How can i use if else validation in regex
I know how to validate a constant string with regex, but I'm really having trouble finding out how to do the following: I want a regex to validate the string edv_ after that I want the validation to be dependent:
- if the user inputs for example
edv_2, only6or7can be the next character. So onlyedv_26oredv_27would be valid - if the user would enter
edv_3then onlyedv_32oredv_39would be valid
Ive tried searching on the internet watched several youtube tutorials. None of them seem to handle this kind of thing. It's always only 1 constant thing they want to validate.
/[e][d][v][_][A]/ig
This matches the first part (edv_digit) but I have no clue how I should continue with the if else conditions.
regex
edited Dec 29 '18 at 10:22
Frederic Klein
2,66631533
asked Dec 28 '18 at 17:59
MajesticOlMajesticOl
61
add a comment |
I know how to validate a constant string with regex, but I'm really having trouble finding out how to do the following: I want a regex to validate the string edv_ after that I want the validation to be dependent:
- if the user inputs for example
edv_2, only6or7can be the next character. So onlyedv_26oredv_27would be valid - if the user would enter
edv_3then onlyedv_32oredv_39would be valid
Ive tried searching on the internet watched several youtube tutorials. None of them seem to handle this kind of thing. It's always only 1 constant thing they want to validate.
/[e][d][v][_][A]/ig
This matches the first part (edv_digit) but I have no clue how I should continue with the if else conditions.
regex
edited Dec 29 '18 at 10:22
Frederic Klein
2,66631533
asked Dec 28 '18 at 17:59
MajesticOlMajesticOl
61
add a comment |
I know how to validate a constant string with regex, but I'm really having trouble finding out how to do the following: I want a regex to validate the string edv_ after that I want the validation to be dependent:
- if the user inputs for example
edv_2, only6or7can be the next character. So onlyedv_26oredv_27would be valid - if the user would enter
edv_3then onlyedv_32oredv_39would be valid
Ive tried searching on the internet watched several youtube tutorials. None of them seem to handle this kind of thing. It's always only 1 constant thing they want to validate.
/[e][d][v][_][A]/ig
This matches the first part (edv_digit) but I have no clue how I should continue with the if else conditions.
regex
edited Dec 29 '18 at 10:22
Frederic Klein
2,66631533
asked Dec 28 '18 at 17:59
MajesticOlMajesticOl
61
I know how to validate a constant string with regex, but I'm really having trouble finding out how to do the following: I want a regex to validate the string edv_ after that I want the validation to be dependent:
- if the user inputs for example
edv_2, only6or7can be the next character. So onlyedv_26oredv_27would be valid - if the user would enter
edv_3then onlyedv_32oredv_39would be valid
Ive tried searching on the internet watched several youtube tutorials. None of them seem to handle this kind of thing. It's always only 1 constant thing they want to validate.
/[e][d][v][_][A]/ig
This matches the first part (edv_digit) but I have no clue how I should continue with the if else conditions.
regex
regex
edited Dec 29 '18 at 10:22
Frederic Klein
2,66631533
asked Dec 28 '18 at 17:59
MajesticOlMajesticOl
61
edited Dec 29 '18 at 10:22
Frederic Klein
2,66631533
asked Dec 28 '18 at 17:59
MajesticOlMajesticOl
61
edited Dec 29 '18 at 10:22
Frederic Klein
2,66631533
edited Dec 29 '18 at 10:22
Frederic Klein
2,66631533
edited Dec 29 '18 at 10:22
Frederic Klein
2,66631533
2,66631533
asked Dec 28 '18 at 17:59
MajesticOlMajesticOl
61
asked Dec 28 '18 at 17:59
MajesticOlMajesticOl
61
asked Dec 28 '18 at 17:59
MajesticOlMajesticOl
61
61
add a comment |
add a comment |
1 Answer
1
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oldest
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You basically need alternations for handling your various cases. You can use this regex which matches as per your criteria.
bedv_(?:2[67]|3[29])b
Here boundaries ensure it doesn't match partial text like abcedv_26 or edv_26111 and it starts matching with edv_ then looks for either 2 followed by either 6 or 7 or looks for 3 followed by 2 or 9.
Live Demo
answered Dec 28 '18 at 18:03
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,7622827
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You basically need alternations for handling your various cases. You can use this regex which matches as per your criteria.
bedv_(?:2[67]|3[29])b
Here boundaries ensure it doesn't match partial text like abcedv_26 or edv_26111 and it starts matching with edv_ then looks for either 2 followed by either 6 or 7 or looks for 3 followed by 2 or 9.
Live Demo
answered Dec 28 '18 at 18:03
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,7622827
add a comment |
You basically need alternations for handling your various cases. You can use this regex which matches as per your criteria.
bedv_(?:2[67]|3[29])b
Here boundaries ensure it doesn't match partial text like abcedv_26 or edv_26111 and it starts matching with edv_ then looks for either 2 followed by either 6 or 7 or looks for 3 followed by 2 or 9.
Live Demo
answered Dec 28 '18 at 18:03
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,7622827
add a comment |
You basically need alternations for handling your various cases. You can use this regex which matches as per your criteria.
bedv_(?:2[67]|3[29])b
Here boundaries ensure it doesn't match partial text like abcedv_26 or edv_26111 and it starts matching with edv_ then looks for either 2 followed by either 6 or 7 or looks for 3 followed by 2 or 9.
Live Demo
answered Dec 28 '18 at 18:03
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,7622827
You basically need alternations for handling your various cases. You can use this regex which matches as per your criteria.
bedv_(?:2[67]|3[29])b
Here boundaries ensure it doesn't match partial text like abcedv_26 or edv_26111 and it starts matching with edv_ then looks for either 2 followed by either 6 or 7 or looks for 3 followed by 2 or 9.
Live Demo
answered Dec 28 '18 at 18:03
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,7622827
edited Dec 28 '18 at 18:10
answered Dec 28 '18 at 18:03
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,7622827
answered Dec 28 '18 at 18:03
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,7622827
answered Dec 28 '18 at 18:03
Pushpesh Kumar RajwanshiPushpesh Kumar Rajwanshi
5,7622827
5,7622827
add a comment |
add a comment |
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