Prometheus: How does the rate function calculate per second rate when scrape interval is longer?












0















From Prometheus documentation rate function does the following:




rate(v range-vector) calculates the per-second average rate of
increase of the time series in the range vector.




How is that possible when scrape interval is longer like 15 seconds? I mean how does Prometheus estimate "per-second" value when the data points are at least 15 seconds far away?
I assume that the change is estimated to be uniform in the scrape interval but want to be sure.










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    0















    From Prometheus documentation rate function does the following:




    rate(v range-vector) calculates the per-second average rate of
    increase of the time series in the range vector.




    How is that possible when scrape interval is longer like 15 seconds? I mean how does Prometheus estimate "per-second" value when the data points are at least 15 seconds far away?
    I assume that the change is estimated to be uniform in the scrape interval but want to be sure.










    share|improve this question

























      0












      0








      0








      From Prometheus documentation rate function does the following:




      rate(v range-vector) calculates the per-second average rate of
      increase of the time series in the range vector.




      How is that possible when scrape interval is longer like 15 seconds? I mean how does Prometheus estimate "per-second" value when the data points are at least 15 seconds far away?
      I assume that the change is estimated to be uniform in the scrape interval but want to be sure.










      share|improve this question














      From Prometheus documentation rate function does the following:




      rate(v range-vector) calculates the per-second average rate of
      increase of the time series in the range vector.




      How is that possible when scrape interval is longer like 15 seconds? I mean how does Prometheus estimate "per-second" value when the data points are at least 15 seconds far away?
      I assume that the change is estimated to be uniform in the scrape interval but want to be sure.







      prometheus






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      asked Jan 2 at 4:49









      Farzad VertigoFarzad Vertigo

      590412




      590412
























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          I assume that the change is estimated to be uniform in the scrape interval but want to be sure.




          Yes, that's the case. The units of the return value are per-second.






          share|improve this answer























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            1 Answer
            1






            active

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            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1















            I assume that the change is estimated to be uniform in the scrape interval but want to be sure.




            Yes, that's the case. The units of the return value are per-second.






            share|improve this answer




























              1















              I assume that the change is estimated to be uniform in the scrape interval but want to be sure.




              Yes, that's the case. The units of the return value are per-second.






              share|improve this answer


























                1












                1








                1








                I assume that the change is estimated to be uniform in the scrape interval but want to be sure.




                Yes, that's the case. The units of the return value are per-second.






                share|improve this answer














                I assume that the change is estimated to be uniform in the scrape interval but want to be sure.




                Yes, that's the case. The units of the return value are per-second.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Jan 2 at 10:04









                brian-brazilbrian-brazil

                15.3k12938




                15.3k12938
































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