Uploading both data and files in one form using POST method, AJAX and jQuery (Error)

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I have a problem. formData.append("id_element",1) doesn`t add the field into formData. I have found a lot of solves but in my case it doesn`t work right.

PHP code here:

var_dump($_FILES);

$("#hw-upload_image-form").submit(function(e) {

        e.preventDefault();



        var formData = new FormData(this);

        formData.append("id_element",1); // doesn`t work here

        $.ajax({

            type:"POST",

            processData: false,

            contentType: false,

            cache: false,

            url:$(this).prop('action'),

            data:formData,

            success:function (data) {

                console.log(data); // show returned data from php

            }

        });



});

<form action="action.php"  method="post" enctype="multipart/form-data" id="hw-upload_image-form">

    <input type="file" name="hwImage"> <!-- hw = homework (just for you :) -->

</form>

Result (from the console)

array(1) {

  ["hwImage"]=>

  array(5) {

    ["name"]=>

    string(70) "73b38ef5d1f5849ea800c18990acde94_ce_1920x1200x0x0_cropped_800x427.jpeg"

    ["type"]=>

    string(10) "image/jpeg"

    ["tmp_name"]=>

    string(36) "D:OSPaneluserdatatempphp9F48.tmp"

    ["error"]=>

    int(0)

    ["size"]=>

    int(68411)

  }

}

edited Jan 4 at 15:36

wanttobeprofessional

1,02931323

asked Jan 3 at 21:02

Nekear

Possible duplicate of Uploading both data and files in one form using Ajax?

– ttrasn
Jan 3 at 21:10

You removed (stealth edit) a console.log() line that would actually be quite helpful in debugging. What was the result/output of that line?

– Patrick Q
Jan 3 at 21:10

I removed it, because the output was: ibb.co/KN3bMyC (random site for share images)

– Nekear
Jan 4 at 13:05

add a comment |

I have a problem. formData.append("id_element",1) doesn`t add the field into formData. I have found a lot of solves but in my case it doesn`t work right.

PHP code here:

var_dump($_FILES);

$("#hw-upload_image-form").submit(function(e) {

        e.preventDefault();



        var formData = new FormData(this);

        formData.append("id_element",1); // doesn`t work here

        $.ajax({

            type:"POST",

            processData: false,

            contentType: false,

            cache: false,

            url:$(this).prop('action'),

            data:formData,

            success:function (data) {

                console.log(data); // show returned data from php

            }

        });



});

<form action="action.php"  method="post" enctype="multipart/form-data" id="hw-upload_image-form">

    <input type="file" name="hwImage"> <!-- hw = homework (just for you :) -->

</form>

Result (from the console)

array(1) {

  ["hwImage"]=>

  array(5) {

    ["name"]=>

    string(70) "73b38ef5d1f5849ea800c18990acde94_ce_1920x1200x0x0_cropped_800x427.jpeg"

    ["type"]=>

    string(10) "image/jpeg"

    ["tmp_name"]=>

    string(36) "D:OSPaneluserdatatempphp9F48.tmp"

    ["error"]=>

    int(0)

    ["size"]=>

    int(68411)

  }

}

edited Jan 4 at 15:36

wanttobeprofessional

1,02931323

asked Jan 3 at 21:02

Nekear

Possible duplicate of Uploading both data and files in one form using Ajax?

– ttrasn
Jan 3 at 21:10

You removed (stealth edit) a console.log() line that would actually be quite helpful in debugging. What was the result/output of that line?

– Patrick Q
Jan 3 at 21:10

I removed it, because the output was: ibb.co/KN3bMyC (random site for share images)

– Nekear
Jan 4 at 13:05

add a comment |

I have a problem. formData.append("id_element",1) doesn`t add the field into formData. I have found a lot of solves but in my case it doesn`t work right.

PHP code here:

var_dump($_FILES);

$("#hw-upload_image-form").submit(function(e) {

        e.preventDefault();



        var formData = new FormData(this);

        formData.append("id_element",1); // doesn`t work here

        $.ajax({

            type:"POST",

            processData: false,

            contentType: false,

            cache: false,

            url:$(this).prop('action'),

            data:formData,

            success:function (data) {

                console.log(data); // show returned data from php

            }

        });



});

<form action="action.php"  method="post" enctype="multipart/form-data" id="hw-upload_image-form">

    <input type="file" name="hwImage"> <!-- hw = homework (just for you :) -->

</form>

Result (from the console)

array(1) {

  ["hwImage"]=>

  array(5) {

    ["name"]=>

    string(70) "73b38ef5d1f5849ea800c18990acde94_ce_1920x1200x0x0_cropped_800x427.jpeg"

    ["type"]=>

    string(10) "image/jpeg"

    ["tmp_name"]=>

    string(36) "D:OSPaneluserdatatempphp9F48.tmp"

    ["error"]=>

    int(0)

    ["size"]=>

    int(68411)

  }

}

edited Jan 4 at 15:36

wanttobeprofessional

1,02931323

asked Jan 3 at 21:02

Nekear

I have a problem. formData.append("id_element",1) doesn`t add the field into formData. I have found a lot of solves but in my case it doesn`t work right.

PHP code here:

var_dump($_FILES);

$("#hw-upload_image-form").submit(function(e) {

        e.preventDefault();



        var formData = new FormData(this);

        formData.append("id_element",1); // doesn`t work here

        $.ajax({

            type:"POST",

            processData: false,

            contentType: false,

            cache: false,

            url:$(this).prop('action'),

            data:formData,

            success:function (data) {

                console.log(data); // show returned data from php

            }

        });



});

<form action="action.php"  method="post" enctype="multipart/form-data" id="hw-upload_image-form">

    <input type="file" name="hwImage"> <!-- hw = homework (just for you :) -->

</form>

Result (from the console)

array(1) {

  ["hwImage"]=>

  array(5) {

    ["name"]=>

    string(70) "73b38ef5d1f5849ea800c18990acde94_ce_1920x1200x0x0_cropped_800x427.jpeg"

    ["type"]=>

    string(10) "image/jpeg"

    ["tmp_name"]=>

    string(36) "D:OSPaneluserdatatempphp9F48.tmp"

    ["error"]=>

    int(0)

    ["size"]=>

    int(68411)

  }

}

$("#hw-upload_image-form").submit(function(e) {

        e.preventDefault();



        var formData = new FormData(this);

        formData.append("id_element",1); // doesn`t work here

        $.ajax({

            type:"POST",

            processData: false,

            contentType: false,

            cache: false,

            url:$(this).prop('action'),

            data:formData,

            success:function (data) {

                console.log(data); // show returned data from php

            }

        });



});

<form action="action.php"  method="post" enctype="multipart/form-data" id="hw-upload_image-form">

    <input type="file" name="hwImage"> <!-- hw = homework (just for you :) -->

</form>

$("#hw-upload_image-form").submit(function(e) {

        e.preventDefault();



        var formData = new FormData(this);

        formData.append("id_element",1); // doesn`t work here

        $.ajax({

            type:"POST",

            processData: false,

            contentType: false,

            cache: false,

            url:$(this).prop('action'),

            data:formData,

            success:function (data) {

                console.log(data); // show returned data from php

            }

        });



});

<form action="action.php"  method="post" enctype="multipart/form-data" id="hw-upload_image-form">

    <input type="file" name="hwImage"> <!-- hw = homework (just for you :) -->

</form>

javascript php jquery ajax

edited Jan 4 at 15:36

wanttobeprofessional

1,02931323

asked Jan 3 at 21:02

Nekear

edited Jan 4 at 15:36

wanttobeprofessional

1,02931323

asked Jan 3 at 21:02

Nekear

edited Jan 4 at 15:36

wanttobeprofessional

1,02931323

edited Jan 4 at 15:36

wanttobeprofessional

1,02931323

edited Jan 4 at 15:36

wanttobeprofessional

1,02931323

asked Jan 3 at 21:02

Nekear

asked Jan 3 at 21:02

Nekear

asked Jan 3 at 21:02

Nekear

Possible duplicate of Uploading both data and files in one form using Ajax?

– ttrasn
Jan 3 at 21:10

You removed (stealth edit) a console.log() line that would actually be quite helpful in debugging. What was the result/output of that line?

– Patrick Q
Jan 3 at 21:10

I removed it, because the output was: ibb.co/KN3bMyC (random site for share images)

– Nekear
Jan 4 at 13:05

add a comment |

Possible duplicate of Uploading both data and files in one form using Ajax?

– ttrasn
Jan 3 at 21:10

You removed (stealth edit) a console.log() line that would actually be quite helpful in debugging. What was the result/output of that line?

– Patrick Q
Jan 3 at 21:10

I removed it, because the output was: ibb.co/KN3bMyC (random site for share images)

– Nekear
Jan 4 at 13:05

Possible duplicate of Uploading both data and files in one form using Ajax?

– ttrasn
Jan 3 at 21:10

You removed (stealth edit) a console.log() line that would actually be quite helpful in debugging. What was the result/output of that line?

– Patrick Q
Jan 3 at 21:10

I removed it, because the output was: ibb.co/KN3bMyC (random site for share images)

– Nekear
Jan 4 at 13:05

add a comment |

1 Answer
1

active

oldest

votes

I have already undestood my mistake.

$_FILES will show me only file data, but if I want to see id_element I have to use $_POST.

The result is:

array(1) {

  ["id_element"]=>

  string(1) "1"

}

answered Jan 4 at 13:17

Nekear

add a comment |

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1 Answer
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active

oldest

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1 Answer
1

active

oldest

votes

I have already undestood my mistake.

$_FILES will show me only file data, but if I want to see id_element I have to use $_POST.

The result is:

array(1) {

  ["id_element"]=>

  string(1) "1"

}

answered Jan 4 at 13:17

Nekear

add a comment |

I have already undestood my mistake.

$_FILES will show me only file data, but if I want to see id_element I have to use $_POST.

The result is:

array(1) {

  ["id_element"]=>

  string(1) "1"

}

answered Jan 4 at 13:17

Nekear

add a comment |

I have already undestood my mistake.

$_FILES will show me only file data, but if I want to see id_element I have to use $_POST.

The result is:

array(1) {

  ["id_element"]=>

  string(1) "1"

}

answered Jan 4 at 13:17

Nekear

I have already undestood my mistake.

$_FILES will show me only file data, but if I want to see id_element I have to use $_POST.

The result is:

array(1) {

  ["id_element"]=>

  string(1) "1"

}

answered Jan 4 at 13:17

Nekear

answered Jan 4 at 13:17

Nekear

answered Jan 4 at 13:17

Nekear

answered Jan 4 at 13:17

Nekear

add a comment |

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