Save XML in custom order of attribute in Python [duplicate]
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This question already has an answer here:
Preserving XML attribute order?
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I am trying to get specific order of XML attribute.
Given
<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>
Required :
<OKV v="1" n="****" i="****" d="****" e="****" m="*****" g="****" a="*****" r="*****" s="*****"/>
I am trying to implement in Python.
So far when I am using xml library.
import xml.etree.ElementTree as ET
tree = ET.parse('adhar.xml')
But it keeps read in that format,
Please tell how to change the order.
As I am reading correctly in internet explorer when opened the file, But getting reversed order while reading the file or see it in Chrome.
python xml sorting encoding
asked Jan 4 at 6:56
Chinmay DasChinmay Das
929
marked as duplicate by kjhughes xml
Users with the xml badge can single-handedly close xml questions as duplicates and reopen them as needed.
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Jan 4 at 15:58
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Preserving XML attribute order?
1 answer
I am trying to get specific order of XML attribute.
Given
<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>
Required :
<OKV v="1" n="****" i="****" d="****" e="****" m="*****" g="****" a="*****" r="*****" s="*****"/>
I am trying to implement in Python.
So far when I am using xml library.
import xml.etree.ElementTree as ET
tree = ET.parse('adhar.xml')
But it keeps read in that format,
Please tell how to change the order.
As I am reading correctly in internet explorer when opened the file, But getting reversed order while reading the file or see it in Chrome.
python xml sorting encoding
asked Jan 4 at 6:56
Chinmay DasChinmay Das
929
marked as duplicate by kjhughes xml
Users with the xml badge can single-handedly close xml questions as duplicates and reopen them as needed.
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Jan 4 at 15:58
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
This question already has an answer here:
Preserving XML attribute order?
1 answer
I am trying to get specific order of XML attribute.
Given
<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>
Required :
<OKV v="1" n="****" i="****" d="****" e="****" m="*****" g="****" a="*****" r="*****" s="*****"/>
I am trying to implement in Python.
So far when I am using xml library.
import xml.etree.ElementTree as ET
tree = ET.parse('adhar.xml')
But it keeps read in that format,
Please tell how to change the order.
As I am reading correctly in internet explorer when opened the file, But getting reversed order while reading the file or see it in Chrome.
python xml sorting encoding
asked Jan 4 at 6:56
Chinmay DasChinmay Das
929
This question already has an answer here:
Preserving XML attribute order?
1 answer
I am trying to get specific order of XML attribute.
Given
<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>
Required :
<OKV v="1" n="****" i="****" d="****" e="****" m="*****" g="****" a="*****" r="*****" s="*****"/>
I am trying to implement in Python.
So far when I am using xml library.
import xml.etree.ElementTree as ET
tree = ET.parse('adhar.xml')
But it keeps read in that format,
Please tell how to change the order.
As I am reading correctly in internet explorer when opened the file, But getting reversed order while reading the file or see it in Chrome.
This question already has an answer here:
Preserving XML attribute order?
1 answer
python xml sorting encoding
python xml sorting encoding
asked Jan 4 at 6:56
Chinmay DasChinmay Das
929
asked Jan 4 at 6:56
Chinmay DasChinmay Das
929
asked Jan 4 at 6:56
Chinmay DasChinmay Das
929
asked Jan 4 at 6:56
Chinmay DasChinmay Das
929
asked Jan 4 at 6:56
Chinmay DasChinmay Das
929
929
marked as duplicate by kjhughes xml
Users with the xml badge can single-handedly close xml questions as duplicates and reopen them as needed.
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Jan 4 at 15:58
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
marked as duplicate by kjhughes xml
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Jan 4 at 15:58
This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.
add a comment |
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2 Answers
2
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oldest
votes
For this specific xml string you could use xmltodict (install with pip install xmltodict). This converts the xml data to a python dictionary. Using the following would reverse the order of the OKV entry:
import xmltodict
import collections
xml_data = '<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>'
xml_data_parsed = xmltodict.parse(xml_data)
xml_data_parsed["OKV"] = collections.OrderedDict(reversed(list(xml_data_parsed["OKV"].items())))
xml_data = xmltodict.unparse(xml_data_parsed)
If the the part you want to reorder is embedded in a larger xml document you would have to select the deeper nested key to get to e.g. OKV.
answered Jan 4 at 7:34
AscurionAscurion
36519
add a comment |
Try using lxml to parse the xml file. As suggested here, it might help get the attributes in the appropriate order.
answered Jan 4 at 7:03
BabokBabok
466
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
For this specific xml string you could use xmltodict (install with pip install xmltodict). This converts the xml data to a python dictionary. Using the following would reverse the order of the OKV entry:
import xmltodict
import collections
xml_data = '<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>'
xml_data_parsed = xmltodict.parse(xml_data)
xml_data_parsed["OKV"] = collections.OrderedDict(reversed(list(xml_data_parsed["OKV"].items())))
xml_data = xmltodict.unparse(xml_data_parsed)
If the the part you want to reorder is embedded in a larger xml document you would have to select the deeper nested key to get to e.g. OKV.
answered Jan 4 at 7:34
AscurionAscurion
36519
add a comment |
For this specific xml string you could use xmltodict (install with pip install xmltodict). This converts the xml data to a python dictionary. Using the following would reverse the order of the OKV entry:
import xmltodict
import collections
xml_data = '<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>'
xml_data_parsed = xmltodict.parse(xml_data)
xml_data_parsed["OKV"] = collections.OrderedDict(reversed(list(xml_data_parsed["OKV"].items())))
xml_data = xmltodict.unparse(xml_data_parsed)
If the the part you want to reorder is embedded in a larger xml document you would have to select the deeper nested key to get to e.g. OKV.
answered Jan 4 at 7:34
AscurionAscurion
36519
add a comment |
For this specific xml string you could use xmltodict (install with pip install xmltodict). This converts the xml data to a python dictionary. Using the following would reverse the order of the OKV entry:
import xmltodict
import collections
xml_data = '<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>'
xml_data_parsed = xmltodict.parse(xml_data)
xml_data_parsed["OKV"] = collections.OrderedDict(reversed(list(xml_data_parsed["OKV"].items())))
xml_data = xmltodict.unparse(xml_data_parsed)
If the the part you want to reorder is embedded in a larger xml document you would have to select the deeper nested key to get to e.g. OKV.
answered Jan 4 at 7:34
AscurionAscurion
36519
For this specific xml string you could use xmltodict (install with pip install xmltodict). This converts the xml data to a python dictionary. Using the following would reverse the order of the OKV entry:
import xmltodict
import collections
xml_data = '<OKV s="*****" r="*****" a="*****" g="****" m="*****" e="****" d="****" i="****" n="****" v="1"/>'
xml_data_parsed = xmltodict.parse(xml_data)
xml_data_parsed["OKV"] = collections.OrderedDict(reversed(list(xml_data_parsed["OKV"].items())))
xml_data = xmltodict.unparse(xml_data_parsed)
If the the part you want to reorder is embedded in a larger xml document you would have to select the deeper nested key to get to e.g. OKV.
answered Jan 4 at 7:34
AscurionAscurion
36519
edited Jan 4 at 9:38
answered Jan 4 at 7:34
AscurionAscurion
36519
answered Jan 4 at 7:34
AscurionAscurion
36519
answered Jan 4 at 7:34
AscurionAscurion
36519
36519
add a comment |
add a comment |
Try using lxml to parse the xml file. As suggested here, it might help get the attributes in the appropriate order.
answered Jan 4 at 7:03
BabokBabok
466
add a comment |
Try using lxml to parse the xml file. As suggested here, it might help get the attributes in the appropriate order.
answered Jan 4 at 7:03
BabokBabok
466
add a comment |
Try using lxml to parse the xml file. As suggested here, it might help get the attributes in the appropriate order.
answered Jan 4 at 7:03
BabokBabok
466
Try using lxml to parse the xml file. As suggested here, it might help get the attributes in the appropriate order.
answered Jan 4 at 7:03
BabokBabok
466
answered Jan 4 at 7:03
BabokBabok
466
answered Jan 4 at 7:03
BabokBabok
466
answered Jan 4 at 7:03
BabokBabok
466
466
add a comment |
add a comment |
