From QVariant to Integer and String












4















The user's entered value can be both: a string or an integer.



QAbstractTableModel's setData() method always gets this value as QtCore.QVariant



Question:



How to implement if/elif/else inside of setData() to distinguish if the received QVariant is a string or an integer? (so a proper QVariant conversion method (such as .toString() or toInt()) is used)



P.s. Interesting that an attempt to convert QVariant toInt() results to a tuple such as: (0, False) or (123, True)










share|improve this question





























    4















    The user's entered value can be both: a string or an integer.



    QAbstractTableModel's setData() method always gets this value as QtCore.QVariant



    Question:



    How to implement if/elif/else inside of setData() to distinguish if the received QVariant is a string or an integer? (so a proper QVariant conversion method (such as .toString() or toInt()) is used)



    P.s. Interesting that an attempt to convert QVariant toInt() results to a tuple such as: (0, False) or (123, True)










    share|improve this question



























      4












      4








      4








      The user's entered value can be both: a string or an integer.



      QAbstractTableModel's setData() method always gets this value as QtCore.QVariant



      Question:



      How to implement if/elif/else inside of setData() to distinguish if the received QVariant is a string or an integer? (so a proper QVariant conversion method (such as .toString() or toInt()) is used)



      P.s. Interesting that an attempt to convert QVariant toInt() results to a tuple such as: (0, False) or (123, True)










      share|improve this question
















      The user's entered value can be both: a string or an integer.



      QAbstractTableModel's setData() method always gets this value as QtCore.QVariant



      Question:



      How to implement if/elif/else inside of setData() to distinguish if the received QVariant is a string or an integer? (so a proper QVariant conversion method (such as .toString() or toInt()) is used)



      P.s. Interesting that an attempt to convert QVariant toInt() results to a tuple such as: (0, False) or (123, True)







      python qt pyqt qtcore qvariant






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 2 '15 at 6:06







      alphanumeric

















      asked Dec 25 '14 at 0:33









      alphanumericalphanumeric

      5,3921388192




      5,3921388192
























          1 Answer
          1






          active

          oldest

          votes


















          6














          You can check against the type:



          if myVariant.type() == QVariant.Int:
          value = myVariant.toInt()
          elif myVariant.type() == QVariant.QString:
          value = myVariant.toString()


          Given that the form above is now obsolete, it is recommended to check it this way:



          if myVariant.canConvert(QMetaType.Int):
          value = myVariant.toInt()
          elif myVariant.canConvert(QMetaType.QString)
          value = myVariant.toString()





          share|improve this answer


























          • Thanks! Simple and it works! :)

            – alphanumeric
            Dec 25 '14 at 0:51











          • I tried to edit the post but my modification would be less than 6 chars so I couldn't. QVariant.type is actually a method, so the first example should be if myVariant.type() == QVariant.Int instead of if myVariant.type == QVariant.Int

            – arainone
            Aug 31 '16 at 12:58














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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

          oldest

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          6














          You can check against the type:



          if myVariant.type() == QVariant.Int:
          value = myVariant.toInt()
          elif myVariant.type() == QVariant.QString:
          value = myVariant.toString()


          Given that the form above is now obsolete, it is recommended to check it this way:



          if myVariant.canConvert(QMetaType.Int):
          value = myVariant.toInt()
          elif myVariant.canConvert(QMetaType.QString)
          value = myVariant.toString()





          share|improve this answer


























          • Thanks! Simple and it works! :)

            – alphanumeric
            Dec 25 '14 at 0:51











          • I tried to edit the post but my modification would be less than 6 chars so I couldn't. QVariant.type is actually a method, so the first example should be if myVariant.type() == QVariant.Int instead of if myVariant.type == QVariant.Int

            – arainone
            Aug 31 '16 at 12:58


















          6














          You can check against the type:



          if myVariant.type() == QVariant.Int:
          value = myVariant.toInt()
          elif myVariant.type() == QVariant.QString:
          value = myVariant.toString()


          Given that the form above is now obsolete, it is recommended to check it this way:



          if myVariant.canConvert(QMetaType.Int):
          value = myVariant.toInt()
          elif myVariant.canConvert(QMetaType.QString)
          value = myVariant.toString()





          share|improve this answer


























          • Thanks! Simple and it works! :)

            – alphanumeric
            Dec 25 '14 at 0:51











          • I tried to edit the post but my modification would be less than 6 chars so I couldn't. QVariant.type is actually a method, so the first example should be if myVariant.type() == QVariant.Int instead of if myVariant.type == QVariant.Int

            – arainone
            Aug 31 '16 at 12:58
















          6












          6








          6







          You can check against the type:



          if myVariant.type() == QVariant.Int:
          value = myVariant.toInt()
          elif myVariant.type() == QVariant.QString:
          value = myVariant.toString()


          Given that the form above is now obsolete, it is recommended to check it this way:



          if myVariant.canConvert(QMetaType.Int):
          value = myVariant.toInt()
          elif myVariant.canConvert(QMetaType.QString)
          value = myVariant.toString()





          share|improve this answer















          You can check against the type:



          if myVariant.type() == QVariant.Int:
          value = myVariant.toInt()
          elif myVariant.type() == QVariant.QString:
          value = myVariant.toString()


          Given that the form above is now obsolete, it is recommended to check it this way:



          if myVariant.canConvert(QMetaType.Int):
          value = myVariant.toInt()
          elif myVariant.canConvert(QMetaType.QString)
          value = myVariant.toString()






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 3 at 17:11









          eyllanesc

          85.5k103564




          85.5k103564










          answered Dec 25 '14 at 0:48









          lpapplpapp

          42.7k1377105




          42.7k1377105













          • Thanks! Simple and it works! :)

            – alphanumeric
            Dec 25 '14 at 0:51











          • I tried to edit the post but my modification would be less than 6 chars so I couldn't. QVariant.type is actually a method, so the first example should be if myVariant.type() == QVariant.Int instead of if myVariant.type == QVariant.Int

            – arainone
            Aug 31 '16 at 12:58





















          • Thanks! Simple and it works! :)

            – alphanumeric
            Dec 25 '14 at 0:51











          • I tried to edit the post but my modification would be less than 6 chars so I couldn't. QVariant.type is actually a method, so the first example should be if myVariant.type() == QVariant.Int instead of if myVariant.type == QVariant.Int

            – arainone
            Aug 31 '16 at 12:58



















          Thanks! Simple and it works! :)

          – alphanumeric
          Dec 25 '14 at 0:51





          Thanks! Simple and it works! :)

          – alphanumeric
          Dec 25 '14 at 0:51













          I tried to edit the post but my modification would be less than 6 chars so I couldn't. QVariant.type is actually a method, so the first example should be if myVariant.type() == QVariant.Int instead of if myVariant.type == QVariant.Int

          – arainone
          Aug 31 '16 at 12:58







          I tried to edit the post but my modification would be less than 6 chars so I couldn't. QVariant.type is actually a method, so the first example should be if myVariant.type() == QVariant.Int instead of if myVariant.type == QVariant.Int

          – arainone
          Aug 31 '16 at 12:58






















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