How to get the link after uploading to Google Drive via api in python?

Here am using google drive API with python to upload files to google drive, how can I get the link of the uploaded file.

I tried print (res['exportLinks']), but it gives me this error.

KeyError: 'exportLinks'

Complete python code

#!/usr/bin/env python



from __future__ import print_function

import os



from apiclient import discovery

from httplib2 import Http

from oauth2client import file, client, tools



SCOPES = 'https://www.googleapis.com/auth/drive'

store = file.Storage('storage.json')

creds = store.get()

if not creds or creds.invalid:

    flow = client.flow_from_clientsecrets('client_secrets.json', SCOPES)

    creds = tools.run_flow(flow, store)

DRIVE = discovery.build('drive', 'v2', http=creds.authorize(Http()))



FILES = (('hello.txt', False),)



for filename, convert in FILES:

    metadata = {'title': filename}

    res = DRIVE.files().insert(convert=convert, body=metadata,

            media_body=filename, fields='mimeType,exportLinks').execute()

    if res:

        print (res['exportLinks'])

Is there any alternate way to do this.

thanks in advance.

edited Dec 28 '18 at 16:15

asked Dec 28 '18 at 16:09

Sumithran

7693822

1

KeyError: 'exportLinks' means there is no key 'exportLinks'. Try printing type(res) and res.keys() if its a dictionary.

– reportgunner
Dec 28 '18 at 16:17

res.keys() gives: ([u'mimeType'])

– Sumithran
Dec 28 '18 at 16:23

can you please add the result of print(res) to your question ? this is the first time I'm seeing apiclient but I figure you can import json and json.dumps(res)

– reportgunner
Dec 28 '18 at 16:33

change the fields to * and the version from v2 to v3

– pinoyyid
Dec 28 '18 at 17:06

add a comment |

Here am using google drive API with python to upload files to google drive, how can I get the link of the uploaded file.

I tried print (res['exportLinks']), but it gives me this error.

KeyError: 'exportLinks'

Complete python code

#!/usr/bin/env python



from __future__ import print_function

import os



from apiclient import discovery

from httplib2 import Http

from oauth2client import file, client, tools



SCOPES = 'https://www.googleapis.com/auth/drive'

store = file.Storage('storage.json')

creds = store.get()

if not creds or creds.invalid:

    flow = client.flow_from_clientsecrets('client_secrets.json', SCOPES)

    creds = tools.run_flow(flow, store)

DRIVE = discovery.build('drive', 'v2', http=creds.authorize(Http()))



FILES = (('hello.txt', False),)



for filename, convert in FILES:

    metadata = {'title': filename}

    res = DRIVE.files().insert(convert=convert, body=metadata,

            media_body=filename, fields='mimeType,exportLinks').execute()

    if res:

        print (res['exportLinks'])

Is there any alternate way to do this.

thanks in advance.

edited Dec 28 '18 at 16:15

asked Dec 28 '18 at 16:09

Sumithran

7693822

1

KeyError: 'exportLinks' means there is no key 'exportLinks'. Try printing type(res) and res.keys() if its a dictionary.

– reportgunner
Dec 28 '18 at 16:17

res.keys() gives: ([u'mimeType'])

– Sumithran
Dec 28 '18 at 16:23

can you please add the result of print(res) to your question ? this is the first time I'm seeing apiclient but I figure you can import json and json.dumps(res)

– reportgunner
Dec 28 '18 at 16:33

change the fields to * and the version from v2 to v3

– pinoyyid
Dec 28 '18 at 17:06

add a comment |

Here am using google drive API with python to upload files to google drive, how can I get the link of the uploaded file.

I tried print (res['exportLinks']), but it gives me this error.

KeyError: 'exportLinks'

Complete python code

#!/usr/bin/env python



from __future__ import print_function

import os



from apiclient import discovery

from httplib2 import Http

from oauth2client import file, client, tools



SCOPES = 'https://www.googleapis.com/auth/drive'

store = file.Storage('storage.json')

creds = store.get()

if not creds or creds.invalid:

    flow = client.flow_from_clientsecrets('client_secrets.json', SCOPES)

    creds = tools.run_flow(flow, store)

DRIVE = discovery.build('drive', 'v2', http=creds.authorize(Http()))



FILES = (('hello.txt', False),)



for filename, convert in FILES:

    metadata = {'title': filename}

    res = DRIVE.files().insert(convert=convert, body=metadata,

            media_body=filename, fields='mimeType,exportLinks').execute()

    if res:

        print (res['exportLinks'])

Is there any alternate way to do this.

thanks in advance.

edited Dec 28 '18 at 16:15

asked Dec 28 '18 at 16:09

Sumithran

7693822

Here am using google drive API with python to upload files to google drive, how can I get the link of the uploaded file.

I tried print (res['exportLinks']), but it gives me this error.

KeyError: 'exportLinks'

Complete python code

#!/usr/bin/env python



from __future__ import print_function

import os



from apiclient import discovery

from httplib2 import Http

from oauth2client import file, client, tools



SCOPES = 'https://www.googleapis.com/auth/drive'

store = file.Storage('storage.json')

creds = store.get()

if not creds or creds.invalid:

    flow = client.flow_from_clientsecrets('client_secrets.json', SCOPES)

    creds = tools.run_flow(flow, store)

DRIVE = discovery.build('drive', 'v2', http=creds.authorize(Http()))



FILES = (('hello.txt', False),)



for filename, convert in FILES:

    metadata = {'title': filename}

    res = DRIVE.files().insert(convert=convert, body=metadata,

            media_body=filename, fields='mimeType,exportLinks').execute()

    if res:

        print (res['exportLinks'])

Is there any alternate way to do this.

thanks in advance.

python google-drive-sdk

edited Dec 28 '18 at 16:15

asked Dec 28 '18 at 16:09

Sumithran

7693822

edited Dec 28 '18 at 16:15

asked Dec 28 '18 at 16:09

Sumithran

7693822

edited Dec 28 '18 at 16:15

asked Dec 28 '18 at 16:09

Sumithran

7693822

asked Dec 28 '18 at 16:09

Sumithran

7693822

asked Dec 28 '18 at 16:09

Sumithran

7693822

1

KeyError: 'exportLinks' means there is no key 'exportLinks'. Try printing type(res) and res.keys() if its a dictionary.

– reportgunner
Dec 28 '18 at 16:17

res.keys() gives: ([u'mimeType'])

– Sumithran
Dec 28 '18 at 16:23

can you please add the result of print(res) to your question ? this is the first time I'm seeing apiclient but I figure you can import json and json.dumps(res)

– reportgunner
Dec 28 '18 at 16:33

change the fields to * and the version from v2 to v3

– pinoyyid
Dec 28 '18 at 17:06

add a comment |

1

KeyError: 'exportLinks' means there is no key 'exportLinks'. Try printing type(res) and res.keys() if its a dictionary.

– reportgunner
Dec 28 '18 at 16:17

res.keys() gives: ([u'mimeType'])

– Sumithran
Dec 28 '18 at 16:23

can you please add the result of print(res) to your question ? this is the first time I'm seeing apiclient but I figure you can import json and json.dumps(res)

– reportgunner
Dec 28 '18 at 16:33

change the fields to * and the version from v2 to v3

– pinoyyid
Dec 28 '18 at 17:06

KeyError: 'exportLinks' means there is no key 'exportLinks'. Try printing type(res) and res.keys() if its a dictionary.

– reportgunner
Dec 28 '18 at 16:17

res.keys() gives: ([u'mimeType'])

– Sumithran
Dec 28 '18 at 16:23

can you please add the result of print(res) to your question ? this is the first time I'm seeing apiclient but I figure you can import json and json.dumps(res)

– reportgunner
Dec 28 '18 at 16:33

change the fields to * and the version from v2 to v3

– pinoyyid
Dec 28 '18 at 17:06

add a comment |

1 Answer
1

active

oldest

votes

I found this page, it says you can get the id of the uploaded file by calling file.get('id') - that is res.get('id') in your case.

try this code

    # ...

    res = DRIVE.files().insert(convert=convert, body=metadata,

        media_body=filename, fields='mimeType,exportLinks,id').execute() # <-- EDIT: added id here

    print('Uploaded file to {url}'.format(url='https://drive.google.com/open?id=' + res.get('id')))

edited Dec 28 '18 at 17:06

answered Dec 28 '18 at 16:41

reportgunner

3339

res.get('id') returns None

– Sumithran
Dec 28 '18 at 17:01

was the file uploaded though ? it would make sense to return None if no file was uploaded

– reportgunner
Dec 28 '18 at 17:04

@Sumithran aha I think I got it, you have to add the id to fields of your .execute(), see my edited answer in a sec

– reportgunner
Dec 28 '18 at 17:06

add a comment |

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1 Answer
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1 Answer
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oldest

votes

I found this page, it says you can get the id of the uploaded file by calling file.get('id') - that is res.get('id') in your case.

try this code

    # ...

    res = DRIVE.files().insert(convert=convert, body=metadata,

        media_body=filename, fields='mimeType,exportLinks,id').execute() # <-- EDIT: added id here

    print('Uploaded file to {url}'.format(url='https://drive.google.com/open?id=' + res.get('id')))

edited Dec 28 '18 at 17:06

answered Dec 28 '18 at 16:41

reportgunner

3339

res.get('id') returns None

– Sumithran
Dec 28 '18 at 17:01

was the file uploaded though ? it would make sense to return None if no file was uploaded

– reportgunner
Dec 28 '18 at 17:04

@Sumithran aha I think I got it, you have to add the id to fields of your .execute(), see my edited answer in a sec

– reportgunner
Dec 28 '18 at 17:06

add a comment |

I found this page, it says you can get the id of the uploaded file by calling file.get('id') - that is res.get('id') in your case.

try this code

    # ...

    res = DRIVE.files().insert(convert=convert, body=metadata,

        media_body=filename, fields='mimeType,exportLinks,id').execute() # <-- EDIT: added id here

    print('Uploaded file to {url}'.format(url='https://drive.google.com/open?id=' + res.get('id')))

edited Dec 28 '18 at 17:06

answered Dec 28 '18 at 16:41

reportgunner

3339

res.get('id') returns None

– Sumithran
Dec 28 '18 at 17:01

was the file uploaded though ? it would make sense to return None if no file was uploaded

– reportgunner
Dec 28 '18 at 17:04

@Sumithran aha I think I got it, you have to add the id to fields of your .execute(), see my edited answer in a sec

– reportgunner
Dec 28 '18 at 17:06

add a comment |

I found this page, it says you can get the id of the uploaded file by calling file.get('id') - that is res.get('id') in your case.

try this code

    # ...

    res = DRIVE.files().insert(convert=convert, body=metadata,

        media_body=filename, fields='mimeType,exportLinks,id').execute() # <-- EDIT: added id here

    print('Uploaded file to {url}'.format(url='https://drive.google.com/open?id=' + res.get('id')))

edited Dec 28 '18 at 17:06

answered Dec 28 '18 at 16:41

reportgunner

3339

I found this page, it says you can get the id of the uploaded file by calling file.get('id') - that is res.get('id') in your case.

try this code

    # ...

    res = DRIVE.files().insert(convert=convert, body=metadata,

        media_body=filename, fields='mimeType,exportLinks,id').execute() # <-- EDIT: added id here

    print('Uploaded file to {url}'.format(url='https://drive.google.com/open?id=' + res.get('id')))

edited Dec 28 '18 at 17:06

answered Dec 28 '18 at 16:41

reportgunner

3339

edited Dec 28 '18 at 17:06

answered Dec 28 '18 at 16:41

reportgunner

3339

answered Dec 28 '18 at 16:41

reportgunner

3339

answered Dec 28 '18 at 16:41

reportgunner

3339

res.get('id') returns None

– Sumithran
Dec 28 '18 at 17:01

was the file uploaded though ? it would make sense to return None if no file was uploaded

– reportgunner
Dec 28 '18 at 17:04

@Sumithran aha I think I got it, you have to add the id to fields of your .execute(), see my edited answer in a sec

– reportgunner
Dec 28 '18 at 17:06

add a comment |

res.get('id') returns None

– Sumithran
Dec 28 '18 at 17:01

was the file uploaded though ? it would make sense to return None if no file was uploaded

– reportgunner
Dec 28 '18 at 17:04

@Sumithran aha I think I got it, you have to add the id to fields of your .execute(), see my edited answer in a sec

– reportgunner
Dec 28 '18 at 17:06

res.get('id') returns None

– Sumithran
Dec 28 '18 at 17:01

was the file uploaded though ? it would make sense to return None if no file was uploaded

– reportgunner
Dec 28 '18 at 17:04

@Sumithran aha I think I got it, you have to add the id to fields of your .execute(), see my edited answer in a sec

– reportgunner
Dec 28 '18 at 17:06

add a comment |

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