In Python, how do I find elements that contain a specific attribute?
I'm using Python 3.7. I want to locate all the elements in my HTML page that have an attribute, "data-permalink", regardless of what its value is, even if the value is empty. However, I'm confused about how to do this. I'm using the bs4 package and tried the following
soup = BeautifulSoup(html)
soup.findAll("data-permalink")
soup.findAll("a")
[<a href=" ... </a>]
soup.findAll("a.data-permalink")
The attribute is normally only found in anchor tags on my page, hence my unsuccessful, "a.data-permalink" attempt. I would like to return the elements that contain the attribute.
python python-3.x beautifulsoup html-parsing
add a comment |
I'm using Python 3.7. I want to locate all the elements in my HTML page that have an attribute, "data-permalink", regardless of what its value is, even if the value is empty. However, I'm confused about how to do this. I'm using the bs4 package and tried the following
soup = BeautifulSoup(html)
soup.findAll("data-permalink")
soup.findAll("a")
[<a href=" ... </a>]
soup.findAll("a.data-permalink")
The attribute is normally only found in anchor tags on my page, hence my unsuccessful, "a.data-permalink" attempt. I would like to return the elements that contain the attribute.
python python-3.x beautifulsoup html-parsing
1
This might be relevant to your question: stackoverflow.com/questions/31416858/…
– Jason Baumgartner
Jan 1 at 23:31
Thanks. Do you know if there's any way to make their example more generic? They have "soup.find_all("div", attrs={"limit":True})" and I was wondering if there is a way to substitute "True" for some kind of expression that means match anything.
– Dave
Jan 1 at 23:55
2
True will match anything. If you prefer css-selectors:soup.select('a[data-permalink]')
.
– t.m.adam
Jan 2 at 0:39
add a comment |
I'm using Python 3.7. I want to locate all the elements in my HTML page that have an attribute, "data-permalink", regardless of what its value is, even if the value is empty. However, I'm confused about how to do this. I'm using the bs4 package and tried the following
soup = BeautifulSoup(html)
soup.findAll("data-permalink")
soup.findAll("a")
[<a href=" ... </a>]
soup.findAll("a.data-permalink")
The attribute is normally only found in anchor tags on my page, hence my unsuccessful, "a.data-permalink" attempt. I would like to return the elements that contain the attribute.
python python-3.x beautifulsoup html-parsing
I'm using Python 3.7. I want to locate all the elements in my HTML page that have an attribute, "data-permalink", regardless of what its value is, even if the value is empty. However, I'm confused about how to do this. I'm using the bs4 package and tried the following
soup = BeautifulSoup(html)
soup.findAll("data-permalink")
soup.findAll("a")
[<a href=" ... </a>]
soup.findAll("a.data-permalink")
The attribute is normally only found in anchor tags on my page, hence my unsuccessful, "a.data-permalink" attempt. I would like to return the elements that contain the attribute.
python python-3.x beautifulsoup html-parsing
python python-3.x beautifulsoup html-parsing
asked Jan 1 at 23:26
DaveDave
1,08870204364
1,08870204364
1
This might be relevant to your question: stackoverflow.com/questions/31416858/…
– Jason Baumgartner
Jan 1 at 23:31
Thanks. Do you know if there's any way to make their example more generic? They have "soup.find_all("div", attrs={"limit":True})" and I was wondering if there is a way to substitute "True" for some kind of expression that means match anything.
– Dave
Jan 1 at 23:55
2
True will match anything. If you prefer css-selectors:soup.select('a[data-permalink]')
.
– t.m.adam
Jan 2 at 0:39
add a comment |
1
This might be relevant to your question: stackoverflow.com/questions/31416858/…
– Jason Baumgartner
Jan 1 at 23:31
Thanks. Do you know if there's any way to make their example more generic? They have "soup.find_all("div", attrs={"limit":True})" and I was wondering if there is a way to substitute "True" for some kind of expression that means match anything.
– Dave
Jan 1 at 23:55
2
True will match anything. If you prefer css-selectors:soup.select('a[data-permalink]')
.
– t.m.adam
Jan 2 at 0:39
1
1
This might be relevant to your question: stackoverflow.com/questions/31416858/…
– Jason Baumgartner
Jan 1 at 23:31
This might be relevant to your question: stackoverflow.com/questions/31416858/…
– Jason Baumgartner
Jan 1 at 23:31
Thanks. Do you know if there's any way to make their example more generic? They have "soup.find_all("div", attrs={"limit":True})" and I was wondering if there is a way to substitute "True" for some kind of expression that means match anything.
– Dave
Jan 1 at 23:55
Thanks. Do you know if there's any way to make their example more generic? They have "soup.find_all("div", attrs={"limit":True})" and I was wondering if there is a way to substitute "True" for some kind of expression that means match anything.
– Dave
Jan 1 at 23:55
2
2
True will match anything. If you prefer css-selectors:
soup.select('a[data-permalink]')
.– t.m.adam
Jan 2 at 0:39
True will match anything. If you prefer css-selectors:
soup.select('a[data-permalink]')
.– t.m.adam
Jan 2 at 0:39
add a comment |
1 Answer
1
active
oldest
votes
Your selector is invalid
soup.findAll("a.data-permalink")
it should be used for the method .select()
but still it invalid because it mean select <a>
with the class not the attribute.
to match everything use the *
for select()
.select('*[data-permalink]')
or True
if using findAll()
.findAll(True, attrs={'data-permalink' : True})
example
from bs4 import BeautifulSoup
html = '''<a data-permalink="a">link</a>
<b>bold</b>
<i data-permalink="i">italic</i>'''
soup= BeautifulSoup(html, 'html.parser')
permalink = soup.select('*[data-permalink]')
# or
# permalink = soup.findAll(True, attrs={'data-permalink' : True})
print(permalink)
Results, the <b>
element is skipped
[<a data-permalink="a">link</a>, <i data-permalink="i">italic</i>]
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your selector is invalid
soup.findAll("a.data-permalink")
it should be used for the method .select()
but still it invalid because it mean select <a>
with the class not the attribute.
to match everything use the *
for select()
.select('*[data-permalink]')
or True
if using findAll()
.findAll(True, attrs={'data-permalink' : True})
example
from bs4 import BeautifulSoup
html = '''<a data-permalink="a">link</a>
<b>bold</b>
<i data-permalink="i">italic</i>'''
soup= BeautifulSoup(html, 'html.parser')
permalink = soup.select('*[data-permalink]')
# or
# permalink = soup.findAll(True, attrs={'data-permalink' : True})
print(permalink)
Results, the <b>
element is skipped
[<a data-permalink="a">link</a>, <i data-permalink="i">italic</i>]
add a comment |
Your selector is invalid
soup.findAll("a.data-permalink")
it should be used for the method .select()
but still it invalid because it mean select <a>
with the class not the attribute.
to match everything use the *
for select()
.select('*[data-permalink]')
or True
if using findAll()
.findAll(True, attrs={'data-permalink' : True})
example
from bs4 import BeautifulSoup
html = '''<a data-permalink="a">link</a>
<b>bold</b>
<i data-permalink="i">italic</i>'''
soup= BeautifulSoup(html, 'html.parser')
permalink = soup.select('*[data-permalink]')
# or
# permalink = soup.findAll(True, attrs={'data-permalink' : True})
print(permalink)
Results, the <b>
element is skipped
[<a data-permalink="a">link</a>, <i data-permalink="i">italic</i>]
add a comment |
Your selector is invalid
soup.findAll("a.data-permalink")
it should be used for the method .select()
but still it invalid because it mean select <a>
with the class not the attribute.
to match everything use the *
for select()
.select('*[data-permalink]')
or True
if using findAll()
.findAll(True, attrs={'data-permalink' : True})
example
from bs4 import BeautifulSoup
html = '''<a data-permalink="a">link</a>
<b>bold</b>
<i data-permalink="i">italic</i>'''
soup= BeautifulSoup(html, 'html.parser')
permalink = soup.select('*[data-permalink]')
# or
# permalink = soup.findAll(True, attrs={'data-permalink' : True})
print(permalink)
Results, the <b>
element is skipped
[<a data-permalink="a">link</a>, <i data-permalink="i">italic</i>]
Your selector is invalid
soup.findAll("a.data-permalink")
it should be used for the method .select()
but still it invalid because it mean select <a>
with the class not the attribute.
to match everything use the *
for select()
.select('*[data-permalink]')
or True
if using findAll()
.findAll(True, attrs={'data-permalink' : True})
example
from bs4 import BeautifulSoup
html = '''<a data-permalink="a">link</a>
<b>bold</b>
<i data-permalink="i">italic</i>'''
soup= BeautifulSoup(html, 'html.parser')
permalink = soup.select('*[data-permalink]')
# or
# permalink = soup.findAll(True, attrs={'data-permalink' : True})
print(permalink)
Results, the <b>
element is skipped
[<a data-permalink="a">link</a>, <i data-permalink="i">italic</i>]
answered Jan 2 at 6:34
ewwinkewwink
12k22339
12k22339
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1
This might be relevant to your question: stackoverflow.com/questions/31416858/…
– Jason Baumgartner
Jan 1 at 23:31
Thanks. Do you know if there's any way to make their example more generic? They have "soup.find_all("div", attrs={"limit":True})" and I was wondering if there is a way to substitute "True" for some kind of expression that means match anything.
– Dave
Jan 1 at 23:55
2
True will match anything. If you prefer css-selectors:
soup.select('a[data-permalink]')
.– t.m.adam
Jan 2 at 0:39