Dynamic array of pointers to structs- how to pass to funcs?

I am trying to figure out how should I get some code done so I will send a dynamic array of pointers to structs to functions and will be able to free all memory at the end of the program.

Void main()

{

Some_struct **array;

array = (Some_struct**)malloc(10 * sizeof(struct));

}

Now should my function be like:

Void My_func(Some_struct** array)

{ //Code}

Or should it be like:

Void My_func(Some_struct*** array)

    { //Code}

I would like some explanation pls :)

asked Dec 31 '18 at 23:16

Idan C.

1

Please include the actual code you are using that reproduces whatever problem you are having (e.g.,1-3 lines of actual use instead of // Code + the calling code and definitions of any required variables). (In this case I suspect that if you do that, the compiler errors when you test that code before posting it here, or lack thereof, will show you which is the correct way.)

– Arkku
Dec 31 '18 at 23:32

sizeof(struct) is invalid C code. Suggest array = malloc(sizeof *array * 10); Easier to code right, review and maintain.

– chux
Jan 1 at 1:54

regarding: Void there is no such modifier in C. Perhaps you meant: void (all lower case) Regarding: Void main() There are only two valid signatures for main() they are: int main( int argc, char *argv ) and int main( void ) Notice that both signatures use a return type of int

– user3629249
Jan 2 at 1:15

please post a Minimal, Complete, and Verifiable example so we can reproduce the problem and help you debug it.

– user3629249
Jan 2 at 1:20

add a comment |

I am trying to figure out how should I get some code done so I will send a dynamic array of pointers to structs to functions and will be able to free all memory at the end of the program.

Void main()

{

Some_struct **array;

array = (Some_struct**)malloc(10 * sizeof(struct));

}

Now should my function be like:

Void My_func(Some_struct** array)

{ //Code}

Or should it be like:

Void My_func(Some_struct*** array)

    { //Code}

I would like some explanation pls :)

asked Dec 31 '18 at 23:16

Idan C.

1

Please include the actual code you are using that reproduces whatever problem you are having (e.g.,1-3 lines of actual use instead of // Code + the calling code and definitions of any required variables). (In this case I suspect that if you do that, the compiler errors when you test that code before posting it here, or lack thereof, will show you which is the correct way.)

– Arkku
Dec 31 '18 at 23:32

sizeof(struct) is invalid C code. Suggest array = malloc(sizeof *array * 10); Easier to code right, review and maintain.

– chux
Jan 1 at 1:54

regarding: Void there is no such modifier in C. Perhaps you meant: void (all lower case) Regarding: Void main() There are only two valid signatures for main() they are: int main( int argc, char *argv ) and int main( void ) Notice that both signatures use a return type of int

– user3629249
Jan 2 at 1:15

please post a Minimal, Complete, and Verifiable example so we can reproduce the problem and help you debug it.

– user3629249
Jan 2 at 1:20

add a comment |

I am trying to figure out how should I get some code done so I will send a dynamic array of pointers to structs to functions and will be able to free all memory at the end of the program.

Void main()

{

Some_struct **array;

array = (Some_struct**)malloc(10 * sizeof(struct));

}

Now should my function be like:

Void My_func(Some_struct** array)

{ //Code}

Or should it be like:

Void My_func(Some_struct*** array)

    { //Code}

I would like some explanation pls :)

asked Dec 31 '18 at 23:16

Idan C.

I am trying to figure out how should I get some code done so I will send a dynamic array of pointers to structs to functions and will be able to free all memory at the end of the program.

Void main()

{

Some_struct **array;

array = (Some_struct**)malloc(10 * sizeof(struct));

}

Now should my function be like:

Void My_func(Some_struct** array)

{ //Code}

Or should it be like:

Void My_func(Some_struct*** array)

    { //Code}

I would like some explanation pls :)

c pointers struct

asked Dec 31 '18 at 23:16

Idan C.

asked Dec 31 '18 at 23:16

Idan C.

asked Dec 31 '18 at 23:16

Idan C.

asked Dec 31 '18 at 23:16

Idan C.

asked Dec 31 '18 at 23:16

Idan C.

1

Please include the actual code you are using that reproduces whatever problem you are having (e.g.,1-3 lines of actual use instead of // Code + the calling code and definitions of any required variables). (In this case I suspect that if you do that, the compiler errors when you test that code before posting it here, or lack thereof, will show you which is the correct way.)

– Arkku
Dec 31 '18 at 23:32

sizeof(struct) is invalid C code. Suggest array = malloc(sizeof *array * 10); Easier to code right, review and maintain.

– chux
Jan 1 at 1:54

regarding: Void there is no such modifier in C. Perhaps you meant: void (all lower case) Regarding: Void main() There are only two valid signatures for main() they are: int main( int argc, char *argv ) and int main( void ) Notice that both signatures use a return type of int

– user3629249
Jan 2 at 1:15

please post a Minimal, Complete, and Verifiable example so we can reproduce the problem and help you debug it.

– user3629249
Jan 2 at 1:20

add a comment |

1

Please include the actual code you are using that reproduces whatever problem you are having (e.g.,1-3 lines of actual use instead of // Code + the calling code and definitions of any required variables). (In this case I suspect that if you do that, the compiler errors when you test that code before posting it here, or lack thereof, will show you which is the correct way.)

– Arkku
Dec 31 '18 at 23:32

sizeof(struct) is invalid C code. Suggest array = malloc(sizeof *array * 10); Easier to code right, review and maintain.

– chux
Jan 1 at 1:54

regarding: Void there is no such modifier in C. Perhaps you meant: void (all lower case) Regarding: Void main() There are only two valid signatures for main() they are: int main( int argc, char *argv ) and int main( void ) Notice that both signatures use a return type of int

– user3629249
Jan 2 at 1:15

please post a Minimal, Complete, and Verifiable example so we can reproduce the problem and help you debug it.

– user3629249
Jan 2 at 1:20

Please include the actual code you are using that reproduces whatever problem you are having (e.g.,1-3 lines of actual use instead of // Code + the calling code and definitions of any required variables). (In this case I suspect that if you do that, the compiler errors when you test that code before posting it here, or lack thereof, will show you which is the correct way.)

– Arkku
Dec 31 '18 at 23:32

sizeof(struct) is invalid C code. Suggest array = malloc(sizeof *array * 10); Easier to code right, review and maintain.

– chux
Jan 1 at 1:54

regarding: Void there is no such modifier in C. Perhaps you meant: void (all lower case) Regarding: Void main() There are only two valid signatures for main() they are: int main( int argc, char *argv ) and int main( void ) Notice that both signatures use a return type of int

– user3629249
Jan 2 at 1:15

please post a Minimal, Complete, and Verifiable example so we can reproduce the problem and help you debug it.

– user3629249
Jan 2 at 1:20

add a comment |

1 Answer
1

active

oldest

votes

It depends on what you intend to do with array within the function. If you intend to, for example, reallocate it, then define your function's parameter with an extra level of pointer (***).

answered Jan 1 at 0:19

James R.

284

Yes I want to reallocate my array, then it seems that the second option is correct. And I should send the array to the function like this: My_func(&array)

– Idan C.
Jan 1 at 6:52

Please read: three star programmer

– user3629249
Jan 2 at 1:18

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

It depends on what you intend to do with array within the function. If you intend to, for example, reallocate it, then define your function's parameter with an extra level of pointer (***).

answered Jan 1 at 0:19

James R.

284

Yes I want to reallocate my array, then it seems that the second option is correct. And I should send the array to the function like this: My_func(&array)

– Idan C.
Jan 1 at 6:52

Please read: three star programmer

– user3629249
Jan 2 at 1:18

add a comment |

It depends on what you intend to do with array within the function. If you intend to, for example, reallocate it, then define your function's parameter with an extra level of pointer (***).

answered Jan 1 at 0:19

James R.

284

Yes I want to reallocate my array, then it seems that the second option is correct. And I should send the array to the function like this: My_func(&array)

– Idan C.
Jan 1 at 6:52

Please read: three star programmer

– user3629249
Jan 2 at 1:18

add a comment |

It depends on what you intend to do with array within the function. If you intend to, for example, reallocate it, then define your function's parameter with an extra level of pointer (***).

answered Jan 1 at 0:19

James R.

284

It depends on what you intend to do with array within the function. If you intend to, for example, reallocate it, then define your function's parameter with an extra level of pointer (***).

answered Jan 1 at 0:19

James R.

284

answered Jan 1 at 0:19

James R.

284

answered Jan 1 at 0:19

James R.

284

answered Jan 1 at 0:19

James R.

284

Yes I want to reallocate my array, then it seems that the second option is correct. And I should send the array to the function like this: My_func(&array)

– Idan C.
Jan 1 at 6:52

Please read: three star programmer

– user3629249
Jan 2 at 1:18

add a comment |

Yes I want to reallocate my array, then it seems that the second option is correct. And I should send the array to the function like this: My_func(&array)

– Idan C.
Jan 1 at 6:52

Please read: three star programmer

– user3629249
Jan 2 at 1:18

Yes I want to reallocate my array, then it seems that the second option is correct. And I should send the array to the function like this: My_func(&array)

– Idan C.
Jan 1 at 6:52

Please read: three star programmer

– user3629249
Jan 2 at 1:18

add a comment |

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