Defining sed command in a groovy string
I am trying to create this as a groovy string:
sed 's/.*value="([^"]*)".*/1n/g'
In groovy I have tried:
def sedCommand = "sed 's/.*value="([^"]*)".*/1n/g'"
but it gives : Groovy:unexpected char: '' @...
I have tried various quotation, back slashing etc. but it keeps complaining.
Eventually the sed expression will be used like this:
Process process = [ 'bash', '-c', "curl -k --silent -X GET --insecure --silent $URL | hxselect '#token' | sed 's/.*value="([^"]*)".*/1n/g' " ].execute()
Any suggestions?
groovy sed
add a comment |
I am trying to create this as a groovy string:
sed 's/.*value="([^"]*)".*/1n/g'
In groovy I have tried:
def sedCommand = "sed 's/.*value="([^"]*)".*/1n/g'"
but it gives : Groovy:unexpected char: '' @...
I have tried various quotation, back slashing etc. but it keeps complaining.
Eventually the sed expression will be used like this:
Process process = [ 'bash', '-c', "curl -k --silent -X GET --insecure --silent $URL | hxselect '#token' | sed 's/.*value="([^"]*)".*/1n/g' " ].execute()
Any suggestions?
groovy sed
1
Trydef sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/
– Wiktor Stribiżew
Jan 3 at 12:28
you have to escape with ` ` each ` ` and ` " ` chars in the string. or escape just/in the regular expression declaration:def sedCommand = "sed 's/" + /.*value="([^"]*)".*/1n/ + "/g'"
– daggett
Jan 3 at 12:38
add a comment |
I am trying to create this as a groovy string:
sed 's/.*value="([^"]*)".*/1n/g'
In groovy I have tried:
def sedCommand = "sed 's/.*value="([^"]*)".*/1n/g'"
but it gives : Groovy:unexpected char: '' @...
I have tried various quotation, back slashing etc. but it keeps complaining.
Eventually the sed expression will be used like this:
Process process = [ 'bash', '-c', "curl -k --silent -X GET --insecure --silent $URL | hxselect '#token' | sed 's/.*value="([^"]*)".*/1n/g' " ].execute()
Any suggestions?
groovy sed
I am trying to create this as a groovy string:
sed 's/.*value="([^"]*)".*/1n/g'
In groovy I have tried:
def sedCommand = "sed 's/.*value="([^"]*)".*/1n/g'"
but it gives : Groovy:unexpected char: '' @...
I have tried various quotation, back slashing etc. but it keeps complaining.
Eventually the sed expression will be used like this:
Process process = [ 'bash', '-c', "curl -k --silent -X GET --insecure --silent $URL | hxselect '#token' | sed 's/.*value="([^"]*)".*/1n/g' " ].execute()
Any suggestions?
groovy sed
groovy sed
asked Jan 3 at 12:26
u123u123
4,40327104177
4,40327104177
1
Trydef sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/
– Wiktor Stribiżew
Jan 3 at 12:28
you have to escape with ` ` each ` ` and ` " ` chars in the string. or escape just/in the regular expression declaration:def sedCommand = "sed 's/" + /.*value="([^"]*)".*/1n/ + "/g'"
– daggett
Jan 3 at 12:38
add a comment |
1
Trydef sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/
– Wiktor Stribiżew
Jan 3 at 12:28
you have to escape with ` ` each ` ` and ` " ` chars in the string. or escape just/in the regular expression declaration:def sedCommand = "sed 's/" + /.*value="([^"]*)".*/1n/ + "/g'"
– daggett
Jan 3 at 12:38
1
1
Try
def sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/– Wiktor Stribiżew
Jan 3 at 12:28
Try
def sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/– Wiktor Stribiżew
Jan 3 at 12:28
you have to escape with ` ` each ` ` and ` " ` chars in the string. or escape just
/ in the regular expression declaration: def sedCommand = "sed 's/" + /.*value="([^"]*)".*/1n/ + "/g'"– daggett
Jan 3 at 12:38
you have to escape with ` ` each ` ` and ` " ` chars in the string. or escape just
/ in the regular expression declaration: def sedCommand = "sed 's/" + /.*value="([^"]*)".*/1n/ + "/g'"– daggett
Jan 3 at 12:38
add a comment |
1 Answer
1
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votes
You may use a slashy string where you only need to escape forward slashes and keep the rest as is:
def sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/
It will represent
sed 's/.*value="([^"]*)".*/1n/g'
See the online Groovy demo
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You may use a slashy string where you only need to escape forward slashes and keep the rest as is:
def sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/
It will represent
sed 's/.*value="([^"]*)".*/1n/g'
See the online Groovy demo
add a comment |
You may use a slashy string where you only need to escape forward slashes and keep the rest as is:
def sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/
It will represent
sed 's/.*value="([^"]*)".*/1n/g'
See the online Groovy demo
add a comment |
You may use a slashy string where you only need to escape forward slashes and keep the rest as is:
def sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/
It will represent
sed 's/.*value="([^"]*)".*/1n/g'
See the online Groovy demo
You may use a slashy string where you only need to escape forward slashes and keep the rest as is:
def sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/
It will represent
sed 's/.*value="([^"]*)".*/1n/g'
See the online Groovy demo
answered Jan 3 at 14:19
Wiktor StribiżewWiktor Stribiżew
326k16147226
326k16147226
add a comment |
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1
Try
def sedCommand = /sed 's/.*value="([^"]*)".*/1n/g'/– Wiktor Stribiżew
Jan 3 at 12:28
you have to escape with ` ` each ` ` and ` " ` chars in the string. or escape just
/in the regular expression declaration:def sedCommand = "sed 's/" + /.*value="([^"]*)".*/1n/ + "/g'"– daggett
Jan 3 at 12:38