not all arguments converted during string formatting.. NO % variables
x = input()
y = 1
print (x)
while 1 == y:
if x == 1:
y == y + 1
elif x % 2 == 0: #even
x = x // 2
print (x)
else:
x = 3 * x + 1
print (x)
If you know what the Collatz conjecture is, I'm trying to make a calculator for that. I want to have x as my input so I don't have to change x's number and save every time I want to try out a new number.
I get below error
TypeError: not all arguments converted during string formatting'
at line 7.
Please help a noobie out.
python python-3.x typeerror
add a comment |
x = input()
y = 1
print (x)
while 1 == y:
if x == 1:
y == y + 1
elif x % 2 == 0: #even
x = x // 2
print (x)
else:
x = 3 * x + 1
print (x)
If you know what the Collatz conjecture is, I'm trying to make a calculator for that. I want to have x as my input so I don't have to change x's number and save every time I want to try out a new number.
I get below error
TypeError: not all arguments converted during string formatting'
at line 7.
Please help a noobie out.
python python-3.x typeerror
Note that the code below the while loop isn't correctly indented.
– Zcode
Aug 4 '17 at 11:51
add a comment |
x = input()
y = 1
print (x)
while 1 == y:
if x == 1:
y == y + 1
elif x % 2 == 0: #even
x = x // 2
print (x)
else:
x = 3 * x + 1
print (x)
If you know what the Collatz conjecture is, I'm trying to make a calculator for that. I want to have x as my input so I don't have to change x's number and save every time I want to try out a new number.
I get below error
TypeError: not all arguments converted during string formatting'
at line 7.
Please help a noobie out.
python python-3.x typeerror
x = input()
y = 1
print (x)
while 1 == y:
if x == 1:
y == y + 1
elif x % 2 == 0: #even
x = x // 2
print (x)
else:
x = 3 * x + 1
print (x)
If you know what the Collatz conjecture is, I'm trying to make a calculator for that. I want to have x as my input so I don't have to change x's number and save every time I want to try out a new number.
I get below error
TypeError: not all arguments converted during string formatting'
at line 7.
Please help a noobie out.
python python-3.x typeerror
python python-3.x typeerror
edited Aug 4 '17 at 10:10
juanpa.arrivillaga
38.3k33975
38.3k33975
asked Aug 4 '17 at 5:56
Lance TecsonLance Tecson
11112
11112
Note that the code below the while loop isn't correctly indented.
– Zcode
Aug 4 '17 at 11:51
add a comment |
Note that the code below the while loop isn't correctly indented.
– Zcode
Aug 4 '17 at 11:51
Note that the code below the while loop isn't correctly indented.
– Zcode
Aug 4 '17 at 11:51
Note that the code below the while loop isn't correctly indented.
– Zcode
Aug 4 '17 at 11:51
add a comment |
1 Answer
1
active
oldest
votes
The problem is that you take user input:
x = input()
Now x
is a str
. So, on this line:
elif x % 2 == 0: #even
The %
operator acts as a string interpolation operator.
>>> mystring = "Here goes a string: %s and here an int: %d" % ('FOO', 88)
>>> print(mystring)
Here goes a string: FOO and here an int: 88
>>>
However, the input
you gave does not have a format specifier, thus:
>>> "a string with no format specifier..." % 10
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: not all arguments converted during string formatting
>>>
You need to convert your user input into an int
for the %
operator to perform the modulo operation.
x = int(input())
Now, it will do what you want:
>>> x = int(input("Gimme an int! "))
Gimme an int! 88
>>> x % 10
8
>>>
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
The problem is that you take user input:
x = input()
Now x
is a str
. So, on this line:
elif x % 2 == 0: #even
The %
operator acts as a string interpolation operator.
>>> mystring = "Here goes a string: %s and here an int: %d" % ('FOO', 88)
>>> print(mystring)
Here goes a string: FOO and here an int: 88
>>>
However, the input
you gave does not have a format specifier, thus:
>>> "a string with no format specifier..." % 10
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: not all arguments converted during string formatting
>>>
You need to convert your user input into an int
for the %
operator to perform the modulo operation.
x = int(input())
Now, it will do what you want:
>>> x = int(input("Gimme an int! "))
Gimme an int! 88
>>> x % 10
8
>>>
add a comment |
The problem is that you take user input:
x = input()
Now x
is a str
. So, on this line:
elif x % 2 == 0: #even
The %
operator acts as a string interpolation operator.
>>> mystring = "Here goes a string: %s and here an int: %d" % ('FOO', 88)
>>> print(mystring)
Here goes a string: FOO and here an int: 88
>>>
However, the input
you gave does not have a format specifier, thus:
>>> "a string with no format specifier..." % 10
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: not all arguments converted during string formatting
>>>
You need to convert your user input into an int
for the %
operator to perform the modulo operation.
x = int(input())
Now, it will do what you want:
>>> x = int(input("Gimme an int! "))
Gimme an int! 88
>>> x % 10
8
>>>
add a comment |
The problem is that you take user input:
x = input()
Now x
is a str
. So, on this line:
elif x % 2 == 0: #even
The %
operator acts as a string interpolation operator.
>>> mystring = "Here goes a string: %s and here an int: %d" % ('FOO', 88)
>>> print(mystring)
Here goes a string: FOO and here an int: 88
>>>
However, the input
you gave does not have a format specifier, thus:
>>> "a string with no format specifier..." % 10
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: not all arguments converted during string formatting
>>>
You need to convert your user input into an int
for the %
operator to perform the modulo operation.
x = int(input())
Now, it will do what you want:
>>> x = int(input("Gimme an int! "))
Gimme an int! 88
>>> x % 10
8
>>>
The problem is that you take user input:
x = input()
Now x
is a str
. So, on this line:
elif x % 2 == 0: #even
The %
operator acts as a string interpolation operator.
>>> mystring = "Here goes a string: %s and here an int: %d" % ('FOO', 88)
>>> print(mystring)
Here goes a string: FOO and here an int: 88
>>>
However, the input
you gave does not have a format specifier, thus:
>>> "a string with no format specifier..." % 10
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: not all arguments converted during string formatting
>>>
You need to convert your user input into an int
for the %
operator to perform the modulo operation.
x = int(input())
Now, it will do what you want:
>>> x = int(input("Gimme an int! "))
Gimme an int! 88
>>> x % 10
8
>>>
answered Aug 4 '17 at 6:11
juanpa.arrivillagajuanpa.arrivillaga
38.3k33975
38.3k33975
add a comment |
add a comment |
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Note that the code below the while loop isn't correctly indented.
– Zcode
Aug 4 '17 at 11:51