is it possible to pass a function with 2 parameters as parameter for another function in java 8/11?
I have this problem.
I am working with some generics and at one point I will need a specific converted depending on each type.
So, so far I have this:
public static <T> List<T> myMethod(List<T> list1, List2<T>, SomeFunction converter) {
//... do suff
return converter.convert(list1, list2);
}
and converter would be like this:
public <T> List<T> converter(List<T> list1, List<T> list2) {
/// cast and do stuff)
return List<T> some stuff;
}
Then I would like to make a call like
myMethod<list1,list2,converter);
I know about the functional internface Function but I need to send two parameters for this, is there any way I could do it in Java8/11?
Ideas?
java generics java-8 functional-interface
edited Dec 31 '18 at 14:48
Aomine
42.1k74172
asked Dec 31 '18 at 13:52
jpganz18jpganz18
1,708103168
add a comment |
I have this problem.
I am working with some generics and at one point I will need a specific converted depending on each type.
So, so far I have this:
public static <T> List<T> myMethod(List<T> list1, List2<T>, SomeFunction converter) {
//... do suff
return converter.convert(list1, list2);
}
and converter would be like this:
public <T> List<T> converter(List<T> list1, List<T> list2) {
/// cast and do stuff)
return List<T> some stuff;
}
Then I would like to make a call like
myMethod<list1,list2,converter);
I know about the functional internface Function but I need to send two parameters for this, is there any way I could do it in Java8/11?
Ideas?
java generics java-8 functional-interface
edited Dec 31 '18 at 14:48
Aomine
42.1k74172
asked Dec 31 '18 at 13:52
jpganz18jpganz18
1,708103168
4
Instead of Function<T,R> you could use BiFunction<T,U,R>
– bhspencer
Dec 31 '18 at 13:54
could you pleae give me an example? sorry about it but Im not good using this interface
– jpganz18
Dec 31 '18 at 13:58
add a comment |
I have this problem.
I am working with some generics and at one point I will need a specific converted depending on each type.
So, so far I have this:
public static <T> List<T> myMethod(List<T> list1, List2<T>, SomeFunction converter) {
//... do suff
return converter.convert(list1, list2);
}
and converter would be like this:
public <T> List<T> converter(List<T> list1, List<T> list2) {
/// cast and do stuff)
return List<T> some stuff;
}
Then I would like to make a call like
myMethod<list1,list2,converter);
I know about the functional internface Function but I need to send two parameters for this, is there any way I could do it in Java8/11?
Ideas?
java generics java-8 functional-interface
edited Dec 31 '18 at 14:48
Aomine
42.1k74172
asked Dec 31 '18 at 13:52
jpganz18jpganz18
1,708103168
I have this problem.
I am working with some generics and at one point I will need a specific converted depending on each type.
So, so far I have this:
public static <T> List<T> myMethod(List<T> list1, List2<T>, SomeFunction converter) {
//... do suff
return converter.convert(list1, list2);
}
and converter would be like this:
public <T> List<T> converter(List<T> list1, List<T> list2) {
/// cast and do stuff)
return List<T> some stuff;
}
Then I would like to make a call like
myMethod<list1,list2,converter);
I know about the functional internface Function but I need to send two parameters for this, is there any way I could do it in Java8/11?
Ideas?
java generics java-8 functional-interface
java generics java-8 functional-interface
edited Dec 31 '18 at 14:48
Aomine
42.1k74172
asked Dec 31 '18 at 13:52
jpganz18jpganz18
1,708103168
edited Dec 31 '18 at 14:48
Aomine
42.1k74172
asked Dec 31 '18 at 13:52
jpganz18jpganz18
1,708103168
edited Dec 31 '18 at 14:48
Aomine
42.1k74172
edited Dec 31 '18 at 14:48
Aomine
42.1k74172
edited Dec 31 '18 at 14:48
Aomine
42.1k74172
42.1k74172
asked Dec 31 '18 at 13:52
jpganz18jpganz18
1,708103168
asked Dec 31 '18 at 13:52
jpganz18jpganz18
1,708103168
asked Dec 31 '18 at 13:52
jpganz18jpganz18
1,708103168
1,708103168
4
Instead of Function<T,R> you could use BiFunction<T,U,R>
– bhspencer
Dec 31 '18 at 13:54
could you pleae give me an example? sorry about it but Im not good using this interface
– jpganz18
Dec 31 '18 at 13:58
add a comment |
4
Instead of Function<T,R> you could use BiFunction<T,U,R>
– bhspencer
Dec 31 '18 at 13:54
could you pleae give me an example? sorry about it but Im not good using this interface
– jpganz18
Dec 31 '18 at 13:58
4
4
Instead of Function<T,R> you could use BiFunction<T,U,R>
– bhspencer
Dec 31 '18 at 13:54
Instead of Function<T,R> you could use BiFunction<T,U,R>
– bhspencer
Dec 31 '18 at 13:54
could you pleae give me an example? sorry about it but Im not good using this interface
– jpganz18
Dec 31 '18 at 13:58
could you pleae give me an example? sorry about it but Im not good using this interface
– jpganz18
Dec 31 '18 at 13:58
add a comment |
2 Answers
2
active
oldest
votes
Look into BinaryOperator which represents an operation upon two operands of the same type, producing a result of the same type as the operands.
public static <T> List<T> someMethodName(List<T> list1, List<T> list2,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
BiFunction is also another option as it represents a function that accepts two arguments and produces a result.
public static <T, R> List<R> someMethodName(List<T> list1, List<T> list2,
BiFunction<List<T>, List<T>, List<R>> converter) {
return converter.apply(list1, list2);
}
To call the function let's assume you have two Integer lists for example sakes:
List<Integer> first = ....
List<Integer> second = ....
and you wanted to concatenate them, you'd pass both lists and a behaviour e.g.
List<Integer> concat = someMethodName(first, second,
(l, r) -> Stream.concat(l.stream(), r.stream())
.collect(Collectors.toList()));
answered Dec 31 '18 at 13:54
AomineAomine
42.1k74172
3
Convention would dictate to have the result type be calledR, so<R> List<R> (List<T> list1, List<T>, BiFunction<List<T>,List<T>, List<R>> converter)which would also add flexibility.
– daniu
Dec 31 '18 at 14:05
4
@daniu Very good point (I never bear that in mind) - although type parameters would have to be declared as<T, R>
– ernest_k
Dec 31 '18 at 14:09
@daniu indeed, edited to accommodate. thanks.
– Aomine
Dec 31 '18 at 14:12
could you please give me an example of how the function to override the converter.apply would look like? I am a little bit lost :s
– jpganz18
Dec 31 '18 at 14:16
1
@jpganz18 for this specific question, I believe it solves the problem at hand, but feel free to post a new question if you're struggling with something you're working on. provided you've made an attempt along with a good description I am sure people on the site would be happy to help. good luck.
– Aomine
Dec 31 '18 at 14:36
|
show 6 more comments
You can make your function take a java.util.function.BinaryOperator<T>, which is a function that takes two parameters of the same type and returns a result of that same type:
public static <T> List<T> (List<T> list1, List<T>,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
answered Dec 31 '18 at 13:55
ernest_kernest_k
22k42446
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Look into BinaryOperator which represents an operation upon two operands of the same type, producing a result of the same type as the operands.
public static <T> List<T> someMethodName(List<T> list1, List<T> list2,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
BiFunction is also another option as it represents a function that accepts two arguments and produces a result.
public static <T, R> List<R> someMethodName(List<T> list1, List<T> list2,
BiFunction<List<T>, List<T>, List<R>> converter) {
return converter.apply(list1, list2);
}
To call the function let's assume you have two Integer lists for example sakes:
List<Integer> first = ....
List<Integer> second = ....
and you wanted to concatenate them, you'd pass both lists and a behaviour e.g.
List<Integer> concat = someMethodName(first, second,
(l, r) -> Stream.concat(l.stream(), r.stream())
.collect(Collectors.toList()));
answered Dec 31 '18 at 13:54
AomineAomine
42.1k74172
3
Convention would dictate to have the result type be calledR, so<R> List<R> (List<T> list1, List<T>, BiFunction<List<T>,List<T>, List<R>> converter)which would also add flexibility.
– daniu
Dec 31 '18 at 14:05
4
@daniu Very good point (I never bear that in mind) - although type parameters would have to be declared as<T, R>
– ernest_k
Dec 31 '18 at 14:09
@daniu indeed, edited to accommodate. thanks.
– Aomine
Dec 31 '18 at 14:12
could you please give me an example of how the function to override the converter.apply would look like? I am a little bit lost :s
– jpganz18
Dec 31 '18 at 14:16
1
@jpganz18 for this specific question, I believe it solves the problem at hand, but feel free to post a new question if you're struggling with something you're working on. provided you've made an attempt along with a good description I am sure people on the site would be happy to help. good luck.
– Aomine
Dec 31 '18 at 14:36
|
show 6 more comments
Look into BinaryOperator which represents an operation upon two operands of the same type, producing a result of the same type as the operands.
public static <T> List<T> someMethodName(List<T> list1, List<T> list2,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
BiFunction is also another option as it represents a function that accepts two arguments and produces a result.
public static <T, R> List<R> someMethodName(List<T> list1, List<T> list2,
BiFunction<List<T>, List<T>, List<R>> converter) {
return converter.apply(list1, list2);
}
To call the function let's assume you have two Integer lists for example sakes:
List<Integer> first = ....
List<Integer> second = ....
and you wanted to concatenate them, you'd pass both lists and a behaviour e.g.
List<Integer> concat = someMethodName(first, second,
(l, r) -> Stream.concat(l.stream(), r.stream())
.collect(Collectors.toList()));
answered Dec 31 '18 at 13:54
AomineAomine
42.1k74172
3
Convention would dictate to have the result type be calledR, so<R> List<R> (List<T> list1, List<T>, BiFunction<List<T>,List<T>, List<R>> converter)which would also add flexibility.
– daniu
Dec 31 '18 at 14:05
4
@daniu Very good point (I never bear that in mind) - although type parameters would have to be declared as<T, R>
– ernest_k
Dec 31 '18 at 14:09
@daniu indeed, edited to accommodate. thanks.
– Aomine
Dec 31 '18 at 14:12
could you please give me an example of how the function to override the converter.apply would look like? I am a little bit lost :s
– jpganz18
Dec 31 '18 at 14:16
1
@jpganz18 for this specific question, I believe it solves the problem at hand, but feel free to post a new question if you're struggling with something you're working on. provided you've made an attempt along with a good description I am sure people on the site would be happy to help. good luck.
– Aomine
Dec 31 '18 at 14:36
|
show 6 more comments
Look into BinaryOperator which represents an operation upon two operands of the same type, producing a result of the same type as the operands.
public static <T> List<T> someMethodName(List<T> list1, List<T> list2,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
BiFunction is also another option as it represents a function that accepts two arguments and produces a result.
public static <T, R> List<R> someMethodName(List<T> list1, List<T> list2,
BiFunction<List<T>, List<T>, List<R>> converter) {
return converter.apply(list1, list2);
}
To call the function let's assume you have two Integer lists for example sakes:
List<Integer> first = ....
List<Integer> second = ....
and you wanted to concatenate them, you'd pass both lists and a behaviour e.g.
List<Integer> concat = someMethodName(first, second,
(l, r) -> Stream.concat(l.stream(), r.stream())
.collect(Collectors.toList()));
answered Dec 31 '18 at 13:54
AomineAomine
42.1k74172
Look into BinaryOperator which represents an operation upon two operands of the same type, producing a result of the same type as the operands.
public static <T> List<T> someMethodName(List<T> list1, List<T> list2,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
BiFunction is also another option as it represents a function that accepts two arguments and produces a result.
public static <T, R> List<R> someMethodName(List<T> list1, List<T> list2,
BiFunction<List<T>, List<T>, List<R>> converter) {
return converter.apply(list1, list2);
}
To call the function let's assume you have two Integer lists for example sakes:
List<Integer> first = ....
List<Integer> second = ....
and you wanted to concatenate them, you'd pass both lists and a behaviour e.g.
List<Integer> concat = someMethodName(first, second,
(l, r) -> Stream.concat(l.stream(), r.stream())
.collect(Collectors.toList()));
answered Dec 31 '18 at 13:54
AomineAomine
42.1k74172
edited Dec 31 '18 at 14:21
answered Dec 31 '18 at 13:54
AomineAomine
42.1k74172
answered Dec 31 '18 at 13:54
AomineAomine
42.1k74172
answered Dec 31 '18 at 13:54
AomineAomine
42.1k74172
42.1k74172
3
Convention would dictate to have the result type be calledR, so<R> List<R> (List<T> list1, List<T>, BiFunction<List<T>,List<T>, List<R>> converter)which would also add flexibility.
– daniu
Dec 31 '18 at 14:05
4
@daniu Very good point (I never bear that in mind) - although type parameters would have to be declared as<T, R>
– ernest_k
Dec 31 '18 at 14:09
@daniu indeed, edited to accommodate. thanks.
– Aomine
Dec 31 '18 at 14:12
could you please give me an example of how the function to override the converter.apply would look like? I am a little bit lost :s
– jpganz18
Dec 31 '18 at 14:16
1
@jpganz18 for this specific question, I believe it solves the problem at hand, but feel free to post a new question if you're struggling with something you're working on. provided you've made an attempt along with a good description I am sure people on the site would be happy to help. good luck.
– Aomine
Dec 31 '18 at 14:36
|
show 6 more comments
3
Convention would dictate to have the result type be calledR, so<R> List<R> (List<T> list1, List<T>, BiFunction<List<T>,List<T>, List<R>> converter)which would also add flexibility.
– daniu
Dec 31 '18 at 14:05
4
@daniu Very good point (I never bear that in mind) - although type parameters would have to be declared as<T, R>
– ernest_k
Dec 31 '18 at 14:09
@daniu indeed, edited to accommodate. thanks.
– Aomine
Dec 31 '18 at 14:12
could you please give me an example of how the function to override the converter.apply would look like? I am a little bit lost :s
– jpganz18
Dec 31 '18 at 14:16
1
@jpganz18 for this specific question, I believe it solves the problem at hand, but feel free to post a new question if you're struggling with something you're working on. provided you've made an attempt along with a good description I am sure people on the site would be happy to help. good luck.
– Aomine
Dec 31 '18 at 14:36
3
3
Convention would dictate to have the result type be called
R, so <R> List<R> (List<T> list1, List<T>, BiFunction<List<T>,List<T>, List<R>> converter) which would also add flexibility.– daniu
Dec 31 '18 at 14:05
Convention would dictate to have the result type be called
R, so <R> List<R> (List<T> list1, List<T>, BiFunction<List<T>,List<T>, List<R>> converter) which would also add flexibility.– daniu
Dec 31 '18 at 14:05
4
4
@daniu Very good point (I never bear that in mind) - although type parameters would have to be declared as
<T, R>– ernest_k
Dec 31 '18 at 14:09
@daniu Very good point (I never bear that in mind) - although type parameters would have to be declared as
<T, R>– ernest_k
Dec 31 '18 at 14:09
@daniu indeed, edited to accommodate. thanks.
– Aomine
Dec 31 '18 at 14:12
@daniu indeed, edited to accommodate. thanks.
– Aomine
Dec 31 '18 at 14:12
could you please give me an example of how the function to override the converter.apply would look like? I am a little bit lost :s
– jpganz18
Dec 31 '18 at 14:16
could you please give me an example of how the function to override the converter.apply would look like? I am a little bit lost :s
– jpganz18
Dec 31 '18 at 14:16
1
1
@jpganz18 for this specific question, I believe it solves the problem at hand, but feel free to post a new question if you're struggling with something you're working on. provided you've made an attempt along with a good description I am sure people on the site would be happy to help. good luck.
– Aomine
Dec 31 '18 at 14:36
@jpganz18 for this specific question, I believe it solves the problem at hand, but feel free to post a new question if you're struggling with something you're working on. provided you've made an attempt along with a good description I am sure people on the site would be happy to help. good luck.
– Aomine
Dec 31 '18 at 14:36
|
show 6 more comments
You can make your function take a java.util.function.BinaryOperator<T>, which is a function that takes two parameters of the same type and returns a result of that same type:
public static <T> List<T> (List<T> list1, List<T>,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
answered Dec 31 '18 at 13:55
ernest_kernest_k
22k42446
add a comment |
You can make your function take a java.util.function.BinaryOperator<T>, which is a function that takes two parameters of the same type and returns a result of that same type:
public static <T> List<T> (List<T> list1, List<T>,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
answered Dec 31 '18 at 13:55
ernest_kernest_k
22k42446
add a comment |
You can make your function take a java.util.function.BinaryOperator<T>, which is a function that takes two parameters of the same type and returns a result of that same type:
public static <T> List<T> (List<T> list1, List<T>,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
answered Dec 31 '18 at 13:55
ernest_kernest_k
22k42446
You can make your function take a java.util.function.BinaryOperator<T>, which is a function that takes two parameters of the same type and returns a result of that same type:
public static <T> List<T> (List<T> list1, List<T>,
BinaryOperator<List<T>> converter) {
return converter.apply(list1, list2);
}
answered Dec 31 '18 at 13:55
ernest_kernest_k
22k42446
answered Dec 31 '18 at 13:55
ernest_kernest_k
22k42446
answered Dec 31 '18 at 13:55
ernest_kernest_k
22k42446
answered Dec 31 '18 at 13:55
ernest_kernest_k
22k42446
22k42446
add a comment |
add a comment |
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4
Instead of Function<T,R> you could use BiFunction<T,U,R>
– bhspencer
Dec 31 '18 at 13:54
could you pleae give me an example? sorry about it but Im not good using this interface
– jpganz18
Dec 31 '18 at 13:58