Why is the interleave_view missing in the range-v3 library?
0
In Eric Niebler's range-v3 calendar example he uses interleave followed by chunk to transpose a matrix.
I wonder why interleave is not part of the range-v3 library...
c++ range-v3
edited Jan 18 at 19:16
marc_s
583k13011241270
asked Jan 3 at 12:36
Porsche9IIPorsche9II
859
add a comment |
0
In Eric Niebler's range-v3 calendar example he uses interleave followed by chunk to transpose a matrix.
I wonder why interleave is not part of the range-v3 library...
c++ range-v3
edited Jan 18 at 19:16
marc_s
583k13011241270
asked Jan 3 at 12:36
Porsche9IIPorsche9II
859
you can raise that issue with Eric Niebler here. Better yet you can even fork from his library and implement the function yourself. Hence the power of open-source software.
– Joey Mallone
Jan 3 at 12:49
5
See github.com/ericniebler/range-v3/issues/776
– Holt
Jan 3 at 12:50
add a comment |
0
0
0
In Eric Niebler's range-v3 calendar example he uses interleave followed by chunk to transpose a matrix.
I wonder why interleave is not part of the range-v3 library...
c++ range-v3
edited Jan 18 at 19:16
marc_s
583k13011241270
asked Jan 3 at 12:36
Porsche9IIPorsche9II
859
In Eric Niebler's range-v3 calendar example he uses interleave followed by chunk to transpose a matrix.
I wonder why interleave is not part of the range-v3 library...
c++ range-v3
c++ range-v3
edited Jan 18 at 19:16
marc_s
583k13011241270
asked Jan 3 at 12:36
Porsche9IIPorsche9II
859
edited Jan 18 at 19:16
marc_s
583k13011241270
asked Jan 3 at 12:36
Porsche9IIPorsche9II
859
edited Jan 18 at 19:16
marc_s
583k13011241270
edited Jan 18 at 19:16
marc_s
583k13011241270
edited Jan 18 at 19:16
marc_s
583k13011241270
583k13011241270
asked Jan 3 at 12:36
Porsche9IIPorsche9II
859
asked Jan 3 at 12:36
Porsche9IIPorsche9II
859
asked Jan 3 at 12:36
Porsche9IIPorsche9II
859
859
you can raise that issue with Eric Niebler here. Better yet you can even fork from his library and implement the function yourself. Hence the power of open-source software.
– Joey Mallone
Jan 3 at 12:49
5
See github.com/ericniebler/range-v3/issues/776
– Holt
Jan 3 at 12:50
add a comment |
you can raise that issue with Eric Niebler here. Better yet you can even fork from his library and implement the function yourself. Hence the power of open-source software.
– Joey Mallone
Jan 3 at 12:49
5
See github.com/ericniebler/range-v3/issues/776
– Holt
Jan 3 at 12:50
you can raise that issue with Eric Niebler here. Better yet you can even fork from his library and implement the function yourself. Hence the power of open-source software.
– Joey Mallone
Jan 3 at 12:49
you can raise that issue with Eric Niebler here. Better yet you can even fork from his library and implement the function yourself. Hence the power of open-source software.
– Joey Mallone
Jan 3 at 12:49
5
5
See github.com/ericniebler/range-v3/issues/776
– Holt
Jan 3 at 12:50
See github.com/ericniebler/range-v3/issues/776
– Holt
Jan 3 at 12:50
add a comment |
1 Answer
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Lack of time, and some unsolved design difficulties. For instance, what does it mean to interleave ranges of different lengths? That wasn't a problem in the calendar example, but it's a question that needs to have an answer before the interleave view can be part of range-v3.
answered Jan 3 at 16:01
Eric NieblerEric Niebler
3,7701431
Thank you for the clarification - for my purposes I want to transpose a matrix - so all ranges have the same lengths. I copied your interleave_view from the calender example to link. Unfortunately, the direct transpose viavector<vector<int>> n_x_m_matrix = m_x_n_matrix | interleave() | chunk(n_cols);is slower thanvector<int> vec_temp = m_x_n_matrix | interleave(); vector<vector<int>> n_x_m_matrix_fast = vec_temp | chunk(n_cols);
– Porsche9II
Jan 3 at 16:47
Interleave for ranges of different size: I would suggest that[1, 2, 3, 4],[a, b, c],[I, II, III, IV, V]]interleaves to[1, a, I, 2, b, II, 3, c, III, 4, IV, V].
– Porsche9II
Jan 3 at 17:03
That is a sensible way to interleave ranges of different sizes, but implementing that comes with runtime cost, if I remember correctly.
– Eric Niebler
Jan 3 at 21:06
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
2
Lack of time, and some unsolved design difficulties. For instance, what does it mean to interleave ranges of different lengths? That wasn't a problem in the calendar example, but it's a question that needs to have an answer before the interleave view can be part of range-v3.
answered Jan 3 at 16:01
Eric NieblerEric Niebler
3,7701431
Thank you for the clarification - for my purposes I want to transpose a matrix - so all ranges have the same lengths. I copied your interleave_view from the calender example to link. Unfortunately, the direct transpose viavector<vector<int>> n_x_m_matrix = m_x_n_matrix | interleave() | chunk(n_cols);is slower thanvector<int> vec_temp = m_x_n_matrix | interleave(); vector<vector<int>> n_x_m_matrix_fast = vec_temp | chunk(n_cols);
– Porsche9II
Jan 3 at 16:47
Interleave for ranges of different size: I would suggest that[1, 2, 3, 4],[a, b, c],[I, II, III, IV, V]]interleaves to[1, a, I, 2, b, II, 3, c, III, 4, IV, V].
– Porsche9II
Jan 3 at 17:03
That is a sensible way to interleave ranges of different sizes, but implementing that comes with runtime cost, if I remember correctly.
– Eric Niebler
Jan 3 at 21:06
add a comment |
2
Lack of time, and some unsolved design difficulties. For instance, what does it mean to interleave ranges of different lengths? That wasn't a problem in the calendar example, but it's a question that needs to have an answer before the interleave view can be part of range-v3.
answered Jan 3 at 16:01
Eric NieblerEric Niebler
3,7701431
Thank you for the clarification - for my purposes I want to transpose a matrix - so all ranges have the same lengths. I copied your interleave_view from the calender example to link. Unfortunately, the direct transpose viavector<vector<int>> n_x_m_matrix = m_x_n_matrix | interleave() | chunk(n_cols);is slower thanvector<int> vec_temp = m_x_n_matrix | interleave(); vector<vector<int>> n_x_m_matrix_fast = vec_temp | chunk(n_cols);
– Porsche9II
Jan 3 at 16:47
Interleave for ranges of different size: I would suggest that[1, 2, 3, 4],[a, b, c],[I, II, III, IV, V]]interleaves to[1, a, I, 2, b, II, 3, c, III, 4, IV, V].
– Porsche9II
Jan 3 at 17:03
That is a sensible way to interleave ranges of different sizes, but implementing that comes with runtime cost, if I remember correctly.
– Eric Niebler
Jan 3 at 21:06
add a comment |
2
2
2
Lack of time, and some unsolved design difficulties. For instance, what does it mean to interleave ranges of different lengths? That wasn't a problem in the calendar example, but it's a question that needs to have an answer before the interleave view can be part of range-v3.
answered Jan 3 at 16:01
Eric NieblerEric Niebler
3,7701431
Lack of time, and some unsolved design difficulties. For instance, what does it mean to interleave ranges of different lengths? That wasn't a problem in the calendar example, but it's a question that needs to have an answer before the interleave view can be part of range-v3.
answered Jan 3 at 16:01
Eric NieblerEric Niebler
3,7701431
answered Jan 3 at 16:01
Eric NieblerEric Niebler
3,7701431
answered Jan 3 at 16:01
Eric NieblerEric Niebler
3,7701431
answered Jan 3 at 16:01
Eric NieblerEric Niebler
3,7701431
3,7701431
Thank you for the clarification - for my purposes I want to transpose a matrix - so all ranges have the same lengths. I copied your interleave_view from the calender example to link. Unfortunately, the direct transpose viavector<vector<int>> n_x_m_matrix = m_x_n_matrix | interleave() | chunk(n_cols);is slower thanvector<int> vec_temp = m_x_n_matrix | interleave(); vector<vector<int>> n_x_m_matrix_fast = vec_temp | chunk(n_cols);
– Porsche9II
Jan 3 at 16:47
Interleave for ranges of different size: I would suggest that[1, 2, 3, 4],[a, b, c],[I, II, III, IV, V]]interleaves to[1, a, I, 2, b, II, 3, c, III, 4, IV, V].
– Porsche9II
Jan 3 at 17:03
That is a sensible way to interleave ranges of different sizes, but implementing that comes with runtime cost, if I remember correctly.
– Eric Niebler
Jan 3 at 21:06
add a comment |
Thank you for the clarification - for my purposes I want to transpose a matrix - so all ranges have the same lengths. I copied your interleave_view from the calender example to link. Unfortunately, the direct transpose viavector<vector<int>> n_x_m_matrix = m_x_n_matrix | interleave() | chunk(n_cols);is slower thanvector<int> vec_temp = m_x_n_matrix | interleave(); vector<vector<int>> n_x_m_matrix_fast = vec_temp | chunk(n_cols);
– Porsche9II
Jan 3 at 16:47
Interleave for ranges of different size: I would suggest that[1, 2, 3, 4],[a, b, c],[I, II, III, IV, V]]interleaves to[1, a, I, 2, b, II, 3, c, III, 4, IV, V].
– Porsche9II
Jan 3 at 17:03
That is a sensible way to interleave ranges of different sizes, but implementing that comes with runtime cost, if I remember correctly.
– Eric Niebler
Jan 3 at 21:06
Thank you for the clarification - for my purposes I want to transpose a matrix - so all ranges have the same lengths. I copied your interleave_view from the calender example to link. Unfortunately, the direct transpose via
vector<vector<int>> n_x_m_matrix = m_x_n_matrix | interleave() | chunk(n_cols); is slower than vector<int> vec_temp = m_x_n_matrix | interleave(); vector<vector<int>> n_x_m_matrix_fast = vec_temp | chunk(n_cols);– Porsche9II
Jan 3 at 16:47
Thank you for the clarification - for my purposes I want to transpose a matrix - so all ranges have the same lengths. I copied your interleave_view from the calender example to link. Unfortunately, the direct transpose via
vector<vector<int>> n_x_m_matrix = m_x_n_matrix | interleave() | chunk(n_cols); is slower than vector<int> vec_temp = m_x_n_matrix | interleave(); vector<vector<int>> n_x_m_matrix_fast = vec_temp | chunk(n_cols);– Porsche9II
Jan 3 at 16:47
Interleave for ranges of different size: I would suggest that
[1, 2, 3, 4],[a, b, c],[I, II, III, IV, V]] interleaves to [1, a, I, 2, b, II, 3, c, III, 4, IV, V].– Porsche9II
Jan 3 at 17:03
Interleave for ranges of different size: I would suggest that
[1, 2, 3, 4],[a, b, c],[I, II, III, IV, V]] interleaves to [1, a, I, 2, b, II, 3, c, III, 4, IV, V].– Porsche9II
Jan 3 at 17:03
That is a sensible way to interleave ranges of different sizes, but implementing that comes with runtime cost, if I remember correctly.
– Eric Niebler
Jan 3 at 21:06
That is a sensible way to interleave ranges of different sizes, but implementing that comes with runtime cost, if I remember correctly.
– Eric Niebler
Jan 3 at 21:06
add a comment |
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you can raise that issue with Eric Niebler here. Better yet you can even fork from his library and implement the function yourself. Hence the power of open-source software.
– Joey Mallone
Jan 3 at 12:49
5
See github.com/ericniebler/range-v3/issues/776
– Holt
Jan 3 at 12:50