findAllUseCountTop1ByIsActiveOrderById(Boolean isActive) does not generate a query with “LIMIT 1”
![Multi tool use Multi tool use](http://sgv.ssvwv.com/sg/ssvwvcomimagb.png)
Multi tool use
Why does JPA not apply "LIMIT 1" to the query?
I am trying to write a repository function in SpringBoot application to get the first result from the top where "isActive" is TRUE when ordered by ID. This function generates a query that does not include "LIMIT 1" this returns multiple results and is failing with "query did not return a unique result:4" exception. I am using Hibernate Core v5.3.7.Final with MySQL v8.0.12 as the database.
Generated Query :
select phoneinfo0_.id as id1_0_, phoneinfo0_.Phone as Phone2_0_, phoneinfo0_.isActive as isActive3_0_, phoneinfo0_.useCount as useCount4_0_ from contactNumbers phoneinfo0_ where phoneinfo0_.isActive=1 order by phoneinfo0_.id asc;
Result Returned :
+--------+------------+--------------+--------------+
| id1_0_ | Phone2_0_ | isActive3_0_ | useCount4_0_ |
+--------+------------+--------------+--------------+
| 1 | 1111111111 | 1 | 0 |
| 2 | 9999999999 | 1 | 0 |
| 3 | 9000000000 | 1 | 0 |
| 4 | 2222222222 | 1 | 0 |
+--------+------------+--------------+--------------+
Also please tell me if "ORDER BY ID" is necessary or is it done by default on every select if ID is Primary key auto-incremented?
mysql hibernate jpa spring-data-jpa
add a comment |
Why does JPA not apply "LIMIT 1" to the query?
I am trying to write a repository function in SpringBoot application to get the first result from the top where "isActive" is TRUE when ordered by ID. This function generates a query that does not include "LIMIT 1" this returns multiple results and is failing with "query did not return a unique result:4" exception. I am using Hibernate Core v5.3.7.Final with MySQL v8.0.12 as the database.
Generated Query :
select phoneinfo0_.id as id1_0_, phoneinfo0_.Phone as Phone2_0_, phoneinfo0_.isActive as isActive3_0_, phoneinfo0_.useCount as useCount4_0_ from contactNumbers phoneinfo0_ where phoneinfo0_.isActive=1 order by phoneinfo0_.id asc;
Result Returned :
+--------+------------+--------------+--------------+
| id1_0_ | Phone2_0_ | isActive3_0_ | useCount4_0_ |
+--------+------------+--------------+--------------+
| 1 | 1111111111 | 1 | 0 |
| 2 | 9999999999 | 1 | 0 |
| 3 | 9000000000 | 1 | 0 |
| 4 | 2222222222 | 1 | 0 |
+--------+------------+--------------+--------------+
Also please tell me if "ORDER BY ID" is necessary or is it done by default on every select if ID is Primary key auto-incremented?
mysql hibernate jpa spring-data-jpa
add a comment |
Why does JPA not apply "LIMIT 1" to the query?
I am trying to write a repository function in SpringBoot application to get the first result from the top where "isActive" is TRUE when ordered by ID. This function generates a query that does not include "LIMIT 1" this returns multiple results and is failing with "query did not return a unique result:4" exception. I am using Hibernate Core v5.3.7.Final with MySQL v8.0.12 as the database.
Generated Query :
select phoneinfo0_.id as id1_0_, phoneinfo0_.Phone as Phone2_0_, phoneinfo0_.isActive as isActive3_0_, phoneinfo0_.useCount as useCount4_0_ from contactNumbers phoneinfo0_ where phoneinfo0_.isActive=1 order by phoneinfo0_.id asc;
Result Returned :
+--------+------------+--------------+--------------+
| id1_0_ | Phone2_0_ | isActive3_0_ | useCount4_0_ |
+--------+------------+--------------+--------------+
| 1 | 1111111111 | 1 | 0 |
| 2 | 9999999999 | 1 | 0 |
| 3 | 9000000000 | 1 | 0 |
| 4 | 2222222222 | 1 | 0 |
+--------+------------+--------------+--------------+
Also please tell me if "ORDER BY ID" is necessary or is it done by default on every select if ID is Primary key auto-incremented?
mysql hibernate jpa spring-data-jpa
Why does JPA not apply "LIMIT 1" to the query?
I am trying to write a repository function in SpringBoot application to get the first result from the top where "isActive" is TRUE when ordered by ID. This function generates a query that does not include "LIMIT 1" this returns multiple results and is failing with "query did not return a unique result:4" exception. I am using Hibernate Core v5.3.7.Final with MySQL v8.0.12 as the database.
Generated Query :
select phoneinfo0_.id as id1_0_, phoneinfo0_.Phone as Phone2_0_, phoneinfo0_.isActive as isActive3_0_, phoneinfo0_.useCount as useCount4_0_ from contactNumbers phoneinfo0_ where phoneinfo0_.isActive=1 order by phoneinfo0_.id asc;
Result Returned :
+--------+------------+--------------+--------------+
| id1_0_ | Phone2_0_ | isActive3_0_ | useCount4_0_ |
+--------+------------+--------------+--------------+
| 1 | 1111111111 | 1 | 0 |
| 2 | 9999999999 | 1 | 0 |
| 3 | 9000000000 | 1 | 0 |
| 4 | 2222222222 | 1 | 0 |
+--------+------------+--------------+--------------+
Also please tell me if "ORDER BY ID" is necessary or is it done by default on every select if ID is Primary key auto-incremented?
mysql hibernate jpa spring-data-jpa
mysql hibernate jpa spring-data-jpa
edited Dec 30 '18 at 23:49
Mahesh P.
asked Dec 30 '18 at 23:42
Mahesh P.Mahesh P.
93
93
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Try to rename it to one of this:
findTop1UseCountByIsActiveOrderById(Boolean isActive)
findFirstUseCountByIsActiveOrderById(Boolean isActive)
Hi @KonstantinLabun thank you for such a quick response. I have tried it and it works when I remove UseCount from the function name. The JPA straight on ignores column that I want to select and selects whole table instead. I got what I need though so thank you. Just one thing do you know how to select just one particular column or why is JPA selecting whole table instead of just getting "UseCount"?
– Mahesh P.
Dec 31 '18 at 1:00
Methods names is quite straightforward thing. Not sure if it will allow you to solve your problem. Try to use JPQL for it:
– Konstantin Labun
Dec 31 '18 at 1:06
I have just read about it. We cannot apparently. We have to use @Query when we want to select particular columns. My solution was "findFirstByIsActiveTrueOrderById()" as I always wanted only the active ones and getting whole object now as its other values could be used later. This helped too [docs.spring.io/spring-data/jpa/docs/current/reference/html/….
– Mahesh P.
Dec 31 '18 at 1:20
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53982346%2ffindallusecounttop1byisactiveorderbyidboolean-isactive-does-not-generate-a-que%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try to rename it to one of this:
findTop1UseCountByIsActiveOrderById(Boolean isActive)
findFirstUseCountByIsActiveOrderById(Boolean isActive)
Hi @KonstantinLabun thank you for such a quick response. I have tried it and it works when I remove UseCount from the function name. The JPA straight on ignores column that I want to select and selects whole table instead. I got what I need though so thank you. Just one thing do you know how to select just one particular column or why is JPA selecting whole table instead of just getting "UseCount"?
– Mahesh P.
Dec 31 '18 at 1:00
Methods names is quite straightforward thing. Not sure if it will allow you to solve your problem. Try to use JPQL for it:
– Konstantin Labun
Dec 31 '18 at 1:06
I have just read about it. We cannot apparently. We have to use @Query when we want to select particular columns. My solution was "findFirstByIsActiveTrueOrderById()" as I always wanted only the active ones and getting whole object now as its other values could be used later. This helped too [docs.spring.io/spring-data/jpa/docs/current/reference/html/….
– Mahesh P.
Dec 31 '18 at 1:20
add a comment |
Try to rename it to one of this:
findTop1UseCountByIsActiveOrderById(Boolean isActive)
findFirstUseCountByIsActiveOrderById(Boolean isActive)
Hi @KonstantinLabun thank you for such a quick response. I have tried it and it works when I remove UseCount from the function name. The JPA straight on ignores column that I want to select and selects whole table instead. I got what I need though so thank you. Just one thing do you know how to select just one particular column or why is JPA selecting whole table instead of just getting "UseCount"?
– Mahesh P.
Dec 31 '18 at 1:00
Methods names is quite straightforward thing. Not sure if it will allow you to solve your problem. Try to use JPQL for it:
– Konstantin Labun
Dec 31 '18 at 1:06
I have just read about it. We cannot apparently. We have to use @Query when we want to select particular columns. My solution was "findFirstByIsActiveTrueOrderById()" as I always wanted only the active ones and getting whole object now as its other values could be used later. This helped too [docs.spring.io/spring-data/jpa/docs/current/reference/html/….
– Mahesh P.
Dec 31 '18 at 1:20
add a comment |
Try to rename it to one of this:
findTop1UseCountByIsActiveOrderById(Boolean isActive)
findFirstUseCountByIsActiveOrderById(Boolean isActive)
Try to rename it to one of this:
findTop1UseCountByIsActiveOrderById(Boolean isActive)
findFirstUseCountByIsActiveOrderById(Boolean isActive)
answered Dec 30 '18 at 23:52
Konstantin LabunKonstantin Labun
1,7231119
1,7231119
Hi @KonstantinLabun thank you for such a quick response. I have tried it and it works when I remove UseCount from the function name. The JPA straight on ignores column that I want to select and selects whole table instead. I got what I need though so thank you. Just one thing do you know how to select just one particular column or why is JPA selecting whole table instead of just getting "UseCount"?
– Mahesh P.
Dec 31 '18 at 1:00
Methods names is quite straightforward thing. Not sure if it will allow you to solve your problem. Try to use JPQL for it:
– Konstantin Labun
Dec 31 '18 at 1:06
I have just read about it. We cannot apparently. We have to use @Query when we want to select particular columns. My solution was "findFirstByIsActiveTrueOrderById()" as I always wanted only the active ones and getting whole object now as its other values could be used later. This helped too [docs.spring.io/spring-data/jpa/docs/current/reference/html/….
– Mahesh P.
Dec 31 '18 at 1:20
add a comment |
Hi @KonstantinLabun thank you for such a quick response. I have tried it and it works when I remove UseCount from the function name. The JPA straight on ignores column that I want to select and selects whole table instead. I got what I need though so thank you. Just one thing do you know how to select just one particular column or why is JPA selecting whole table instead of just getting "UseCount"?
– Mahesh P.
Dec 31 '18 at 1:00
Methods names is quite straightforward thing. Not sure if it will allow you to solve your problem. Try to use JPQL for it:
– Konstantin Labun
Dec 31 '18 at 1:06
I have just read about it. We cannot apparently. We have to use @Query when we want to select particular columns. My solution was "findFirstByIsActiveTrueOrderById()" as I always wanted only the active ones and getting whole object now as its other values could be used later. This helped too [docs.spring.io/spring-data/jpa/docs/current/reference/html/….
– Mahesh P.
Dec 31 '18 at 1:20
Hi @KonstantinLabun thank you for such a quick response. I have tried it and it works when I remove UseCount from the function name. The JPA straight on ignores column that I want to select and selects whole table instead. I got what I need though so thank you. Just one thing do you know how to select just one particular column or why is JPA selecting whole table instead of just getting "UseCount"?
– Mahesh P.
Dec 31 '18 at 1:00
Hi @KonstantinLabun thank you for such a quick response. I have tried it and it works when I remove UseCount from the function name. The JPA straight on ignores column that I want to select and selects whole table instead. I got what I need though so thank you. Just one thing do you know how to select just one particular column or why is JPA selecting whole table instead of just getting "UseCount"?
– Mahesh P.
Dec 31 '18 at 1:00
Methods names is quite straightforward thing. Not sure if it will allow you to solve your problem. Try to use JPQL for it:
– Konstantin Labun
Dec 31 '18 at 1:06
Methods names is quite straightforward thing. Not sure if it will allow you to solve your problem. Try to use JPQL for it:
– Konstantin Labun
Dec 31 '18 at 1:06
I have just read about it. We cannot apparently. We have to use @Query when we want to select particular columns. My solution was "findFirstByIsActiveTrueOrderById()" as I always wanted only the active ones and getting whole object now as its other values could be used later. This helped too [docs.spring.io/spring-data/jpa/docs/current/reference/html/….
– Mahesh P.
Dec 31 '18 at 1:20
I have just read about it. We cannot apparently. We have to use @Query when we want to select particular columns. My solution was "findFirstByIsActiveTrueOrderById()" as I always wanted only the active ones and getting whole object now as its other values could be used later. This helped too [docs.spring.io/spring-data/jpa/docs/current/reference/html/….
– Mahesh P.
Dec 31 '18 at 1:20
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53982346%2ffindallusecounttop1byisactiveorderbyidboolean-isactive-does-not-generate-a-que%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
rweyRm7Cqns,E3as7Ikf