Comparison of a part of composite key
I use spring boot 2.1, jpa and hibernate.
In my Samples entity
@EmbeddedId
private SampleId id;
@MapsId("samplingId")
@ManyToOne(optional = false)
private Samplings sampling;
My composite object
@Embeddable
public class SampleId implements Serializable{
private Integer samplingId;
private String sampleLetter;
//get //set
}
@Query(
value = "select s from Samples s "
+ "Join fetch s.sampling sp "
+ "where sp.id >= :sampleId.samplingId and s.id !=:sampleId "
+ "order by s.id.samplingId,s.id.sampleLetter"
)
public List<Samples> findNextAbsorptionTest(@Param("sampleId") SampleId sampleId);
Seem like hibernate don't like this part
sp.id >= :sampleId.samplingId
If I remove it, that work
Paste of the error
https://pastebin.com/TF0BJn7a
hibernate jpa spring-data-jpa
add a comment |
I use spring boot 2.1, jpa and hibernate.
In my Samples entity
@EmbeddedId
private SampleId id;
@MapsId("samplingId")
@ManyToOne(optional = false)
private Samplings sampling;
My composite object
@Embeddable
public class SampleId implements Serializable{
private Integer samplingId;
private String sampleLetter;
//get //set
}
@Query(
value = "select s from Samples s "
+ "Join fetch s.sampling sp "
+ "where sp.id >= :sampleId.samplingId and s.id !=:sampleId "
+ "order by s.id.samplingId,s.id.sampleLetter"
)
public List<Samples> findNextAbsorptionTest(@Param("sampleId") SampleId sampleId);
Seem like hibernate don't like this part
sp.id >= :sampleId.samplingId
If I remove it, that work
Paste of the error
https://pastebin.com/TF0BJn7a
hibernate jpa spring-data-jpa
1
It's not possible to use . with a parameter. Can you please post all code of your entities. How does Sampling look like?
– Simon Martinelli
Dec 28 '18 at 16:34
add a comment |
I use spring boot 2.1, jpa and hibernate.
In my Samples entity
@EmbeddedId
private SampleId id;
@MapsId("samplingId")
@ManyToOne(optional = false)
private Samplings sampling;
My composite object
@Embeddable
public class SampleId implements Serializable{
private Integer samplingId;
private String sampleLetter;
//get //set
}
@Query(
value = "select s from Samples s "
+ "Join fetch s.sampling sp "
+ "where sp.id >= :sampleId.samplingId and s.id !=:sampleId "
+ "order by s.id.samplingId,s.id.sampleLetter"
)
public List<Samples> findNextAbsorptionTest(@Param("sampleId") SampleId sampleId);
Seem like hibernate don't like this part
sp.id >= :sampleId.samplingId
If I remove it, that work
Paste of the error
https://pastebin.com/TF0BJn7a
hibernate jpa spring-data-jpa
I use spring boot 2.1, jpa and hibernate.
In my Samples entity
@EmbeddedId
private SampleId id;
@MapsId("samplingId")
@ManyToOne(optional = false)
private Samplings sampling;
My composite object
@Embeddable
public class SampleId implements Serializable{
private Integer samplingId;
private String sampleLetter;
//get //set
}
@Query(
value = "select s from Samples s "
+ "Join fetch s.sampling sp "
+ "where sp.id >= :sampleId.samplingId and s.id !=:sampleId "
+ "order by s.id.samplingId,s.id.sampleLetter"
)
public List<Samples> findNextAbsorptionTest(@Param("sampleId") SampleId sampleId);
Seem like hibernate don't like this part
sp.id >= :sampleId.samplingId
If I remove it, that work
Paste of the error
https://pastebin.com/TF0BJn7a
hibernate jpa spring-data-jpa
hibernate jpa spring-data-jpa
asked Dec 28 '18 at 16:08
robert trudelrobert trudel
1,03142651
1,03142651
1
It's not possible to use . with a parameter. Can you please post all code of your entities. How does Sampling look like?
– Simon Martinelli
Dec 28 '18 at 16:34
add a comment |
1
It's not possible to use . with a parameter. Can you please post all code of your entities. How does Sampling look like?
– Simon Martinelli
Dec 28 '18 at 16:34
1
1
It's not possible to use . with a parameter. Can you please post all code of your entities. How does Sampling look like?
– Simon Martinelli
Dec 28 '18 at 16:34
It's not possible to use . with a parameter. Can you please post all code of your entities. How does Sampling look like?
– Simon Martinelli
Dec 28 '18 at 16:34
add a comment |
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1
It's not possible to use . with a parameter. Can you please post all code of your entities. How does Sampling look like?
– Simon Martinelli
Dec 28 '18 at 16:34