Obtain 2nd Character in a list [closed]

-1

I am trying to create a loop function whereby if the 2nd character of each word in a sentence = 'R', then it will be printed out.

st = 'Print only the words'



for word in st.split():

    if word[1] == 'r':

        print(word)

I keep getting the error string index is out of range.

asked Jan 2 at 4:48

Javier

314212

closed as off-topic by tripleee, jww, andrew_reece, Machavity, Makyen Jan 4 at 22:27

This question appears to be off-topic. The users who voted to close gave this specific reason:

"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – tripleee, jww, andrew_reece, Machavity

If this question can be reworded to fit the rules in the help center, please edit the question.

5

Works for me. You sure this is the exact example? No input data with 1-letter words like 'a'?

– schwobaseggl
Jan 2 at 4:50

It works for me too.

– GeekSambhu
Jan 2 at 4:51

Either catch the exception or check the string length.

– t.m.adam
Jan 2 at 4:53

@schwobaseggl nope this is just a simplified version of what I'm trying to achieve. I think I made a mistake in the qn somewhere! Thanks!

– Javier
Jan 2 at 4:53

in question statement you mentions R and in code you are using r . is your 2nd character is case sensitive ?

– prashant rana
Jan 2 at 5:39

add a comment |

-1

I am trying to create a loop function whereby if the 2nd character of each word in a sentence = 'R', then it will be printed out.

st = 'Print only the words'



for word in st.split():

    if word[1] == 'r':

        print(word)

I keep getting the error string index is out of range.

asked Jan 2 at 4:48

Javier

314212

closed as off-topic by tripleee, jww, andrew_reece, Machavity, Makyen Jan 4 at 22:27

This question appears to be off-topic. The users who voted to close gave this specific reason:

"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – tripleee, jww, andrew_reece, Machavity

If this question can be reworded to fit the rules in the help center, please edit the question.

5

Works for me. You sure this is the exact example? No input data with 1-letter words like 'a'?

– schwobaseggl
Jan 2 at 4:50

It works for me too.

– GeekSambhu
Jan 2 at 4:51

Either catch the exception or check the string length.

– t.m.adam
Jan 2 at 4:53

@schwobaseggl nope this is just a simplified version of what I'm trying to achieve. I think I made a mistake in the qn somewhere! Thanks!

– Javier
Jan 2 at 4:53

in question statement you mentions R and in code you are using r . is your 2nd character is case sensitive ?

– prashant rana
Jan 2 at 5:39

add a comment |

-1

I am trying to create a loop function whereby if the 2nd character of each word in a sentence = 'R', then it will be printed out.

st = 'Print only the words'



for word in st.split():

    if word[1] == 'r':

        print(word)

I keep getting the error string index is out of range.

asked Jan 2 at 4:48

Javier

314212

I am trying to create a loop function whereby if the 2nd character of each word in a sentence = 'R', then it will be printed out.

st = 'Print only the words'



for word in st.split():

    if word[1] == 'r':

        print(word)

I keep getting the error string index is out of range.

python

asked Jan 2 at 4:48

Javier

314212

asked Jan 2 at 4:48

Javier

314212

asked Jan 2 at 4:48

Javier

314212

asked Jan 2 at 4:48

Javier

314212

asked Jan 2 at 4:48

Javier

314212

closed as off-topic by tripleee, jww, andrew_reece, Machavity, Makyen Jan 4 at 22:27

This question appears to be off-topic. The users who voted to close gave this specific reason:

"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – tripleee, jww, andrew_reece, Machavity

If this question can be reworded to fit the rules in the help center, please edit the question.

closed as off-topic by tripleee, jww, andrew_reece, Machavity, Makyen Jan 4 at 22:27

This question appears to be off-topic. The users who voted to close gave this specific reason:

"This question was caused by a problem that can no longer be reproduced or a simple typographical error. While similar questions may be on-topic here, this one was resolved in a manner unlikely to help future readers. This can often be avoided by identifying and closely inspecting the shortest program necessary to reproduce the problem before posting." – tripleee, jww, andrew_reece, Machavity

If this question can be reworded to fit the rules in the help center, please edit the question.

5

Works for me. You sure this is the exact example? No input data with 1-letter words like 'a'?

– schwobaseggl
Jan 2 at 4:50

It works for me too.

– GeekSambhu
Jan 2 at 4:51

Either catch the exception or check the string length.

– t.m.adam
Jan 2 at 4:53

@schwobaseggl nope this is just a simplified version of what I'm trying to achieve. I think I made a mistake in the qn somewhere! Thanks!

– Javier
Jan 2 at 4:53

in question statement you mentions R and in code you are using r . is your 2nd character is case sensitive ?

– prashant rana
Jan 2 at 5:39

add a comment |

5

Works for me. You sure this is the exact example? No input data with 1-letter words like 'a'?

– schwobaseggl
Jan 2 at 4:50

It works for me too.

– GeekSambhu
Jan 2 at 4:51

Either catch the exception or check the string length.

– t.m.adam
Jan 2 at 4:53

@schwobaseggl nope this is just a simplified version of what I'm trying to achieve. I think I made a mistake in the qn somewhere! Thanks!

– Javier
Jan 2 at 4:53

in question statement you mentions R and in code you are using r . is your 2nd character is case sensitive ?

– prashant rana
Jan 2 at 5:39

Works for me. You sure this is the exact example? No input data with 1-letter words like 'a'?

– schwobaseggl
Jan 2 at 4:50

It works for me too.

– GeekSambhu
Jan 2 at 4:51

Either catch the exception or check the string length.

– t.m.adam
Jan 2 at 4:53

@schwobaseggl nope this is just a simplified version of what I'm trying to achieve. I think I made a mistake in the qn somewhere! Thanks!

– Javier
Jan 2 at 4:53

in question statement you mentions R and in code you are using r . is your 2nd character is case sensitive ?

– prashant rana
Jan 2 at 5:39

add a comment |

3 Answers
3

active

oldest

votes

You can explicitly filter out words with len(word) < 2, that should solve your IndexError problem:

st = 'Print only a word with at least two letters that has r in index 2'



for word in st.split():

    if len(word) > 1 and word[1] == 'r':

        print(word)

# 'Print'

answered Jan 2 at 4:55

andrew_reece

10.6k2928

add a comment |

The index is out of range if the word only has one letter.

st = 'Print only a word, orange'



for word in st.split():

    if len(word) > 1:

        if word[1] == 'r':

            print(word)

answered Jan 2 at 4:58

Strom

2,303322

My answer and andrew_reece's answer are identical in operation. He answered four minutes before me and therefore should get the credit. I am leaving my answer open, since splitting the if may be easier to read for new users to python.

– Strom
Jan 2 at 8:17

add a comment |

How about using regexp ?

import re

re.findall(r'b(.r.*?)b',"Print the string or trim the string your lucky dry day")

['Print', 'or', 'trim', 'dry']

answered Jan 2 at 5:40

sakhunzai

6,6281167115

add a comment |

3 Answers
3

active

oldest

votes

3 Answers
3

active

oldest

votes

You can explicitly filter out words with len(word) < 2, that should solve your IndexError problem:

st = 'Print only a word with at least two letters that has r in index 2'



for word in st.split():

    if len(word) > 1 and word[1] == 'r':

        print(word)

# 'Print'

answered Jan 2 at 4:55

andrew_reece

10.6k2928

add a comment |

You can explicitly filter out words with len(word) < 2, that should solve your IndexError problem:

st = 'Print only a word with at least two letters that has r in index 2'



for word in st.split():

    if len(word) > 1 and word[1] == 'r':

        print(word)

# 'Print'

answered Jan 2 at 4:55

andrew_reece

10.6k2928

add a comment |

You can explicitly filter out words with len(word) < 2, that should solve your IndexError problem:

st = 'Print only a word with at least two letters that has r in index 2'



for word in st.split():

    if len(word) > 1 and word[1] == 'r':

        print(word)

# 'Print'

answered Jan 2 at 4:55

andrew_reece

10.6k2928

You can explicitly filter out words with len(word) < 2, that should solve your IndexError problem:

st = 'Print only a word with at least two letters that has r in index 2'



for word in st.split():

    if len(word) > 1 and word[1] == 'r':

        print(word)

# 'Print'

answered Jan 2 at 4:55

andrew_reece

10.6k2928

answered Jan 2 at 4:55

andrew_reece

10.6k2928

answered Jan 2 at 4:55

andrew_reece

10.6k2928

answered Jan 2 at 4:55

andrew_reece

10.6k2928

add a comment |

The index is out of range if the word only has one letter.

st = 'Print only a word, orange'



for word in st.split():

    if len(word) > 1:

        if word[1] == 'r':

            print(word)

answered Jan 2 at 4:58

Strom

2,303322

My answer and andrew_reece's answer are identical in operation. He answered four minutes before me and therefore should get the credit. I am leaving my answer open, since splitting the if may be easier to read for new users to python.

– Strom
Jan 2 at 8:17

add a comment |

The index is out of range if the word only has one letter.

st = 'Print only a word, orange'



for word in st.split():

    if len(word) > 1:

        if word[1] == 'r':

            print(word)

answered Jan 2 at 4:58

Strom

2,303322

My answer and andrew_reece's answer are identical in operation. He answered four minutes before me and therefore should get the credit. I am leaving my answer open, since splitting the if may be easier to read for new users to python.

– Strom
Jan 2 at 8:17

add a comment |

The index is out of range if the word only has one letter.

st = 'Print only a word, orange'



for word in st.split():

    if len(word) > 1:

        if word[1] == 'r':

            print(word)

answered Jan 2 at 4:58

Strom

2,303322

The index is out of range if the word only has one letter.

st = 'Print only a word, orange'



for word in st.split():

    if len(word) > 1:

        if word[1] == 'r':

            print(word)

answered Jan 2 at 4:58

Strom

2,303322

answered Jan 2 at 4:58

Strom

2,303322

answered Jan 2 at 4:58

Strom

2,303322

answered Jan 2 at 4:58

Strom

2,303322

My answer and andrew_reece's answer are identical in operation. He answered four minutes before me and therefore should get the credit. I am leaving my answer open, since splitting the if may be easier to read for new users to python.

– Strom
Jan 2 at 8:17

add a comment |

My answer and andrew_reece's answer are identical in operation. He answered four minutes before me and therefore should get the credit. I am leaving my answer open, since splitting the if may be easier to read for new users to python.

– Strom
Jan 2 at 8:17

My answer and andrew_reece's answer are identical in operation. He answered four minutes before me and therefore should get the credit. I am leaving my answer open, since splitting the if may be easier to read for new users to python.

– Strom
Jan 2 at 8:17

add a comment |

How about using regexp ?

import re

re.findall(r'b(.r.*?)b',"Print the string or trim the string your lucky dry day")

['Print', 'or', 'trim', 'dry']

answered Jan 2 at 5:40

sakhunzai

6,6281167115

add a comment |

How about using regexp ?

import re

re.findall(r'b(.r.*?)b',"Print the string or trim the string your lucky dry day")

['Print', 'or', 'trim', 'dry']

answered Jan 2 at 5:40

sakhunzai

6,6281167115

add a comment |

How about using regexp ?

import re

re.findall(r'b(.r.*?)b',"Print the string or trim the string your lucky dry day")

['Print', 'or', 'trim', 'dry']

answered Jan 2 at 5:40

sakhunzai

6,6281167115

How about using regexp ?

import re

re.findall(r'b(.r.*?)b',"Print the string or trim the string your lucky dry day")

['Print', 'or', 'trim', 'dry']

answered Jan 2 at 5:40

sakhunzai

6,6281167115

answered Jan 2 at 5:40

sakhunzai

6,6281167115

answered Jan 2 at 5:40

sakhunzai

6,6281167115

answered Jan 2 at 5:40

sakhunzai

6,6281167115

add a comment |

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