How can I update list values inside a dictionary in python
-1
I have a dictionary like this:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ], }
I need to replace 0 with -1 in this dict.
It's what I tried:
for key in perfect_data.keys():
perfect_data[key]*=2-1
print(perfect_data[key])
But nothing changes when I print each item.
python list dictionary
asked Dec 27 at 14:25
Ahmad
2,76333058
add a comment |
-1
I have a dictionary like this:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ], }
I need to replace 0 with -1 in this dict.
It's what I tried:
for key in perfect_data.keys():
perfect_data[key]*=2-1
print(perfect_data[key])
But nothing changes when I print each item.
python list dictionary
asked Dec 27 at 14:25
Ahmad
2,76333058
1
x *= 2-1is the same asx *= 1.
– interjay
Dec 27 at 14:28
okey, how can I multiply each item of a list by two and then subtract 1 from it?
– Ahmad
Dec 27 at 14:30
and multiplying a list doesn't yield the result you'd expect anyway <g>
– bruno desthuilliers
Dec 27 at 14:30
add a comment |
-1
-1
-1
I have a dictionary like this:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ], }
I need to replace 0 with -1 in this dict.
It's what I tried:
for key in perfect_data.keys():
perfect_data[key]*=2-1
print(perfect_data[key])
But nothing changes when I print each item.
python list dictionary
asked Dec 27 at 14:25
Ahmad
2,76333058
I have a dictionary like this:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ], }
I need to replace 0 with -1 in this dict.
It's what I tried:
for key in perfect_data.keys():
perfect_data[key]*=2-1
print(perfect_data[key])
But nothing changes when I print each item.
python list dictionary
python list dictionary
asked Dec 27 at 14:25
Ahmad
2,76333058
asked Dec 27 at 14:25
Ahmad
2,76333058
edited Dec 27 at 14:31
asked Dec 27 at 14:25
Ahmad
2,76333058
asked Dec 27 at 14:25
Ahmad
2,76333058
asked Dec 27 at 14:25
Ahmad
2,76333058
2,76333058
1
x *= 2-1is the same asx *= 1.
– interjay
Dec 27 at 14:28
okey, how can I multiply each item of a list by two and then subtract 1 from it?
– Ahmad
Dec 27 at 14:30
and multiplying a list doesn't yield the result you'd expect anyway <g>
– bruno desthuilliers
Dec 27 at 14:30
add a comment |
1
x *= 2-1is the same asx *= 1.
– interjay
Dec 27 at 14:28
okey, how can I multiply each item of a list by two and then subtract 1 from it?
– Ahmad
Dec 27 at 14:30
and multiplying a list doesn't yield the result you'd expect anyway <g>
– bruno desthuilliers
Dec 27 at 14:30
1
1
x *= 2-1 is the same as x *= 1.– interjay
Dec 27 at 14:28
x *= 2-1 is the same as x *= 1.– interjay
Dec 27 at 14:28
okey, how can I multiply each item of a list by two and then subtract 1 from it?
– Ahmad
Dec 27 at 14:30
okey, how can I multiply each item of a list by two and then subtract 1 from it?
– Ahmad
Dec 27 at 14:30
and multiplying a list doesn't yield the result you'd expect anyway <g>
– bruno desthuilliers
Dec 27 at 14:30
and multiplying a list doesn't yield the result you'd expect anyway <g>
– bruno desthuilliers
Dec 27 at 14:30
add a comment |
5 Answers
5
active
oldest
votes
1
Replace this line perfect_data[key]*=2-1 with perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
for key in perfect_data.keys():
perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
print(perfect_data[key])
Output:
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1,
-1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1,
1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
answered Dec 27 at 14:35
Sam
556416
add a comment |
1
It's what I tried and worked:
for key,value in perfect_data.items():
perfect_data[key]=[2*x-1 for x in value]
print(perfect_data[key])
answered Dec 27 at 14:33
Ahmad
2,76333058
add a comment |
1
No idea, what are you trying to achieve, but if strictly following your question, the answer is:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ],
}
for k,v in perfect_data.items():
perfect_data[k] = [x or -1 for x in v]
print(perfect_data)
Output
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
Statement x or -1 uses the fact that 0 gives False and or-operator returns first non-false argument.
answered Dec 27 at 14:33
grapes
2,5471115
add a comment |
1
If I get the point, try this way:
for value in perfect_data.values():
for i, e in enumerate(value):
if e == 0:
value[i] = -1
print(perfect_data)
edited Dec 27 at 14:36
bruno desthuilliers
47.9k54162
answered Dec 27 at 14:33
iGian
3,2402622
if you only want the dict's values, usedict.values();-)
– bruno desthuilliers
Dec 27 at 14:34
@brunodesthuilliers, why not? Thanks!
– iGian
Dec 27 at 14:35
add a comment |
0
As simple as this:
perfect_data['1'] = [i if i else -1 for i in perfect_data['1']]
answered Dec 27 at 14:37
Ssein
1,0161921
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
Replace this line perfect_data[key]*=2-1 with perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
for key in perfect_data.keys():
perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
print(perfect_data[key])
Output:
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1,
-1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1,
1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
answered Dec 27 at 14:35
Sam
556416
add a comment |
1
Replace this line perfect_data[key]*=2-1 with perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
for key in perfect_data.keys():
perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
print(perfect_data[key])
Output:
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1,
-1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1,
1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
answered Dec 27 at 14:35
Sam
556416
add a comment |
1
1
1
Replace this line perfect_data[key]*=2-1 with perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
for key in perfect_data.keys():
perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
print(perfect_data[key])
Output:
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1,
-1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1,
1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
answered Dec 27 at 14:35
Sam
556416
Replace this line perfect_data[key]*=2-1 with perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
for key in perfect_data.keys():
perfect_data[key] = [x*2 -1 for x in perfect_data[key]]
print(perfect_data[key])
Output:
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1,
-1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1,
1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
answered Dec 27 at 14:35
Sam
556416
answered Dec 27 at 14:35
Sam
556416
answered Dec 27 at 14:35
Sam
556416
answered Dec 27 at 14:35
Sam
556416
556416
add a comment |
add a comment |
1
It's what I tried and worked:
for key,value in perfect_data.items():
perfect_data[key]=[2*x-1 for x in value]
print(perfect_data[key])
answered Dec 27 at 14:33
Ahmad
2,76333058
add a comment |
1
It's what I tried and worked:
for key,value in perfect_data.items():
perfect_data[key]=[2*x-1 for x in value]
print(perfect_data[key])
answered Dec 27 at 14:33
Ahmad
2,76333058
add a comment |
1
1
1
It's what I tried and worked:
for key,value in perfect_data.items():
perfect_data[key]=[2*x-1 for x in value]
print(perfect_data[key])
answered Dec 27 at 14:33
Ahmad
2,76333058
It's what I tried and worked:
for key,value in perfect_data.items():
perfect_data[key]=[2*x-1 for x in value]
print(perfect_data[key])
answered Dec 27 at 14:33
Ahmad
2,76333058
answered Dec 27 at 14:33
Ahmad
2,76333058
answered Dec 27 at 14:33
Ahmad
2,76333058
answered Dec 27 at 14:33
Ahmad
2,76333058
2,76333058
add a comment |
add a comment |
1
No idea, what are you trying to achieve, but if strictly following your question, the answer is:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ],
}
for k,v in perfect_data.items():
perfect_data[k] = [x or -1 for x in v]
print(perfect_data)
Output
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
Statement x or -1 uses the fact that 0 gives False and or-operator returns first non-false argument.
answered Dec 27 at 14:33
grapes
2,5471115
add a comment |
1
No idea, what are you trying to achieve, but if strictly following your question, the answer is:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ],
}
for k,v in perfect_data.items():
perfect_data[k] = [x or -1 for x in v]
print(perfect_data)
Output
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
Statement x or -1 uses the fact that 0 gives False and or-operator returns first non-false argument.
answered Dec 27 at 14:33
grapes
2,5471115
add a comment |
1
1
1
No idea, what are you trying to achieve, but if strictly following your question, the answer is:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ],
}
for k,v in perfect_data.items():
perfect_data[k] = [x or -1 for x in v]
print(perfect_data)
Output
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
Statement x or -1 uses the fact that 0 gives False and or-operator returns first non-false argument.
answered Dec 27 at 14:33
grapes
2,5471115
No idea, what are you trying to achieve, but if strictly following your question, the answer is:
perfect_data = {
"1": [1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 0, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1,
1, 1, 1, 0, 0, 1, 1, 1 ],
}
for k,v in perfect_data.items():
perfect_data[k] = [x or -1 for x in v]
print(perfect_data)
Output
{'1': [1, 1, -1, -1, -1, 1, 1, 1, 1, 1, -1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1, 1, 1, 1, -1, -1, 1, 1, 1]}
Statement x or -1 uses the fact that 0 gives False and or-operator returns first non-false argument.
answered Dec 27 at 14:33
grapes
2,5471115
answered Dec 27 at 14:33
grapes
2,5471115
answered Dec 27 at 14:33
grapes
2,5471115
answered Dec 27 at 14:33
grapes
2,5471115
2,5471115
add a comment |
add a comment |
1
If I get the point, try this way:
for value in perfect_data.values():
for i, e in enumerate(value):
if e == 0:
value[i] = -1
print(perfect_data)
edited Dec 27 at 14:36
bruno desthuilliers
47.9k54162
answered Dec 27 at 14:33
iGian
3,2402622
if you only want the dict's values, usedict.values();-)
– bruno desthuilliers
Dec 27 at 14:34
@brunodesthuilliers, why not? Thanks!
– iGian
Dec 27 at 14:35
add a comment |
1
If I get the point, try this way:
for value in perfect_data.values():
for i, e in enumerate(value):
if e == 0:
value[i] = -1
print(perfect_data)
edited Dec 27 at 14:36
bruno desthuilliers
47.9k54162
answered Dec 27 at 14:33
iGian
3,2402622
if you only want the dict's values, usedict.values();-)
– bruno desthuilliers
Dec 27 at 14:34
@brunodesthuilliers, why not? Thanks!
– iGian
Dec 27 at 14:35
add a comment |
1
1
1
If I get the point, try this way:
for value in perfect_data.values():
for i, e in enumerate(value):
if e == 0:
value[i] = -1
print(perfect_data)
edited Dec 27 at 14:36
bruno desthuilliers
47.9k54162
answered Dec 27 at 14:33
iGian
3,2402622
If I get the point, try this way:
for value in perfect_data.values():
for i, e in enumerate(value):
if e == 0:
value[i] = -1
print(perfect_data)
edited Dec 27 at 14:36
bruno desthuilliers
47.9k54162
answered Dec 27 at 14:33
iGian
3,2402622
edited Dec 27 at 14:36
bruno desthuilliers
47.9k54162
edited Dec 27 at 14:36
bruno desthuilliers
47.9k54162
edited Dec 27 at 14:36
bruno desthuilliers
47.9k54162
47.9k54162
answered Dec 27 at 14:33
iGian
3,2402622
answered Dec 27 at 14:33
iGian
3,2402622
answered Dec 27 at 14:33
iGian
3,2402622
3,2402622
if you only want the dict's values, usedict.values();-)
– bruno desthuilliers
Dec 27 at 14:34
@brunodesthuilliers, why not? Thanks!
– iGian
Dec 27 at 14:35
add a comment |
if you only want the dict's values, usedict.values();-)
– bruno desthuilliers
Dec 27 at 14:34
@brunodesthuilliers, why not? Thanks!
– iGian
Dec 27 at 14:35
if you only want the dict's values, use
dict.values() ;-)– bruno desthuilliers
Dec 27 at 14:34
if you only want the dict's values, use
dict.values() ;-)– bruno desthuilliers
Dec 27 at 14:34
@brunodesthuilliers, why not? Thanks!
– iGian
Dec 27 at 14:35
@brunodesthuilliers, why not? Thanks!
– iGian
Dec 27 at 14:35
add a comment |
0
As simple as this:
perfect_data['1'] = [i if i else -1 for i in perfect_data['1']]
answered Dec 27 at 14:37
Ssein
1,0161921
add a comment |
0
As simple as this:
perfect_data['1'] = [i if i else -1 for i in perfect_data['1']]
answered Dec 27 at 14:37
Ssein
1,0161921
add a comment |
0
0
0
As simple as this:
perfect_data['1'] = [i if i else -1 for i in perfect_data['1']]
answered Dec 27 at 14:37
Ssein
1,0161921
As simple as this:
perfect_data['1'] = [i if i else -1 for i in perfect_data['1']]
answered Dec 27 at 14:37
Ssein
1,0161921
answered Dec 27 at 14:37
Ssein
1,0161921
answered Dec 27 at 14:37
Ssein
1,0161921
answered Dec 27 at 14:37
Ssein
1,0161921
1,0161921
add a comment |
add a comment |
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1
x *= 2-1is the same asx *= 1.– interjay
Dec 27 at 14:28
okey, how can I multiply each item of a list by two and then subtract 1 from it?
– Ahmad
Dec 27 at 14:30
and multiplying a list doesn't yield the result you'd expect anyway <g>
– bruno desthuilliers
Dec 27 at 14:30