Bdtjtk

We may do

df1 %>% group_by(id) %>% do(if(all(is.na(.$val))) replace(.[1, ], 2, 0) else na.omit(.))

# A tibble: 5 x 2

# Groups:   id [2]

#   id      val

#   <fct> <dbl>

# 1 a         0

# 2 b         1

# 3 b         2

# 4 b         2

# 5 b         3

After grouping by id, if everything in val is NA, then we leave only the first row with the second element replaced by 0, otherwise the same data is returned after applying na.omit.

In a more readable format that would be

df1 %>% group_by(id) %>% 

  do(if(all(is.na(.$val))) data.frame(id = .$id[1], val = 0) else na.omit(.))

(Here I presume that you indeed want to get rid of all NA values; otherwise there is no need for na.omit.)

df1[is.na(df1)] <- 0

df1[!(duplicated(df1$id) & df1$val == 0), ]



  id val

1  a   0

5  b   1

6  b   2

7  b   2

8  b   3

Base R option is to find groups with all NAs and transform them by changing their val to 0 and select only unique rows so that there is only one row per group. We rbind this dataframe with the groups which are !all_NA.

all_NA <- with(df1, ave(is.na(val), id, FUN = all))

rbind(unique(transform(df1[all_NA, ], val = 0)), df1[!all_NA, ])



#  id val

#1  a   0

#5  b   1

#6  b   2

#7  b   2

#8  b   3

dplyr option looks ugly but one way is to make two groups of dataframes one with groups of all NA values and other with groups of all non-NA values. For groups with all NA values we add row with it's id and val as 0 and bind this to the other group.

library(dplyr)



bind_rows(df1 %>%

            group_by(id) %>%

            filter(all(!is.na(val))), 

          df1 %>%

             group_by(id) %>%

             filter(all(is.na(val))) %>%

             ungroup() %>%

             summarise(id = unique(id), 

                       val = 0)) %>%

arrange(id)





#   id      val

#  <fct> <dbl>

#1  a         0

#2  b         1

#3  b         2

#4  b         2

#5  b         3

Changed the df to make example more exhaustive -

df1 <- data.frame(id = rep(c("a", "b","c"), each = 4),

                  val = c(NA, NA, NA, NA, 1, 2, 2, 3,NA,2,NA,3))

library(dplyr)

df1 %>%

  group_by(id) %>%

  mutate(case=sum(is.na(val))==n(), row_num=row_number() ) %>%

  mutate(val=ifelse(is.na(val)&case,0,val)) %>%

  filter( !(case&row_num!=1) ) %>%

  select(id, val)

Output

  id      val

  <fct> <dbl>

1 a         0

2 b         1

3 b         2

4 b         2

5 b         3

6 c        NA

7 c         2

8 c        NA

9 c         3

Another base approach, one that doesn't maintain the order of the rows and takes advantage of factors remembering lost values:

df1 <- na.omit(df1)



df1 <- rbind(

  df1, 

  data.frame(

    id  = levels(df1$id)[!levels(df1$id) %in% df1$id], 

    val = 0)

  )

I do personally prefer the dplyr approach given by Sotos, as I don't like rbind-ing data.frames back together so it's a matter of taste, but this isn't unbearably complicated by my eye. It's easy enough to adapt to a character id column with a unique(df1$id) variable.

Here is an option too:

df1 %>% 

  mutate_if(is.factor,as.character) %>% 

 mutate_all(funs(replace(.,is.na(.),0))) %>% 

  slice(4:nrow(.))

This gives:

 id val

1  a   0

2  b   1

3  b   2

4  b   2

5  b   3

Alternative:

df1 %>% 

  mutate_if(is.factor,as.character) %>% 

 mutate_all(funs(replace(.,is.na(.),0))) %>% 

  unique()

UPDATE based on other requirements:
Some users suggested to test on this dataframe. Of course this answer assumes you'll look at everything by hand. Might be less useful if you have to look at everything by "hand" but here goes:

df1 <- data.frame(id = rep(c("a", "b","c"), each = 4), val = c(NA, NA, NA, NA, 1, 2, 2, 3,NA,2,NA,3))





df1 %>% 

  mutate_if(is.factor,as.character) %>% 

  mutate(val=ifelse(id=="a",0,val)) %>% 

  slice(4:nrow(.))

This yields:

 id val

1  a   0

2  b   1

3  b   2

4  b   2

5  b   3

6  c  NA

7  c   2

8  c  NA

9  c   3

Here is a base R solution.

res <- lapply(split(df1, df1$id), function(DF){

  if(anyNA(DF$val)) {

    i <- is.na(DF$val)

    DF$val[i] <- 0

    DF <- rbind(DF[i & !duplicated(DF[i, ]), ], DF[!i, ])

  }

  DF

})

res <- do.call(rbind, res)

row.names(res) <- NULL

res

#  id val

#1  a   0

#2  b   1

#3  b   2

#4  b   2

#5  b   3

Edit.

A dplyr solution could be the following.
It was tested with the original dataset posted by the OP, with the dataset in Vivek Kalyanarangan's answer and with the dataset in markus' comment, renamed df2 and df3, respectively.

library(dplyr)



na2zero <- function(DF){

  DF %>%

    group_by(id) %>%

    mutate(val = ifelse(is.na(val), 0, val),

           crit = val == 0 & duplicated(val)) %>%

    filter(!crit) %>%

    select(-crit)

}



na2zero(df1)

na2zero(df2)

na2zero(df3)

One may try this :

df1 = data.frame(id = rep(c("a", "b","c"), each = 4),

                  val = c(NA, NA, NA, NA, 1, 2, 2, 3,NA,2,NA,3))

df1

#   id val

#1   a  NA

#2   a  NA

#3   a  NA

#4   a  NA

#5   b   1

#6   b   2

#7   b   2

#8   b   3

#9   c  NA

#10  c   2

#11  c  NA

#12  c   3

Task is to remove all rows corresponding to any id IFF val for the corresponding id is all NAs and add new row with this id and val = 0.

In this example, id = a.

Note : val for c also has NAs but all the val corresponding to c are not NA therefore we need to remove the corresponding row for c where val = NA.

So lets create another column say, val2 which indicates 0 means its all NAs and 1 otherwise.

library(dplyr)



df1 = df1 %>% 

     group_by(id) %>%

     mutate(val2 = if_else(condition = all(is.na(val)),true = 0, false =  1))

df1



# A tibble: 12 x 3

# Groups:   id [3]

#   id      val  val2

#   <fct> <dbl> <dbl>

#1 a        NA     0

#2 a        NA     0

#3 a        NA     0

#4 a        NA     0

#5 b         1     1

#6 b         2     1

#7 b         2     1

#8 b         3     1

#9 c        NA     1

#10 c        2     1

#11 c       NA     1

#12 c        3     1

Get the list of ids with corresponding val = NA for all.

all_na = unique(df1$id[df1$val2 == 0])

Then remove theids from the dataframe df1 with val = NA.

df1 = na.omit(df1)

df1

# A tibble: 6 x 3

# Groups:   id [2]

# id      val  val2

# <fct> <dbl> <dbl>

# 1 b         1     1

# 2 b         2     1

# 3 b         2     1

# 4 b         3     1

# 5 c         2     1

# 6 c         3     1

And create a new dataframe with ids in all_na and val = 0

all_na_df = data.frame(id = all_na, val = 0) 

all_na_df

# id val

# 1  a   0

then combine these two dataframes.

df1 = bind_rows(all_na_df, df1[,c('id', 'val')])

df1



#    id val

# 1  a   0

# 2  b   1

# 3  b   2

# 4  b   2

# 5  b   3

# 6  c   2

# 7  c   3

Hope this helps and Edits are most welcomed :-)