How to discern if a file (path) is on a local disk?





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Suppose I have a path to a file (e.g. "H:dir1file.zip") and I need to make some decisions based on whether the file is already stored locally or not. (In my case, I want to expand an archive, and I only want to perform the expand once the file is on a local disk.)



Is there a reliable way to discern whether the file is on a local disk vs a remote share? I'd prefer not to have to parse/understand the path since there are numerous paths to a file that could easily be misunderstood by such logic.



There's a way to accomplish this with WMI (and therefore, PowerShell). Is there an easy way to do WMI in Python?



I'd prefer pure Python solutions, but The Right Way™ is OK, too. I'm working on Windows 10.










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  • If you just want to determine if the drive is remote, or even if the directory "dir1" is a local-to-remote symlink, use win32file.GetDriveType("H:\dir1\") == win32file.DRIVE_REMOTE. Note that this requires opening a handle for the path (i.e. may access the network), and the path must have a trailing backslash. If "file.zip" itself can be a remote symlink, you'll have to use pathlib.Path(path).resolve() and pass its parent directory to GetDriveType.

    – eryksun
    Jan 3 at 23:45




















0















Suppose I have a path to a file (e.g. "H:dir1file.zip") and I need to make some decisions based on whether the file is already stored locally or not. (In my case, I want to expand an archive, and I only want to perform the expand once the file is on a local disk.)



Is there a reliable way to discern whether the file is on a local disk vs a remote share? I'd prefer not to have to parse/understand the path since there are numerous paths to a file that could easily be misunderstood by such logic.



There's a way to accomplish this with WMI (and therefore, PowerShell). Is there an easy way to do WMI in Python?



I'd prefer pure Python solutions, but The Right Way™ is OK, too. I'm working on Windows 10.










share|improve this question























  • If you just want to determine if the drive is remote, or even if the directory "dir1" is a local-to-remote symlink, use win32file.GetDriveType("H:\dir1\") == win32file.DRIVE_REMOTE. Note that this requires opening a handle for the path (i.e. may access the network), and the path must have a trailing backslash. If "file.zip" itself can be a remote symlink, you'll have to use pathlib.Path(path).resolve() and pass its parent directory to GetDriveType.

    – eryksun
    Jan 3 at 23:45
















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Suppose I have a path to a file (e.g. "H:dir1file.zip") and I need to make some decisions based on whether the file is already stored locally or not. (In my case, I want to expand an archive, and I only want to perform the expand once the file is on a local disk.)



Is there a reliable way to discern whether the file is on a local disk vs a remote share? I'd prefer not to have to parse/understand the path since there are numerous paths to a file that could easily be misunderstood by such logic.



There's a way to accomplish this with WMI (and therefore, PowerShell). Is there an easy way to do WMI in Python?



I'd prefer pure Python solutions, but The Right Way™ is OK, too. I'm working on Windows 10.










share|improve this question














Suppose I have a path to a file (e.g. "H:dir1file.zip") and I need to make some decisions based on whether the file is already stored locally or not. (In my case, I want to expand an archive, and I only want to perform the expand once the file is on a local disk.)



Is there a reliable way to discern whether the file is on a local disk vs a remote share? I'd prefer not to have to parse/understand the path since there are numerous paths to a file that could easily be misunderstood by such logic.



There's a way to accomplish this with WMI (and therefore, PowerShell). Is there an easy way to do WMI in Python?



I'd prefer pure Python solutions, but The Right Way™ is OK, too. I'm working on Windows 10.







python-3.x windows






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asked Jan 3 at 21:04









mojomojo

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  • If you just want to determine if the drive is remote, or even if the directory "dir1" is a local-to-remote symlink, use win32file.GetDriveType("H:\dir1\") == win32file.DRIVE_REMOTE. Note that this requires opening a handle for the path (i.e. may access the network), and the path must have a trailing backslash. If "file.zip" itself can be a remote symlink, you'll have to use pathlib.Path(path).resolve() and pass its parent directory to GetDriveType.

    – eryksun
    Jan 3 at 23:45





















  • If you just want to determine if the drive is remote, or even if the directory "dir1" is a local-to-remote symlink, use win32file.GetDriveType("H:\dir1\") == win32file.DRIVE_REMOTE. Note that this requires opening a handle for the path (i.e. may access the network), and the path must have a trailing backslash. If "file.zip" itself can be a remote symlink, you'll have to use pathlib.Path(path).resolve() and pass its parent directory to GetDriveType.

    – eryksun
    Jan 3 at 23:45



















If you just want to determine if the drive is remote, or even if the directory "dir1" is a local-to-remote symlink, use win32file.GetDriveType("H:\dir1\") == win32file.DRIVE_REMOTE. Note that this requires opening a handle for the path (i.e. may access the network), and the path must have a trailing backslash. If "file.zip" itself can be a remote symlink, you'll have to use pathlib.Path(path).resolve() and pass its parent directory to GetDriveType.

– eryksun
Jan 3 at 23:45







If you just want to determine if the drive is remote, or even if the directory "dir1" is a local-to-remote symlink, use win32file.GetDriveType("H:\dir1\") == win32file.DRIVE_REMOTE. Note that this requires opening a handle for the path (i.e. may access the network), and the path must have a trailing backslash. If "file.zip" itself can be a remote symlink, you'll have to use pathlib.Path(path).resolve() and pass its parent directory to GetDriveType.

– eryksun
Jan 3 at 23:45














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