C++ : good practice of declare map of custom type












2















I am trying to define a map like below within my MyTreeNode class:



std::unordered_map<int, MyTreeNode> children_map;


This seems to be fine. However, I am wondering would it be better to define the map using the pointer like?



std::unordered_map<int, MyTreeNode*> children_map;


For my specific case, I have



class MyTreeNode {
// some code
std::unordered_map<int, MyTreeNode> children_map; // line_1
// std::unordered_map<int, MyTreeNode*> children_map; // line_2

}


Is there a good practice for such scenario? Should I use line_1 or line_2? Thanks!










share|improve this question




















  • 7





    That depends entirely on the context. If you already have the instances of MyTreeNode stored e.g. in a vector and only want to use the std::unordered_map as a kind of index into the vector then use the second version. If the map owns the MyTreeNode instances then use the first version.

    – Corristo
    Dec 31 '18 at 23:19






  • 1





    @edamame - Um..... Is this supposed to be a map that holds custom types, or is it some device that holds entities in special clothing?

    – enhzflep
    Dec 31 '18 at 23:26











  • @enhzflep it is a map that holds custom types. Thanks!

    – Edamame
    Dec 31 '18 at 23:31






  • 2





    If you are able to do either then use the first one (don't use pointers if you don't have to). Otherwise they have different uses.

    – Galik
    Dec 31 '18 at 23:45








  • 1





    If you are relying on unordered_map for your search tree, why not just use a single unordered_map for all of your nodes? What advantage does a tree structure give you for children that a single unordered_map would not be able to provide?

    – jxh
    Dec 31 '18 at 23:57
















2















I am trying to define a map like below within my MyTreeNode class:



std::unordered_map<int, MyTreeNode> children_map;


This seems to be fine. However, I am wondering would it be better to define the map using the pointer like?



std::unordered_map<int, MyTreeNode*> children_map;


For my specific case, I have



class MyTreeNode {
// some code
std::unordered_map<int, MyTreeNode> children_map; // line_1
// std::unordered_map<int, MyTreeNode*> children_map; // line_2

}


Is there a good practice for such scenario? Should I use line_1 or line_2? Thanks!










share|improve this question




















  • 7





    That depends entirely on the context. If you already have the instances of MyTreeNode stored e.g. in a vector and only want to use the std::unordered_map as a kind of index into the vector then use the second version. If the map owns the MyTreeNode instances then use the first version.

    – Corristo
    Dec 31 '18 at 23:19






  • 1





    @edamame - Um..... Is this supposed to be a map that holds custom types, or is it some device that holds entities in special clothing?

    – enhzflep
    Dec 31 '18 at 23:26











  • @enhzflep it is a map that holds custom types. Thanks!

    – Edamame
    Dec 31 '18 at 23:31






  • 2





    If you are able to do either then use the first one (don't use pointers if you don't have to). Otherwise they have different uses.

    – Galik
    Dec 31 '18 at 23:45








  • 1





    If you are relying on unordered_map for your search tree, why not just use a single unordered_map for all of your nodes? What advantage does a tree structure give you for children that a single unordered_map would not be able to provide?

    – jxh
    Dec 31 '18 at 23:57














2












2








2








I am trying to define a map like below within my MyTreeNode class:



std::unordered_map<int, MyTreeNode> children_map;


This seems to be fine. However, I am wondering would it be better to define the map using the pointer like?



std::unordered_map<int, MyTreeNode*> children_map;


For my specific case, I have



class MyTreeNode {
// some code
std::unordered_map<int, MyTreeNode> children_map; // line_1
// std::unordered_map<int, MyTreeNode*> children_map; // line_2

}


Is there a good practice for such scenario? Should I use line_1 or line_2? Thanks!










share|improve this question
















I am trying to define a map like below within my MyTreeNode class:



std::unordered_map<int, MyTreeNode> children_map;


This seems to be fine. However, I am wondering would it be better to define the map using the pointer like?



std::unordered_map<int, MyTreeNode*> children_map;


For my specific case, I have



class MyTreeNode {
// some code
std::unordered_map<int, MyTreeNode> children_map; // line_1
// std::unordered_map<int, MyTreeNode*> children_map; // line_2

}


Is there a good practice for such scenario? Should I use line_1 or line_2? Thanks!







c++ pointers treenode






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Dec 31 '18 at 23:40







Edamame

















asked Dec 31 '18 at 23:17









EdamameEdamame

4,7252379157




4,7252379157








  • 7





    That depends entirely on the context. If you already have the instances of MyTreeNode stored e.g. in a vector and only want to use the std::unordered_map as a kind of index into the vector then use the second version. If the map owns the MyTreeNode instances then use the first version.

    – Corristo
    Dec 31 '18 at 23:19






  • 1





    @edamame - Um..... Is this supposed to be a map that holds custom types, or is it some device that holds entities in special clothing?

    – enhzflep
    Dec 31 '18 at 23:26











  • @enhzflep it is a map that holds custom types. Thanks!

    – Edamame
    Dec 31 '18 at 23:31






  • 2





    If you are able to do either then use the first one (don't use pointers if you don't have to). Otherwise they have different uses.

    – Galik
    Dec 31 '18 at 23:45








  • 1





    If you are relying on unordered_map for your search tree, why not just use a single unordered_map for all of your nodes? What advantage does a tree structure give you for children that a single unordered_map would not be able to provide?

    – jxh
    Dec 31 '18 at 23:57














  • 7





    That depends entirely on the context. If you already have the instances of MyTreeNode stored e.g. in a vector and only want to use the std::unordered_map as a kind of index into the vector then use the second version. If the map owns the MyTreeNode instances then use the first version.

    – Corristo
    Dec 31 '18 at 23:19






  • 1





    @edamame - Um..... Is this supposed to be a map that holds custom types, or is it some device that holds entities in special clothing?

    – enhzflep
    Dec 31 '18 at 23:26











  • @enhzflep it is a map that holds custom types. Thanks!

    – Edamame
    Dec 31 '18 at 23:31






  • 2





    If you are able to do either then use the first one (don't use pointers if you don't have to). Otherwise they have different uses.

    – Galik
    Dec 31 '18 at 23:45








  • 1





    If you are relying on unordered_map for your search tree, why not just use a single unordered_map for all of your nodes? What advantage does a tree structure give you for children that a single unordered_map would not be able to provide?

    – jxh
    Dec 31 '18 at 23:57








7




7





That depends entirely on the context. If you already have the instances of MyTreeNode stored e.g. in a vector and only want to use the std::unordered_map as a kind of index into the vector then use the second version. If the map owns the MyTreeNode instances then use the first version.

– Corristo
Dec 31 '18 at 23:19





That depends entirely on the context. If you already have the instances of MyTreeNode stored e.g. in a vector and only want to use the std::unordered_map as a kind of index into the vector then use the second version. If the map owns the MyTreeNode instances then use the first version.

– Corristo
Dec 31 '18 at 23:19




1




1





@edamame - Um..... Is this supposed to be a map that holds custom types, or is it some device that holds entities in special clothing?

– enhzflep
Dec 31 '18 at 23:26





@edamame - Um..... Is this supposed to be a map that holds custom types, or is it some device that holds entities in special clothing?

– enhzflep
Dec 31 '18 at 23:26













@enhzflep it is a map that holds custom types. Thanks!

– Edamame
Dec 31 '18 at 23:31





@enhzflep it is a map that holds custom types. Thanks!

– Edamame
Dec 31 '18 at 23:31




2




2





If you are able to do either then use the first one (don't use pointers if you don't have to). Otherwise they have different uses.

– Galik
Dec 31 '18 at 23:45







If you are able to do either then use the first one (don't use pointers if you don't have to). Otherwise they have different uses.

– Galik
Dec 31 '18 at 23:45






1




1





If you are relying on unordered_map for your search tree, why not just use a single unordered_map for all of your nodes? What advantage does a tree structure give you for children that a single unordered_map would not be able to provide?

– jxh
Dec 31 '18 at 23:57





If you are relying on unordered_map for your search tree, why not just use a single unordered_map for all of your nodes? What advantage does a tree structure give you for children that a single unordered_map would not be able to provide?

– jxh
Dec 31 '18 at 23:57












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