Using subqueries to show multiple answers which have this same value
I want to show this products which has the highest prize (group by manufacturer). But if two products has this same prize, SQL shows me one of them.
SELECT name, manufacturer, MAX(prize)
FROM products p
GROUP BY manufacturer
HAVING MAX(prize) = (SELECT MAX(p1.prize)
FROM products p1
WHERE p.manufacturer = p1.manufacturer
LIMIT 1
);
mysql sql database
edited Dec 27 at 13:42
Anson Aricatt
25313
asked Dec 27 at 13:30
programmer001
61
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add a comment |
I want to show this products which has the highest prize (group by manufacturer). But if two products has this same prize, SQL shows me one of them.
SELECT name, manufacturer, MAX(prize)
FROM products p
GROUP BY manufacturer
HAVING MAX(prize) = (SELECT MAX(p1.prize)
FROM products p1
WHERE p.manufacturer = p1.manufacturer
LIMIT 1
);
mysql sql database
edited Dec 27 at 13:42
Anson Aricatt
25313
asked Dec 27 at 13:30
programmer001
61
New contributor
programmer001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Sample data and desired results would help.
– Gordon Linoff
Dec 27 at 13:42
add a comment |
I want to show this products which has the highest prize (group by manufacturer). But if two products has this same prize, SQL shows me one of them.
SELECT name, manufacturer, MAX(prize)
FROM products p
GROUP BY manufacturer
HAVING MAX(prize) = (SELECT MAX(p1.prize)
FROM products p1
WHERE p.manufacturer = p1.manufacturer
LIMIT 1
);
mysql sql database
edited Dec 27 at 13:42
Anson Aricatt
25313
asked Dec 27 at 13:30
programmer001
61
New contributor
programmer001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I want to show this products which has the highest prize (group by manufacturer). But if two products has this same prize, SQL shows me one of them.
SELECT name, manufacturer, MAX(prize)
FROM products p
GROUP BY manufacturer
HAVING MAX(prize) = (SELECT MAX(p1.prize)
FROM products p1
WHERE p.manufacturer = p1.manufacturer
LIMIT 1
);
mysql sql database
mysql sql database
edited Dec 27 at 13:42
Anson Aricatt
25313
asked Dec 27 at 13:30
programmer001
61
New contributor
programmer001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 27 at 13:42
Anson Aricatt
25313
asked Dec 27 at 13:30
programmer001
61
New contributor
programmer001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited Dec 27 at 13:42
Anson Aricatt
25313
edited Dec 27 at 13:42
Anson Aricatt
25313
edited Dec 27 at 13:42
Anson Aricatt
25313
25313
asked Dec 27 at 13:30
programmer001
61
New contributor
programmer001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked Dec 27 at 13:30
programmer001
61
asked Dec 27 at 13:30
programmer001
61
61
New contributor
programmer001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
programmer001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
programmer001 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
Sample data and desired results would help.
– Gordon Linoff
Dec 27 at 13:42
add a comment |
1
Sample data and desired results would help.
– Gordon Linoff
Dec 27 at 13:42
1
1
Sample data and desired results would help.
– Gordon Linoff
Dec 27 at 13:42
Sample data and desired results would help.
– Gordon Linoff
Dec 27 at 13:42
add a comment |
2 Answers
2
active
oldest
votes
First select all the max prizes group by maufacturer and join to the main table:
select p.* from
(select manufacturer, MAX(prize) AS maxprize from products GROUP BY manufacturer) AS m
inner join products p
on m.manufacturer = p.manufacturer and m.maxprize = p.prize
order by p.manufacturer, p.name
See demo
answered Dec 27 at 14:07
forpas
8,3961419
add a comment |
You seem to want a simple subquery -- no aggregation in the outer query:
SELECT p.*
FROM products p
WHERE p.prize = (SELECT MAX(p2.prize)
FROM products p2
WHERE p2.manufacturer = p.manufacturer
);
As mentioned in your previous question, your use of GROUP BY is not correct. You have unaggregated columns in the SELECT that are not in the GROUP BY.
Your use of aggregation in the outer query is why you are getting only one row per manufacturer.
In terms of performance, this is often the fastest method -- with the right indexes. In this case, the right index is on (manufacturer, prize).
answered Dec 27 at 13:42
Gordon Linoff
758k35291399
You're right. This is correct.
– MarCPlusPlus
Dec 27 at 14:14
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
First select all the max prizes group by maufacturer and join to the main table:
select p.* from
(select manufacturer, MAX(prize) AS maxprize from products GROUP BY manufacturer) AS m
inner join products p
on m.manufacturer = p.manufacturer and m.maxprize = p.prize
order by p.manufacturer, p.name
See demo
answered Dec 27 at 14:07
forpas
8,3961419
add a comment |
First select all the max prizes group by maufacturer and join to the main table:
select p.* from
(select manufacturer, MAX(prize) AS maxprize from products GROUP BY manufacturer) AS m
inner join products p
on m.manufacturer = p.manufacturer and m.maxprize = p.prize
order by p.manufacturer, p.name
See demo
answered Dec 27 at 14:07
forpas
8,3961419
add a comment |
First select all the max prizes group by maufacturer and join to the main table:
select p.* from
(select manufacturer, MAX(prize) AS maxprize from products GROUP BY manufacturer) AS m
inner join products p
on m.manufacturer = p.manufacturer and m.maxprize = p.prize
order by p.manufacturer, p.name
See demo
answered Dec 27 at 14:07
forpas
8,3961419
First select all the max prizes group by maufacturer and join to the main table:
select p.* from
(select manufacturer, MAX(prize) AS maxprize from products GROUP BY manufacturer) AS m
inner join products p
on m.manufacturer = p.manufacturer and m.maxprize = p.prize
order by p.manufacturer, p.name
See demo
answered Dec 27 at 14:07
forpas
8,3961419
answered Dec 27 at 14:07
forpas
8,3961419
answered Dec 27 at 14:07
forpas
8,3961419
answered Dec 27 at 14:07
forpas
8,3961419
8,3961419
add a comment |
add a comment |
You seem to want a simple subquery -- no aggregation in the outer query:
SELECT p.*
FROM products p
WHERE p.prize = (SELECT MAX(p2.prize)
FROM products p2
WHERE p2.manufacturer = p.manufacturer
);
As mentioned in your previous question, your use of GROUP BY is not correct. You have unaggregated columns in the SELECT that are not in the GROUP BY.
Your use of aggregation in the outer query is why you are getting only one row per manufacturer.
In terms of performance, this is often the fastest method -- with the right indexes. In this case, the right index is on (manufacturer, prize).
answered Dec 27 at 13:42
Gordon Linoff
758k35291399
You're right. This is correct.
– MarCPlusPlus
Dec 27 at 14:14
add a comment |
You seem to want a simple subquery -- no aggregation in the outer query:
SELECT p.*
FROM products p
WHERE p.prize = (SELECT MAX(p2.prize)
FROM products p2
WHERE p2.manufacturer = p.manufacturer
);
As mentioned in your previous question, your use of GROUP BY is not correct. You have unaggregated columns in the SELECT that are not in the GROUP BY.
Your use of aggregation in the outer query is why you are getting only one row per manufacturer.
In terms of performance, this is often the fastest method -- with the right indexes. In this case, the right index is on (manufacturer, prize).
answered Dec 27 at 13:42
Gordon Linoff
758k35291399
You're right. This is correct.
– MarCPlusPlus
Dec 27 at 14:14
add a comment |
You seem to want a simple subquery -- no aggregation in the outer query:
SELECT p.*
FROM products p
WHERE p.prize = (SELECT MAX(p2.prize)
FROM products p2
WHERE p2.manufacturer = p.manufacturer
);
As mentioned in your previous question, your use of GROUP BY is not correct. You have unaggregated columns in the SELECT that are not in the GROUP BY.
Your use of aggregation in the outer query is why you are getting only one row per manufacturer.
In terms of performance, this is often the fastest method -- with the right indexes. In this case, the right index is on (manufacturer, prize).
answered Dec 27 at 13:42
Gordon Linoff
758k35291399
You seem to want a simple subquery -- no aggregation in the outer query:
SELECT p.*
FROM products p
WHERE p.prize = (SELECT MAX(p2.prize)
FROM products p2
WHERE p2.manufacturer = p.manufacturer
);
As mentioned in your previous question, your use of GROUP BY is not correct. You have unaggregated columns in the SELECT that are not in the GROUP BY.
Your use of aggregation in the outer query is why you are getting only one row per manufacturer.
In terms of performance, this is often the fastest method -- with the right indexes. In this case, the right index is on (manufacturer, prize).
answered Dec 27 at 13:42
Gordon Linoff
758k35291399
edited Dec 27 at 14:10
answered Dec 27 at 13:42
Gordon Linoff
758k35291399
answered Dec 27 at 13:42
Gordon Linoff
758k35291399
answered Dec 27 at 13:42
Gordon Linoff
758k35291399
758k35291399
You're right. This is correct.
– MarCPlusPlus
Dec 27 at 14:14
add a comment |
You're right. This is correct.
– MarCPlusPlus
Dec 27 at 14:14
You're right. This is correct.
– MarCPlusPlus
Dec 27 at 14:14
You're right. This is correct.
– MarCPlusPlus
Dec 27 at 14:14
add a comment |
programmer001 is a new contributor. Be nice, and check out our Code of Conduct.
programmer001 is a new contributor. Be nice, and check out our Code of Conduct.
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1
Sample data and desired results would help.
– Gordon Linoff
Dec 27 at 13:42