How to run shell script (.sh files) in Gulp 4?
Hello to everyone and Happy New Year!
Since Gulp version 4 I can't run a shell script.
I have simple shell script.
if application id "com.adobe.estoolkit-4.0" is running then
display dialog "Close The App!" buttons {"OK"} default button 1
end if
When I run it this way, it works
const { exec } = require('child_process');
function checkAppisOpen() {
return exec('./utils/check.sh');
};
exports.run = checkAppisOpen;
But when I'm trying to use npm gulp-shell plugin it won't work.
Error: Did you forget to signal async completion?
See the code:
const shell = require('gulp-shell');
function checkAppisOpen() {
return shell('./utils/check.sh');
};
exports.run = checkAppisOpen;
I know I'm doing something wrong. Could please someone explain how this async completion works under the hood. Or at least where I could read about it. Because it seems like gulp documentation is not enough for me https://gulpjs.com/docs/en/getting-started/async-completion
shell gulp exec gulp-4 gulp-shell
asked Jan 3 at 12:25
VladVlad
1615
add a comment |
Hello to everyone and Happy New Year!
Since Gulp version 4 I can't run a shell script.
I have simple shell script.
if application id "com.adobe.estoolkit-4.0" is running then
display dialog "Close The App!" buttons {"OK"} default button 1
end if
When I run it this way, it works
const { exec } = require('child_process');
function checkAppisOpen() {
return exec('./utils/check.sh');
};
exports.run = checkAppisOpen;
But when I'm trying to use npm gulp-shell plugin it won't work.
Error: Did you forget to signal async completion?
See the code:
const shell = require('gulp-shell');
function checkAppisOpen() {
return shell('./utils/check.sh');
};
exports.run = checkAppisOpen;
I know I'm doing something wrong. Could please someone explain how this async completion works under the hood. Or at least where I could read about it. Because it seems like gulp documentation is not enough for me https://gulpjs.com/docs/en/getting-started/async-completion
shell gulp exec gulp-4 gulp-shell
asked Jan 3 at 12:25
VladVlad
1615
It looks like the preferred way to use gulp.shell is via shell.task. What happens if you use return shell.task(….)? Otherwise try the callback function route: function checkAppisOpen(done) { return shell(…..); done(); };
– Mark
Jan 3 at 15:05
Thank you for the reply @Mark. Unfortunately, in both ways, you pointed, still the same result. The error is: The following tasks did not complete: run [02:21:56] Did you forget to signal async completion?
– Vlad
Jan 4 at 0:23
add a comment |
Hello to everyone and Happy New Year!
Since Gulp version 4 I can't run a shell script.
I have simple shell script.
if application id "com.adobe.estoolkit-4.0" is running then
display dialog "Close The App!" buttons {"OK"} default button 1
end if
When I run it this way, it works
const { exec } = require('child_process');
function checkAppisOpen() {
return exec('./utils/check.sh');
};
exports.run = checkAppisOpen;
But when I'm trying to use npm gulp-shell plugin it won't work.
Error: Did you forget to signal async completion?
See the code:
const shell = require('gulp-shell');
function checkAppisOpen() {
return shell('./utils/check.sh');
};
exports.run = checkAppisOpen;
I know I'm doing something wrong. Could please someone explain how this async completion works under the hood. Or at least where I could read about it. Because it seems like gulp documentation is not enough for me https://gulpjs.com/docs/en/getting-started/async-completion
shell gulp exec gulp-4 gulp-shell
asked Jan 3 at 12:25
VladVlad
1615
Hello to everyone and Happy New Year!
Since Gulp version 4 I can't run a shell script.
I have simple shell script.
if application id "com.adobe.estoolkit-4.0" is running then
display dialog "Close The App!" buttons {"OK"} default button 1
end if
When I run it this way, it works
const { exec } = require('child_process');
function checkAppisOpen() {
return exec('./utils/check.sh');
};
exports.run = checkAppisOpen;
But when I'm trying to use npm gulp-shell plugin it won't work.
Error: Did you forget to signal async completion?
See the code:
const shell = require('gulp-shell');
function checkAppisOpen() {
return shell('./utils/check.sh');
};
exports.run = checkAppisOpen;
I know I'm doing something wrong. Could please someone explain how this async completion works under the hood. Or at least where I could read about it. Because it seems like gulp documentation is not enough for me https://gulpjs.com/docs/en/getting-started/async-completion
shell gulp exec gulp-4 gulp-shell
shell gulp exec gulp-4 gulp-shell
asked Jan 3 at 12:25
VladVlad
1615
asked Jan 3 at 12:25
VladVlad
1615
asked Jan 3 at 12:25
VladVlad
1615
asked Jan 3 at 12:25
VladVlad
1615
asked Jan 3 at 12:25
VladVlad
1615
1615
It looks like the preferred way to use gulp.shell is via shell.task. What happens if you use return shell.task(….)? Otherwise try the callback function route: function checkAppisOpen(done) { return shell(…..); done(); };
– Mark
Jan 3 at 15:05
Thank you for the reply @Mark. Unfortunately, in both ways, you pointed, still the same result. The error is: The following tasks did not complete: run [02:21:56] Did you forget to signal async completion?
– Vlad
Jan 4 at 0:23
add a comment |
It looks like the preferred way to use gulp.shell is via shell.task. What happens if you use return shell.task(….)? Otherwise try the callback function route: function checkAppisOpen(done) { return shell(…..); done(); };
– Mark
Jan 3 at 15:05
Thank you for the reply @Mark. Unfortunately, in both ways, you pointed, still the same result. The error is: The following tasks did not complete: run [02:21:56] Did you forget to signal async completion?
– Vlad
Jan 4 at 0:23
It looks like the preferred way to use gulp.shell is via shell.task. What happens if you use return shell.task(….)? Otherwise try the callback function route: function checkAppisOpen(done) { return shell(…..); done(); };
– Mark
Jan 3 at 15:05
It looks like the preferred way to use gulp.shell is via shell.task. What happens if you use return shell.task(….)? Otherwise try the callback function route: function checkAppisOpen(done) { return shell(…..); done(); };
– Mark
Jan 3 at 15:05
Thank you for the reply @Mark. Unfortunately, in both ways, you pointed, still the same result. The error is: The following tasks did not complete: run [02:21:56] Did you forget to signal async completion?
– Vlad
Jan 4 at 0:23
Thank you for the reply @Mark. Unfortunately, in both ways, you pointed, still the same result. The error is: The following tasks did not complete: run [02:21:56] Did you forget to signal async completion?
– Vlad
Jan 4 at 0:23
add a comment |
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It looks like the preferred way to use gulp.shell is via shell.task. What happens if you use return shell.task(….)? Otherwise try the callback function route: function checkAppisOpen(done) { return shell(…..); done(); };
– Mark
Jan 3 at 15:05
Thank you for the reply @Mark. Unfortunately, in both ways, you pointed, still the same result. The error is: The following tasks did not complete: run [02:21:56] Did you forget to signal async completion?
– Vlad
Jan 4 at 0:23