RestClient send IFormFile
0
I am receiving a file from my controller as
public async Task<IActionResult> ScanFile(IFormFile request)
and how can I pass this in RestSharp as shown below in AddParameter.
I tried setting my own boundary and serialize IFormFile nothing worked out.
var client = new RestClient("https://api_url/requests");
var request = new RestRequest(Method.POST);
request.AddHeader("authorization", "bearer API_TOKEN");
request.AddHeader("accept", "application/json");
request.AddHeader("content-type", "multipart/form-data; boundary=---011000010111000001101001");
request.AddParameter("multipart/form-data; boundary=---011000010111000001101001", "-----011000010111000001101001rnContent-Disposition: form-data; name="file"; filename="eicar.com"rnContent-Type: text/plainrnrnX5O!P%@AP[4\PZX54(P^)7CC)7}$EICAR-STANDARD-ANTIVIRUS-TEST-FILE!$H+H*rn-----011000010111000001101001--", ParameterType.RequestBody);
IRestResponse response = client.Execute(request);
c# asp.net-core multipartform-data restsharp
asked Mar 8 '18 at 14:09
HulkHulk
1961415
add a comment |
0
I am receiving a file from my controller as
public async Task<IActionResult> ScanFile(IFormFile request)
and how can I pass this in RestSharp as shown below in AddParameter.
I tried setting my own boundary and serialize IFormFile nothing worked out.
var client = new RestClient("https://api_url/requests");
var request = new RestRequest(Method.POST);
request.AddHeader("authorization", "bearer API_TOKEN");
request.AddHeader("accept", "application/json");
request.AddHeader("content-type", "multipart/form-data; boundary=---011000010111000001101001");
request.AddParameter("multipart/form-data; boundary=---011000010111000001101001", "-----011000010111000001101001rnContent-Disposition: form-data; name="file"; filename="eicar.com"rnContent-Type: text/plainrnrnX5O!P%@AP[4\PZX54(P^)7CC)7}$EICAR-STANDARD-ANTIVIRUS-TEST-FILE!$H+H*rn-----011000010111000001101001--", ParameterType.RequestBody);
IRestResponse response = client.Execute(request);
c# asp.net-core multipartform-data restsharp
asked Mar 8 '18 at 14:09
HulkHulk
1961415
Did you check this post if it helps? stackoverflow.com/questions/22799392/…
– alsami
Mar 8 '18 at 14:17
You would need to read theIFormFilestream into a byte array. The easiest way to do that is to copy it to aMemoryStreamand then utilizeToArrayon that. Then, send the byte array in your request.
– Chris Pratt
Mar 8 '18 at 14:38
add a comment |
0
0
0
I am receiving a file from my controller as
public async Task<IActionResult> ScanFile(IFormFile request)
and how can I pass this in RestSharp as shown below in AddParameter.
I tried setting my own boundary and serialize IFormFile nothing worked out.
var client = new RestClient("https://api_url/requests");
var request = new RestRequest(Method.POST);
request.AddHeader("authorization", "bearer API_TOKEN");
request.AddHeader("accept", "application/json");
request.AddHeader("content-type", "multipart/form-data; boundary=---011000010111000001101001");
request.AddParameter("multipart/form-data; boundary=---011000010111000001101001", "-----011000010111000001101001rnContent-Disposition: form-data; name="file"; filename="eicar.com"rnContent-Type: text/plainrnrnX5O!P%@AP[4\PZX54(P^)7CC)7}$EICAR-STANDARD-ANTIVIRUS-TEST-FILE!$H+H*rn-----011000010111000001101001--", ParameterType.RequestBody);
IRestResponse response = client.Execute(request);
c# asp.net-core multipartform-data restsharp
asked Mar 8 '18 at 14:09
HulkHulk
1961415
I am receiving a file from my controller as
public async Task<IActionResult> ScanFile(IFormFile request)
and how can I pass this in RestSharp as shown below in AddParameter.
I tried setting my own boundary and serialize IFormFile nothing worked out.
var client = new RestClient("https://api_url/requests");
var request = new RestRequest(Method.POST);
request.AddHeader("authorization", "bearer API_TOKEN");
request.AddHeader("accept", "application/json");
request.AddHeader("content-type", "multipart/form-data; boundary=---011000010111000001101001");
request.AddParameter("multipart/form-data; boundary=---011000010111000001101001", "-----011000010111000001101001rnContent-Disposition: form-data; name="file"; filename="eicar.com"rnContent-Type: text/plainrnrnX5O!P%@AP[4\PZX54(P^)7CC)7}$EICAR-STANDARD-ANTIVIRUS-TEST-FILE!$H+H*rn-----011000010111000001101001--", ParameterType.RequestBody);
IRestResponse response = client.Execute(request);
c# asp.net-core multipartform-data restsharp
c# asp.net-core multipartform-data restsharp
asked Mar 8 '18 at 14:09
HulkHulk
1961415
asked Mar 8 '18 at 14:09
HulkHulk
1961415
asked Mar 8 '18 at 14:09
HulkHulk
1961415
asked Mar 8 '18 at 14:09
HulkHulk
1961415
asked Mar 8 '18 at 14:09
HulkHulk
1961415
1961415
Did you check this post if it helps? stackoverflow.com/questions/22799392/…
– alsami
Mar 8 '18 at 14:17
You would need to read theIFormFilestream into a byte array. The easiest way to do that is to copy it to aMemoryStreamand then utilizeToArrayon that. Then, send the byte array in your request.
– Chris Pratt
Mar 8 '18 at 14:38
add a comment |
Did you check this post if it helps? stackoverflow.com/questions/22799392/…
– alsami
Mar 8 '18 at 14:17
You would need to read theIFormFilestream into a byte array. The easiest way to do that is to copy it to aMemoryStreamand then utilizeToArrayon that. Then, send the byte array in your request.
– Chris Pratt
Mar 8 '18 at 14:38
Did you check this post if it helps? stackoverflow.com/questions/22799392/…
– alsami
Mar 8 '18 at 14:17
Did you check this post if it helps? stackoverflow.com/questions/22799392/…
– alsami
Mar 8 '18 at 14:17
You would need to read the
IFormFile stream into a byte array. The easiest way to do that is to copy it to a MemoryStream and then utilize ToArray on that. Then, send the byte array in your request.– Chris Pratt
Mar 8 '18 at 14:38
You would need to read the
IFormFile stream into a byte array. The easiest way to do that is to copy it to a MemoryStream and then utilize ToArray on that. Then, send the byte array in your request.– Chris Pratt
Mar 8 '18 at 14:38
add a comment |
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Did you check this post if it helps? stackoverflow.com/questions/22799392/…
– alsami
Mar 8 '18 at 14:17
You would need to read the
IFormFilestream into a byte array. The easiest way to do that is to copy it to aMemoryStreamand then utilizeToArrayon that. Then, send the byte array in your request.– Chris Pratt
Mar 8 '18 at 14:38