima

432411

add a comment |

You can simply user Array.filter function to filter out array to new array object. Here I am using variable searchModels which will have list of models which you want to filter and inside filter I am checking condition searchModels.indexOf(item.model) to check model value.

var array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];





var searchModels = ['model1', 'model3'];

var filteredArray = array.filter((item) => { return searchModels.indexOf(item.model) !== -1 });

console.log("Original: " , array);

console.log("Filtered: " , filteredArray);

answered Jan 4 at 10:42

sriharsha_bhat

529311

add a comment |

You could so something like that for example :)
In this case I am creating a Map, I think it's easier for search

var newData = new Map();



var originalData = [{"type": 130, "model": "model1"}, {"type": 130, "model": "model2"}];

var formattedData = originalData.map(obj => { 

  newData[obj.model].push(obj.type); 

});

You will get something like :

newData = ([

    [ "model1", "130" ],

    [ "model1", "128" ],

    [ "model2", "3" ]

]);

And you can get any values using the model key newData["model2"] = ["3"]

answered Jan 4 at 10:47

andrea06590

682313

add a comment |

you can use Array.prototype.reduce method to group all.

let array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]



let all = [...array.reduce((acc, curr) => {

  acc.has(curr.model) ? acc.set(curr.model, [...acc.get(curr.model), curr]): acc.set(curr.model, [curr]);

  return acc;

}, new Map()).values()];

console.log(...all)

answered Jan 4 at 11:21

AZ_

917310

add a comment |

try this @raulicious,

var arrayList= [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 131, "model": "model2" }

];





   var filteredArray = ;

   var filtered = ;

   

   arrayList.sort((a, b) => {

         if(a.model == b.model) {

             filtered.push(b);

         } else {

             filtered.push(b);

             filteredArray.push(filtered);

             filtered = ;

           }

       filtered.push(a);

       filteredArray.push(filtered);

     });

    console.log(filteredArray);

I know this has some redundant code, I am trying to reduce that soon

edited Jan 4 at 12:05

answered Jan 4 at 11:22

ganesh045

1,340515

add a comment |

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6 Answers
6

active

oldest

votes

6 Answers
6

active

oldest

votes

See, if this help with lodash

var data = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];



var grouped = _.groupBy(data, function(item) {

  return item.model;

});



console.log(grouped);

<script src='https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js'></script>

answered Jan 4 at 11:15

Rohit.007

1,7892521

add a comment |

See, if this help with lodash

var data = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];



var grouped = _.groupBy(data, function(item) {

  return item.model;

});



console.log(grouped);

<script src='https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js'></script>

answered Jan 4 at 11:15

Rohit.007

1,7892521

add a comment |

See, if this help with lodash

var data = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];



var grouped = _.groupBy(data, function(item) {

  return item.model;

});



console.log(grouped);

<script src='https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js'></script>

answered Jan 4 at 11:15

Rohit.007

1,7892521

See, if this help with lodash

var data = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];



var grouped = _.groupBy(data, function(item) {

  return item.model;

});



console.log(grouped);

<script src='https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js'></script>

var data = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];



var grouped = _.groupBy(data, function(item) {

  return item.model;

});



console.log(grouped);

<script src='https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js'></script>

var data = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];



var grouped = _.groupBy(data, function(item) {

  return item.model;

});



console.log(grouped);

<script src='https://cdn.jsdelivr.net/lodash/4.17.2/lodash.min.js'></script>

answered Jan 4 at 11:15

Rohit.007

1,7892521

answered Jan 4 at 11:15

Rohit.007

1,7892521

answered Jan 4 at 11:15

Rohit.007

1,7892521

answered Jan 4 at 11:15

Rohit.007

1,7892521

add a comment |

You can use .filter, like this:

let newarray1 = array.filter(obj => obj.model === 'model1');

let newarray2 = array.filter(obj => obj.model === 'model2');

...

answered Jan 4 at 10:40

Pedro Lima

432411

add a comment |

You can use .filter, like this:

let newarray1 = array.filter(obj => obj.model === 'model1');

let newarray2 = array.filter(obj => obj.model === 'model2');

...

answered Jan 4 at 10:40

Pedro Lima

432411

add a comment |

You can use .filter, like this:

let newarray1 = array.filter(obj => obj.model === 'model1');

let newarray2 = array.filter(obj => obj.model === 'model2');

...

answered Jan 4 at 10:40

Pedro Lima

432411

You can use .filter, like this:

let newarray1 = array.filter(obj => obj.model === 'model1');

let newarray2 = array.filter(obj => obj.model === 'model2');

...

answered Jan 4 at 10:40

Pedro Lima

432411

answered Jan 4 at 10:40

Pedro Lima

432411

answered Jan 4 at 10:40

Pedro Lima

432411

answered Jan 4 at 10:40

Pedro Lima

432411

add a comment |

var array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];





var searchModels = ['model1', 'model3'];

var filteredArray = array.filter((item) => { return searchModels.indexOf(item.model) !== -1 });

console.log("Original: " , array);

console.log("Filtered: " , filteredArray);

answered Jan 4 at 10:42

sriharsha_bhat

529311

add a comment |

var array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];





var searchModels = ['model1', 'model3'];

var filteredArray = array.filter((item) => { return searchModels.indexOf(item.model) !== -1 });

console.log("Original: " , array);

console.log("Filtered: " , filteredArray);

answered Jan 4 at 10:42

sriharsha_bhat

529311

add a comment |

var array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];





var searchModels = ['model1', 'model3'];

var filteredArray = array.filter((item) => { return searchModels.indexOf(item.model) !== -1 });

console.log("Original: " , array);

console.log("Filtered: " , filteredArray);

answered Jan 4 at 10:42

sriharsha_bhat

529311

var array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];





var searchModels = ['model1', 'model3'];

var filteredArray = array.filter((item) => { return searchModels.indexOf(item.model) !== -1 });

console.log("Original: " , array);

console.log("Filtered: " , filteredArray);

var array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];





var searchModels = ['model1', 'model3'];

var filteredArray = array.filter((item) => { return searchModels.indexOf(item.model) !== -1 });

console.log("Original: " , array);

console.log("Filtered: " , filteredArray);

var array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

];





var searchModels = ['model1', 'model3'];

var filteredArray = array.filter((item) => { return searchModels.indexOf(item.model) !== -1 });

console.log("Original: " , array);

console.log("Filtered: " , filteredArray);

answered Jan 4 at 10:42

sriharsha_bhat

529311

answered Jan 4 at 10:42

sriharsha_bhat

529311

answered Jan 4 at 10:42

sriharsha_bhat

529311

answered Jan 4 at 10:42

sriharsha_bhat

529311

add a comment |

You could so something like that for example :)
In this case I am creating a Map, I think it's easier for search

var newData = new Map();



var originalData = [{"type": 130, "model": "model1"}, {"type": 130, "model": "model2"}];

var formattedData = originalData.map(obj => { 

  newData[obj.model].push(obj.type); 

});

You will get something like :

newData = ([

    [ "model1", "130" ],

    [ "model1", "128" ],

    [ "model2", "3" ]

]);

And you can get any values using the model key newData["model2"] = ["3"]

answered Jan 4 at 10:47

andrea06590

682313

add a comment |

You could so something like that for example :)
In this case I am creating a Map, I think it's easier for search

var newData = new Map();



var originalData = [{"type": 130, "model": "model1"}, {"type": 130, "model": "model2"}];

var formattedData = originalData.map(obj => { 

  newData[obj.model].push(obj.type); 

});

You will get something like :

newData = ([

    [ "model1", "130" ],

    [ "model1", "128" ],

    [ "model2", "3" ]

]);

And you can get any values using the model key newData["model2"] = ["3"]

answered Jan 4 at 10:47

andrea06590

682313

add a comment |

You could so something like that for example :)
In this case I am creating a Map, I think it's easier for search

var newData = new Map();



var originalData = [{"type": 130, "model": "model1"}, {"type": 130, "model": "model2"}];

var formattedData = originalData.map(obj => { 

  newData[obj.model].push(obj.type); 

});

You will get something like :

newData = ([

    [ "model1", "130" ],

    [ "model1", "128" ],

    [ "model2", "3" ]

]);

And you can get any values using the model key newData["model2"] = ["3"]

answered Jan 4 at 10:47

andrea06590

682313

You could so something like that for example :)
In this case I am creating a Map, I think it's easier for search

var newData = new Map();



var originalData = [{"type": 130, "model": "model1"}, {"type": 130, "model": "model2"}];

var formattedData = originalData.map(obj => { 

  newData[obj.model].push(obj.type); 

});

You will get something like :

newData = ([

    [ "model1", "130" ],

    [ "model1", "128" ],

    [ "model2", "3" ]

]);

And you can get any values using the model key newData["model2"] = ["3"]

answered Jan 4 at 10:47

andrea06590

682313

answered Jan 4 at 10:47

andrea06590

682313

answered Jan 4 at 10:47

andrea06590

682313

answered Jan 4 at 10:47

andrea06590

682313

add a comment |

you can use Array.prototype.reduce method to group all.

let array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]



let all = [...array.reduce((acc, curr) => {

  acc.has(curr.model) ? acc.set(curr.model, [...acc.get(curr.model), curr]): acc.set(curr.model, [curr]);

  return acc;

}, new Map()).values()];

console.log(...all)

answered Jan 4 at 11:21

AZ_

917310

add a comment |

you can use Array.prototype.reduce method to group all.

let array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]



let all = [...array.reduce((acc, curr) => {

  acc.has(curr.model) ? acc.set(curr.model, [...acc.get(curr.model), curr]): acc.set(curr.model, [curr]);

  return acc;

}, new Map()).values()];

console.log(...all)

answered Jan 4 at 11:21

AZ_

917310

add a comment |

you can use Array.prototype.reduce method to group all.

let array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]



let all = [...array.reduce((acc, curr) => {

  acc.has(curr.model) ? acc.set(curr.model, [...acc.get(curr.model), curr]): acc.set(curr.model, [curr]);

  return acc;

}, new Map()).values()];

console.log(...all)

answered Jan 4 at 11:21

AZ_

917310

you can use Array.prototype.reduce method to group all.

let array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]



let all = [...array.reduce((acc, curr) => {

  acc.has(curr.model) ? acc.set(curr.model, [...acc.get(curr.model), curr]): acc.set(curr.model, [curr]);

  return acc;

}, new Map()).values()];

console.log(...all)

let array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]



let all = [...array.reduce((acc, curr) => {

  acc.has(curr.model) ? acc.set(curr.model, [...acc.get(curr.model), curr]): acc.set(curr.model, [curr]);

  return acc;

}, new Map()).values()];

console.log(...all)

let array = [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 130, "model": "model2" }

]



let all = [...array.reduce((acc, curr) => {

  acc.has(curr.model) ? acc.set(curr.model, [...acc.get(curr.model), curr]): acc.set(curr.model, [curr]);

  return acc;

}, new Map()).values()];

console.log(...all)

answered Jan 4 at 11:21

AZ_

917310

answered Jan 4 at 11:21

AZ_

917310

answered Jan 4 at 11:21

AZ_

917310

answered Jan 4 at 11:21

AZ_

917310

add a comment |

try this @raulicious,

var arrayList= [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 131, "model": "model2" }

];





   var filteredArray = ;

   var filtered = ;

   

   arrayList.sort((a, b) => {

         if(a.model == b.model) {

             filtered.push(b);

         } else {

             filtered.push(b);

             filteredArray.push(filtered);

             filtered = ;

           }

       filtered.push(a);

       filteredArray.push(filtered);

     });

    console.log(filteredArray);

I know this has some redundant code, I am trying to reduce that soon

edited Jan 4 at 12:05

answered Jan 4 at 11:22

ganesh045

1,340515

add a comment |

try this @raulicious,

var arrayList= [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 131, "model": "model2" }

];





   var filteredArray = ;

   var filtered = ;

   

   arrayList.sort((a, b) => {

         if(a.model == b.model) {

             filtered.push(b);

         } else {

             filtered.push(b);

             filteredArray.push(filtered);

             filtered = ;

           }

       filtered.push(a);

       filteredArray.push(filtered);

     });

    console.log(filteredArray);

I know this has some redundant code, I am trying to reduce that soon

edited Jan 4 at 12:05

answered Jan 4 at 11:22

ganesh045

1,340515

add a comment |

try this @raulicious,

var arrayList= [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 131, "model": "model2" }

];





   var filteredArray = ;

   var filtered = ;

   

   arrayList.sort((a, b) => {

         if(a.model == b.model) {

             filtered.push(b);

         } else {

             filtered.push(b);

             filteredArray.push(filtered);

             filtered = ;

           }

       filtered.push(a);

       filteredArray.push(filtered);

     });

    console.log(filteredArray);

I know this has some redundant code, I am trying to reduce that soon

edited Jan 4 at 12:05

answered Jan 4 at 11:22

ganesh045

1,340515

try this @raulicious,

var arrayList= [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 131, "model": "model2" }

];





   var filteredArray = ;

   var filtered = ;

   

   arrayList.sort((a, b) => {

         if(a.model == b.model) {

             filtered.push(b);

         } else {

             filtered.push(b);

             filteredArray.push(filtered);

             filtered = ;

           }

       filtered.push(a);

       filteredArray.push(filtered);

     });

    console.log(filteredArray);

I know this has some redundant code, I am trying to reduce that soon

var arrayList= [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 131, "model": "model2" }

];





   var filteredArray = ;

   var filtered = ;

   

   arrayList.sort((a, b) => {

         if(a.model == b.model) {

             filtered.push(b);

         } else {

             filtered.push(b);

             filteredArray.push(filtered);

             filtered = ;

           }

       filtered.push(a);

       filteredArray.push(filtered);

     });

    console.log(filteredArray);

var arrayList= [

  { "type": 121, "model": "model1" },

  { "type": 128, "model": "model2" },

  { "type": 130, "model": "model2" },

  { "type": 131, "model": "model2" }

];





   var filteredArray = ;

   var filtered = ;

   

   arrayList.sort((a, b) => {

         if(a.model == b.model) {

             filtered.push(b);

         } else {

             filtered.push(b);

             filteredArray.push(filtered);

             filtered = ;

           }

       filtered.push(a);

       filteredArray.push(filtered);

     });

    console.log(filteredArray);

edited Jan 4 at 12:05

answered Jan 4 at 11:22

ganesh045

1,340515

edited Jan 4 at 12:05

answered Jan 4 at 11:22

ganesh045

1,340515

answered Jan 4 at 11:22

ganesh045

1,340515

answered Jan 4 at 11:22

ganesh045

1,340515

add a comment |

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