Get another image if the main image is not available












-1















I have an API, which returns some data with image links.
The problem is that there is a type of image that is main but not always available.
When that happens, I want another image to appear, but it's also in the API.



API Extract



"images": {
"icon": "https://image.fnbr.co/outfit/5c2aad8560e93a37d9635605/icon.png", // secondary
"png": false,
"gallery": false,
"featured":
"https://image.fnbr.co/outfit/5c2aad8560e93a37d9635605/featured.png" // main
}


I have tried the label "onerror" but since it is not a error (because it says null) it does not replace the image.



PHP Code



<img src="<?php echo $image_data['data']['featured'][$i]['images'] 
['featured'] ?>";>









share|improve this question























  • You can solve that with a simple IF statement

    – Second2None
    Jan 2 at 23:54
















-1















I have an API, which returns some data with image links.
The problem is that there is a type of image that is main but not always available.
When that happens, I want another image to appear, but it's also in the API.



API Extract



"images": {
"icon": "https://image.fnbr.co/outfit/5c2aad8560e93a37d9635605/icon.png", // secondary
"png": false,
"gallery": false,
"featured":
"https://image.fnbr.co/outfit/5c2aad8560e93a37d9635605/featured.png" // main
}


I have tried the label "onerror" but since it is not a error (because it says null) it does not replace the image.



PHP Code



<img src="<?php echo $image_data['data']['featured'][$i]['images'] 
['featured'] ?>";>









share|improve this question























  • You can solve that with a simple IF statement

    – Second2None
    Jan 2 at 23:54














-1












-1








-1








I have an API, which returns some data with image links.
The problem is that there is a type of image that is main but not always available.
When that happens, I want another image to appear, but it's also in the API.



API Extract



"images": {
"icon": "https://image.fnbr.co/outfit/5c2aad8560e93a37d9635605/icon.png", // secondary
"png": false,
"gallery": false,
"featured":
"https://image.fnbr.co/outfit/5c2aad8560e93a37d9635605/featured.png" // main
}


I have tried the label "onerror" but since it is not a error (because it says null) it does not replace the image.



PHP Code



<img src="<?php echo $image_data['data']['featured'][$i]['images'] 
['featured'] ?>";>









share|improve this question














I have an API, which returns some data with image links.
The problem is that there is a type of image that is main but not always available.
When that happens, I want another image to appear, but it's also in the API.



API Extract



"images": {
"icon": "https://image.fnbr.co/outfit/5c2aad8560e93a37d9635605/icon.png", // secondary
"png": false,
"gallery": false,
"featured":
"https://image.fnbr.co/outfit/5c2aad8560e93a37d9635605/featured.png" // main
}


I have tried the label "onerror" but since it is not a error (because it says null) it does not replace the image.



PHP Code



<img src="<?php echo $image_data['data']['featured'][$i]['images'] 
['featured'] ?>";>






php api






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asked Jan 2 at 23:48









Nacho AldamaNacho Aldama

1




1













  • You can solve that with a simple IF statement

    – Second2None
    Jan 2 at 23:54



















  • You can solve that with a simple IF statement

    – Second2None
    Jan 2 at 23:54

















You can solve that with a simple IF statement

– Second2None
Jan 2 at 23:54





You can solve that with a simple IF statement

– Second2None
Jan 2 at 23:54












2 Answers
2






active

oldest

votes


















1














you need to check if the main image is empty:



$images = ...; // your current image object 
$image = ($images['featured'] !== null) ? $images['featured'] : $images['icon']; // featured or icon image





share|improve this answer
























  • I've added it, but I'm getting an error 500. I don't know if something can be done, but I can change the class depending on the type of object. for example, <img class="card-img-top <?php echo $image_data['data']['featured'][$i]['type'] ?>"

    – Nacho Aldama
    Jan 3 at 9:20





















0














$img = $image_data['data']['featured'][$i]['images']['featured'];
$alternativ = $image_data['data']['featured'][$i]['images']['icon'];

<img src="<?php echo ($img) ? $img:$alternativ ?>";>


or check null



<img src="<?php echo ($img === NULL) ? $alternativ:$img ?>";>





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    2 Answers
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    2 Answers
    2






    active

    oldest

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    active

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    active

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    1














    you need to check if the main image is empty:



    $images = ...; // your current image object 
    $image = ($images['featured'] !== null) ? $images['featured'] : $images['icon']; // featured or icon image





    share|improve this answer
























    • I've added it, but I'm getting an error 500. I don't know if something can be done, but I can change the class depending on the type of object. for example, <img class="card-img-top <?php echo $image_data['data']['featured'][$i]['type'] ?>"

      – Nacho Aldama
      Jan 3 at 9:20


















    1














    you need to check if the main image is empty:



    $images = ...; // your current image object 
    $image = ($images['featured'] !== null) ? $images['featured'] : $images['icon']; // featured or icon image





    share|improve this answer
























    • I've added it, but I'm getting an error 500. I don't know if something can be done, but I can change the class depending on the type of object. for example, <img class="card-img-top <?php echo $image_data['data']['featured'][$i]['type'] ?>"

      – Nacho Aldama
      Jan 3 at 9:20
















    1












    1








    1







    you need to check if the main image is empty:



    $images = ...; // your current image object 
    $image = ($images['featured'] !== null) ? $images['featured'] : $images['icon']; // featured or icon image





    share|improve this answer













    you need to check if the main image is empty:



    $images = ...; // your current image object 
    $image = ($images['featured'] !== null) ? $images['featured'] : $images['icon']; // featured or icon image






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Jan 2 at 23:55









    Eriks KlotinsEriks Klotins

    1,4031518




    1,4031518













    • I've added it, but I'm getting an error 500. I don't know if something can be done, but I can change the class depending on the type of object. for example, <img class="card-img-top <?php echo $image_data['data']['featured'][$i]['type'] ?>"

      – Nacho Aldama
      Jan 3 at 9:20





















    • I've added it, but I'm getting an error 500. I don't know if something can be done, but I can change the class depending on the type of object. for example, <img class="card-img-top <?php echo $image_data['data']['featured'][$i]['type'] ?>"

      – Nacho Aldama
      Jan 3 at 9:20



















    I've added it, but I'm getting an error 500. I don't know if something can be done, but I can change the class depending on the type of object. for example, <img class="card-img-top <?php echo $image_data['data']['featured'][$i]['type'] ?>"

    – Nacho Aldama
    Jan 3 at 9:20







    I've added it, but I'm getting an error 500. I don't know if something can be done, but I can change the class depending on the type of object. for example, <img class="card-img-top <?php echo $image_data['data']['featured'][$i]['type'] ?>"

    – Nacho Aldama
    Jan 3 at 9:20















    0














    $img = $image_data['data']['featured'][$i]['images']['featured'];
    $alternativ = $image_data['data']['featured'][$i]['images']['icon'];

    <img src="<?php echo ($img) ? $img:$alternativ ?>";>


    or check null



    <img src="<?php echo ($img === NULL) ? $alternativ:$img ?>";>





    share|improve this answer




























      0














      $img = $image_data['data']['featured'][$i]['images']['featured'];
      $alternativ = $image_data['data']['featured'][$i]['images']['icon'];

      <img src="<?php echo ($img) ? $img:$alternativ ?>";>


      or check null



      <img src="<?php echo ($img === NULL) ? $alternativ:$img ?>";>





      share|improve this answer


























        0












        0








        0







        $img = $image_data['data']['featured'][$i]['images']['featured'];
        $alternativ = $image_data['data']['featured'][$i]['images']['icon'];

        <img src="<?php echo ($img) ? $img:$alternativ ?>";>


        or check null



        <img src="<?php echo ($img === NULL) ? $alternativ:$img ?>";>





        share|improve this answer













        $img = $image_data['data']['featured'][$i]['images']['featured'];
        $alternativ = $image_data['data']['featured'][$i]['images']['icon'];

        <img src="<?php echo ($img) ? $img:$alternativ ?>";>


        or check null



        <img src="<?php echo ($img === NULL) ? $alternativ:$img ?>";>






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Jan 2 at 23:56









        Mohammad bMohammad b

        1,59121735




        1,59121735






























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