Bdtjtk

I've googled, read the docs (kinda hard for me to understand), googled some more, looked at examples, and I just can't find an answer. Maybe there is no way to do it.

self.button = self.add(npyscreen.Button, name="Button")

This produces a button but it seems to be more of a True or False selector. Can one do something on-press with it, like launch another form?

Below is a working example application I put together to get started. Can you show me how to make that button launch the second form? If it can't be done with a button, is there another way to essentially do the same thing?

Ultimately I would like the first menu to display a list of options that upon selecting one of them, would open up a second form. When done in the second form, they would be directed back to the main menu to select further options as needed or exit the application. I think I have everything I need worked out except this. Thanks for your help!

#!/usr/bin/python

# encoding=utf8



import npyscreen



# This is a form object

class WizardFormMain(npyscreen.ActionForm, npyscreen.SplitForm, npyscreen.FormWithMenus):

  def create(self):



    self.button = self.add(npyscreen.Button, name="Button") # Make this button go to FORM2



    # Since we are inheriting the npyscreen.FormWithMenus class we can use menus, this will add an option to the menu to exit the program

    self.menu = self.new_menu(name="Main Menu", shortcut='^M')

    self.menu.addItem("Exit Program", self.exit, "^X")

  # END DEF



  def exit(self):

    self.parentApp.switchForm(None) # causes the app to exit on OK

  # END DEF



  # Save data to conf file and Go back to first form...

  def on_ok(self):

    npyscreen.notify_confirm("OK Pressed, going to FORM2 now.", title="Notice", wrap=True, wide=True, editw=1)

    self.parentApp.setNextForm('FORM2')

  # END DEF



  def on_cancel(self):

    self.parentApp.setNextForm(None) # Also exit's the program

  # END DEF



# END CLASS



# FORM2

class WizardForm2(npyscreen.ActionForm, npyscreen.SplitForm, npyscreen.FormWithMenus):

  def create(self):



    self.name = self.add( npyscreen.TitleText, name="Username: " )

    self.passwd = self.add( npyscreen.TitleText, name="Password: " )



  # Save data to conf file and Go back to first form...

  def on_ok(self):

    npyscreen.notify_confirm("Saved! Going back to main form", title="OK Presed", wrap=True, wide=True, editw=1)

    self.parentApp.setNextForm('MAIN')

  # END DEF



  def on_cancel(self):

    npyscreen.notify_confirm("NOT Saved, going back to main form", title="OK Presed", wrap=True, wide=True, editw=1)

    self.parentApp.setNextForm('MAIN') # Back to main form

  # END DEF

# END CLASS



# This is the Wizards form manager function

class WizardApp(npyscreen.NPSAppManaged):

  def onStart(self):

    self.addForm('MAIN', WizardFormMain, name = "First Form!", lines=20, columns=60, draw_line_at=16 )

    self.addForm('FORM2', WizardForm2, name = "Second Form!", lines=20, columns=60, draw_line_at=16 )

  # END DEF

# END CLASS





if ( __name__ == "__main__"):

  wizard = WizardApp().run()

So I think I have figured out how to do this. The docs regarding the button method is basically absent, so I figured out how to do this by examining the button method output.

First on the button we can specify a callback function (similar to javascript) with value_changed_callback=self.buttonPress inside of the self.add() statement.

Then inside of the buttonPress function in the example shows a notification and then moves over to FORM2 - moving to the new form is done by specifying the form with this: self.parentApp.switchForm('FORM2')

Here it is the important stuff:

class WizardFormMain(npyscreen.ActionForm, npyscreen.SplitForm, npyscreen.FormWithMenus):

  def create(self):

    self.button = self.add(npyscreen.Button, name="Button", value_changed_callback=self.buttonPress) # Make this button go to FORM2



    # Since we are inheriting the npyscreen.FormWithMenus class we can use menus, this will add an option to the menu to exit the program

    self.menu = self.new_menu(name="Main Menu", shortcut='^M')

    self.menu.addItem("Exit Program", self.exit, "^X")

  # END DEF



  def buttonPress(self, widget):

    npyscreen.notify_confirm("BUTTON PRESSED!", title="Woot!", wrap=True, wide=True, editw=1)

    self.parentApp.switchForm('FORM2')