Facing issues in JS Filter function in IE 11
I have following lambda expression
if (MyObject.eId.filter(e => e === record.Id).length > 0)
{
return;
}
This works in all broswers except IE(checked in IE 11)
I tried to convert this to following way but getting syntax error.Please help me to rewrite above function.
MyObject.eId.filter(function (e) {
if (e === record.Id).length > 0
{
return;
}
});
javascript jquery
asked Jan 3 at 12:39
aniltcaniltc
194118
add a comment |
I have following lambda expression
if (MyObject.eId.filter(e => e === record.Id).length > 0)
{
return;
}
This works in all broswers except IE(checked in IE 11)
I tried to convert this to following way but getting syntax error.Please help me to rewrite above function.
MyObject.eId.filter(function (e) {
if (e === record.Id).length > 0
{
return;
}
});
javascript jquery
asked Jan 3 at 12:39
aniltcaniltc
194118
Maybe you want to use a polyfill? Take a look at this.
– JO3-W3B-D3V
Jan 3 at 12:41
1
For non arrow function your code should look like:if ( MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0 ) {
– HMR
Jan 3 at 12:47
add a comment |
I have following lambda expression
if (MyObject.eId.filter(e => e === record.Id).length > 0)
{
return;
}
This works in all broswers except IE(checked in IE 11)
I tried to convert this to following way but getting syntax error.Please help me to rewrite above function.
MyObject.eId.filter(function (e) {
if (e === record.Id).length > 0
{
return;
}
});
javascript jquery
asked Jan 3 at 12:39
aniltcaniltc
194118
I have following lambda expression
if (MyObject.eId.filter(e => e === record.Id).length > 0)
{
return;
}
This works in all broswers except IE(checked in IE 11)
I tried to convert this to following way but getting syntax error.Please help me to rewrite above function.
MyObject.eId.filter(function (e) {
if (e === record.Id).length > 0
{
return;
}
});
javascript jquery
javascript jquery
asked Jan 3 at 12:39
aniltcaniltc
194118
asked Jan 3 at 12:39
aniltcaniltc
194118
asked Jan 3 at 12:39
aniltcaniltc
194118
asked Jan 3 at 12:39
aniltcaniltc
194118
asked Jan 3 at 12:39
aniltcaniltc
194118
194118
Maybe you want to use a polyfill? Take a look at this.
– JO3-W3B-D3V
Jan 3 at 12:41
1
For non arrow function your code should look like:if ( MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0 ) {
– HMR
Jan 3 at 12:47
add a comment |
Maybe you want to use a polyfill? Take a look at this.
– JO3-W3B-D3V
Jan 3 at 12:41
1
For non arrow function your code should look like:if ( MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0 ) {
– HMR
Jan 3 at 12:47
Maybe you want to use a polyfill? Take a look at this.
– JO3-W3B-D3V
Jan 3 at 12:41
Maybe you want to use a polyfill? Take a look at this.
– JO3-W3B-D3V
Jan 3 at 12:41
1
1
For non arrow function your code should look like:
if ( MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0 ) {– HMR
Jan 3 at 12:47
For non arrow function your code should look like:
if ( MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0 ) {– HMR
Jan 3 at 12:47
add a comment |
1 Answer
1
active
oldest
votes
Your non-arrow function is incorrect: Basically in the callback/predicate of the .filter method, you should only check if e matches the record ID, without checking for length. The length check should be performed on the returned/filtered array instead:
if (MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0) {
return;
}
To break down the complicated one-liner above, you can see it as this:
// Step 1: Get an filtered array of IDs that match record ID
var filteredIds = MyObject.eId.filter(function(e) {
return e === recordId;
});
// Step 2: Check length of filtered array
if (filteredIds.length) {
return;
}
answered Jan 3 at 12:52
TerryTerry
30.5k44369
1
This should be the accepted answer due to compatibility.
– BRO_THOM
Jan 3 at 12:56
It showing an error in step1
– aniltc
Jan 3 at 12:58
if (MyObject.eId.filter(function(e) { return e === record.Id }).length > 0) This works fine
– aniltc
Jan 3 at 13:05
1
@aniltc Sorry, had a minor typo: should befunctionnotfuntion. Fixed it now.
– Terry
Jan 3 at 13:08
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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active
oldest
votes
Your non-arrow function is incorrect: Basically in the callback/predicate of the .filter method, you should only check if e matches the record ID, without checking for length. The length check should be performed on the returned/filtered array instead:
if (MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0) {
return;
}
To break down the complicated one-liner above, you can see it as this:
// Step 1: Get an filtered array of IDs that match record ID
var filteredIds = MyObject.eId.filter(function(e) {
return e === recordId;
});
// Step 2: Check length of filtered array
if (filteredIds.length) {
return;
}
answered Jan 3 at 12:52
TerryTerry
30.5k44369
1
This should be the accepted answer due to compatibility.
– BRO_THOM
Jan 3 at 12:56
It showing an error in step1
– aniltc
Jan 3 at 12:58
if (MyObject.eId.filter(function(e) { return e === record.Id }).length > 0) This works fine
– aniltc
Jan 3 at 13:05
1
@aniltc Sorry, had a minor typo: should befunctionnotfuntion. Fixed it now.
– Terry
Jan 3 at 13:08
add a comment |
Your non-arrow function is incorrect: Basically in the callback/predicate of the .filter method, you should only check if e matches the record ID, without checking for length. The length check should be performed on the returned/filtered array instead:
if (MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0) {
return;
}
To break down the complicated one-liner above, you can see it as this:
// Step 1: Get an filtered array of IDs that match record ID
var filteredIds = MyObject.eId.filter(function(e) {
return e === recordId;
});
// Step 2: Check length of filtered array
if (filteredIds.length) {
return;
}
answered Jan 3 at 12:52
TerryTerry
30.5k44369
1
This should be the accepted answer due to compatibility.
– BRO_THOM
Jan 3 at 12:56
It showing an error in step1
– aniltc
Jan 3 at 12:58
if (MyObject.eId.filter(function(e) { return e === record.Id }).length > 0) This works fine
– aniltc
Jan 3 at 13:05
1
@aniltc Sorry, had a minor typo: should befunctionnotfuntion. Fixed it now.
– Terry
Jan 3 at 13:08
add a comment |
Your non-arrow function is incorrect: Basically in the callback/predicate of the .filter method, you should only check if e matches the record ID, without checking for length. The length check should be performed on the returned/filtered array instead:
if (MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0) {
return;
}
To break down the complicated one-liner above, you can see it as this:
// Step 1: Get an filtered array of IDs that match record ID
var filteredIds = MyObject.eId.filter(function(e) {
return e === recordId;
});
// Step 2: Check length of filtered array
if (filteredIds.length) {
return;
}
answered Jan 3 at 12:52
TerryTerry
30.5k44369
Your non-arrow function is incorrect: Basically in the callback/predicate of the .filter method, you should only check if e matches the record ID, without checking for length. The length check should be performed on the returned/filtered array instead:
if (MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0) {
return;
}
To break down the complicated one-liner above, you can see it as this:
// Step 1: Get an filtered array of IDs that match record ID
var filteredIds = MyObject.eId.filter(function(e) {
return e === recordId;
});
// Step 2: Check length of filtered array
if (filteredIds.length) {
return;
}
answered Jan 3 at 12:52
TerryTerry
30.5k44369
edited Jan 3 at 13:07
answered Jan 3 at 12:52
TerryTerry
30.5k44369
answered Jan 3 at 12:52
TerryTerry
30.5k44369
answered Jan 3 at 12:52
TerryTerry
30.5k44369
30.5k44369
1
This should be the accepted answer due to compatibility.
– BRO_THOM
Jan 3 at 12:56
It showing an error in step1
– aniltc
Jan 3 at 12:58
if (MyObject.eId.filter(function(e) { return e === record.Id }).length > 0) This works fine
– aniltc
Jan 3 at 13:05
1
@aniltc Sorry, had a minor typo: should befunctionnotfuntion. Fixed it now.
– Terry
Jan 3 at 13:08
add a comment |
1
This should be the accepted answer due to compatibility.
– BRO_THOM
Jan 3 at 12:56
It showing an error in step1
– aniltc
Jan 3 at 12:58
if (MyObject.eId.filter(function(e) { return e === record.Id }).length > 0) This works fine
– aniltc
Jan 3 at 13:05
1
@aniltc Sorry, had a minor typo: should befunctionnotfuntion. Fixed it now.
– Terry
Jan 3 at 13:08
1
1
This should be the accepted answer due to compatibility.
– BRO_THOM
Jan 3 at 12:56
This should be the accepted answer due to compatibility.
– BRO_THOM
Jan 3 at 12:56
It showing an error in step1
– aniltc
Jan 3 at 12:58
It showing an error in step1
– aniltc
Jan 3 at 12:58
if (MyObject.eId.filter(function(e) { return e === record.Id }).length > 0) This works fine
– aniltc
Jan 3 at 13:05
if (MyObject.eId.filter(function(e) { return e === record.Id }).length > 0) This works fine
– aniltc
Jan 3 at 13:05
1
1
@aniltc Sorry, had a minor typo: should be
function not funtion. Fixed it now.– Terry
Jan 3 at 13:08
@aniltc Sorry, had a minor typo: should be
function not funtion. Fixed it now.– Terry
Jan 3 at 13:08
add a comment |
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Maybe you want to use a polyfill? Take a look at this.
– JO3-W3B-D3V
Jan 3 at 12:41
1
For non arrow function your code should look like:
if ( MyObject.eId.filter(function(e) { return e === record.Id; }).length > 0 ) {– HMR
Jan 3 at 12:47