How to deserialize XML starting from child element by using XStream












1















I have an XML document that contains data like the following:



<Properties>

    ...

    <util>

        <parameters>

            <parameter name="a">

               <externalProvider code="02">

                  <attribute key="B" value="BB"/>

                  <attribute key="CC" value="AA"/>

               </externalProvider>

            </parameter>

            <parameter name="B">

                <externalProvider code="02">

                    <attribute key="paramName" value="AVV"/>

                    <attribute key="applicationName" value="DD"/>

                </externalProvider>

            </parameter>

        </parameters>

    </util>        

    <security>

        <permissions>

            <parameter name="c">

               <externalProvider code="02">

                  <attribute key="zz" value="cc"/>

                  <attribute key="dd" value="ddw"/>

               </externalProvider>

            </parameter>

            <parameter name="q">

                <externalProvider code="02">

                    <attribute key="paramName" value="as"/>

                    <attribute key="saw" value="dd"/>

                </externalProvider>

            </parameter>

        </permissions>

    </security>

    ...

</Properties>


I need to deserialize the XML above in order to take the elements that are in the 'permission' tag.



My probem is that inside '...' there are 6 xml tags that i do not want to define as Java class and so i do not want to define all the hiearchy.



I need to use XStream to deserialize the object.



Can someone tell me how to do it?



Thanks






unmarshalling pojo xstream







share|improve this question

























  • Sorry, wrong title. Deserialize XML

    – Luigi
    Jan 3 at 11:32
















1















I have an XML document that contains data like the following:



<Properties>

    ...

    <util>

        <parameters>

            <parameter name="a">

               <externalProvider code="02">

                  <attribute key="B" value="BB"/>

                  <attribute key="CC" value="AA"/>

               </externalProvider>

            </parameter>

            <parameter name="B">

                <externalProvider code="02">

                    <attribute key="paramName" value="AVV"/>

                    <attribute key="applicationName" value="DD"/>

                </externalProvider>

            </parameter>

        </parameters>

    </util>        

    <security>

        <permissions>

            <parameter name="c">

               <externalProvider code="02">

                  <attribute key="zz" value="cc"/>

                  <attribute key="dd" value="ddw"/>

               </externalProvider>

            </parameter>

            <parameter name="q">

                <externalProvider code="02">

                    <attribute key="paramName" value="as"/>

                    <attribute key="saw" value="dd"/>

                </externalProvider>

            </parameter>

        </permissions>

    </security>

    ...

</Properties>


I need to deserialize the XML above in order to take the elements that are in the 'permission' tag.



My probem is that inside '...' there are 6 xml tags that i do not want to define as Java class and so i do not want to define all the hiearchy.



I need to use XStream to deserialize the object.



Can someone tell me how to do it?



Thanks






unmarshalling pojo xstream







share|improve this question

























  • Sorry, wrong title. Deserialize XML

    – Luigi
    Jan 3 at 11:32














1












1








1








I have an XML document that contains data like the following:



<Properties>

    ...

    <util>

        <parameters>

            <parameter name="a">

               <externalProvider code="02">

                  <attribute key="B" value="BB"/>

                  <attribute key="CC" value="AA"/>

               </externalProvider>

            </parameter>

            <parameter name="B">

                <externalProvider code="02">

                    <attribute key="paramName" value="AVV"/>

                    <attribute key="applicationName" value="DD"/>

                </externalProvider>

            </parameter>

        </parameters>

    </util>        

    <security>

        <permissions>

            <parameter name="c">

               <externalProvider code="02">

                  <attribute key="zz" value="cc"/>

                  <attribute key="dd" value="ddw"/>

               </externalProvider>

            </parameter>

            <parameter name="q">

                <externalProvider code="02">

                    <attribute key="paramName" value="as"/>

                    <attribute key="saw" value="dd"/>

                </externalProvider>

            </parameter>

        </permissions>

    </security>

    ...

</Properties>


I need to deserialize the XML above in order to take the elements that are in the 'permission' tag.



My probem is that inside '...' there are 6 xml tags that i do not want to define as Java class and so i do not want to define all the hiearchy.



I need to use XStream to deserialize the object.



Can someone tell me how to do it?



Thanks






unmarshalling pojo xstream







share|improve this question
















I have an XML document that contains data like the following:



<Properties>

    ...

    <util>

        <parameters>

            <parameter name="a">

               <externalProvider code="02">

                  <attribute key="B" value="BB"/>

                  <attribute key="CC" value="AA"/>

               </externalProvider>

            </parameter>

            <parameter name="B">

                <externalProvider code="02">

                    <attribute key="paramName" value="AVV"/>

                    <attribute key="applicationName" value="DD"/>

                </externalProvider>

            </parameter>

        </parameters>

    </util>        

    <security>

        <permissions>

            <parameter name="c">

               <externalProvider code="02">

                  <attribute key="zz" value="cc"/>

                  <attribute key="dd" value="ddw"/>

               </externalProvider>

            </parameter>

            <parameter name="q">

                <externalProvider code="02">

                    <attribute key="paramName" value="as"/>

                    <attribute key="saw" value="dd"/>

                </externalProvider>

            </parameter>

        </permissions>

    </security>

    ...

</Properties>


I need to deserialize the XML above in order to take the elements that are in the 'permission' tag.



My probem is that inside '...' there are 6 xml tags that i do not want to define as Java class and so i do not want to define all the hiearchy.



I need to use XStream to deserialize the object.



Can someone tell me how to do it?



Thanks






unmarshalling pojo xstream




unmarshalling pojo xstream






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jan 3 at 13:02







Luigi

















asked Jan 3 at 11:26









LuigiLuigi

63




63













  • Sorry, wrong title. Deserialize XML

    – Luigi
    Jan 3 at 11:32



















  • Sorry, wrong title. Deserialize XML

    – Luigi
    Jan 3 at 11:32

















Sorry, wrong title. Deserialize XML

– Luigi
Jan 3 at 11:32





Sorry, wrong title. Deserialize XML

– Luigi
Jan 3 at 11:32












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