Accessing varibles inside Self-Executing Anonymous Function












-3















as per my knowledge varibles inside Self-Executing Anonymous Function are not accessible from outside but how come var q is accessible outside and why not var p then



(function(){ 
var p = q = 20;
})()
alert(q) --> 10
alert(p) --> p is undefined is the result im getting,









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  • 2





    please format your code properly - this is unreadable

    – Robin Zigmond
    Dec 30 '18 at 15:12






  • 1





    variables declared inside functions are not accessible outside, but you never declare q here. If you assign a value to a variable without declaring it, it gets implicitly declared as a global (except in strict mode, where this throws an error).

    – Robin Zigmond
    Dec 30 '18 at 15:27
















-3















as per my knowledge varibles inside Self-Executing Anonymous Function are not accessible from outside but how come var q is accessible outside and why not var p then



(function(){ 
var p = q = 20;
})()
alert(q) --> 10
alert(p) --> p is undefined is the result im getting,









share|improve this question




















  • 2





    please format your code properly - this is unreadable

    – Robin Zigmond
    Dec 30 '18 at 15:12






  • 1





    variables declared inside functions are not accessible outside, but you never declare q here. If you assign a value to a variable without declaring it, it gets implicitly declared as a global (except in strict mode, where this throws an error).

    – Robin Zigmond
    Dec 30 '18 at 15:27














-3












-3








-3








as per my knowledge varibles inside Self-Executing Anonymous Function are not accessible from outside but how come var q is accessible outside and why not var p then



(function(){ 
var p = q = 20;
})()
alert(q) --> 10
alert(p) --> p is undefined is the result im getting,









share|improve this question
















as per my knowledge varibles inside Self-Executing Anonymous Function are not accessible from outside but how come var q is accessible outside and why not var p then



(function(){ 
var p = q = 20;
})()
alert(q) --> 10
alert(p) --> p is undefined is the result im getting,






javascript






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share|improve this question













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edited Dec 30 '18 at 15:17









joelgullander

292112




292112










asked Dec 30 '18 at 15:06









rahul kumarrahul kumar

1




1








  • 2





    please format your code properly - this is unreadable

    – Robin Zigmond
    Dec 30 '18 at 15:12






  • 1





    variables declared inside functions are not accessible outside, but you never declare q here. If you assign a value to a variable without declaring it, it gets implicitly declared as a global (except in strict mode, where this throws an error).

    – Robin Zigmond
    Dec 30 '18 at 15:27














  • 2





    please format your code properly - this is unreadable

    – Robin Zigmond
    Dec 30 '18 at 15:12






  • 1





    variables declared inside functions are not accessible outside, but you never declare q here. If you assign a value to a variable without declaring it, it gets implicitly declared as a global (except in strict mode, where this throws an error).

    – Robin Zigmond
    Dec 30 '18 at 15:27








2




2





please format your code properly - this is unreadable

– Robin Zigmond
Dec 30 '18 at 15:12





please format your code properly - this is unreadable

– Robin Zigmond
Dec 30 '18 at 15:12




1




1





variables declared inside functions are not accessible outside, but you never declare q here. If you assign a value to a variable without declaring it, it gets implicitly declared as a global (except in strict mode, where this throws an error).

– Robin Zigmond
Dec 30 '18 at 15:27





variables declared inside functions are not accessible outside, but you never declare q here. If you assign a value to a variable without declaring it, it gets implicitly declared as a global (except in strict mode, where this throws an error).

– Robin Zigmond
Dec 30 '18 at 15:27












2 Answers
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Variables defined within a anonymous function will not be accessible outside. However in your example you are setting variable p as a scoped variable & q as a global variable. The correct way you are looking for here would be:



var p;
var q;
p = q = 20;





share|improve this answer































    2














    To avoid global variable you need to add ‘var’, ‘const’ or ‘let’ before each variable name. If you omit these keywords the variable begin global. In your case q is global






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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

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      active

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      active

      oldest

      votes









      2














      Variables defined within a anonymous function will not be accessible outside. However in your example you are setting variable p as a scoped variable & q as a global variable. The correct way you are looking for here would be:



      var p;
      var q;
      p = q = 20;





      share|improve this answer




























        2














        Variables defined within a anonymous function will not be accessible outside. However in your example you are setting variable p as a scoped variable & q as a global variable. The correct way you are looking for here would be:



        var p;
        var q;
        p = q = 20;





        share|improve this answer


























          2












          2








          2







          Variables defined within a anonymous function will not be accessible outside. However in your example you are setting variable p as a scoped variable & q as a global variable. The correct way you are looking for here would be:



          var p;
          var q;
          p = q = 20;





          share|improve this answer













          Variables defined within a anonymous function will not be accessible outside. However in your example you are setting variable p as a scoped variable & q as a global variable. The correct way you are looking for here would be:



          var p;
          var q;
          p = q = 20;






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Dec 30 '18 at 15:12









          joelgullanderjoelgullander

          292112




          292112

























              2














              To avoid global variable you need to add ‘var’, ‘const’ or ‘let’ before each variable name. If you omit these keywords the variable begin global. In your case q is global






              share|improve this answer




























                2














                To avoid global variable you need to add ‘var’, ‘const’ or ‘let’ before each variable name. If you omit these keywords the variable begin global. In your case q is global






                share|improve this answer


























                  2












                  2








                  2







                  To avoid global variable you need to add ‘var’, ‘const’ or ‘let’ before each variable name. If you omit these keywords the variable begin global. In your case q is global






                  share|improve this answer













                  To avoid global variable you need to add ‘var’, ‘const’ or ‘let’ before each variable name. If you omit these keywords the variable begin global. In your case q is global







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered Dec 30 '18 at 15:52









                  LaurentLaurent

                  2915




                  2915






























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