How to connect two systems (thrift server and client) using serial connection?
I am a beginner in thrift concept and I want to connect my thrift client to thrift server using serial connection. I am using java on client side.
I already have connected both the client and server using TCP/IP by providing the IP and port of the server to which the client needs to be connected.
Question is how to connect the both on serial connection?
What information do I need to provide in order to establish the connection?
To establish the TCP/IP connection,I have used:
TTransport transport = new TSocket("xx.xx.xx.xx", xxxxx);
Any help would be appreciated!
java thrift
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I am a beginner in thrift concept and I want to connect my thrift client to thrift server using serial connection. I am using java on client side.
I already have connected both the client and server using TCP/IP by providing the IP and port of the server to which the client needs to be connected.
Question is how to connect the both on serial connection?
What information do I need to provide in order to establish the connection?
To establish the TCP/IP connection,I have used:
TTransport transport = new TSocket("xx.xx.xx.xx", xxxxx);
Any help would be appreciated!
java thrift
add a comment |
I am a beginner in thrift concept and I want to connect my thrift client to thrift server using serial connection. I am using java on client side.
I already have connected both the client and server using TCP/IP by providing the IP and port of the server to which the client needs to be connected.
Question is how to connect the both on serial connection?
What information do I need to provide in order to establish the connection?
To establish the TCP/IP connection,I have used:
TTransport transport = new TSocket("xx.xx.xx.xx", xxxxx);
Any help would be appreciated!
java thrift
I am a beginner in thrift concept and I want to connect my thrift client to thrift server using serial connection. I am using java on client side.
I already have connected both the client and server using TCP/IP by providing the IP and port of the server to which the client needs to be connected.
Question is how to connect the both on serial connection?
What information do I need to provide in order to establish the connection?
To establish the TCP/IP connection,I have used:
TTransport transport = new TSocket("xx.xx.xx.xx", xxxxx);
Any help would be appreciated!
java thrift
java thrift
edited Jan 3 at 11:10
JensG
9,68633141
9,68633141
asked Jan 3 at 6:51
AnonAnon
586
586
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You will have to write a customized endpoint transport for the serial connection. There is no built-in transport for RS232.
Use one of the existing transports (e.g. the one for sockets) as a model. The TTransport abstract class consists only of a handful of methods that need to be implemented.
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You will have to write a customized endpoint transport for the serial connection. There is no built-in transport for RS232.
Use one of the existing transports (e.g. the one for sockets) as a model. The TTransport abstract class consists only of a handful of methods that need to be implemented.
add a comment |
You will have to write a customized endpoint transport for the serial connection. There is no built-in transport for RS232.
Use one of the existing transports (e.g. the one for sockets) as a model. The TTransport abstract class consists only of a handful of methods that need to be implemented.
add a comment |
You will have to write a customized endpoint transport for the serial connection. There is no built-in transport for RS232.
Use one of the existing transports (e.g. the one for sockets) as a model. The TTransport abstract class consists only of a handful of methods that need to be implemented.
You will have to write a customized endpoint transport for the serial connection. There is no built-in transport for RS232.
Use one of the existing transports (e.g. the one for sockets) as a model. The TTransport abstract class consists only of a handful of methods that need to be implemented.
answered Jan 3 at 11:15
JensGJensG
9,68633141
9,68633141
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