Spring web,xml with Basic and Saml Both configuration
0
I have the two DispatcherServlet named as spring-saml and another one as spring-basic, I want to configure the saml authentication for spring-saml and basic auth for spring-basic, But I'm getting exception java.lang.IllegalArgumentException: <login-config> element is limited to 1 occurrence. My web.xml file is
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>spring-saml</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>spring-basic</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-saml</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<login-config>
<auth-method>FORM</auth-method>
</login-config>
<servlet-mapping>
<servlet-name>spring-basic</servlet-name>
<url-pattern>/basic/*</url-pattern>
</servlet-mapping>
<login-config>
<auth-method>BASIC</auth-method>
</login-config>
<security-constraint>
<web-resource-collection>
<web-resource-name>Protected
Area
</web-resource-name>
<url-pattern>/rest/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>Everyone</role-name>
</auth-constraint>
</security-constraint>
<security-constraint>
<web-resource-collection>
<web-resource-name>Protected
Area
</web-resource-name>
<url-pattern>/basic/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>Everyone</role-name>
</auth-constraint>
</security-constraint>
</web-app>
Please tell me how can I achieve this.
spring spring-mvc web.xml
asked Dec 31 '18 at 9:50
lucky Barkanelucky Barkane
155
add a comment |
0
I have the two DispatcherServlet named as spring-saml and another one as spring-basic, I want to configure the saml authentication for spring-saml and basic auth for spring-basic, But I'm getting exception java.lang.IllegalArgumentException: <login-config> element is limited to 1 occurrence. My web.xml file is
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>spring-saml</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>spring-basic</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-saml</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<login-config>
<auth-method>FORM</auth-method>
</login-config>
<servlet-mapping>
<servlet-name>spring-basic</servlet-name>
<url-pattern>/basic/*</url-pattern>
</servlet-mapping>
<login-config>
<auth-method>BASIC</auth-method>
</login-config>
<security-constraint>
<web-resource-collection>
<web-resource-name>Protected
Area
</web-resource-name>
<url-pattern>/rest/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>Everyone</role-name>
</auth-constraint>
</security-constraint>
<security-constraint>
<web-resource-collection>
<web-resource-name>Protected
Area
</web-resource-name>
<url-pattern>/basic/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>Everyone</role-name>
</auth-constraint>
</security-constraint>
</web-app>
Please tell me how can I achieve this.
spring spring-mvc web.xml
asked Dec 31 '18 at 9:50
lucky Barkanelucky Barkane
155
There is two ways 1. Configure your web.xml to use FORM auth-method 2. Set the url-pattern you want to authenticate BASIC way with no auth-constraint: 3. Configure a filter for that pattern 4. Process login manually in the filter OR configure Spring Security to work with two different login
– Govind Parashar
Dec 31 '18 at 10:31
add a comment |
0
0
0
I have the two DispatcherServlet named as spring-saml and another one as spring-basic, I want to configure the saml authentication for spring-saml and basic auth for spring-basic, But I'm getting exception java.lang.IllegalArgumentException: <login-config> element is limited to 1 occurrence. My web.xml file is
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>spring-saml</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>spring-basic</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-saml</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<login-config>
<auth-method>FORM</auth-method>
</login-config>
<servlet-mapping>
<servlet-name>spring-basic</servlet-name>
<url-pattern>/basic/*</url-pattern>
</servlet-mapping>
<login-config>
<auth-method>BASIC</auth-method>
</login-config>
<security-constraint>
<web-resource-collection>
<web-resource-name>Protected
Area
</web-resource-name>
<url-pattern>/rest/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>Everyone</role-name>
</auth-constraint>
</security-constraint>
<security-constraint>
<web-resource-collection>
<web-resource-name>Protected
Area
</web-resource-name>
<url-pattern>/basic/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>Everyone</role-name>
</auth-constraint>
</security-constraint>
</web-app>
Please tell me how can I achieve this.
spring spring-mvc web.xml
asked Dec 31 '18 at 9:50
lucky Barkanelucky Barkane
155
I have the two DispatcherServlet named as spring-saml and another one as spring-basic, I want to configure the saml authentication for spring-saml and basic auth for spring-basic, But I'm getting exception java.lang.IllegalArgumentException: <login-config> element is limited to 1 occurrence. My web.xml file is
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
id="WebApp_ID" version="2.5">
<display-name>Archetype Created Web Application</display-name>
<servlet>
<servlet-name>spring-saml</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet>
<servlet-name>spring-basic</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>spring-saml</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
<login-config>
<auth-method>FORM</auth-method>
</login-config>
<servlet-mapping>
<servlet-name>spring-basic</servlet-name>
<url-pattern>/basic/*</url-pattern>
</servlet-mapping>
<login-config>
<auth-method>BASIC</auth-method>
</login-config>
<security-constraint>
<web-resource-collection>
<web-resource-name>Protected
Area
</web-resource-name>
<url-pattern>/rest/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>Everyone</role-name>
</auth-constraint>
</security-constraint>
<security-constraint>
<web-resource-collection>
<web-resource-name>Protected
Area
</web-resource-name>
<url-pattern>/basic/*</url-pattern>
</web-resource-collection>
<auth-constraint>
<role-name>Everyone</role-name>
</auth-constraint>
</security-constraint>
</web-app>
Please tell me how can I achieve this.
spring spring-mvc web.xml
spring spring-mvc web.xml
asked Dec 31 '18 at 9:50
lucky Barkanelucky Barkane
155
asked Dec 31 '18 at 9:50
lucky Barkanelucky Barkane
155
asked Dec 31 '18 at 9:50
lucky Barkanelucky Barkane
155
asked Dec 31 '18 at 9:50
lucky Barkanelucky Barkane
155
asked Dec 31 '18 at 9:50
lucky Barkanelucky Barkane
155
155
There is two ways 1. Configure your web.xml to use FORM auth-method 2. Set the url-pattern you want to authenticate BASIC way with no auth-constraint: 3. Configure a filter for that pattern 4. Process login manually in the filter OR configure Spring Security to work with two different login
– Govind Parashar
Dec 31 '18 at 10:31
add a comment |
There is two ways 1. Configure your web.xml to use FORM auth-method 2. Set the url-pattern you want to authenticate BASIC way with no auth-constraint: 3. Configure a filter for that pattern 4. Process login manually in the filter OR configure Spring Security to work with two different login
– Govind Parashar
Dec 31 '18 at 10:31
There is two ways 1. Configure your web.xml to use FORM auth-method 2. Set the url-pattern you want to authenticate BASIC way with no auth-constraint: 3. Configure a filter for that pattern 4. Process login manually in the filter OR configure Spring Security to work with two different login
– Govind Parashar
Dec 31 '18 at 10:31
There is two ways 1. Configure your web.xml to use FORM auth-method 2. Set the url-pattern you want to authenticate BASIC way with no auth-constraint: 3. Configure a filter for that pattern 4. Process login manually in the filter OR configure Spring Security to work with two different login
– Govind Parashar
Dec 31 '18 at 10:31
add a comment |
0
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There is two ways 1. Configure your web.xml to use FORM auth-method 2. Set the url-pattern you want to authenticate BASIC way with no auth-constraint: 3. Configure a filter for that pattern 4. Process login manually in the filter OR configure Spring Security to work with two different login
– Govind Parashar
Dec 31 '18 at 10:31