How to pass args and kwargs to multiprocessing Pool?
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If I have the following function:
def foo(a, b, c=2, d=6):
return a + b + c + d
and I want to parallelize with multiprocessing.
How can I pass the following arguments 1, 2, d=10? i.e. 2 args and 1 kwarg?
I saw this post, but it does not seem to make it actually parallel. Another possibly useful example was provided here, but it is hard to untangle.
python python-3.x multiprocessing
edited Jan 3 at 21:20
martineau
70.2k1092186
asked Jan 3 at 21:17
NewskoolerNewskooler
64521128
add a comment |
-1
If I have the following function:
def foo(a, b, c=2, d=6):
return a + b + c + d
and I want to parallelize with multiprocessing.
How can I pass the following arguments 1, 2, d=10? i.e. 2 args and 1 kwarg?
I saw this post, but it does not seem to make it actually parallel. Another possibly useful example was provided here, but it is hard to untangle.
python python-3.x multiprocessing
edited Jan 3 at 21:20
martineau
70.2k1092186
asked Jan 3 at 21:17
NewskoolerNewskooler
64521128
3
It's all clearly documented. I doubt you can get a better answer than just reading the docs in this case.
– wim
Jan 3 at 21:23
add a comment |
-1
-1
-1
If I have the following function:
def foo(a, b, c=2, d=6):
return a + b + c + d
and I want to parallelize with multiprocessing.
How can I pass the following arguments 1, 2, d=10? i.e. 2 args and 1 kwarg?
I saw this post, but it does not seem to make it actually parallel. Another possibly useful example was provided here, but it is hard to untangle.
python python-3.x multiprocessing
edited Jan 3 at 21:20
martineau
70.2k1092186
asked Jan 3 at 21:17
NewskoolerNewskooler
64521128
If I have the following function:
def foo(a, b, c=2, d=6):
return a + b + c + d
and I want to parallelize with multiprocessing.
How can I pass the following arguments 1, 2, d=10? i.e. 2 args and 1 kwarg?
I saw this post, but it does not seem to make it actually parallel. Another possibly useful example was provided here, but it is hard to untangle.
python python-3.x multiprocessing
python python-3.x multiprocessing
edited Jan 3 at 21:20
martineau
70.2k1092186
asked Jan 3 at 21:17
NewskoolerNewskooler
64521128
edited Jan 3 at 21:20
martineau
70.2k1092186
asked Jan 3 at 21:17
NewskoolerNewskooler
64521128
edited Jan 3 at 21:20
martineau
70.2k1092186
edited Jan 3 at 21:20
martineau
70.2k1092186
edited Jan 3 at 21:20
martineau
70.2k1092186
70.2k1092186
asked Jan 3 at 21:17
NewskoolerNewskooler
64521128
asked Jan 3 at 21:17
NewskoolerNewskooler
64521128
asked Jan 3 at 21:17
NewskoolerNewskooler
64521128
64521128
3
It's all clearly documented. I doubt you can get a better answer than just reading the docs in this case.
– wim
Jan 3 at 21:23
add a comment |
3
It's all clearly documented. I doubt you can get a better answer than just reading the docs in this case.
– wim
Jan 3 at 21:23
3
3
It's all clearly documented. I doubt you can get a better answer than just reading the docs in this case.
– wim
Jan 3 at 21:23
It's all clearly documented. I doubt you can get a better answer than just reading the docs in this case.
– wim
Jan 3 at 21:23
add a comment |
1 Answer
1
active
oldest
votes
1
How about:
import multiprocessing
def foo(a, b, c=2, d=6):
return a + b + c + d
def foo_callback(result):
print(result)
def foo_error(error):
raise error
pool = multiprocessing.Pool()
for (a, b, c, d) in ((1, 2, 3, 4),
(2, 4, 6, 8),
(3, 6, 9, 12)):
pool.apply_async(
foo,
args=(a, b),
kwds={"c":c, "d":d},
callback=foo_callback,
error_callback=foo_error
)
pool.close()
pool.join()
Which prints:
10
20
30
Process finished with exit code 0
I guess that you want to pass the kwds as a dict. The keys need to be strings.
answered Jan 4 at 9:14
Enda FarrellEnda Farrell
19111
How can I get rid of the loop and not passcas a parameter?
– Newskooler
Jan 4 at 15:08
Also, all the results are not in alistas they usually are withmap, which is confusing as well. Could you please elaborate on the usage of this?
– Newskooler
Jan 4 at 15:11
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
How about:
import multiprocessing
def foo(a, b, c=2, d=6):
return a + b + c + d
def foo_callback(result):
print(result)
def foo_error(error):
raise error
pool = multiprocessing.Pool()
for (a, b, c, d) in ((1, 2, 3, 4),
(2, 4, 6, 8),
(3, 6, 9, 12)):
pool.apply_async(
foo,
args=(a, b),
kwds={"c":c, "d":d},
callback=foo_callback,
error_callback=foo_error
)
pool.close()
pool.join()
Which prints:
10
20
30
Process finished with exit code 0
I guess that you want to pass the kwds as a dict. The keys need to be strings.
answered Jan 4 at 9:14
Enda FarrellEnda Farrell
19111
How can I get rid of the loop and not passcas a parameter?
– Newskooler
Jan 4 at 15:08
Also, all the results are not in alistas they usually are withmap, which is confusing as well. Could you please elaborate on the usage of this?
– Newskooler
Jan 4 at 15:11
add a comment |
1
How about:
import multiprocessing
def foo(a, b, c=2, d=6):
return a + b + c + d
def foo_callback(result):
print(result)
def foo_error(error):
raise error
pool = multiprocessing.Pool()
for (a, b, c, d) in ((1, 2, 3, 4),
(2, 4, 6, 8),
(3, 6, 9, 12)):
pool.apply_async(
foo,
args=(a, b),
kwds={"c":c, "d":d},
callback=foo_callback,
error_callback=foo_error
)
pool.close()
pool.join()
Which prints:
10
20
30
Process finished with exit code 0
I guess that you want to pass the kwds as a dict. The keys need to be strings.
answered Jan 4 at 9:14
Enda FarrellEnda Farrell
19111
How can I get rid of the loop and not passcas a parameter?
– Newskooler
Jan 4 at 15:08
Also, all the results are not in alistas they usually are withmap, which is confusing as well. Could you please elaborate on the usage of this?
– Newskooler
Jan 4 at 15:11
add a comment |
1
1
1
How about:
import multiprocessing
def foo(a, b, c=2, d=6):
return a + b + c + d
def foo_callback(result):
print(result)
def foo_error(error):
raise error
pool = multiprocessing.Pool()
for (a, b, c, d) in ((1, 2, 3, 4),
(2, 4, 6, 8),
(3, 6, 9, 12)):
pool.apply_async(
foo,
args=(a, b),
kwds={"c":c, "d":d},
callback=foo_callback,
error_callback=foo_error
)
pool.close()
pool.join()
Which prints:
10
20
30
Process finished with exit code 0
I guess that you want to pass the kwds as a dict. The keys need to be strings.
answered Jan 4 at 9:14
Enda FarrellEnda Farrell
19111
How about:
import multiprocessing
def foo(a, b, c=2, d=6):
return a + b + c + d
def foo_callback(result):
print(result)
def foo_error(error):
raise error
pool = multiprocessing.Pool()
for (a, b, c, d) in ((1, 2, 3, 4),
(2, 4, 6, 8),
(3, 6, 9, 12)):
pool.apply_async(
foo,
args=(a, b),
kwds={"c":c, "d":d},
callback=foo_callback,
error_callback=foo_error
)
pool.close()
pool.join()
Which prints:
10
20
30
Process finished with exit code 0
I guess that you want to pass the kwds as a dict. The keys need to be strings.
answered Jan 4 at 9:14
Enda FarrellEnda Farrell
19111
answered Jan 4 at 9:14
Enda FarrellEnda Farrell
19111
answered Jan 4 at 9:14
Enda FarrellEnda Farrell
19111
answered Jan 4 at 9:14
Enda FarrellEnda Farrell
19111
19111
How can I get rid of the loop and not passcas a parameter?
– Newskooler
Jan 4 at 15:08
Also, all the results are not in alistas they usually are withmap, which is confusing as well. Could you please elaborate on the usage of this?
– Newskooler
Jan 4 at 15:11
add a comment |
How can I get rid of the loop and not passcas a parameter?
– Newskooler
Jan 4 at 15:08
Also, all the results are not in alistas they usually are withmap, which is confusing as well. Could you please elaborate on the usage of this?
– Newskooler
Jan 4 at 15:11
How can I get rid of the loop and not pass
c as a parameter?– Newskooler
Jan 4 at 15:08
How can I get rid of the loop and not pass
c as a parameter?– Newskooler
Jan 4 at 15:08
Also, all the results are not in a
list as they usually are with map, which is confusing as well. Could you please elaborate on the usage of this?– Newskooler
Jan 4 at 15:11
Also, all the results are not in a
list as they usually are with map, which is confusing as well. Could you please elaborate on the usage of this?– Newskooler
Jan 4 at 15:11
add a comment |
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3
It's all clearly documented. I doubt you can get a better answer than just reading the docs in this case.
– wim
Jan 3 at 21:23