Split/Strip a set of lines on encountering newline or comma












1















I have a set of lines in a textpad.



Eg:



643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968, 39859 ewktgklh, 35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,235907 sdkgji,25689-8, 29067490,wtyuoew


How can I read this using python and have the text split into different list values on newline as well as , (comma)?



For instance, the output for the example text should come out as



643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968,
39859 ewktgklh,
35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,
235907 sdkgji,
25689-8,
29067490,
wtyuoew









share|improve this question

























  • Your expected output has all the spaces intact, but the title mentions stripping. Which one is it?

    – Mad Physicist
    Jan 2 at 4:29











  • Sorry, the spaces at the end of the lines can be trimmed..

    – asimo
    Jan 2 at 4:31
















1















I have a set of lines in a textpad.



Eg:



643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968, 39859 ewktgklh, 35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,235907 sdkgji,25689-8, 29067490,wtyuoew


How can I read this using python and have the text split into different list values on newline as well as , (comma)?



For instance, the output for the example text should come out as



643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968,
39859 ewktgklh,
35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,
235907 sdkgji,
25689-8,
29067490,
wtyuoew









share|improve this question

























  • Your expected output has all the spaces intact, but the title mentions stripping. Which one is it?

    – Mad Physicist
    Jan 2 at 4:29











  • Sorry, the spaces at the end of the lines can be trimmed..

    – asimo
    Jan 2 at 4:31














1












1








1








I have a set of lines in a textpad.



Eg:



643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968, 39859 ewktgklh, 35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,235907 sdkgji,25689-8, 29067490,wtyuoew


How can I read this using python and have the text split into different list values on newline as well as , (comma)?



For instance, the output for the example text should come out as



643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968,
39859 ewktgklh,
35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,
235907 sdkgji,
25689-8,
29067490,
wtyuoew









share|improve this question
















I have a set of lines in a textpad.



Eg:



643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968, 39859 ewktgklh, 35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,235907 sdkgji,25689-8, 29067490,wtyuoew


How can I read this using python and have the text split into different list values on newline as well as , (comma)?



For instance, the output for the example text should come out as



643 ABCF aksdjgk 1q25hgn
239056 dsgkn 32968,
39859 ewktgklh,
35927369
9689846 dklsghdkls 23-608 dsklgnk
ewth834056 sidtguoi,
235907 sdkgji,
25689-8,
29067490,
wtyuoew






python






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 2 at 6:40







asimo

















asked Jan 2 at 4:15









asimoasimo

610213




610213













  • Your expected output has all the spaces intact, but the title mentions stripping. Which one is it?

    – Mad Physicist
    Jan 2 at 4:29











  • Sorry, the spaces at the end of the lines can be trimmed..

    – asimo
    Jan 2 at 4:31



















  • Your expected output has all the spaces intact, but the title mentions stripping. Which one is it?

    – Mad Physicist
    Jan 2 at 4:29











  • Sorry, the spaces at the end of the lines can be trimmed..

    – asimo
    Jan 2 at 4:31

















Your expected output has all the spaces intact, but the title mentions stripping. Which one is it?

– Mad Physicist
Jan 2 at 4:29





Your expected output has all the spaces intact, but the title mentions stripping. Which one is it?

– Mad Physicist
Jan 2 at 4:29













Sorry, the spaces at the end of the lines can be trimmed..

– asimo
Jan 2 at 4:31





Sorry, the spaces at the end of the lines can be trimmed..

– asimo
Jan 2 at 4:31












2 Answers
2






active

oldest

votes


















6














Try using re.sub, and replace all commas with comma followed by a newline:



result = re.sub(',s*', ',n', input)


Note that we actually match ,s*, to remove any whitespace which might occur after a comma separator.






share|improve this answer





















  • 1





    Op keeps all the whitespace after the comma, despite what the title implies. +1 regardless

    – Mad Physicist
    Jan 2 at 4:29











  • @MadPhysicist You're right.

    – Tim Biegeleisen
    Jan 2 at 4:35











  • Not that OP wants this (after clarification), but you can replace with ` '\0n'` to keep the spaces. I haven't tested, but \0 might actually have to be \g<0> to work properly.

    – Mad Physicist
    Jan 2 at 4:40











  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • My answer appears to cover your expected output.

    – Tim Biegeleisen
    Jan 2 at 6:41



















2














Assuming that "textpad" means text file, you have a couple of options. For a small file like the one shown, the easiest solution would be to read in the entire file as a string, and replace the commas with a comma + newline, as @TimBiegeleisen's answer shows.



For larger files, this may not be a good option due to memory constraints. In that case, and for the sake of generality, I like to iterate over the lines of a file. Here is a fairly simple generator that behaves like a normal file iterator, but also splits on commas:



from itertools import zip_longest, repeat
import re

def spliterator(file):
for line in file:
segments = re.split(r',s*', line)
ends = repeat(',n', len(segments) - 1)
for item in zip_longest(segments, ends, fillvalue=''):
yield ''.join(item)


It would be pretty simple to make this accept the split pattern as an argument, optionally keep the trailing spaces, and return the whole line with newline characters inserted.



Using the generator is simple, since it just wraps a normal file object or any other iterable of lines:



with open('textpad.txt') as file:
print(''.join(spliterator(file)))


Here is an IDEOne link with a demo.



To get the contents of the whole file as though read in by readlines, just wrap in list:



lines = list(spliterator(file))


To write back to an open output file, use writelines directly:



output.writelines(spliterator(file))





share|improve this answer


























  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • @Asimo. Please don't change your question after you've received valid answers. Instead, select an answer and ask another question if you have to.

    – Mad Physicist
    Jan 2 at 6:38











  • Let me revert back..Sorry for the hassle.. I have anways found a workaround to get the output in my desired format using your answer.. simply adding with open(r'H:Messengertest_Nov2.txt') as file: lines = ''.join(spliterator(file)) lines2 = lines.splitlines()

    – asimo
    Jan 2 at 6:39











  • @Asimo. The change you made is something you should be able to figure out in your own, or at least attempt, given the answers posted here.

    – Mad Physicist
    Jan 2 at 6:39











  • @asimo. Why not just list(spliterator(file))? No need for the extra hoops. Or you could just use the generator directly. I'm guessing you don't actually need the list.

    – Mad Physicist
    Jan 2 at 6:41











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









6














Try using re.sub, and replace all commas with comma followed by a newline:



result = re.sub(',s*', ',n', input)


Note that we actually match ,s*, to remove any whitespace which might occur after a comma separator.






share|improve this answer





















  • 1





    Op keeps all the whitespace after the comma, despite what the title implies. +1 regardless

    – Mad Physicist
    Jan 2 at 4:29











  • @MadPhysicist You're right.

    – Tim Biegeleisen
    Jan 2 at 4:35











  • Not that OP wants this (after clarification), but you can replace with ` '\0n'` to keep the spaces. I haven't tested, but \0 might actually have to be \g<0> to work properly.

    – Mad Physicist
    Jan 2 at 4:40











  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • My answer appears to cover your expected output.

    – Tim Biegeleisen
    Jan 2 at 6:41
















6














Try using re.sub, and replace all commas with comma followed by a newline:



result = re.sub(',s*', ',n', input)


Note that we actually match ,s*, to remove any whitespace which might occur after a comma separator.






share|improve this answer





















  • 1





    Op keeps all the whitespace after the comma, despite what the title implies. +1 regardless

    – Mad Physicist
    Jan 2 at 4:29











  • @MadPhysicist You're right.

    – Tim Biegeleisen
    Jan 2 at 4:35











  • Not that OP wants this (after clarification), but you can replace with ` '\0n'` to keep the spaces. I haven't tested, but \0 might actually have to be \g<0> to work properly.

    – Mad Physicist
    Jan 2 at 4:40











  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • My answer appears to cover your expected output.

    – Tim Biegeleisen
    Jan 2 at 6:41














6












6








6







Try using re.sub, and replace all commas with comma followed by a newline:



result = re.sub(',s*', ',n', input)


Note that we actually match ,s*, to remove any whitespace which might occur after a comma separator.






share|improve this answer















Try using re.sub, and replace all commas with comma followed by a newline:



result = re.sub(',s*', ',n', input)


Note that we actually match ,s*, to remove any whitespace which might occur after a comma separator.







share|improve this answer














share|improve this answer



share|improve this answer








edited Jan 2 at 5:03

























answered Jan 2 at 4:18









Tim BiegeleisenTim Biegeleisen

230k1395147




230k1395147








  • 1





    Op keeps all the whitespace after the comma, despite what the title implies. +1 regardless

    – Mad Physicist
    Jan 2 at 4:29











  • @MadPhysicist You're right.

    – Tim Biegeleisen
    Jan 2 at 4:35











  • Not that OP wants this (after clarification), but you can replace with ` '\0n'` to keep the spaces. I haven't tested, but \0 might actually have to be \g<0> to work properly.

    – Mad Physicist
    Jan 2 at 4:40











  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • My answer appears to cover your expected output.

    – Tim Biegeleisen
    Jan 2 at 6:41














  • 1





    Op keeps all the whitespace after the comma, despite what the title implies. +1 regardless

    – Mad Physicist
    Jan 2 at 4:29











  • @MadPhysicist You're right.

    – Tim Biegeleisen
    Jan 2 at 4:35











  • Not that OP wants this (after clarification), but you can replace with ` '\0n'` to keep the spaces. I haven't tested, but \0 might actually have to be \g<0> to work properly.

    – Mad Physicist
    Jan 2 at 4:40











  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • My answer appears to cover your expected output.

    – Tim Biegeleisen
    Jan 2 at 6:41








1




1





Op keeps all the whitespace after the comma, despite what the title implies. +1 regardless

– Mad Physicist
Jan 2 at 4:29





Op keeps all the whitespace after the comma, despite what the title implies. +1 regardless

– Mad Physicist
Jan 2 at 4:29













@MadPhysicist You're right.

– Tim Biegeleisen
Jan 2 at 4:35





@MadPhysicist You're right.

– Tim Biegeleisen
Jan 2 at 4:35













Not that OP wants this (after clarification), but you can replace with ` '\0n'` to keep the spaces. I haven't tested, but \0 might actually have to be \g<0> to work properly.

– Mad Physicist
Jan 2 at 4:40





Not that OP wants this (after clarification), but you can replace with ` '\0n'` to keep the spaces. I haven't tested, but \0 might actually have to be \g<0> to work properly.

– Mad Physicist
Jan 2 at 4:40













Apologies, i have just edited my required output..

– asimo
Jan 2 at 6:34





Apologies, i have just edited my required output..

– asimo
Jan 2 at 6:34













My answer appears to cover your expected output.

– Tim Biegeleisen
Jan 2 at 6:41





My answer appears to cover your expected output.

– Tim Biegeleisen
Jan 2 at 6:41













2














Assuming that "textpad" means text file, you have a couple of options. For a small file like the one shown, the easiest solution would be to read in the entire file as a string, and replace the commas with a comma + newline, as @TimBiegeleisen's answer shows.



For larger files, this may not be a good option due to memory constraints. In that case, and for the sake of generality, I like to iterate over the lines of a file. Here is a fairly simple generator that behaves like a normal file iterator, but also splits on commas:



from itertools import zip_longest, repeat
import re

def spliterator(file):
for line in file:
segments = re.split(r',s*', line)
ends = repeat(',n', len(segments) - 1)
for item in zip_longest(segments, ends, fillvalue=''):
yield ''.join(item)


It would be pretty simple to make this accept the split pattern as an argument, optionally keep the trailing spaces, and return the whole line with newline characters inserted.



Using the generator is simple, since it just wraps a normal file object or any other iterable of lines:



with open('textpad.txt') as file:
print(''.join(spliterator(file)))


Here is an IDEOne link with a demo.



To get the contents of the whole file as though read in by readlines, just wrap in list:



lines = list(spliterator(file))


To write back to an open output file, use writelines directly:



output.writelines(spliterator(file))





share|improve this answer


























  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • @Asimo. Please don't change your question after you've received valid answers. Instead, select an answer and ask another question if you have to.

    – Mad Physicist
    Jan 2 at 6:38











  • Let me revert back..Sorry for the hassle.. I have anways found a workaround to get the output in my desired format using your answer.. simply adding with open(r'H:Messengertest_Nov2.txt') as file: lines = ''.join(spliterator(file)) lines2 = lines.splitlines()

    – asimo
    Jan 2 at 6:39











  • @Asimo. The change you made is something you should be able to figure out in your own, or at least attempt, given the answers posted here.

    – Mad Physicist
    Jan 2 at 6:39











  • @asimo. Why not just list(spliterator(file))? No need for the extra hoops. Or you could just use the generator directly. I'm guessing you don't actually need the list.

    – Mad Physicist
    Jan 2 at 6:41
















2














Assuming that "textpad" means text file, you have a couple of options. For a small file like the one shown, the easiest solution would be to read in the entire file as a string, and replace the commas with a comma + newline, as @TimBiegeleisen's answer shows.



For larger files, this may not be a good option due to memory constraints. In that case, and for the sake of generality, I like to iterate over the lines of a file. Here is a fairly simple generator that behaves like a normal file iterator, but also splits on commas:



from itertools import zip_longest, repeat
import re

def spliterator(file):
for line in file:
segments = re.split(r',s*', line)
ends = repeat(',n', len(segments) - 1)
for item in zip_longest(segments, ends, fillvalue=''):
yield ''.join(item)


It would be pretty simple to make this accept the split pattern as an argument, optionally keep the trailing spaces, and return the whole line with newline characters inserted.



Using the generator is simple, since it just wraps a normal file object or any other iterable of lines:



with open('textpad.txt') as file:
print(''.join(spliterator(file)))


Here is an IDEOne link with a demo.



To get the contents of the whole file as though read in by readlines, just wrap in list:



lines = list(spliterator(file))


To write back to an open output file, use writelines directly:



output.writelines(spliterator(file))





share|improve this answer


























  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • @Asimo. Please don't change your question after you've received valid answers. Instead, select an answer and ask another question if you have to.

    – Mad Physicist
    Jan 2 at 6:38











  • Let me revert back..Sorry for the hassle.. I have anways found a workaround to get the output in my desired format using your answer.. simply adding with open(r'H:Messengertest_Nov2.txt') as file: lines = ''.join(spliterator(file)) lines2 = lines.splitlines()

    – asimo
    Jan 2 at 6:39











  • @Asimo. The change you made is something you should be able to figure out in your own, or at least attempt, given the answers posted here.

    – Mad Physicist
    Jan 2 at 6:39











  • @asimo. Why not just list(spliterator(file))? No need for the extra hoops. Or you could just use the generator directly. I'm guessing you don't actually need the list.

    – Mad Physicist
    Jan 2 at 6:41














2












2








2







Assuming that "textpad" means text file, you have a couple of options. For a small file like the one shown, the easiest solution would be to read in the entire file as a string, and replace the commas with a comma + newline, as @TimBiegeleisen's answer shows.



For larger files, this may not be a good option due to memory constraints. In that case, and for the sake of generality, I like to iterate over the lines of a file. Here is a fairly simple generator that behaves like a normal file iterator, but also splits on commas:



from itertools import zip_longest, repeat
import re

def spliterator(file):
for line in file:
segments = re.split(r',s*', line)
ends = repeat(',n', len(segments) - 1)
for item in zip_longest(segments, ends, fillvalue=''):
yield ''.join(item)


It would be pretty simple to make this accept the split pattern as an argument, optionally keep the trailing spaces, and return the whole line with newline characters inserted.



Using the generator is simple, since it just wraps a normal file object or any other iterable of lines:



with open('textpad.txt') as file:
print(''.join(spliterator(file)))


Here is an IDEOne link with a demo.



To get the contents of the whole file as though read in by readlines, just wrap in list:



lines = list(spliterator(file))


To write back to an open output file, use writelines directly:



output.writelines(spliterator(file))





share|improve this answer















Assuming that "textpad" means text file, you have a couple of options. For a small file like the one shown, the easiest solution would be to read in the entire file as a string, and replace the commas with a comma + newline, as @TimBiegeleisen's answer shows.



For larger files, this may not be a good option due to memory constraints. In that case, and for the sake of generality, I like to iterate over the lines of a file. Here is a fairly simple generator that behaves like a normal file iterator, but also splits on commas:



from itertools import zip_longest, repeat
import re

def spliterator(file):
for line in file:
segments = re.split(r',s*', line)
ends = repeat(',n', len(segments) - 1)
for item in zip_longest(segments, ends, fillvalue=''):
yield ''.join(item)


It would be pretty simple to make this accept the split pattern as an argument, optionally keep the trailing spaces, and return the whole line with newline characters inserted.



Using the generator is simple, since it just wraps a normal file object or any other iterable of lines:



with open('textpad.txt') as file:
print(''.join(spliterator(file)))


Here is an IDEOne link with a demo.



To get the contents of the whole file as though read in by readlines, just wrap in list:



lines = list(spliterator(file))


To write back to an open output file, use writelines directly:



output.writelines(spliterator(file))






share|improve this answer














share|improve this answer



share|improve this answer








edited Jan 2 at 6:47

























answered Jan 2 at 4:50









Mad PhysicistMad Physicist

38k1674108




38k1674108













  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • @Asimo. Please don't change your question after you've received valid answers. Instead, select an answer and ask another question if you have to.

    – Mad Physicist
    Jan 2 at 6:38











  • Let me revert back..Sorry for the hassle.. I have anways found a workaround to get the output in my desired format using your answer.. simply adding with open(r'H:Messengertest_Nov2.txt') as file: lines = ''.join(spliterator(file)) lines2 = lines.splitlines()

    – asimo
    Jan 2 at 6:39











  • @Asimo. The change you made is something you should be able to figure out in your own, or at least attempt, given the answers posted here.

    – Mad Physicist
    Jan 2 at 6:39











  • @asimo. Why not just list(spliterator(file))? No need for the extra hoops. Or you could just use the generator directly. I'm guessing you don't actually need the list.

    – Mad Physicist
    Jan 2 at 6:41



















  • Apologies, i have just edited my required output..

    – asimo
    Jan 2 at 6:34











  • @Asimo. Please don't change your question after you've received valid answers. Instead, select an answer and ask another question if you have to.

    – Mad Physicist
    Jan 2 at 6:38











  • Let me revert back..Sorry for the hassle.. I have anways found a workaround to get the output in my desired format using your answer.. simply adding with open(r'H:Messengertest_Nov2.txt') as file: lines = ''.join(spliterator(file)) lines2 = lines.splitlines()

    – asimo
    Jan 2 at 6:39











  • @Asimo. The change you made is something you should be able to figure out in your own, or at least attempt, given the answers posted here.

    – Mad Physicist
    Jan 2 at 6:39











  • @asimo. Why not just list(spliterator(file))? No need for the extra hoops. Or you could just use the generator directly. I'm guessing you don't actually need the list.

    – Mad Physicist
    Jan 2 at 6:41

















Apologies, i have just edited my required output..

– asimo
Jan 2 at 6:34





Apologies, i have just edited my required output..

– asimo
Jan 2 at 6:34













@Asimo. Please don't change your question after you've received valid answers. Instead, select an answer and ask another question if you have to.

– Mad Physicist
Jan 2 at 6:38





@Asimo. Please don't change your question after you've received valid answers. Instead, select an answer and ask another question if you have to.

– Mad Physicist
Jan 2 at 6:38













Let me revert back..Sorry for the hassle.. I have anways found a workaround to get the output in my desired format using your answer.. simply adding with open(r'H:Messengertest_Nov2.txt') as file: lines = ''.join(spliterator(file)) lines2 = lines.splitlines()

– asimo
Jan 2 at 6:39





Let me revert back..Sorry for the hassle.. I have anways found a workaround to get the output in my desired format using your answer.. simply adding with open(r'H:Messengertest_Nov2.txt') as file: lines = ''.join(spliterator(file)) lines2 = lines.splitlines()

– asimo
Jan 2 at 6:39













@Asimo. The change you made is something you should be able to figure out in your own, or at least attempt, given the answers posted here.

– Mad Physicist
Jan 2 at 6:39





@Asimo. The change you made is something you should be able to figure out in your own, or at least attempt, given the answers posted here.

– Mad Physicist
Jan 2 at 6:39













@asimo. Why not just list(spliterator(file))? No need for the extra hoops. Or you could just use the generator directly. I'm guessing you don't actually need the list.

– Mad Physicist
Jan 2 at 6:41





@asimo. Why not just list(spliterator(file))? No need for the extra hoops. Or you could just use the generator directly. I'm guessing you don't actually need the list.

– Mad Physicist
Jan 2 at 6:41


















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