How to input char array in c++ in a single line?
I just encountered an input statement for char array in c++ and I didn't understand how it works.
char s[100];
cin >> s + 1;
cout << s + 1;
Input : Harold
Output: Harold
Can anyone explain to me how it works?
c++ input c++14
edited Dec 28 '18 at 21:41
HolyBlackCat
15.9k33363
asked Dec 28 '18 at 18:04
Bhashkar PanditBhashkar Pandit
43
|
show 1 more comment
I just encountered an input statement for char array in c++ and I didn't understand how it works.
char s[100];
cin >> s + 1;
cout << s + 1;
Input : Harold
Output: Harold
Can anyone explain to me how it works?
c++ input c++14
edited Dec 28 '18 at 21:41
HolyBlackCat
15.9k33363
asked Dec 28 '18 at 18:04
Bhashkar PanditBhashkar Pandit
43
2
It works exactly like any otherchararray. Sorry we don't know how much of C++ you know, so it's a bit difficult to pick a starting point for an explanation. Why exactly are you confused about these lines?
– n.m.
Dec 28 '18 at 18:58
If it said((&s[0]) + 1)would you understand it?
– David Schwartz
Dec 28 '18 at 21:55
Make these changeschar s[100] = "a";Now at the end addcout << 'n' << s << 'n';With that, can you tell what is going on?
– David C. Rankin
Dec 28 '18 at 22:02
@n.m. I was wondering how it works. We used to use loops to input an array but didn't know about this. Now I get this. Thanks a lot
– Bhashkar Pandit
Dec 30 '18 at 6:40
@DavidSchwartz Yeah i got this. Thanks a lot.
– Bhashkar Pandit
Dec 30 '18 at 6:44
|
show 1 more comment
I just encountered an input statement for char array in c++ and I didn't understand how it works.
char s[100];
cin >> s + 1;
cout << s + 1;
Input : Harold
Output: Harold
Can anyone explain to me how it works?
c++ input c++14
edited Dec 28 '18 at 21:41
HolyBlackCat
15.9k33363
asked Dec 28 '18 at 18:04
Bhashkar PanditBhashkar Pandit
43
I just encountered an input statement for char array in c++ and I didn't understand how it works.
char s[100];
cin >> s + 1;
cout << s + 1;
Input : Harold
Output: Harold
Can anyone explain to me how it works?
c++ input c++14
c++ input c++14
edited Dec 28 '18 at 21:41
HolyBlackCat
15.9k33363
asked Dec 28 '18 at 18:04
Bhashkar PanditBhashkar Pandit
43
edited Dec 28 '18 at 21:41
HolyBlackCat
15.9k33363
asked Dec 28 '18 at 18:04
Bhashkar PanditBhashkar Pandit
43
edited Dec 28 '18 at 21:41
HolyBlackCat
15.9k33363
edited Dec 28 '18 at 21:41
HolyBlackCat
15.9k33363
edited Dec 28 '18 at 21:41
HolyBlackCat
15.9k33363
15.9k33363
asked Dec 28 '18 at 18:04
Bhashkar PanditBhashkar Pandit
43
asked Dec 28 '18 at 18:04
Bhashkar PanditBhashkar Pandit
43
asked Dec 28 '18 at 18:04
Bhashkar PanditBhashkar Pandit
43
43
2
It works exactly like any otherchararray. Sorry we don't know how much of C++ you know, so it's a bit difficult to pick a starting point for an explanation. Why exactly are you confused about these lines?
– n.m.
Dec 28 '18 at 18:58
If it said((&s[0]) + 1)would you understand it?
– David Schwartz
Dec 28 '18 at 21:55
Make these changeschar s[100] = "a";Now at the end addcout << 'n' << s << 'n';With that, can you tell what is going on?
– David C. Rankin
Dec 28 '18 at 22:02
@n.m. I was wondering how it works. We used to use loops to input an array but didn't know about this. Now I get this. Thanks a lot
– Bhashkar Pandit
Dec 30 '18 at 6:40
@DavidSchwartz Yeah i got this. Thanks a lot.
– Bhashkar Pandit
Dec 30 '18 at 6:44
|
show 1 more comment
2
It works exactly like any otherchararray. Sorry we don't know how much of C++ you know, so it's a bit difficult to pick a starting point for an explanation. Why exactly are you confused about these lines?
– n.m.
Dec 28 '18 at 18:58
If it said((&s[0]) + 1)would you understand it?
– David Schwartz
Dec 28 '18 at 21:55
Make these changeschar s[100] = "a";Now at the end addcout << 'n' << s << 'n';With that, can you tell what is going on?
– David C. Rankin
Dec 28 '18 at 22:02
@n.m. I was wondering how it works. We used to use loops to input an array but didn't know about this. Now I get this. Thanks a lot
– Bhashkar Pandit
Dec 30 '18 at 6:40
@DavidSchwartz Yeah i got this. Thanks a lot.
– Bhashkar Pandit
Dec 30 '18 at 6:44
2
2
It works exactly like any other
char array. Sorry we don't know how much of C++ you know, so it's a bit difficult to pick a starting point for an explanation. Why exactly are you confused about these lines?– n.m.
Dec 28 '18 at 18:58
It works exactly like any other
char array. Sorry we don't know how much of C++ you know, so it's a bit difficult to pick a starting point for an explanation. Why exactly are you confused about these lines?– n.m.
Dec 28 '18 at 18:58
If it said
((&s[0]) + 1) would you understand it?– David Schwartz
Dec 28 '18 at 21:55
If it said
((&s[0]) + 1) would you understand it?– David Schwartz
Dec 28 '18 at 21:55
Make these changes
char s[100] = "a"; Now at the end add cout << 'n' << s << 'n'; With that, can you tell what is going on?– David C. Rankin
Dec 28 '18 at 22:02
Make these changes
char s[100] = "a"; Now at the end add cout << 'n' << s << 'n'; With that, can you tell what is going on?– David C. Rankin
Dec 28 '18 at 22:02
@n.m. I was wondering how it works. We used to use loops to input an array but didn't know about this. Now I get this. Thanks a lot
– Bhashkar Pandit
Dec 30 '18 at 6:40
@n.m. I was wondering how it works. We used to use loops to input an array but didn't know about this. Now I get this. Thanks a lot
– Bhashkar Pandit
Dec 30 '18 at 6:40
@DavidSchwartz Yeah i got this. Thanks a lot.
– Bhashkar Pandit
Dec 30 '18 at 6:44
@DavidSchwartz Yeah i got this. Thanks a lot.
– Bhashkar Pandit
Dec 30 '18 at 6:44
|
show 1 more comment
1 Answer
1
active
oldest
votes
When you give the input 'Harold', the indices from 1 to 6 (As you do with s+1) will be assigned with the given characters. Other indices still contain garbages.
This array looks like this: {'X','H','a','r','o','l','d','X','X',........} (Here 'X' means garbage)
But the thing is that when you want to get this array as output from s+1 (literally s[1]), It shows only the value you have assigned. Hence the output 'Harold'.
edited Dec 28 '18 at 22:28
smac89
12.3k43675
answered Dec 28 '18 at 22:24
Muhimin_OsimMuhimin_Osim
112
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
When you give the input 'Harold', the indices from 1 to 6 (As you do with s+1) will be assigned with the given characters. Other indices still contain garbages.
This array looks like this: {'X','H','a','r','o','l','d','X','X',........} (Here 'X' means garbage)
But the thing is that when you want to get this array as output from s+1 (literally s[1]), It shows only the value you have assigned. Hence the output 'Harold'.
edited Dec 28 '18 at 22:28
smac89
12.3k43675
answered Dec 28 '18 at 22:24
Muhimin_OsimMuhimin_Osim
112
add a comment |
When you give the input 'Harold', the indices from 1 to 6 (As you do with s+1) will be assigned with the given characters. Other indices still contain garbages.
This array looks like this: {'X','H','a','r','o','l','d','X','X',........} (Here 'X' means garbage)
But the thing is that when you want to get this array as output from s+1 (literally s[1]), It shows only the value you have assigned. Hence the output 'Harold'.
edited Dec 28 '18 at 22:28
smac89
12.3k43675
answered Dec 28 '18 at 22:24
Muhimin_OsimMuhimin_Osim
112
add a comment |
When you give the input 'Harold', the indices from 1 to 6 (As you do with s+1) will be assigned with the given characters. Other indices still contain garbages.
This array looks like this: {'X','H','a','r','o','l','d','X','X',........} (Here 'X' means garbage)
But the thing is that when you want to get this array as output from s+1 (literally s[1]), It shows only the value you have assigned. Hence the output 'Harold'.
edited Dec 28 '18 at 22:28
smac89
12.3k43675
answered Dec 28 '18 at 22:24
Muhimin_OsimMuhimin_Osim
112
When you give the input 'Harold', the indices from 1 to 6 (As you do with s+1) will be assigned with the given characters. Other indices still contain garbages.
This array looks like this: {'X','H','a','r','o','l','d','X','X',........} (Here 'X' means garbage)
But the thing is that when you want to get this array as output from s+1 (literally s[1]), It shows only the value you have assigned. Hence the output 'Harold'.
edited Dec 28 '18 at 22:28
smac89
12.3k43675
answered Dec 28 '18 at 22:24
Muhimin_OsimMuhimin_Osim
112
edited Dec 28 '18 at 22:28
smac89
12.3k43675
edited Dec 28 '18 at 22:28
smac89
12.3k43675
edited Dec 28 '18 at 22:28
smac89
12.3k43675
12.3k43675
answered Dec 28 '18 at 22:24
Muhimin_OsimMuhimin_Osim
112
answered Dec 28 '18 at 22:24
Muhimin_OsimMuhimin_Osim
112
answered Dec 28 '18 at 22:24
Muhimin_OsimMuhimin_Osim
112
112
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2
It works exactly like any other
chararray. Sorry we don't know how much of C++ you know, so it's a bit difficult to pick a starting point for an explanation. Why exactly are you confused about these lines?– n.m.
Dec 28 '18 at 18:58
If it said
((&s[0]) + 1)would you understand it?– David Schwartz
Dec 28 '18 at 21:55
Make these changes
char s[100] = "a";Now at the end addcout << 'n' << s << 'n';With that, can you tell what is going on?– David C. Rankin
Dec 28 '18 at 22:02
@n.m. I was wondering how it works. We used to use loops to input an array but didn't know about this. Now I get this. Thanks a lot
– Bhashkar Pandit
Dec 30 '18 at 6:40
@DavidSchwartz Yeah i got this. Thanks a lot.
– Bhashkar Pandit
Dec 30 '18 at 6:44