mysql query showing wrong result












0















I have a database table look like this



+======+===========+============+

|  ID  | user Name |user surname|

+======+===========+============+

| 100  |  name     |  surname   |

| 101  |  name     |  surname   |

| 102  |  name     |  surname   |

+===============================+


When i run this query which should show me no rows because there is no row with 101foo2 value :




SELECT * FROM tableName WHERE ID = '101foo2'




I am getting a result with same ID without the foo2 word



+======+===========+============+

|  ID  | user Name |user surname|

+======+===========+============+

| 101  |  name     |  surname   |

+===============================+


how it is showing the row with ID 101 if my query is ID = '101foo2'






mysql sql phpmyadmin







share|improve this question


















  • 1





    Rule 1 if the datatype is a INT type don't use strings to fetch it. MySQL trys auto converting '101foo2' into 101 if the column datatype is a INT.. That why your query results into getting that record.

    – Raymond Nijland
    Jan 3 at 17:13


















0















I have a database table look like this



+======+===========+============+

|  ID  | user Name |user surname|

+======+===========+============+

| 100  |  name     |  surname   |

| 101  |  name     |  surname   |

| 102  |  name     |  surname   |

+===============================+


When i run this query which should show me no rows because there is no row with 101foo2 value :




SELECT * FROM tableName WHERE ID = '101foo2'




I am getting a result with same ID without the foo2 word



+======+===========+============+

|  ID  | user Name |user surname|

+======+===========+============+

| 101  |  name     |  surname   |

+===============================+


how it is showing the row with ID 101 if my query is ID = '101foo2'






mysql sql phpmyadmin







share|improve this question


















  • 1





    Rule 1 if the datatype is a INT type don't use strings to fetch it. MySQL trys auto converting '101foo2' into 101 if the column datatype is a INT.. That why your query results into getting that record.

    – Raymond Nijland
    Jan 3 at 17:13
















0












0








0








I have a database table look like this



+======+===========+============+

|  ID  | user Name |user surname|

+======+===========+============+

| 100  |  name     |  surname   |

| 101  |  name     |  surname   |

| 102  |  name     |  surname   |

+===============================+


When i run this query which should show me no rows because there is no row with 101foo2 value :




SELECT * FROM tableName WHERE ID = '101foo2'




I am getting a result with same ID without the foo2 word



+======+===========+============+

|  ID  | user Name |user surname|

+======+===========+============+

| 101  |  name     |  surname   |

+===============================+


how it is showing the row with ID 101 if my query is ID = '101foo2'






mysql sql phpmyadmin







share|improve this question














I have a database table look like this



+======+===========+============+

|  ID  | user Name |user surname|

+======+===========+============+

| 100  |  name     |  surname   |

| 101  |  name     |  surname   |

| 102  |  name     |  surname   |

+===============================+


When i run this query which should show me no rows because there is no row with 101foo2 value :




SELECT * FROM tableName WHERE ID = '101foo2'




I am getting a result with same ID without the foo2 word



+======+===========+============+

|  ID  | user Name |user surname|

+======+===========+============+

| 101  |  name     |  surname   |

+===============================+


how it is showing the row with ID 101 if my query is ID = '101foo2'






mysql sql phpmyadmin




mysql sql phpmyadmin






share|improve this question













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asked Jan 3 at 17:10









NasserNasser

74




74








  • 1





    Rule 1 if the datatype is a INT type don't use strings to fetch it. MySQL trys auto converting '101foo2' into 101 if the column datatype is a INT.. That why your query results into getting that record.

    – Raymond Nijland
    Jan 3 at 17:13
















  • 1





    Rule 1 if the datatype is a INT type don't use strings to fetch it. MySQL trys auto converting '101foo2' into 101 if the column datatype is a INT.. That why your query results into getting that record.

    – Raymond Nijland
    Jan 3 at 17:13










1




1





Rule 1 if the datatype is a INT type don't use strings to fetch it. MySQL trys auto converting '101foo2' into 101 if the column datatype is a INT.. That why your query results into getting that record.

– Raymond Nijland
Jan 3 at 17:13







Rule 1 if the datatype is a INT type don't use strings to fetch it. MySQL trys auto converting '101foo2' into 101 if the column datatype is a INT.. That why your query results into getting that record.

– Raymond Nijland
Jan 3 at 17:13














1 Answer
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You are mixing types. ID is an integer (or number). You are comparing it to a string. So, MySQL needs to decide what type to use for the comparison. What types gets used? Well, a string? No. A number. The string is converted to a number, using the leading digits. So, it becomes 101 and matches.



You should really only compare numbers to numbers, and strings to strings. You could try to write the code as:



SELECT * FROM tableName WHERE ID = 101foo2


However, you would get an error. Another possibility is to force the conversion to a string:



SELECT * FROM tableName WHERE CAST(ID as CHAR) = '101foo2'





share|improve this answer
























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    1 Answer
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    You are mixing types. ID is an integer (or number). You are comparing it to a string. So, MySQL needs to decide what type to use for the comparison. What types gets used? Well, a string? No. A number. The string is converted to a number, using the leading digits. So, it becomes 101 and matches.



    You should really only compare numbers to numbers, and strings to strings. You could try to write the code as:



    SELECT * FROM tableName WHERE ID = 101foo2


    However, you would get an error. Another possibility is to force the conversion to a string:



    SELECT * FROM tableName WHERE CAST(ID as CHAR) = '101foo2'





    share|improve this answer




























      2














      You are mixing types. ID is an integer (or number). You are comparing it to a string. So, MySQL needs to decide what type to use for the comparison. What types gets used? Well, a string? No. A number. The string is converted to a number, using the leading digits. So, it becomes 101 and matches.



      You should really only compare numbers to numbers, and strings to strings. You could try to write the code as:



      SELECT * FROM tableName WHERE ID = 101foo2


      However, you would get an error. Another possibility is to force the conversion to a string:



      SELECT * FROM tableName WHERE CAST(ID as CHAR) = '101foo2'





      share|improve this answer


























        2












        2








        2







        You are mixing types. ID is an integer (or number). You are comparing it to a string. So, MySQL needs to decide what type to use for the comparison. What types gets used? Well, a string? No. A number. The string is converted to a number, using the leading digits. So, it becomes 101 and matches.



        You should really only compare numbers to numbers, and strings to strings. You could try to write the code as:



        SELECT * FROM tableName WHERE ID = 101foo2


        However, you would get an error. Another possibility is to force the conversion to a string:



        SELECT * FROM tableName WHERE CAST(ID as CHAR) = '101foo2'





        share|improve this answer













        You are mixing types. ID is an integer (or number). You are comparing it to a string. So, MySQL needs to decide what type to use for the comparison. What types gets used? Well, a string? No. A number. The string is converted to a number, using the leading digits. So, it becomes 101 and matches.



        You should really only compare numbers to numbers, and strings to strings. You could try to write the code as:



        SELECT * FROM tableName WHERE ID = 101foo2


        However, you would get an error. Another possibility is to force the conversion to a string:



        SELECT * FROM tableName WHERE CAST(ID as CHAR) = '101foo2'






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 3 at 17:13









        Gordon LinoffGordon Linoff

        793k36316419




        793k36316419
































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