How to plot a 3D histogram with matplotlib/mplot3d?












3















I have three arrays and I am trying to make a 3D histogram.



x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50, 60]
z = [105, 25, 26, 74, 39, 85, 74, 153, 52, 98]


Here's my attempt so far:



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = plt.axes(projection='3d')

binsOne = sorted(set(x))
binsTwo = sorted(set(y))
hist, xedges, yedges = np.histogram2d(x, y, bins=[binsOne, binsTwo])
xpos, ypos = np.meshgrid(xedges[:-1] + 0.25 , yedges[:-1] + 0.25)
xpos = xpos.flatten('F')
ypos = ypos.flatten('F')
zpos = np.zeros_like(xpos)

dx = dx.flatten()
dy = dy.flatten()
dz = hist.flatten()

ax.bar3d(xpos, ypos, zpos, dx, dy, dz, color='b', zsort='average')


How do I incorporate the z array into my 3D histogram?










share|improve this question

























  • I advice you this post: stackoverflow.com/questions/53611716/… Matplotlib have some issues with the 3D plotting, so pay attention!

    – Alessandro Peca
    Jan 3 at 8:25
















3















I have three arrays and I am trying to make a 3D histogram.



x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50, 60]
z = [105, 25, 26, 74, 39, 85, 74, 153, 52, 98]


Here's my attempt so far:



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = plt.axes(projection='3d')

binsOne = sorted(set(x))
binsTwo = sorted(set(y))
hist, xedges, yedges = np.histogram2d(x, y, bins=[binsOne, binsTwo])
xpos, ypos = np.meshgrid(xedges[:-1] + 0.25 , yedges[:-1] + 0.25)
xpos = xpos.flatten('F')
ypos = ypos.flatten('F')
zpos = np.zeros_like(xpos)

dx = dx.flatten()
dy = dy.flatten()
dz = hist.flatten()

ax.bar3d(xpos, ypos, zpos, dx, dy, dz, color='b', zsort='average')


How do I incorporate the z array into my 3D histogram?










share|improve this question

























  • I advice you this post: stackoverflow.com/questions/53611716/… Matplotlib have some issues with the 3D plotting, so pay attention!

    – Alessandro Peca
    Jan 3 at 8:25














3












3








3








I have three arrays and I am trying to make a 3D histogram.



x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50, 60]
z = [105, 25, 26, 74, 39, 85, 74, 153, 52, 98]


Here's my attempt so far:



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = plt.axes(projection='3d')

binsOne = sorted(set(x))
binsTwo = sorted(set(y))
hist, xedges, yedges = np.histogram2d(x, y, bins=[binsOne, binsTwo])
xpos, ypos = np.meshgrid(xedges[:-1] + 0.25 , yedges[:-1] + 0.25)
xpos = xpos.flatten('F')
ypos = ypos.flatten('F')
zpos = np.zeros_like(xpos)

dx = dx.flatten()
dy = dy.flatten()
dz = hist.flatten()

ax.bar3d(xpos, ypos, zpos, dx, dy, dz, color='b', zsort='average')


How do I incorporate the z array into my 3D histogram?










share|improve this question
















I have three arrays and I am trying to make a 3D histogram.



x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50, 60]
z = [105, 25, 26, 74, 39, 85, 74, 153, 52, 98]


Here's my attempt so far:



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = plt.axes(projection='3d')

binsOne = sorted(set(x))
binsTwo = sorted(set(y))
hist, xedges, yedges = np.histogram2d(x, y, bins=[binsOne, binsTwo])
xpos, ypos = np.meshgrid(xedges[:-1] + 0.25 , yedges[:-1] + 0.25)
xpos = xpos.flatten('F')
ypos = ypos.flatten('F')
zpos = np.zeros_like(xpos)

dx = dx.flatten()
dy = dy.flatten()
dz = hist.flatten()

ax.bar3d(xpos, ypos, zpos, dx, dy, dz, color='b', zsort='average')


How do I incorporate the z array into my 3D histogram?







python matplotlib mplot3d






share|improve this question















share|improve this question













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edited Jan 3 at 0:07







Matt-pow

















asked Jan 2 at 23:45









Matt-powMatt-pow

155416




155416













  • I advice you this post: stackoverflow.com/questions/53611716/… Matplotlib have some issues with the 3D plotting, so pay attention!

    – Alessandro Peca
    Jan 3 at 8:25



















  • I advice you this post: stackoverflow.com/questions/53611716/… Matplotlib have some issues with the 3D plotting, so pay attention!

    – Alessandro Peca
    Jan 3 at 8:25

















I advice you this post: stackoverflow.com/questions/53611716/… Matplotlib have some issues with the 3D plotting, so pay attention!

– Alessandro Peca
Jan 3 at 8:25





I advice you this post: stackoverflow.com/questions/53611716/… Matplotlib have some issues with the 3D plotting, so pay attention!

– Alessandro Peca
Jan 3 at 8:25












1 Answer
1






active

oldest

votes


















1














The z array must have the same shape not of x and y but of xpos and ypos (which are of themselves the same shape). You may find this example more useful than the one you appear to be drawing from. The following code is to demonstrate the example in the first link applied to your question,



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

_x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
_y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50]
_xx, _yy = np.meshgrid(_x, _y)
x, y = _xx.ravel(), _yy.ravel()
_z = np.array([105, 25, 26, 74, 39, 85, 74, 153, 52, 98])

# There may be an easier way to do this, but I am not aware of it
z = np.zeros(len(x))
for i in range(1, len(x)):
z[i] = _z[(i*len(_z)) / len(x)]

bottom = np.zeros_like(z)
width = depth = 1

ax.bar3d(x, y, bottom, width, depth, z, shade=True)
plt.show()


enter image description here






share|improve this answer
























  • Thanks for your answer, why is the z not following x and y in ax.bar3d? Also can you explain to me what does the for loop does for _z?

    – Matt-pow
    Jan 3 at 6:04













  • @Matt-pow I don't understand your question, the z values in the array are determining the height of the the bar, the x values determine the x position and the y values determine the y position. For x and y pairs that correspond to a common z value you see multiple bars. The values on the y and x axis are a little confusing since the bar 1 in x actually goes from 1 to 2 and 8 goes from 8 to 9.

    – William Miller
    Jan 3 at 6:25











  • @Matt-pow The for loop for _z converts _z, a shape (10L, ) array into z a shape (100L, ) array populated by 10 instances of each value

    – William Miller
    Jan 3 at 6:37






  • 1





    Thanks for the explaination

    – Matt-pow
    Jan 3 at 21:45











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














The z array must have the same shape not of x and y but of xpos and ypos (which are of themselves the same shape). You may find this example more useful than the one you appear to be drawing from. The following code is to demonstrate the example in the first link applied to your question,



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

_x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
_y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50]
_xx, _yy = np.meshgrid(_x, _y)
x, y = _xx.ravel(), _yy.ravel()
_z = np.array([105, 25, 26, 74, 39, 85, 74, 153, 52, 98])

# There may be an easier way to do this, but I am not aware of it
z = np.zeros(len(x))
for i in range(1, len(x)):
z[i] = _z[(i*len(_z)) / len(x)]

bottom = np.zeros_like(z)
width = depth = 1

ax.bar3d(x, y, bottom, width, depth, z, shade=True)
plt.show()


enter image description here






share|improve this answer
























  • Thanks for your answer, why is the z not following x and y in ax.bar3d? Also can you explain to me what does the for loop does for _z?

    – Matt-pow
    Jan 3 at 6:04













  • @Matt-pow I don't understand your question, the z values in the array are determining the height of the the bar, the x values determine the x position and the y values determine the y position. For x and y pairs that correspond to a common z value you see multiple bars. The values on the y and x axis are a little confusing since the bar 1 in x actually goes from 1 to 2 and 8 goes from 8 to 9.

    – William Miller
    Jan 3 at 6:25











  • @Matt-pow The for loop for _z converts _z, a shape (10L, ) array into z a shape (100L, ) array populated by 10 instances of each value

    – William Miller
    Jan 3 at 6:37






  • 1





    Thanks for the explaination

    – Matt-pow
    Jan 3 at 21:45
















1














The z array must have the same shape not of x and y but of xpos and ypos (which are of themselves the same shape). You may find this example more useful than the one you appear to be drawing from. The following code is to demonstrate the example in the first link applied to your question,



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

_x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
_y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50]
_xx, _yy = np.meshgrid(_x, _y)
x, y = _xx.ravel(), _yy.ravel()
_z = np.array([105, 25, 26, 74, 39, 85, 74, 153, 52, 98])

# There may be an easier way to do this, but I am not aware of it
z = np.zeros(len(x))
for i in range(1, len(x)):
z[i] = _z[(i*len(_z)) / len(x)]

bottom = np.zeros_like(z)
width = depth = 1

ax.bar3d(x, y, bottom, width, depth, z, shade=True)
plt.show()


enter image description here






share|improve this answer
























  • Thanks for your answer, why is the z not following x and y in ax.bar3d? Also can you explain to me what does the for loop does for _z?

    – Matt-pow
    Jan 3 at 6:04













  • @Matt-pow I don't understand your question, the z values in the array are determining the height of the the bar, the x values determine the x position and the y values determine the y position. For x and y pairs that correspond to a common z value you see multiple bars. The values on the y and x axis are a little confusing since the bar 1 in x actually goes from 1 to 2 and 8 goes from 8 to 9.

    – William Miller
    Jan 3 at 6:25











  • @Matt-pow The for loop for _z converts _z, a shape (10L, ) array into z a shape (100L, ) array populated by 10 instances of each value

    – William Miller
    Jan 3 at 6:37






  • 1





    Thanks for the explaination

    – Matt-pow
    Jan 3 at 21:45














1












1








1







The z array must have the same shape not of x and y but of xpos and ypos (which are of themselves the same shape). You may find this example more useful than the one you appear to be drawing from. The following code is to demonstrate the example in the first link applied to your question,



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

_x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
_y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50]
_xx, _yy = np.meshgrid(_x, _y)
x, y = _xx.ravel(), _yy.ravel()
_z = np.array([105, 25, 26, 74, 39, 85, 74, 153, 52, 98])

# There may be an easier way to do this, but I am not aware of it
z = np.zeros(len(x))
for i in range(1, len(x)):
z[i] = _z[(i*len(_z)) / len(x)]

bottom = np.zeros_like(z)
width = depth = 1

ax.bar3d(x, y, bottom, width, depth, z, shade=True)
plt.show()


enter image description here






share|improve this answer













The z array must have the same shape not of x and y but of xpos and ypos (which are of themselves the same shape). You may find this example more useful than the one you appear to be drawing from. The following code is to demonstrate the example in the first link applied to your question,



from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
import numpy as np

fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')

_x = [1, 2, 3, 2, 5, 2, 6, 8, 6, 7]
_y = [10, 10, 20, 50, 20, 20, 30, 10, 40, 50]
_xx, _yy = np.meshgrid(_x, _y)
x, y = _xx.ravel(), _yy.ravel()
_z = np.array([105, 25, 26, 74, 39, 85, 74, 153, 52, 98])

# There may be an easier way to do this, but I am not aware of it
z = np.zeros(len(x))
for i in range(1, len(x)):
z[i] = _z[(i*len(_z)) / len(x)]

bottom = np.zeros_like(z)
width = depth = 1

ax.bar3d(x, y, bottom, width, depth, z, shade=True)
plt.show()


enter image description here







share|improve this answer












share|improve this answer



share|improve this answer










answered Jan 3 at 0:31









William MillerWilliam Miller

1,478317




1,478317













  • Thanks for your answer, why is the z not following x and y in ax.bar3d? Also can you explain to me what does the for loop does for _z?

    – Matt-pow
    Jan 3 at 6:04













  • @Matt-pow I don't understand your question, the z values in the array are determining the height of the the bar, the x values determine the x position and the y values determine the y position. For x and y pairs that correspond to a common z value you see multiple bars. The values on the y and x axis are a little confusing since the bar 1 in x actually goes from 1 to 2 and 8 goes from 8 to 9.

    – William Miller
    Jan 3 at 6:25











  • @Matt-pow The for loop for _z converts _z, a shape (10L, ) array into z a shape (100L, ) array populated by 10 instances of each value

    – William Miller
    Jan 3 at 6:37






  • 1





    Thanks for the explaination

    – Matt-pow
    Jan 3 at 21:45



















  • Thanks for your answer, why is the z not following x and y in ax.bar3d? Also can you explain to me what does the for loop does for _z?

    – Matt-pow
    Jan 3 at 6:04













  • @Matt-pow I don't understand your question, the z values in the array are determining the height of the the bar, the x values determine the x position and the y values determine the y position. For x and y pairs that correspond to a common z value you see multiple bars. The values on the y and x axis are a little confusing since the bar 1 in x actually goes from 1 to 2 and 8 goes from 8 to 9.

    – William Miller
    Jan 3 at 6:25











  • @Matt-pow The for loop for _z converts _z, a shape (10L, ) array into z a shape (100L, ) array populated by 10 instances of each value

    – William Miller
    Jan 3 at 6:37






  • 1





    Thanks for the explaination

    – Matt-pow
    Jan 3 at 21:45

















Thanks for your answer, why is the z not following x and y in ax.bar3d? Also can you explain to me what does the for loop does for _z?

– Matt-pow
Jan 3 at 6:04







Thanks for your answer, why is the z not following x and y in ax.bar3d? Also can you explain to me what does the for loop does for _z?

– Matt-pow
Jan 3 at 6:04















@Matt-pow I don't understand your question, the z values in the array are determining the height of the the bar, the x values determine the x position and the y values determine the y position. For x and y pairs that correspond to a common z value you see multiple bars. The values on the y and x axis are a little confusing since the bar 1 in x actually goes from 1 to 2 and 8 goes from 8 to 9.

– William Miller
Jan 3 at 6:25





@Matt-pow I don't understand your question, the z values in the array are determining the height of the the bar, the x values determine the x position and the y values determine the y position. For x and y pairs that correspond to a common z value you see multiple bars. The values on the y and x axis are a little confusing since the bar 1 in x actually goes from 1 to 2 and 8 goes from 8 to 9.

– William Miller
Jan 3 at 6:25













@Matt-pow The for loop for _z converts _z, a shape (10L, ) array into z a shape (100L, ) array populated by 10 instances of each value

– William Miller
Jan 3 at 6:37





@Matt-pow The for loop for _z converts _z, a shape (10L, ) array into z a shape (100L, ) array populated by 10 instances of each value

– William Miller
Jan 3 at 6:37




1




1





Thanks for the explaination

– Matt-pow
Jan 3 at 21:45





Thanks for the explaination

– Matt-pow
Jan 3 at 21:45




















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