Graphviz Decision tree display separately for the same elements












0















I have the codes here, 



import graphviz as gv

d=gv.Digraph()

d.edge('a','b')

d.edge('a','c')

d.edge('b','c')


the output is as pic:



enter image description here



How can I get a graph like this:



enter image description here






python-3.x graphviz







share|improve this question





























    0















    I have the codes here, 



    import graphviz as gv
    
d=gv.Digraph()
    
d.edge('a','b')
    
d.edge('a','c')
    
d.edge('b','c')


    the output is as pic:



    enter image description here



    How can I get a graph like this:



    enter image description here






    python-3.x graphviz







    share|improve this question



























      0












      0








      0








      I have the codes here, 



      import graphviz as gv
      
d=gv.Digraph()
      
d.edge('a','b')
      
d.edge('a','c')
      
d.edge('b','c')


      the output is as pic:



      enter image description here



      How can I get a graph like this:



      enter image description here






      python-3.x graphviz







      share|improve this question
















      I have the codes here, 



      import graphviz as gv
      
d=gv.Digraph()
      
d.edge('a','b')
      
d.edge('a','c')
      
d.edge('b','c')


      the output is as pic:



      enter image description here



      How can I get a graph like this:



      enter image description here






      python-3.x graphviz




      python-3.x graphviz






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Jan 2 at 9:04









      albert

      2,96931123




      2,96931123










      asked Jan 2 at 3:47









      S.GuS.Gu

      8410




      8410
























          1 Answer
          1






          active

          oldest

          votes


















          1














          Not using Python, I only have a pure graphviz answer but you should be able to translate that easily into Python.



          You need to do two things:




          • Create four nodes, not three, and give them the label you want

          • Put the nodes you want to have on the same level into a rank = same instruction (not strictly necessary in the example context but may be needed for more complex graphs)


          Here we go:



          digraph so 
          
{
          
    n_1[ label = "a" ];
          
    n_2[ label = "b" ];
          
    n_3[ label = "c" ];
          
    n_4[ label = "c" ];
          

          
    { rank = same; n_2 n_3 }
          

          
    n_1 -> { n_2 n_3 };
          
    n_2 -> n_4;
          
}


          which gives you



          enter image description here






          share|improve this answer


























          • When necessary you can easily test something at webgraphviz.com

            – albert
            Jan 2 at 9:10











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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Not using Python, I only have a pure graphviz answer but you should be able to translate that easily into Python.



          You need to do two things:




          • Create four nodes, not three, and give them the label you want

          • Put the nodes you want to have on the same level into a rank = same instruction (not strictly necessary in the example context but may be needed for more complex graphs)


          Here we go:



          digraph so 
          
{
          
    n_1[ label = "a" ];
          
    n_2[ label = "b" ];
          
    n_3[ label = "c" ];
          
    n_4[ label = "c" ];
          

          
    { rank = same; n_2 n_3 }
          

          
    n_1 -> { n_2 n_3 };
          
    n_2 -> n_4;
          
}


          which gives you



          enter image description here






          share|improve this answer


























          • When necessary you can easily test something at webgraphviz.com

            – albert
            Jan 2 at 9:10
















          1














          Not using Python, I only have a pure graphviz answer but you should be able to translate that easily into Python.



          You need to do two things:




          • Create four nodes, not three, and give them the label you want

          • Put the nodes you want to have on the same level into a rank = same instruction (not strictly necessary in the example context but may be needed for more complex graphs)


          Here we go:



          digraph so 
          
{
          
    n_1[ label = "a" ];
          
    n_2[ label = "b" ];
          
    n_3[ label = "c" ];
          
    n_4[ label = "c" ];
          

          
    { rank = same; n_2 n_3 }
          

          
    n_1 -> { n_2 n_3 };
          
    n_2 -> n_4;
          
}


          which gives you



          enter image description here






          share|improve this answer


























          • When necessary you can easily test something at webgraphviz.com

            – albert
            Jan 2 at 9:10














          1












          1








          1







          Not using Python, I only have a pure graphviz answer but you should be able to translate that easily into Python.



          You need to do two things:




          • Create four nodes, not three, and give them the label you want

          • Put the nodes you want to have on the same level into a rank = same instruction (not strictly necessary in the example context but may be needed for more complex graphs)


          Here we go:



          digraph so 
          
{
          
    n_1[ label = "a" ];
          
    n_2[ label = "b" ];
          
    n_3[ label = "c" ];
          
    n_4[ label = "c" ];
          

          
    { rank = same; n_2 n_3 }
          

          
    n_1 -> { n_2 n_3 };
          
    n_2 -> n_4;
          
}


          which gives you



          enter image description here






          share|improve this answer















          Not using Python, I only have a pure graphviz answer but you should be able to translate that easily into Python.



          You need to do two things:




          • Create four nodes, not three, and give them the label you want

          • Put the nodes you want to have on the same level into a rank = same instruction (not strictly necessary in the example context but may be needed for more complex graphs)


          Here we go:



          digraph so 
          
{
          
    n_1[ label = "a" ];
          
    n_2[ label = "b" ];
          
    n_3[ label = "c" ];
          
    n_4[ label = "c" ];
          

          
    { rank = same; n_2 n_3 }
          

          
    n_1 -> { n_2 n_3 };
          
    n_2 -> n_4;
          
}


          which gives you



          enter image description here







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jan 2 at 11:53

























          answered Jan 2 at 9:06









          vaettchenvaettchen

          5,2601332




          5,2601332













          • When necessary you can easily test something at webgraphviz.com

            – albert
            Jan 2 at 9:10



















          • When necessary you can easily test something at webgraphviz.com

            – albert
            Jan 2 at 9:10

















          When necessary you can easily test something at webgraphviz.com

          – albert
          Jan 2 at 9:10





          When necessary you can easily test something at webgraphviz.com

          – albert
          Jan 2 at 9:10




















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