Gmail api - browser quickstart error: bad request
I followed Google gmail api browser quickstart step by step, but when I try to open index.html I get the following error:
{
"error": {
"errors": [
{
"domain": "usageLimits",
"reason": "keyInvalid",
"message": "Bad Request"
}
],
"code": 400,
"message": "Bad Request"
}
}
=(
javascript gmail gmail-api
add a comment |
I followed Google gmail api browser quickstart step by step, but when I try to open index.html I get the following error:
{
"error": {
"errors": [
{
"domain": "usageLimits",
"reason": "keyInvalid",
"message": "Bad Request"
}
],
"code": 400,
"message": "Bad Request"
}
}
=(
javascript gmail gmail-api
add a comment |
I followed Google gmail api browser quickstart step by step, but when I try to open index.html I get the following error:
{
"error": {
"errors": [
{
"domain": "usageLimits",
"reason": "keyInvalid",
"message": "Bad Request"
}
],
"code": 400,
"message": "Bad Request"
}
}
=(
javascript gmail gmail-api
I followed Google gmail api browser quickstart step by step, but when I try to open index.html I get the following error:
{
"error": {
"errors": [
{
"domain": "usageLimits",
"reason": "keyInvalid",
"message": "Bad Request"
}
],
"code": 400,
"message": "Bad Request"
}
}
=(
javascript gmail gmail-api
javascript gmail gmail-api
asked Dec 31 '18 at 23:04
Jasper BlooJasper Bloo
32
32
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1 Answer
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votes
If you are not planning to use the API Key, kindly remove it in the request:
function initClient() {
gapi.client.init({
apiKey: API_KEY, ///this one, since you didn't provide any value it will return an error.
clientId: CLIENT_ID,
discoveryDocs: DISCOVERY_DOCS,
scope: SCOPES
}).then(function () {
// Listen for sign-in state changes.
gapi.auth2.getAuthInstance().isSignedIn.listen(updateSigninStatus);
// Handle the initial sign-in state.
updateSigninStatus(gapi.auth2.getAuthInstance().isSignedIn.get());
authorizeButton.onclick = handleAuthClick;
signoutButton.onclick = handleSignoutClick;
}, function(error) {
appendPre(JSON.stringify(error, null, 2));
});
}
That should eliminate the issue you are encountering. My suggestion would be provide a valid API key from the console or remove it from the request (not sure how it will behave since in the quickstart they require both client ID and API key).
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you are not planning to use the API Key, kindly remove it in the request:
function initClient() {
gapi.client.init({
apiKey: API_KEY, ///this one, since you didn't provide any value it will return an error.
clientId: CLIENT_ID,
discoveryDocs: DISCOVERY_DOCS,
scope: SCOPES
}).then(function () {
// Listen for sign-in state changes.
gapi.auth2.getAuthInstance().isSignedIn.listen(updateSigninStatus);
// Handle the initial sign-in state.
updateSigninStatus(gapi.auth2.getAuthInstance().isSignedIn.get());
authorizeButton.onclick = handleAuthClick;
signoutButton.onclick = handleSignoutClick;
}, function(error) {
appendPre(JSON.stringify(error, null, 2));
});
}
That should eliminate the issue you are encountering. My suggestion would be provide a valid API key from the console or remove it from the request (not sure how it will behave since in the quickstart they require both client ID and API key).
add a comment |
If you are not planning to use the API Key, kindly remove it in the request:
function initClient() {
gapi.client.init({
apiKey: API_KEY, ///this one, since you didn't provide any value it will return an error.
clientId: CLIENT_ID,
discoveryDocs: DISCOVERY_DOCS,
scope: SCOPES
}).then(function () {
// Listen for sign-in state changes.
gapi.auth2.getAuthInstance().isSignedIn.listen(updateSigninStatus);
// Handle the initial sign-in state.
updateSigninStatus(gapi.auth2.getAuthInstance().isSignedIn.get());
authorizeButton.onclick = handleAuthClick;
signoutButton.onclick = handleSignoutClick;
}, function(error) {
appendPre(JSON.stringify(error, null, 2));
});
}
That should eliminate the issue you are encountering. My suggestion would be provide a valid API key from the console or remove it from the request (not sure how it will behave since in the quickstart they require both client ID and API key).
add a comment |
If you are not planning to use the API Key, kindly remove it in the request:
function initClient() {
gapi.client.init({
apiKey: API_KEY, ///this one, since you didn't provide any value it will return an error.
clientId: CLIENT_ID,
discoveryDocs: DISCOVERY_DOCS,
scope: SCOPES
}).then(function () {
// Listen for sign-in state changes.
gapi.auth2.getAuthInstance().isSignedIn.listen(updateSigninStatus);
// Handle the initial sign-in state.
updateSigninStatus(gapi.auth2.getAuthInstance().isSignedIn.get());
authorizeButton.onclick = handleAuthClick;
signoutButton.onclick = handleSignoutClick;
}, function(error) {
appendPre(JSON.stringify(error, null, 2));
});
}
That should eliminate the issue you are encountering. My suggestion would be provide a valid API key from the console or remove it from the request (not sure how it will behave since in the quickstart they require both client ID and API key).
If you are not planning to use the API Key, kindly remove it in the request:
function initClient() {
gapi.client.init({
apiKey: API_KEY, ///this one, since you didn't provide any value it will return an error.
clientId: CLIENT_ID,
discoveryDocs: DISCOVERY_DOCS,
scope: SCOPES
}).then(function () {
// Listen for sign-in state changes.
gapi.auth2.getAuthInstance().isSignedIn.listen(updateSigninStatus);
// Handle the initial sign-in state.
updateSigninStatus(gapi.auth2.getAuthInstance().isSignedIn.get());
authorizeButton.onclick = handleAuthClick;
signoutButton.onclick = handleSignoutClick;
}, function(error) {
appendPre(JSON.stringify(error, null, 2));
});
}
That should eliminate the issue you are encountering. My suggestion would be provide a valid API key from the console or remove it from the request (not sure how it will behave since in the quickstart they require both client ID and API key).
answered Jan 1 at 23:53
Mr.RebotMr.Rebot
5,1362757
5,1362757
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