Bokeh BoxPlot > KeyError: 'the label [SomeCategory] is not in the [index]'
I'm attempting to create a BoxPlot using Bokeh. When I get to the section where I need to identify outliers, it fails if a given category has no outliers.
If I remove the "problem" category, the BoxPlot executes properly. it's only when I attempt to create this BoxPlot with a category that has no outliers it fails.
Any instruction on how to remedy this?
The failure occurs at the commented section "Prepare outlier data for plotting [...]"
import numpy as np
import pandas as pd
import datetime
import math
from bokeh.plotting import figure, show, output_file
from bokeh.models import NumeralTickFormatter
# Create time stamps to allow for figure to display span in title
today = datetime.date.today()
delta1 = datetime.timedelta(days=7)
delta2 = datetime.timedelta(days=1)
start = str(today - delta1)
end = str(today - delta2)
#Identify location of prices
itemloc = 'Everywhere'
df = pd.read_excel(r'C:Usersmeprices.xlsx')
# Create a list from the dataframe that identifies distinct categories for the separate box plots
cats = df['subcategory_desc'].unique().tolist()
# Find the quartiles and IQR for each category
groups = df.groupby('subcategory_desc', sort=False)
q1 = groups.quantile(q=0.25)
q2 = groups.quantile(q=0.5)
q3 = groups.quantile(q=0.75)
iqr = q3 - q1
upper = q3 + 1.5*iqr
lower = q1 - 1.5*iqr
# Find the outliers for each category
def outliers(group):
cat = group.name
return group[(group.price > upper.loc[cat][0]) | (group.price < lower.loc[cat][0])]['price']
out = groups.apply(outliers).dropna()
# Prepare outlier data for plotting, we need coordinates for every outlier.
outx =
outy =
for cat in cats:
# only add outliers if they exist
if not out.loc[cat].empty:
for value in out[cat]:
outx.append(cat)
outy.append(value)
I expect that the Box-and-whisker portion of categories with no outliers merely show up without the outlier dots.
python-3.x
asked Dec 31 '18 at 13:43
Kyle CorrieKyle Corrie
12
add a comment |
I'm attempting to create a BoxPlot using Bokeh. When I get to the section where I need to identify outliers, it fails if a given category has no outliers.
If I remove the "problem" category, the BoxPlot executes properly. it's only when I attempt to create this BoxPlot with a category that has no outliers it fails.
Any instruction on how to remedy this?
The failure occurs at the commented section "Prepare outlier data for plotting [...]"
import numpy as np
import pandas as pd
import datetime
import math
from bokeh.plotting import figure, show, output_file
from bokeh.models import NumeralTickFormatter
# Create time stamps to allow for figure to display span in title
today = datetime.date.today()
delta1 = datetime.timedelta(days=7)
delta2 = datetime.timedelta(days=1)
start = str(today - delta1)
end = str(today - delta2)
#Identify location of prices
itemloc = 'Everywhere'
df = pd.read_excel(r'C:Usersmeprices.xlsx')
# Create a list from the dataframe that identifies distinct categories for the separate box plots
cats = df['subcategory_desc'].unique().tolist()
# Find the quartiles and IQR for each category
groups = df.groupby('subcategory_desc', sort=False)
q1 = groups.quantile(q=0.25)
q2 = groups.quantile(q=0.5)
q3 = groups.quantile(q=0.75)
iqr = q3 - q1
upper = q3 + 1.5*iqr
lower = q1 - 1.5*iqr
# Find the outliers for each category
def outliers(group):
cat = group.name
return group[(group.price > upper.loc[cat][0]) | (group.price < lower.loc[cat][0])]['price']
out = groups.apply(outliers).dropna()
# Prepare outlier data for plotting, we need coordinates for every outlier.
outx =
outy =
for cat in cats:
# only add outliers if they exist
if not out.loc[cat].empty:
for value in out[cat]:
outx.append(cat)
outy.append(value)
I expect that the Box-and-whisker portion of categories with no outliers merely show up without the outlier dots.
python-3.x
asked Dec 31 '18 at 13:43
Kyle CorrieKyle Corrie
12
add a comment |
I'm attempting to create a BoxPlot using Bokeh. When I get to the section where I need to identify outliers, it fails if a given category has no outliers.
If I remove the "problem" category, the BoxPlot executes properly. it's only when I attempt to create this BoxPlot with a category that has no outliers it fails.
Any instruction on how to remedy this?
The failure occurs at the commented section "Prepare outlier data for plotting [...]"
import numpy as np
import pandas as pd
import datetime
import math
from bokeh.plotting import figure, show, output_file
from bokeh.models import NumeralTickFormatter
# Create time stamps to allow for figure to display span in title
today = datetime.date.today()
delta1 = datetime.timedelta(days=7)
delta2 = datetime.timedelta(days=1)
start = str(today - delta1)
end = str(today - delta2)
#Identify location of prices
itemloc = 'Everywhere'
df = pd.read_excel(r'C:Usersmeprices.xlsx')
# Create a list from the dataframe that identifies distinct categories for the separate box plots
cats = df['subcategory_desc'].unique().tolist()
# Find the quartiles and IQR for each category
groups = df.groupby('subcategory_desc', sort=False)
q1 = groups.quantile(q=0.25)
q2 = groups.quantile(q=0.5)
q3 = groups.quantile(q=0.75)
iqr = q3 - q1
upper = q3 + 1.5*iqr
lower = q1 - 1.5*iqr
# Find the outliers for each category
def outliers(group):
cat = group.name
return group[(group.price > upper.loc[cat][0]) | (group.price < lower.loc[cat][0])]['price']
out = groups.apply(outliers).dropna()
# Prepare outlier data for plotting, we need coordinates for every outlier.
outx =
outy =
for cat in cats:
# only add outliers if they exist
if not out.loc[cat].empty:
for value in out[cat]:
outx.append(cat)
outy.append(value)
I expect that the Box-and-whisker portion of categories with no outliers merely show up without the outlier dots.
python-3.x
asked Dec 31 '18 at 13:43
Kyle CorrieKyle Corrie
12
I'm attempting to create a BoxPlot using Bokeh. When I get to the section where I need to identify outliers, it fails if a given category has no outliers.
If I remove the "problem" category, the BoxPlot executes properly. it's only when I attempt to create this BoxPlot with a category that has no outliers it fails.
Any instruction on how to remedy this?
The failure occurs at the commented section "Prepare outlier data for plotting [...]"
import numpy as np
import pandas as pd
import datetime
import math
from bokeh.plotting import figure, show, output_file
from bokeh.models import NumeralTickFormatter
# Create time stamps to allow for figure to display span in title
today = datetime.date.today()
delta1 = datetime.timedelta(days=7)
delta2 = datetime.timedelta(days=1)
start = str(today - delta1)
end = str(today - delta2)
#Identify location of prices
itemloc = 'Everywhere'
df = pd.read_excel(r'C:Usersmeprices.xlsx')
# Create a list from the dataframe that identifies distinct categories for the separate box plots
cats = df['subcategory_desc'].unique().tolist()
# Find the quartiles and IQR for each category
groups = df.groupby('subcategory_desc', sort=False)
q1 = groups.quantile(q=0.25)
q2 = groups.quantile(q=0.5)
q3 = groups.quantile(q=0.75)
iqr = q3 - q1
upper = q3 + 1.5*iqr
lower = q1 - 1.5*iqr
# Find the outliers for each category
def outliers(group):
cat = group.name
return group[(group.price > upper.loc[cat][0]) | (group.price < lower.loc[cat][0])]['price']
out = groups.apply(outliers).dropna()
# Prepare outlier data for plotting, we need coordinates for every outlier.
outx =
outy =
for cat in cats:
# only add outliers if they exist
if not out.loc[cat].empty:
for value in out[cat]:
outx.append(cat)
outy.append(value)
I expect that the Box-and-whisker portion of categories with no outliers merely show up without the outlier dots.
python-3.x
python-3.x
asked Dec 31 '18 at 13:43
Kyle CorrieKyle Corrie
12
asked Dec 31 '18 at 13:43
Kyle CorrieKyle Corrie
12
asked Dec 31 '18 at 13:43
Kyle CorrieKyle Corrie
12
asked Dec 31 '18 at 13:43
Kyle CorrieKyle Corrie
12
asked Dec 31 '18 at 13:43
Kyle CorrieKyle Corrie
12
12
add a comment |
add a comment |
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