Angular 7 - Define routes with queryParams

Multi tool use
Multi tool use












0















I want to declare two Angular routes:




  1. For a specific item (/items?id=SOME_ITEM_ID)

  2. For a list of all items (/items)


As the following isn't working, I want to know how I can define my routes to suite my needs?



export const routes: Routes = [
{ path: 'items?id=someItemId', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];









share|improve this question


















  • 1





    You can't separate routes by query parameters.

    – cgTag
    Jan 2 at 16:06
















0















I want to declare two Angular routes:




  1. For a specific item (/items?id=SOME_ITEM_ID)

  2. For a list of all items (/items)


As the following isn't working, I want to know how I can define my routes to suite my needs?



export const routes: Routes = [
{ path: 'items?id=someItemId', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];









share|improve this question


















  • 1





    You can't separate routes by query parameters.

    – cgTag
    Jan 2 at 16:06














0












0








0








I want to declare two Angular routes:




  1. For a specific item (/items?id=SOME_ITEM_ID)

  2. For a list of all items (/items)


As the following isn't working, I want to know how I can define my routes to suite my needs?



export const routes: Routes = [
{ path: 'items?id=someItemId', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];









share|improve this question














I want to declare two Angular routes:




  1. For a specific item (/items?id=SOME_ITEM_ID)

  2. For a list of all items (/items)


As the following isn't working, I want to know how I can define my routes to suite my needs?



export const routes: Routes = [
{ path: 'items?id=someItemId', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];






angular typescript url angular-routing angular7






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Jan 2 at 16:01









FlorianFlorian

53423




53423








  • 1





    You can't separate routes by query parameters.

    – cgTag
    Jan 2 at 16:06














  • 1





    You can't separate routes by query parameters.

    – cgTag
    Jan 2 at 16:06








1




1





You can't separate routes by query parameters.

– cgTag
Jan 2 at 16:06





You can't separate routes by query parameters.

– cgTag
Jan 2 at 16:06












1 Answer
1






active

oldest

votes


















4














I think you don't want queryParams but params, you should define your route like this :



export const routes: Routes = [
{ path: 'items/:id', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];


As @cgTag says in comment, queryParams are transparent and you don't need to declare them in route definition.






share|improve this answer
























  • Okay, I thought it would also be possible to declare queryParams. Thank you.

    – Florian
    Jan 2 at 16:11






  • 1





    @Florian, that's not needed. You can write anything inside the queryString and the route will still work (:

    – enf0rcer
    Jan 2 at 17:53











Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54009430%2fangular-7-define-routes-with-queryparams%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














I think you don't want queryParams but params, you should define your route like this :



export const routes: Routes = [
{ path: 'items/:id', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];


As @cgTag says in comment, queryParams are transparent and you don't need to declare them in route definition.






share|improve this answer
























  • Okay, I thought it would also be possible to declare queryParams. Thank you.

    – Florian
    Jan 2 at 16:11






  • 1





    @Florian, that's not needed. You can write anything inside the queryString and the route will still work (:

    – enf0rcer
    Jan 2 at 17:53
















4














I think you don't want queryParams but params, you should define your route like this :



export const routes: Routes = [
{ path: 'items/:id', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];


As @cgTag says in comment, queryParams are transparent and you don't need to declare them in route definition.






share|improve this answer
























  • Okay, I thought it would also be possible to declare queryParams. Thank you.

    – Florian
    Jan 2 at 16:11






  • 1





    @Florian, that's not needed. You can write anything inside the queryString and the route will still work (:

    – enf0rcer
    Jan 2 at 17:53














4












4








4







I think you don't want queryParams but params, you should define your route like this :



export const routes: Routes = [
{ path: 'items/:id', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];


As @cgTag says in comment, queryParams are transparent and you don't need to declare them in route definition.






share|improve this answer













I think you don't want queryParams but params, you should define your route like this :



export const routes: Routes = [
{ path: 'items/:id', component: ItemComponent },
{ path: 'items', component: AllItemsComponent },
];


As @cgTag says in comment, queryParams are transparent and you don't need to declare them in route definition.







share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 2 at 16:05









Louis RLouis R

492212




492212













  • Okay, I thought it would also be possible to declare queryParams. Thank you.

    – Florian
    Jan 2 at 16:11






  • 1





    @Florian, that's not needed. You can write anything inside the queryString and the route will still work (:

    – enf0rcer
    Jan 2 at 17:53



















  • Okay, I thought it would also be possible to declare queryParams. Thank you.

    – Florian
    Jan 2 at 16:11






  • 1





    @Florian, that's not needed. You can write anything inside the queryString and the route will still work (:

    – enf0rcer
    Jan 2 at 17:53

















Okay, I thought it would also be possible to declare queryParams. Thank you.

– Florian
Jan 2 at 16:11





Okay, I thought it would also be possible to declare queryParams. Thank you.

– Florian
Jan 2 at 16:11




1




1





@Florian, that's not needed. You can write anything inside the queryString and the route will still work (:

– enf0rcer
Jan 2 at 17:53





@Florian, that's not needed. You can write anything inside the queryString and the route will still work (:

– enf0rcer
Jan 2 at 17:53




















draft saved

draft discarded




















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f54009430%2fangular-7-define-routes-with-queryparams%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







w3,ughGl p trp0xMbrTB,Xz9kv DT 8if,XnF zV Sx1Jh,OhY P BsIcYnNjVxP9u K7 5 5kda,OEs,6HR99Ct5eDuDIT6YT
7EC0VLiUgTzK9Dq4PUGVz4dThwiaLzZHDxVdjeugeRRd vZ0Ex3 eAZvE

Popular posts from this blog

Monofisismo

Angular Downloading a file using contenturl with Basic Authentication

Olmecas